On one of my webpage, I show a list of customer details with default pagination [Paginator helper]. Each customer row has a corresponding 'edit' button which when clicked shows a DIV populated with that customer information. [This DIV has textboxes etc. where I can change customer info] After re-entering/modifying customer details, when I click on "Save" button, 2 ajax calls are made..
First one to save the edited record
The second one Updates the customer Listing on the same page with modified information
My problem : If I am on page 3 and edit one customer record, the 2nd ajax call refreshes the list but does not go to the page 3. It starts from page 1.
Please help.
You can get your current page here:
<?php echo $this->Paginator->counter(array(
'format' => ('{:page}')
)); ?>
This is part of the solution. :)
You can get your current page here:
$this->request->params['named']['page']
Did you try to use the link from Paginator? It maintains the page # to the controller.
Something like
// same parameters as $this->Html->link
<?php echo $this->Paginator->link( ... ) ?>
Check also the reference documentation for the Paginator Helper
I use jquery / javascript to store the page on a cookie and then read it from the controller.
// -------------------------------------------------------------------------
// on action click remember current page
$('td.actions').click( function( event )
{
var page = $('li.active a').html();
var name = window.location.href.split('-').join('_').split('/').pop();
$.cookie.raw = true;
$.cookie( 'CakeCookie[' + name + '_page]', page, { expires: 365, path: '/' } );
});
Related
Controller Name : SaleController.php
action name : index.ctp
When I write localhost/cakephp/Sale/index is written in address bar,
index page of SaleController is shown.
When I write localhost/cakephp/Sale/ is written in address bar,
index page of SaleController is shown.
Now,problem is I don't want to go index file when localhost/cakephp/Sale/ is written.
My cakephp version is 2.5.7.
If know ways,help me plz.
there is a lot of solutions :
Select view in the controller
in your SaleController.php
function index(){
$this->view="nameview.ctp";
}
Routes :
Router::connect(
'Sale/',
array('controller' => 'Sale' , 'action'=>'youraction' ),
array('option' => 'matchingRegex')
);
Select an other action in index
function index(){
$this->actionName();
}
First of all, your controller name should be SalesController (plural s).
Second, action is a method within controller not a file (here index mehod).
Third, index.ctp is a view file.
Fourth, you can change view in action method with render function (e.g. $this->render('other.ctp'); )
Fifth you can have custom URLs with routes.
And last but not least! you've not grabbed a good understanding of the framework, It's better to restudy the documentation.
How can I get next navigation url without html code ?
$this->Paginator->next();
//output
Next
I just need url only.
The paginator helper itself doesn't support that, the least HTML'd return value (tag => false) is a simple anchor element, so you'll have to build the URL on your own, which is pretty simple tough.
What you need is the current page number, this can be retrieved via PaginatorHelper::params(), the page key in the returned array holds the current page.
All you have to do then is add 1 to it, and pass a URL array with the key page and the new page number as its value to Router::url() and you'll get the URL for the next page:
$params = $this->Paginator->params();
$url = array(
'page' => $params['page'] + 1
);
echo Router::url($url);
ps. you might want to check whether there is actually a next page using PaginatorHelper::hasNext()
if($this->Paginator->hasNext())
{
// ...
}
I have designed page in cakephp contains form which input filed name 'id' and submit button. I want to display the data filtered by the 'id' in view page. Please give me an example with code for this.
So you wanna search into a database for this ID and return back all stored data to the view?
First of all,you have to retrieve your data. See here: http://book.cakephp.org/2.0/en/models/retrieving-your-data.html
Secondly, you have to use
$this->set('var_name', $var_name_containing_found_data);
and finally you can handle your data into the view by manipulating as you wish the $var_name variable.
Put this action in your controller:
public function your_action($id = null) {//your action
if ($this->request->is('post')) {
$search = $this->YourModel->find('all', array('conditions' => array('id' => $this->request->data['id'])));//assuming id is submitted like you said $_POST['id']
$this->set('search', $search);
}
}
You can access the search variable in your view (your_view.ctp) like this $this->search
assuming your cakephp version is 2.x
Am working with views and am wondering if there is a way to get the view to update the breadcrumb trail. When on my first view called homme the breadcrumbs are not updated it still just says "home >" as if it is still on the homepage. When I click a post the breadcrumbs update to "Home › Blogs › admin's blog › ". I need it to say Home > Homme > Name of Article, basically what you would expect when going to a blog site or post.
Can I get the view to act like a blog?
One option is to try overriding the themeable output generated by the default breadcrumb function.
Assuming you've created your own theme - create a file called template.php at the root of your theme. Create a function named YOURTHEME_breadcrumb, where YOURTHEME is the name of the theme. The HTML returned by this function will be the breadcrumb. Modify the return values as necessary here to get what you want. Consider using Drupal's menu functions to build a more satisfactory breadcrumb.
Check the comments of this API article for more detail: http://api.drupal.org/api/drupal/includes--theme.inc/function/theme_breadcrumb/7
Adding this to your template.php file should work with d7 sites:
function theme_breadcrumb($breadcrumb)
{
if (substr($_GET['q'], 0, 13) == 'news/category') {
$breadcrumb[] = l('News', 'news/');
}
if (count($breadcrumb) > 1) {
if ($breadcrumb) {
return '<div class="breadcrumb">'. implode(' › ', $breadcrumb) ."</div>\n";
}
}
}
I ve tried to implemented filtering data (list base on selected category) using dropdown with observefield and ajax pagination. I use session to remember selected category in order to keep pagination.
Here is my code (Cakephp 1.2)
In view :
echo $form->select('Category.id', $categories, null, array('id' => 'categories'),'Filter by Categories')
echo $ajax->observeField('categories' ,array('url' =>'update_category','update' => 'collectionDiv'));
In Controller:
if(!empty($this->data['Category']['id']))
{
$cat_id=$this->data['Category']['id'];
$filters=array('Collection.category_id' => $cat_id);
$this->set('collections', $this->paginate('Collection', $filters));
$this->Session->write($this->name.'.$cat_id', $category_id);
}
else
{
$cat_id=$this->Session->read($this->name.'.cat_id');
$filters=array('Collection.category_id' => $cat_id);
$this->set('collections', $this->paginate('Collection'));
}
The filter work as I wanted but the problem is when I select empty value('Filter by Category) it still remember last category session so I can't back to the default list (All record list without filter).
I've tried to make some condition but still not success. Is there another way? Please I appreciate your help. thank
hermawan
Perhaps I don't understand the question, but it looks to me like it might be worth changing:
else
{
$cat_id=$this->Session->read($this->name.'.cat_id');
$filters=array('Collection.category_id' => $cat_id);
$this->set('collections', $this->paginate('Collection'));
}
to:
else
{
$this->set('collections', $this->paginate('Collection',array()));
}
In effect your code appears to be doing this anyway. Check what the URL is at the top of the browser window after it has returned. Does it still contain pagination directives from the previous query?
You might want to review http://book.cakephp.org/view/167/AJAX-Pagination and make sure you've 'ticked all the boxes'.
I got it, It work as I hope now. I my self explain the condition and solution.
When I select category from combobox, then it render the page the code is :
If ($this->data['Category']['id']) {
$cat_id=$this->data['Category']['id'];
$this->Session->write($this->name.'.category_id', $category_id);
// I will use this session next when I click page number
$filters=array('Collection.art_type_id' => $category_id);
$this->set('collections', $this->paginate('Collection', $filters));
}else{
//if clik page number, next or whatever, $this->data['Category']['id'] will empty so
// use session to remember the category so the page will display next page or prev
// page with the proper category, But the problem is, when I set category fillter to
// "All Category" it will dislpay last category taked from the session. To prevent it
// I used $this->passedArgs['page']. When I clik the page paginator it will return
// current number page, but it will be empty if we click dropdown.
if (!empty($this->passedArgs['page']) {
$cat_id=$this->Session->read($this->name.'.category_id');
$filters=array('Collection.category_id' => $cat_id);
$this->set('collections', $this->paginate('Collection',$filters));
}else{
$this->set('collections', $this->paginate('Collection'));
}
}
From this case, I think that observefield will not send passedArg as we get from url such from ajax link or html->link. I hope this will usefull to anybody