I have a table in which i am storing dates and other information.
I wanna display the records for the dates which are not stored in the table.
Eg.. i have dates 01/01/2012[dd/mm/yyyy] , 03/01/2012 , 06/01/2012.
I wanna show the output for the dates 02/01/2012 ,04/05/2012 , 05/01/2012.
Query for this please in SQLServer2008
You can use the DATEADD function. For example, to add 1 day to current date:
SELECT DATEADD(dd, 1, GETDATE())
You can find more information on MSDN.
;WITH MYCTE AS
(
SELECT CAST('1900-01-01' AS DATETIME) DateValue
UNION ALL
SELECT DateValue + 1
FROM MYCTE
WHERE DateValue + 1 < '3550-12-31'
)
SELECT DateValue, B.SomeColumn
FROM MYCTE A
LEFT JOIN MyTable B ON A.DateValue = B.DateValue
OPTION (MAXRECURSION 0)
I got the date range cte from here (and it takes 4 seconds to generate a table of 250000 rows)
This code displays all dates from 2011 year missing in your table:
create table #dates (d datetime);
declare #start_period datetime;
set #start_period='01.01.2011';
declare #end_period datetime;
set #end_period='01.01.2012';
declare #d datetime;
set #d=#start_period
while(#d<#end_period)
begin
insert into #dates (d) values (#d)
SET #d=#d+1
end
select d from #dates where d not in (select <date> from <your_table>)
Related
There is a table in SQL Server where data is entered day by day. In this table, data is not filled in some days.
Therefore, there are no records in the table.
Sample: dataTable
I need to generate a report like the one below from this table.
Create a table with all the days of the year. I know that I can output a report by "joining" the "dataTable" table.
But this solution seems a bit strange to me.
Is there another way?
the code i use for temp date table
CREATE TABLE tempDate (
calendarDate date,
PRIMARY KEY (calendarDate)
)
DECLARE
#start DATE= '2021-01-01',
#dateCount INT= 730,
#rowNumber INT=1
WHILE (#rowNumber < #dateCount)
BEGIN
INSERT INTO tempDate values (DATEADD(DAY, #rowNumber, #start))
set #rowNumber=#rowNumber+1
END
GO
select * from tempDate
This is how I join using this table
SELECT
*
FROM
tempDate td WITH (NOLOCK)
LEFT JOIN dataTable dt WITH (NOLOCK) ON dt.reportDate = td.calendarDate
WHERE
td.calendarDate BETWEEN '2021-09-05' AND '2021-09-15'
Create a table with all the days of the year. I know that I can output a report by "joining" the "dataTable" table.
This is the way. You can generate that "table" on the fly if you really want to, but normally the best way is to simply have a calendar table.
You can use common expression tables for dates. The code you need:
IF(OBJECT_ID('tempdb..#t') IS NOT NULL)
BEGIN
DROP TABLE #t
END
CREATE TABLE #t
(
id int,
dt date,
dsc varchar(100),
)
INSERT INTO #t
VALUES
(1, '2021.09.08', 'a'),
(1, '2021.09.09', 'b'),
(1, '2021.09.12', 'c')
DECLARE #minDate AS DATE
SET #minDate = (SELECT MIN(dt) FROM #t)
DECLARE #maxDate AS DATE
SET #maxDate = (SELECT MAX(dt) FROM #t)
;WITH cte
AS
(
SELECT #minDate AS [dt]
UNION ALL
SELECT DATEADD(DAY, 1, [dt])
FROM cte
WHERE DATEADD(DAY, 1, [dt])<=#maxDate
)
SELECT
ISNULL(CAST(t.id AS VARCHAR(10)), '') AS [id],
cte.dt AS [dt],
ISNULL(t.dsc, 'No record has been entered in the table.') AS [dsc]
FROM
cte
LEFT JOIN #t t on t.dt=cte.dt
The fastest method is to use a numbers table, you can get a date list between 2 dates with that:
DECLARE #Date1 DATE, #Date2 DATE
SET #Date1 = '20200528'
SET #Date2 = '20200625'
SELECT DATEADD(DAY,number+1,#Date1) [Date]
FROM master..spt_values
WHERE type = 'P'
AND DATEADD(DAY,number+1,#Date1) < #Date2
If you go go in LEFT JOIN this select, whit your table, you have the result that you want.
SELECT *
FROM (SELECT DATEADD(DAY,number+1,#Date1) [Date]
FROM master..spt_values WITH (NOLOCK)
WHERE type = 'P'
AND DATEADD(DAY,number+1,#Date1) < #Date2 ) as a
LEFT JOIN yourTable dt WITH (NOLOCK) ON a.date = dt.reportDate
WHERE td.[Date] BETWEEN '2021-09-05' AND '2021-09-15'
I wrote a query that should select the last record of each month in a year. I'd like to create a View based on this select, that I could run later in my project, but unfortunately I can't use any while loops or variables in a view command. Is there a way to select all these records - last days of a month in a View that I can use later?
My desired effect of the view:
The query that I'm trying to implement in a view:
DECLARE #var_day01 DATETIME;
DECLARE #month int;
SET #month = 1;
DROP TABLE IF EXISTS #TempTable2;
CREATE TABLE #TempTable2 (ID int, date datetime, INP2D float, INP3D float, ID_device varchar(max));
WHILE #month < 13
BEGIN
SELECT #var_day01 = CONVERT(nvarchar, date) FROM (SELECT TOP 1 * FROM data
WHERE DATEPART(MINUTE, CONVERT(nvarchar, date)) = '59'
AND
MONTH(CONVERT(nvarchar, date)) = (CONVERT(nvarchar, #month))
ORDER BY date DESC
) results
ORDER BY date DESC;
INSERT INTO #TempTable2 (ID, date, INP2D,INP3D,ID_device)
SELECT * FROM data
WHERE DATEPART(MINUTE, CONVERT(nvarchar, date)) = '59'
AND
MONTH(CONVERT(nvarchar, date)) = (CONVERT(nvarchar, #month))
AND
DAY(CONVERT(nvarchar, date)) = CONVERT(datetime, DATEPART(DAY, #var_day01))
ORDER BY date DESC
PRINT #var_day01
SET #month = #month +1;
END
SELECT * FROM #TempTable2;
If you are actually just after the single most recent row for each month, there is no need for a while loop to achieve this. You just need to identify the max date value for each month and then filter your source data for those for those rows.
One way to achieve this is via a row_number window function:
declare #t table(id int,dt datetime2);
insert into #t values(1,getdate()-40),(2,getdate()-35),(3,getdate()-25),(4,getdate()-10),(5,getdate());
select id
,id_device
,dt
from(select id
,id_device
,dt
,row_number() over (partition by id_device, year(dt), month(dt) order by dt desc) as rn
from #t
) as d
where rn = 1;
You can add a simple where to your select statement, in where clause you will add one day to the date field and then select the day from the resultant date. If the result date is 1 then only you will select that record
the where clause for your query will be : Where Day(DATEADD(d,1,[date])) = 1
I need to populate a temp table with dates between and including 2 date parameters, let's say start date is 2014-01 and end date is present.
So far, I had managed to do it, but I need only "year-month" format.
Don't need any days involved.
declare #StartDate date = '2014-01-01';
declare #EndDate date = getdate();
;WITH cte AS (
SELECT #StartDate AS myDate
UNION ALL
SELECT DATEADD(day,1,myDate) as myDate
FROM cte
WHERE DATEADD(day,1,myDate) <= #EndDate
)
SELECT myDate
FROM cte
OPTION (MAXRECURSION 0)
Actual Results
2014-01-01
2014-01-02
Expected Result
2014-01
2014-02
2014-03
Replace day with month as in:
declare #StartDate date = '2014-01-01';
declare #EndDate date = getdate();
;WITH cte AS (
SELECT #StartDate AS myDate
UNION ALL
SELECT DATEADD(month,1,myDate) as myDate
FROM cte
WHERE DATEADD(month,1,myDate) <= #EndDate
)
and using the conversion suggested here:
SELECT FORMAT(myDate, 'yyyy-MM')
FROM cte
OPTION (MAXRECURSION 0)
I am trying to get the activity codes for specific days to show the 31 days in every month of the year for a specific staff member.
If the staff member was present, sick, holiday leave, etc... I want those activity codes to display based on the output below for a year act_date range.
Thanks!
Pivot Activity Code Days Months
This can be achieved with pivoting. Here you can enter the staff id in the query to fetch the results for that particular staff.
--create table
create table staff_info
(
staffId int,
actDate datetime,
activityCode int
)
--insert values
insert into staff_info values
(2699, '01/02/2017', 101),
(2699, '05/14/2017', 303),
(2699, '08/06/2017', 101),
(1927, '10/25/2017', 105)
--actual solution
select * from
(
select staffId, day(actDate) as act_day,month(actDate) as actual_month,
activityCode
from staff_info
where staffId=2699 ----- enter the staff id here
) src
pivot
(
sum(activityCode)
for act_day in ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12],[13],
[14],[15],
[16],[17],[18],[19],[20],[21],[22],[23],[24],[25],[26],[27],[28],[29],[30],
[31]
)
) p
Result:
Firstly, create a function which would give the date values for a specific range
CREATE FUNCTION [dbo].[GetAllDatesBetweenRange]
(
#FromDate DATE
,#ToDate DATE
)
RETURNS #Dates TABLE
(
DateVal DATE
)
AS
BEGIN
;WITH CTE
AS
(
SELECT #FromDate AS FromDate
UNION ALL
SELECT DATEADD(DD,1,FromDate)
FROM CTE
WHERE FromDate < #ToDate
)
INSERT INTO #Dates
SELECT FromDate FROM CTE
OPTION (MAXRECURSION 0)
RETURN;
END
GO
Use the below dynamic query to pivot for the specific date range
DECLARE #Sql NVARCHAR(MAX);
DECLARE #DateVal NVARCHAR(MAX);
SELECT #DateVal = STUFF((SELECT ',['+CAST(DateVal AS NVARCHAR(50))+']'
FROM [dbo].[GetAllDatesBetweenRange]('2017-01-01','2017-12-31')
FOR XML PATH('')),1,1,'')
SET #Sql = '
;WITH CTE
AS
(
SELECT Res1.STAFF_ID
,Res2.DateVal
,Res1.ACTIVITY_CODE
FROM [dbo].[GetAllDatesBetweenRange](''''2017-01-01'''',''''2017-12-31'''') Res1
LEFT JOIN TableA A ON A.ACT_DATE = Res1.DateVal
)
SELECT STAFF_ID
,*
FROM CTE
PIVOT
(
MAX(ACTIVITY_CODE)
FOR DateVal IN ('+#DateVal+')'+'
)'
EXEC SP_EXECUTESQL #Sql
Given the following example query, what is a sound and performant approach to counting the total days in a date range when also given a set of ranges to exclude, given that those ranges may have dates which overlap?
More simply, I have a table with a set of date ranges where the billing is turned off, I start with a date range (say Jan1 - Jan31) and I need to determine how many billable days occured in that range. Simply a datediff of the days minus a sum of the datediff on the disabled days. However, there is a chance that the disabled date ranges overlap, ie disabled Jan5-Jan8 in one record and Jan7-Jan10 in another record - thus a simple sum would double count Jan7. What is the best way to exclude these overlaps and get an accurage count.
Declare #disableranges table (disableFrom datetime, disableTo datetime)
insert into #disableranges
select '01/05/2013', '01/08/2013' union
select '01/07/2013', '01/10/2013' union
select '01/15/2013', '01/20/2013'
declare #fromDate datetime = '01/01/2013'
declare #toDate datetime = '01/31/2013'
declare #totalDays int = DATEDIFF(day,#fromDate,#toDate)
declare #disabledDays int = (0 /*not sure best way to calc this*/)
select #totalDays - #disabledDays
You can use a recursive CTE to generate dates between #dateFrom and #dateTo. Then compare the dates with the ranges, and find all dates that are in any range. Finally, count the number of rows in the result to get the count of disabled dates (DEMO):
-- recursive CTE to generate dates
;with dates as (
select #fromDate as date
union all
select dateadd(day, 1, date)
from dates
where date < #toDate
)
-- join with disable ranges to find dates in any range
, disabledDates as (
select date from dates D
left join #disableranges R
on D.date >= R.disableFrom and d.Date < R.disableTo
group by date
having count(R.disablefrom) >= 1
)
-- count up the total disabled dates
select #disabledDays=count(*) from disabledDates;
Tried this and working okay as far as I am concerned.
Declare #disableranges table (disableFrom datetime, disableTo datetime)
insert into #disableranges
select '01/05/2013', '01/08/2013' union
select '01/07/2013', '01/10/2013' union
select '01/15/2013', '01/20/2013'
declare #fromDate datetime = '01/01/2013'
declare #toDate datetime = '01/31/2013'
declare #totalDays int = DATEDIFF(day,#fromDate,#toDate) + 1 /*Without +1 it is giving 30 instead of 31*/
declare #disabledDays int = (0 /*not sure best way to calc this*/)
/*Fill temporary table with the given date range.*/
SELECT DATEADD(DAY, nbr - 1, #fromDate) TempDate INTO #Temp
FROM ( SELECT ROW_NUMBER() OVER ( ORDER BY c.object_id ) AS Nbr
FROM sys.columns c
) nbrs
WHERE nbr - 1 <= DATEDIFF(DAY, #fromDate, #toDate)
/*Check how many dates exists in the disableranges table*/
SELECT #disabledDays=count(*) from #Temp t WHERE
EXISTS(SELECT * FROM #disableranges
WHERE t.TempDate BETWEEN disableFrom AND DATEADD(d, -1, disableTo))
select #totalDays /*Output:31*/
select #disabledDays /*Output:10*/
select #totalDays - #disabledDays /*Output:21*/
drop table #Temp
Taken help from the answer https://stackoverflow.com/a/7825036/341117 to fill table with date range