Migrating code from a PIC18F2480 to a PIC18F2680 Microcontroller - c

I have bootloader code written in MPLAB for an 18F2480 processor. My current project requires me to upgrade the microcontroller to an 18F2680.
(The main difference between the two chips is that the 2480 has 16K of program memory/768B RAM/ 256B EEPROM while the 2680 chip has 64K of program memory/3K of RAM and 1K of EEPROM.)
I have changed the selected device to "PIC18f2680" as well as replaced the 2480 header file for the 18f2680.h file. I am having complications communicating with the 2680 using the program I normally use to update the 2480 firmware.
(I cannot provide details on this software as it is propietary.)
I just wanted to know if there are any known issues/complications that come with migrating code from a 2480 to a 2680.
And FWIW, I have successfully replaced the 2480 with a 2580 which has 32K of program memory, 1536 RAM bytes, and 256B of EEPROM. The code works fine and all I had to do was replace the header file and choose a different device in MPLAB. Could it have to do with the different size of EEPROM for the 24/2580 and the 2680?

The PIC 18f2480 has a programming block of 32 bytes ( Datasheet Chapter 7.5 ).
The PIC 18F2680 has a programming block of 64 bytes ( Datasheet Chapter 6.5 ).
So the boot loader needs to be changed to use a different block size.

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What does it mean for a program to be 32 or 64 bit? [closed]

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This question: How many bits does a WORD contain in 32/64 bit OS respectively?, mentions that word size refers to the bit size of a processor register - which i take to mean the number of bits that a computer processor operates on / i.e. the smallest 'indivisible' amount of bits that a processor operates on.
Is that correct? Using software like Word/Excel/etc, the installers have the option for a 32bit or a 64bit installation. What is the difference?
Since the computer architecture is fixed, it would seem to me that software that is '32 bit' would be designed to align with a computer architecture that has a 32 bit architecture. And a 64 bit program would make efforts to align instruction sets with 64 bit word sizes.
Is that correct?
A very similar question is asked here: From a programming point of view, what does it mean when a program is 32 or 64 bit? - and the accepted answer mentions that the difference is the amount of memory that can be allocated to an application. But this is too vague - unless 32 bit / 64 bit software as a concept is completely unrelated to 32 bit / 64 bit word processor size?
Word size is a major difference, but it's not the only one. It tends to define the number of bits a CPU is "rated" for, but word size and overall capability are only loosely related. And overall capability is what matters.
On an Intel or AMD CPU, 32-bit vs. 64-bit software really refers to the mode in which the CPU operates when running it. 32-bit mode has fewer/smaller registers and instructions available, but the most important limitation is the amount of memory available. 32-bit software is generally limited to using between 2GB and just under 4GB of memory.
Each byte of memory has a unique address, which is not very different from each house having a unique postal address. A memory address is just a number that a program can use to find a piece of data again once it has saved it in memory, and each byte of memory has to have an address. If an address is 32 bits, then there are 2^32 possible addresses, and that means 2^32 addressable bytes of memory. On today's Intel/AMD CPUs, the size of a memory address is the same as the size of the registers (although this wasn't always true).
With 32 bit addresses, 4GB (2^32 bytes) can be addressed by the program, however up to half of that space is reserved by the OS. Into the available memory space must fit program code, data, and often also files being accessed. In today's PCs, with many gigabytes of RAM, this fails to take advantage of available memory. That is the main reason why 64-bit has become popular. 64-bit CPUs were available and widely used (typically in 32-bit mode) for several years, until memory sizes larger than 2GB became common, at which point 64-bit mode started to offer real-world advantages and it became popular. 64 bits of memory address space provides 16 exabytes of addressable memory (~18 quintillion bytes), which is more than any current software can use, and certainly no PC has anywhere near that much RAM.
The majority of data used in typical applications, even in 64-bit mode, does not need to be 64-bit and so most of it is still stored in 32-bit (or even smaller) formats. The common ASCII and UTF-8 representations of text use 8-bit data formats. If the program needs to move a large block of text from one place to another in memory, it may try to do it 64 bits at a time, but if it needs to interpret the text, it will probably do it 8 bits at a time. Similarly, 32 bits is a common size for integers (maximum range of +/- 2^31, or approximately +/- 2.1 billion). 2.1 billion is enough range for many uses. Graphics data is usually naturally represented pixel by pixel, and each pixel, usually, contains at most 32 bits of data.
There are disadvantages to using 64-bit data needlessly. 64-bit data takes up more space in memory, and more space in the CPU cache (very fast memory used by the CPU for short-term storage). Memory can only transfer data at a maximum rate, and 64-bit data is twice as big. This can reduce performance if used wastefully. And if it's necessary to support both 32-bit and 64-bit versions of software, using 32-bit values where possible can reduce the differences between the two versions and make development easier (doesn't always work out that way, though).
Prior to 32-bit, the address and word size were usually different (e.g. 16-bit 8086/88 with 20-bit memory addresses but 16-bit registers, or 8-bit 6502 with 16-bit memory addresses, or even early 32-bit ARM with 26-bit addresses). While no programmer ever turned up their nose at better registers, memory space was usually the real driving force for each advancing generation of technology. This is because most programmers rarely work directly with registers, but do work directly with memory, and memory limitations directly cause unpleasantness for the programmer, and in the 32-bit to 64-bit case, for the user as well.
To sum up, while there are real and important technological differences between the various bit sizes, what 32-bit or 64-bit (or 16-bit or 8-bit) really means is simply a collection of capabilities that tend to be associated with CPUs of a particular technological generation, and/or software that takes advantage of those capabilities. Word length is a part of that, but not the only, or necessarily the most important part.
Source: Have been programmer through all these technological eras.
The answer you reference describes benefits of 64-bit over 32-bit. As far as what's actually different about the program itself, it depends on your perspective.
Generally speaking, the program source code does not have to be different at all. Most programs can be written so that they compile perfectly well as either 32-bit or 64-bit programs, as controlled by appropriate choice of compiler and / or compiler options. There is often some impact on the source, however, in that a (C) compiler targeting 64-bit may choose to define its types differently. In particular, long int is ubiquitously 32 bits wide on 32-bit platforms, but it is 64 bits wide on many (but not all) 64-bit platforms. This can be a source of bugs in code that makes unwarranted assumptions about such details.
The main differences are all in the binary. 64-bit programs make use of the full instruction sets of their 64-bit target CPUs, which invariably contain instructions that 32-bit counterpart CPUs do not contain. They will use registers that 32-bit counterpart CPUs do not have. They will use function-call conventions appropriate for their target CPU, which often means passing more arguments in registers than 32-bit programs do. Use of these and other facilities of 64-bit CPUs affords functional advantages such as the ability to use more memory and (sometimes) improved performance.
A program runs on top of a given architecture (arch, or ISA), which is implemented by processors. Typically, an architecture defines a "main" word size, which is the size most of the registers and operations on those registers run (although you can design architectures that work differently). This is usually called the "native" word size, although an architecture may allow operations using different sized registers.
Further, processors use memory, and need to address that memory somehow -- this means operating with those addresses. Therefore, the addresses are typically able to be stored and manipulated like any other number, which means you have registers capable of holding them. Although it is not required that those registers to match the word size nor it is required that an address is computed out of a single register, in some architectures this is the case.
Throughout history, there have been many architectures of different word sizes, even weird ones. Nowadays, you can easily find processors around you that are not just 32-bit and 64-bit, but also e.g. 8-bit and 16-bit (typically in embedded devices). In the typical desktop computer, you are using x86 or x64, which are 32-bit and 64-bit respectively.
Therefore, when you say that a program is 32-bit or 64-bit, you are referring to a particular architecture. In the popular desktop scenario, you are referring to x86 vs. x64. There are many questions, articles and books discussing the differences between the two.
Now, a final note: for compatibility reasons, x64 processors can operate in different modes, one of which is capable of running the 32-bit code from x86. This means that if your computer is x64 (likely) and if your operating system has support for it (also likely, e.g. Windows 64-bit), it can still run programs compiled for x86.
Using software like Word/Excel/etc, the installers have the option for a 32bit or a 64bit installation. What is the difference?
This depends on the CPU used:
On SPARC CPUs, the difference between "32-bit" and "64-bit" programs is exactly what you think:
64-bit programs use additional operations that are not supported by 32-bit SPARC CPUs. On the other hand the Solaris or Linux operating system places the data accessed by 64-bit programs in memory areas which can only be accessed using 64-bit instructions. This means that a 64-bit program even MUST use instructions not supported by 32-bit CPUs.
For x86 CPUs this is different:
Modern x86 CPUs have different operating modes and they can execute different types of code. In the different modes, they can execute 16-, 32- or 64-bit code.
In 16-, 32- and 64-bit code, the CPU interprets the bytes differently:
The bytes (hexadecimal) b8 4e 61 bc 00 c3 would be interpreted as:
mov eax,0xbc614e
ret
... in 32-bit code and as:
mov ax,0x614e
mov sp,0xc300
... in 16 bit code.
The bytes in the EXE file of the "64-bit installation" and of the "32-bit installation" must be interpreted differently by the CPU.
And a 64 bit program would make efforts to align instruction sets with 64 bit word sizes.
16-bit code (see above) can access 32-bit registers when the CPU is not a 16-bit CPU.
So a "16-bit program" can access 32-bit registers on a 32- or 64-bit x86 CPU.
mentions that word size refers to the bit size of a processor register
Generally yes (though there are some exceptions/complications)
which I take to mean the number of bits that a computer processor operates on / i.e. the smallest 'indivisible' amount of bits that a processor operates on.
No, most processor architectures can work on values smaller than their native word size. A better (but not perfect) definition would be the largest piece of data that the processor can process (through the main integer datapath) as a single unit.
In general on modern 32-bit and 64-bit systems pointers are the same size as the word size, though on many 64-bit systems not all bits of said pointer are actually usable. It is possible to have a memory model where addressable memory is greater than the system's native word size and it was common to do so in the 8-bit and 16-bit eras, but it has fallen out of favour since the introduction of 32-bit CPUs.
Since the computer architecture is fixed
While the physical architecture is of course fixed, many processors have multiple operating modes with different instructions and registers available to the programmer. In 64-bit mode, the full features of the CPU are available, in 32-bit mode, the processor presents a backwards compatible interface which limits the features and the address space. The modes are sufficiently different that code must be compiled for a particular mode.
As a general rule, an OS running in 64-bit mode can support applications running in 32-bit mode but not vice-versa.
So a 32-bit application runs in 32-bit mode on either a 32-bit processor running a 32-bit OS, a 64-bit processor running a 32-bit OS or a 64-bit processor running a 64-bit OS.
A 64-bit application on the other hand normally runs only on a 64-bit processor running a 64-bit OS.
The information you have is a good part of the picture, but not all of it. I'm not a processor expert, so there are likely some details that my answer will be missing.
The 32 bit vs 64 bit is related to the processor architecture. An increase in word size does a few things:
Larger word size enables more instructions to be defined. For instance, and 8-bit processor that does a single load instruction can only have 256 total instructions, where a larger word size allows more instructions to be defined in the processors micro-code. Obviously, there is a limit to how many truly useful instructions are defined.
More data can be processed with a single instruction cycle as there are more bits available. This speeds up execution.
Like you stated, it also allows access to a larger memory space without having to do things like multiple address cycles, or multiplexing high/low data words.
When the processor architecture moves from 32-bit to 64-bit, the chip manufacturer will likely maintain compatibility with the previous instruction set, so that all the software that was developed previously will still run on the new architecture. When you target the 64-bit architecture, the compiler will have new instructions available and memory addressing schemes with which to process data more efficiently.
Short answer: This is a convention based solely on the width of the underlying data bus
An n-bit program is a program that is optimized for an n-bit CPU. Said otherwise a 64-bit program is a binary program compiled for a 64 bit CPU. A 64 bit CPU, in turn, is one taking advantage of a 64-bit data bus for the exchange of data between CPU and memory.
That's as simple, but you can read more below.
The definition actually redirects to understanding what is a 32/64 bit CPU, indirectly to what is a 32/64 bit operating system, and how compilers optimize binaries for a given architecture.
Optimization here encompasses the format of the binary itself. 32 bit and 64-bit binaries for a given OS, e.g. a Windows binary, have different formats. However, a given 64 bit OS, e.g. Windows 64, will be able to read and launch a 32-bit binary file written for the 32-bit version and a 32-bit wide data bus.
32/64 bit CPU, first definition
The CPU can store/recall a certain quantity of data in memory in a single instruction. A 32-bit CPU can transfer 4 bytes (32 bits) at once and a 64-bit CPU can transfer 8 bytes (64 bits) at once. So "32/64 bit" prefix comes from the quantity of RAM transferred in a single read/write cycle.
This quantity impacts the execution time: The fewer transfer cycles are required, the less the CPU waits for the memory, the program executes faster. It's like carrying a large quantity of water with a small or a large bucket.
The size of the bucket (the number of bits used for data transfer) is used to indicate how efficient the architecture is, hence for the same CPU, a 32-bit application is less efficient than a 64-bit application.
32/64 bit CPU, technical definition
Obviously, the RAM and the CPU must be both able to manage a 32/64-bit data transfer, which in turn determines the number of wires used to connect the CPU to the RAM (system bus). 32/64 bit is actually the number of wires/tracks composing the data bus (usually named the bus "width").
(Wikipedia: System bus - The data bus width determines the prefix 32/64 bit for a CPU, a program, an OS, ...)
(Another bus is the address bus, which is usually wider, but the address bus width is irrelevant in naming a CPU as 32 or 64 bit CPU. This address bus width determines the total quantity of RAM which can be reached / "addressed" by the CPU, e.g. 2 GB or 32 GB. As for the control bus, it is a small bus used to synchronize everything connected to the data bus, in particular, it indicates when the data bus is stable and ready to be sampled in a data transfer operation).
When bits are transferred between the CPU and the RAM, the voltage on the different copper tracks of the data bus must be stable prior to reading data on the bus, else one or more bit values would be wrong. It takes less time to stabilize 8 bits than 64 bits, so increasing the data bus width is not without problems to solve.
32/64 bit program: A compiler matter
Programs don't always need to transfer 4 bytes (32-bit data bus) or 8 bytes (64-bit data bus), so they use different instructions to read 1 byte, 2 bytes, 4 bytes, and 8 bits, for performance reasons.
Binaries (native assembly language programs) are written either with the 32-bit architecture in mind, or the 64-bit architecture, and the associated instruction set. So the name 32/64 bit program.
The choice of the target architecture is a matter of compiler/compiler options used when converting the source program into a binary. Most compilers are able to produce a 32 bit or a 64 binary from the same source program. That's why you'll find both versions of an application when downloading your preferred program or tool.
However, most programs rely on ready-made libraries written by other programmers (e.g. a video editing program may use FFmpeg library). To produce a fully 64-bit application, the compiler (actually the link editor, but let's keep it simple) needs to access a 64-bit version of any library used, which may not be possible.
This also applies to operating systems themselves, as an OS is just a suite of individual programs and libraries. However, an OS is itself a kind of big library for the user programs, acting as a gateway between the computer hardware and the user programs, for efficiency and security reasons. The way OS is written car prevent the user programs to access the full potential of the underlying CPU architecture.
32-bit program compatibility with 64-bit CPU
A 64-bit operating system is able to run a 32-bit binary on a 64-bit architecture, as the 64 bit CPU instruction set is retro-compatible. However, some adjustments are required.
In addition of the data bus width and read/write instructions subset, there are many other differences between 32 bit and 64 bit CPU (register operations, memory caches, data alignment/boundaries, timing, ...).
Running a 32-bit program on a 64-bit architecture:
is more efficient than running it on an older 32-bit architecture (almost solely due to CPU clock speed improvement compared to older 32/64 bit CPU generations)
is less efficient than running the same application compiled into a 64-bit binary to take advantage of the 64-bit architecture, in particular, the ability to transfer 64 bits at once from/to memory.
When compiling a source into a 32-bit binary, the compiler will still use small buckets, instead of the larger available with the 64-bit data bus. This has the largest impact on execution speed, compared to the same application compiled to use large buckets.
For information, the applications compiled into 16 bit Windows binaries (earlier versions of Windows running on 80-286 CPU with a 16-bit data bus) are not fully supported anymore, though there is still a possibility on Windows 10 to activate NTVDM.
The case of .NET, Java and other interpreted "byte-code"
While until recent years, compilers were used to translate a source program (e.g. a C++ source) into a machine language program, this method is now in regression.
The main problem is that machine language for some CPU is not the same than for another (think about differences between a smartphone using an ARM chip and a server using an Intel chip). You definitely can't use the same binary on both hardware, they are not talking the same language, and even if this were possible it would be inefficient on both machines due to the huge differences in how they work.
The current idea is to use an intermediate representation (IR) of the instructions, derived from the source. Java (Sun, sadly now Oracle) and IL (Microsoft) are such intermediate representations. The same IR file can be used on any OS supporting the IR.
Once the OS opens the file, it performs the final compilation into the "local" machine language understood by the actual CPU and taking into account the final architecture on which to run the program. For example, for Microsoft .NET, the universal version is executed by a CoreCLR virtual machine located on the final computer. There is usually no notion of data bus width in such intermediate languages, hence less and less application will have this n-bit prefix.
However we cannot forget the actual architecture, so there will be still 32 and 64 bit versions produced for the CoreCLR to optimize the final code, even if the application itself, at the IR level, is not optimized for a given architecture (only one IR version to download and install).

C code modification from stm32F to stm32L

I'm trying to learn and master embedded C, so I was just gonna test a code that I found on Github, which is built for STM32F4 discovery board. The board that I'm actually working on is STM32L152. when I tried to build/run the code (obviously it won't work) the errors I'm getting are mostly related to functions not being defined or "identifier 'function_name' is undefined", note that the code file includes a library (lib).
take a look at the code file:
https://github.com/TDAbboud/STM32F4_Examples/tree/master/04_PWM_Servo
Generally speaking, What modifications should be done to successfully run the code on STM32L1?
Thanks
These are two different chips. Just because they are from ST just because they are ARM based, they are not the same chip. for starters the stm32f4 is a cortex-m4 the stm32l might not be, 99.9% of your code wont care, just some assembly might. if the stm32l is a cortex-m0 then you have far fewer instructions so the assembly will matter if it is a cortex-m3 then it wont.
The real isssue is peripherals not that this is two st chips not that this is two arm chips, the peripherals can/will vary. ST has a number of chips that use the same uart or same gpio or other, but they have more than one uart they use for STM32 chips, and more than one GPIO. And they mix and match as they make new chips, so if you want to port from one to the other you need to go peripheral by peripheral reading the new and old docs to see what if anything changed.
Sounds like you are using a library so the tool may know from the chip you have chosen what peripherals you have and which library you need, so it might not be finding them because for that chip that peripheral and thus that function and those defines do not apply. Take it one perpheral at a time and port between chips.
stm32 (L) serise incloud EEPROM which are important when they go to sleep mode and want to recover variables after wakup . so make sure application is running in sleep modes need to save data somewhere. so if you use STM (F) series care needs to attache a external EEPROM

Usage of CONFIG_SYS_MAX_NAND_DEVICE macro in U-boot

I could see following macro definitions in IMX53 evk board config file(mx53_evk.h).
#define CONFIG_SYS_NAND_MAX_CHIPS 8
#define CONFIG_SYS_MAX_NAND_DEVICE 1
The CONFIG_SYS_NAND_MAX_CHIPS macro value defines no.of NAND chips we have on the board, but what is the usage of CONFIG_SYS_MAX_NAND_DEVICE macro. can you help me to understand. U-boot(2009.08) is using for IMX53 evk board.
First, I assume that you're using a release from Freescale with patches for i.MX rather than the stock v2009.08 release. Aside from suggesting that you switch to mainline (i.MX5 is very well supported these days), I believe the answer here (based on a Freescale release I happen to have around) is that for that tree (and not mainline) you should set CONFIG_SYS_NAND_MAX_CHIPS to 8 (Freescale sets this to 8 everywhere) and CONFIG_SYS_MAX_NAND_DEVICE to the number that you have. This appears to be related to making a distinction in how the NAND chip itself works that is no longer done.

Extracting the MBR from a raspberry Pi

I tried extracting the MBR from my raspberry pi(with raspbian loaded on the SDCARD) as I would have with any Linux machine.
dd if=/dev/<devname> of=mbr.bin bs=512 count=1
However, upon doing a file on mbr.bin I get the following message :-
mbr.bin: x86 boot sector; partition 1: ID=0xc, starthead 130, startsector 8192, 114688 sectors; partition 2: ID=0x83, starthead 0, startsector 122880, 15400960 sectors, code offset 0xb8
Why does it say that it is an x86 boot sector?
[EDIT]
I also read about the boot sequence here; does the raspberry pi even use the MBR?
Why does it say that it is an x86 boot sector?
Because it is. Technically even "x86" is too broad, and "IBM PC-XT compatible" is more accurate, but these days MBR is one of those lowest-common-denominator de-facto standards thanks to the ubiquity of IBM-compatibles over the years.
does the raspberry pi even use the MBR?
Yes and no. Since the MBR contains both (16-bit) BIOS bootstrap code and the partition table, anything that doesn't boot through an IBM-compatible BIOS* cares about the latter but can ignore the former. Thanks to the simplicity of both the MBR and FAT formats (on account of being 30 years old) it's pretty easy for firmware to simply grovel into the data structures, pull out the first partition and look for the file it wants, which is exactly what many systems including the Pi do - quoting from the page linked in the question:
Also notice that there is no partition marked as Active (bootable). The RPi firmware is coded to look for the file bootcode.bin in the first FAT32 partition - the normal MBR - partition boot process is not followed.
The whole complicated BIOS chained bootstrap setup is the legacy of a 16-bit machine with 128k of RAM. Now thanks to EFI and GPT it's finally going the way of other features of that machine, like ROM BASIC and the audio cassette interface ;)
* including most x86 PCs these days, because EFI disposes of the "boot up in 16-bit real mode pretending to be an 8086" silliness

1k of Program Space, 64 bytes of RAM. Is 1 wire communication possible?

(If your lazy see bottom for TL;DR)
Hello, I am planning to build a new (prototype) project dealing with physical computing. Basically, I have wires. These wires all need to have their voltage read at the same time. More than a few hundred microseconds difference between the readings of each wire will completely screw it up. The Arduino takes about 114 microseconds. So the most I could read is 2 or 3 wires before the latency would skew the accuracy of the readings.
So my plan is to have an Arduino as the "master" of an array of ATTinys. The arduino is pretty cramped for space, but it's a massive playground compared to the tinys. An ATTiny13A has 1k of flash ROM(program space), 64 bytes of RAM, and 64 bytes of (not-durable and slow) EEPROM. (I'm choosing this for price as well as size)
The ATTinys in my system will not do much. Basically, all they will do is wait for a signal from the Master, and then read the voltage of 1 or 2 wires and store it in RAM(or possibly EEPROM if it's that cramped). And then send it to the Master using only 1 wire for data.(no room for more than that!).
So far then, all I should have to do is implement trivial voltage reading code (using built in ADC). But this communication bit I'm worried about. Do you think a communication protocol(using just 1 wire!) could even be implemented in such constraints?
TL;DR: In less than 1k of program space and 64 bytes of RAM(and 64 bytes of EEPROM) do you think it is possible to implement a 1 wire communication protocol? Would I need to drop to assembly to make it fit?
I know that currently my Arduino programs linking to the Wiring library are over 8k, so I'm a bit concerned.
Since you only need to send data (which is simpler than receiving) and you can select your own protocol, it should not be a problem to fit the code in the available memory space.
I once created software for an industrial control panel that contained 8x14 segment LCD display, some LEDs, some buttons, a serial (I2C) EEPROM, and serial interface to the host. A 4 bit processor was used. The device did not have any serial interface, so both the RS232C interface and I2C bus had to be implemented in software. On top of that, there was Modbus protocol (which among other things requires CRC calculations some exact timing), and the application program.
The device had some 128 x 4 bits of RAM and 1kW, 2kW, 3kW or 4kW of ROM (10 bits per word). The size of the final program was about 1100 words, so it did not quite fit in the smallest device. I used Assembler, of course.
However, instead of using multiple microcontrollers, you could consider using a hardware solution.
You could use a sample and hold circuit. For that, you need an array of analog switches and capacitors and perhaps op-amps. Just issue a trigger to latch all the voltages into the capacitors. Then you can use as much time as you need to read the voltages with your master processor.
Update: Forgot to mention that there are ready-made sample-and-hold amplifiers that need very little or no external components. This is probably the easiest solution.
1k of program space should be plenty, considering that your protocol only needs to be complicated enough to send a single integer when tickled. Look into Manchester Encoding.
You can probably get away with using a C compiler that targets this architecture, but you'll have to create your own runtime environment and not rely on the one supplied with the compiler. That's doable, but I'm not sure if the additional work to essentially create your own mini-OS outweighs the productivity benefit of using C over assembler.
I've done embedded programming in similar constraints. I used Borland Turbo C (it was a long time ago) in the tiny model and obtained code that was hardly bulkier than I could have done in assembler, with a fraction of the effort. What I'm saying is: It's quite feasible and sensible to use C as a high level assembler.
Just like me, though, you will be facing the problem of providing C with a (tiny) runtime environment. Ideally, you will only need to set up the stack and a few registers. Also, you won't have room for the C library, so you will need to program any needed functions yourself.
Yes, probably, though if you know your compiler very well you might be able to get away with c.
What you could do, is use a compiler to emit any standalone functions you need based on c code, then glue them together with a little of your own. (You'll certainly have to do the c runtime setup yourself - stacks etc.)
You may consider upgrading to the ATTiny25. It is a more capable 8-pin AVR that includes Atmel's Universal Serial Interface. It is capable of doing 1-wire serial comms in hardware, given only a few bytes of software.
Why wouldn't you just use sample-and-hold hardware, rather than a pile of microcontrollers?
I designed a master-slave system recently using an AT90USB646 master and ATtiny85 slaves. Obviously I had a lot more memory to work with on the slaves, but what I wanted to share with you is this:
With regard to your communication protocol, bear in mind that the uncalibrated internal oscillator on the ATtiny13 has an accuracy of +/- 10%. This means you won't be able to use, e.g., RS-232 communications.
I used a variant of the Dallas 1-Wire protocol in my system. Including full support for slave enumeration etc., the C source code compiles into 1626 bytes.
Edit: Whoops, didn't realize the question is so old. Hopefully this may still be of some help.

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