combobox input of form using array variable in CakePHP - cakephp

Question

<?php
$types_size=sizeof($types)-1;
$array_type=' ';
while($types_size!=-1)
{
$array_type.='"'.$types[$types_size]["Type"]["name_type"].'", ';
$types_size--;
}
echo $array_type;
echo $this -> form -> input ('id_type', array('options' => array($array_type)));
echo $this -> form -> input ('id_type', array('options' => array(shoes, shirts, jeans,)));
?>
I created $array_type to store types data.
I got the types data : "shoes", "shirts", "jeans",
I wanna created an combobox input with 3 values just like the second input
Question : The code above doesn't show as I expected. The combobox of the first input shows only one value: shoes, shirts, jeans, not like the expected second input
Hopefully someone understand my problem !!!

Answer 1

In the above code you will be realized that $array_type is a string variable not an array.
You should declare an array variable using $array_type = array() not $array_type = ''
You can try to print $array_type variable and verify whether it is an array or a string.
Now your code should looks like:
<?php
$types_size=sizeof($types)-1;
$array_type= array();
while($types_size!=-1)
{
$array_type[] = $types[$types_size]["Type"]["name_type"];
$types_size--;
}
//echo $array_type; // if you echo an array variable it will print `Array`.
//Use print_r() to print an array
print_r($array_type);
echo $this -> form -> input ('id_type', array('options' => $array_type));
echo $this -> form -> input ('id_type', array('options' => array(shoes, shirts, jeans,)));
?>

Answer 2

<?php
$types_size=sizeof($types)-1;
$array_type= array();
while($types_size!=-1)
{
$array_type[] = $types[$types_size]["Type"]["name_type"];
$types_size--;
}
//echo $array_type; // if you echo an array variable it will print `Array`.
//Use print_r() to print an array
print_r($array_type);
echo $this -> form -> input ('id_type', array('options' => $array_type));
echo $this -> form -> input ('id_type', array('options' => array(shoes, shirts, jeans,)));