I am trying to send across a character array using a transmitter and a receiver program using raw sockets. I am able to get the correct number of bytes sent at the receiver side, but the values printed out are garbage. Could someone help me out here?
Transmitter:
int create_raw_socket(char *dev)
{
struct sockaddr_ll sll;
struct ifreq ifr;
int fd, ifi, rb;
bzero(&sll, sizeof(sll));
bzero(&ifr, sizeof(ifr));
fd = socket(PF_PACKET, SOCK_RAW, htons(ETH_P_ALL));
assert(fd != -1);
strncpy((char *)ifr.ifr_name, dev, IFNAMSIZ);
ifi = ioctl(fd, SIOCGIFINDEX, &ifr);
assert(ifi != -1);
sll.sll_protocol = htons(ETH_P_ALL);
sll.sll_family = AF_PACKET;
sll.sll_ifindex = ifr.ifr_ifindex;
rb = bind(fd, (struct sockaddr *)&sll,sizeof(sll));
assert(rb != -1);
return fd;
}
int SendPacket(char *dev ,unsigned char *send_packet, int packet_len)
{
int num_sent= 0;
int sockaddress = create_raw_socket(dev);
if((num_sent = write(sockaddress, &send_packet, packet_len)) != packet_len)
{
close(sockaddress);
return 0;
}
else
{
close(sockaddress);
return 1;
}
}
int main(int argc, char**argv)
{
int x,fd,s;
char *send_packet="HELLO";
int len = sizeof(send_packet);
while(1)
{
if(!SendPacket((argv[1]), send_packet, len))
perror("Error sending packet");
else
printf("Packet sent successfully with payload : %s\n" ,send_packet);
}
return 0;
}
Receiver :
int main(int argc, char **argv)
{
struct sockaddr addr;
int sock_fd, fromlen,s;
char buf[PACKET_LENGTH];
char *dev = argv[1];
while(1)
{
fromlen=sizeof(addr);
sock_fd = create_raw_socket(dev); /* Creating the raw socket */
int x= recvfrom(sock_fd,&buf,sizeof(buf),0,&addr,&fromlen);
printf("\n Number of bytes of data received is %d \n",x);
printf("\nPayload Received from client... is %s \n", buf);
close(sock_fd);
}
return 0;
}
Change
write(sockaddress, &send_packet, packet_len)
to
write(sockaddress, send_packet, packet_len)
send_packet is already the address of the buffer to be sent, if you take the address of this address (more precisely the address of the variable holding the address), you will read the wrong memory for the buffer
Similarly for recvfrom:
recvfrom(sock_fd, buf, sizeof(buf), 0, &addr, &fromlen)
You have several problems:
This line
if((num_sent = write(sockaddress, &send_packet, packet_len)) != packet_len)
Should say just send_packet instead of &send_packet. send_packet is a pointer that points to the desired packet data, so there's no need to take its address -- you don't want to write out the literal address of that pointer into the packet, that just simply won't work.
This is wrong:
char *send_packet="HELLO";
int len = sizeof(send_packet);
sizeof(send_packet) will always be the size of a pointer on your system, typically either 4 or 8 bytes. You really want to either declare send_packet as an array type (e.g. char send_packet[] = ...), or use strlen to compute its length at runtime (e.g. int len = strlen(send_packet) + 1;). In your case, you're either sending too little data (4 bytes) or too much data (8 bytes), both of which are problematic.
Your printf code in the client assumes that the data it receives is null-terminated, which it is not necessarily. You should either manually null-terminate the data before printing it (or using any other string functions, for that matter), or tell printf the limit of how much data to print. I'd suggest null-terminating it like so:
char buf[PACKET_LENGTH + 1]; // +1 for null terminator
int x = recvfrom(sock_fd,buf,PACKET_LENGTH,0,&addr,&fromlen);
if(x >= 0)
buf[x] = 0;
Your code has poor const correctness. SendPacket should take a const char* instead of char* parameter, and send_packet should either be declared as char[] or as const char*. The conversion from string literals to char* is deprecated and should be avoided in all new C code.
Using printf to print the buffer will print a string until the en of string character is reached. If you see the original string followed by garbage characters, this may be the reason.
You should probably introduce a 0 after the last byte returned by recvfrom, or you will print whatever value was in the memory that recvfrom did not overwrite. It could even try to access memory outside the buffer.
Try adding something like:
int x= recvfrom(sock_fd,&buf,sizeof(buf) - 1,0,&addr,&fromlen);
buf[x - 1] = 0;
Note: that changes the maximum size of what is read, it is just an example of how to do it.
Related
I am working on BSD sockets and I use this function
int recvfrom( int socket , void *buffer , size_t nbytes , int flags , struct sockaddr *sender , int *addrlen)
but before printing a message in server I want to save value of buffer in array of char and make some operations. How to do it?
EDIT: example
Buffer stores a message "Hello", my array should look like arr[]={'h','e','l','l','o'}
recvfrom() function
int recvfrom( int socket , void *buffer , size_t nbytes ,
int flags , struct sockaddr *sender , int *addrlen);
allows the user to receive data from an UDP socket. On success (return value > 0) it returns the number of received bytes, writing up to nbytes bytes to memory area pointed by buffer. Originator's address and its len are also written by the function respectively in sender and addrlen pointers provided by the caller.
So, in order to have incoming bytes in your char array (chars are bytes!) you simply have to pass it to the recvfrom as buffer parameter.
#define MAX_RECV_BUF_LEN 100
char arr[MAX_RECV_BUF_LEN + 1];
struct sockaddr senderAddr;
int addrLen, res;
res = recvfrom( yourSocketDescr , arr, MAX_RECV_BUF_LEN, yourFlags , &senderAddr, &addrLen);
if ( res > 0 )
{
arr[res] = 0; // Add a string terminator. Useful only if you expect 'printable' data
// ... some operations
}
/* else... manage errors */
I'm doing an exercise about UDP sockets in C. When the client sends a specific message (e.g hi) the server has to send "Nice to meet you". If no standard reply is found the server sends "No suitable reply". My problem is that memset fails if I try to return the reply like this:
return "No suitable reply";
and it doesn't if I return the reply in this way:
char* foo = malloc(sizeof(char*));
memset(foo, 0, strlen(ses));
memcpy(foo, "No suitable reply", 17);
return foo;
I tried to google a solution to this and I found this and this, but they don't seem to address my problem (I first thought that memset doesn't work on a string declared like char string[] = "something" but in the second example they use memset on a static string).
Here is the whole code (the memset I'm talking about is right at the end):
/*
Alessandro Dussin 5AI
2018-17-11
Write a program to handle a single UDP "connection"
*/
//Standard libraries
#include <stdio.h>
#include <stdlib.h>
//Sockets libraries and connection ahndling
#include <sys/socket.h>
#include <netinet/in.h>
#include <sys/types.h>
#include <arpa/inet.h>
//Read/write ops on file descriptors
#include <unistd.h>
//String ops
#include <string.h>
#include <assert.h>
void chopN(char *str, size_t n)
{
assert(n != 0 && str != 0);
size_t len = strlen(str);
if (n > len)
return; // Or: n = len;
memmove(str, str+n, len - n + 1);
}
//Required by the exercise. Given a certain word or phrase, reply with a specific string
char* switchreply(char* str){
//Extracts the word or phrase (Basically removes the "/command " word)
chopN(str, strlen("/stdreply "));
int i = 0;
for(; i < strlen(str); i++){
if(str[i] == '\n'){
str[i] = '\0';
break;
}
}
if(strcmp(str, "ciao") == 0){
return "ciao anche a te!";
}
else if(strcmp(str, "I hate you") == 0){
return "I hate you too!";
}
return "";
}
char* stdreply(char *str){
char* tmp = malloc(sizeof(char)*128);
int i = 0;
//printf("Entered stdreply... str at the start of the func: %s\n", str);
for(; i < strlen(str); i++){
tmp[i] = str[i];
//printf("tmp: %s\n", tmp); //DEBUG
if(strcmp(tmp, "/echo ") == 0){ // if(strcmp() == 0) is necessary because
//otherwise 0 would be interpreted as FALSE
//printf("Echo detected\n"); //DEBUG
chopN(str, strlen("/echo "));
str[strlen(str)] = '\0';
return str;
}
else if(strcmp(tmp, "/stdreply ") == 0){
//printf("I got into the else if\n"); //DEBUG
char* tmpreply = calloc(strlen(str), sizeof(char*));
tmpreply = switchreply(str);
//printf("tmpreply: %s\n", tmpreply);
str = malloc(sizeof(char*)*strlen(tmpreply));
memcpy(str, tmpreply, strlen(tmpreply));
//str[strlen(str)] = '\0'; //DEBUG
//printf("str: %s\n", str); //DEBUG
return str;
}
else if(strcmp(tmp, "/TODO") == 0){
char* ses = malloc(sizeof(char*));
memset(ses, 0, strlen(ses));
memcpy(ses, "work in progress", 17);
return ses;
}
}
return "No suitable reply";
}
int main(int argc, char **argv){
if(argc < 2){
printf("Usage: ./server port");
exit(0);
}
int serverfd;
serverfd = socket(AF_INET, SOCK_DGRAM, 0);
struct sockaddr_in server;
server.sin_port = htons(atoi(argv[1]));
server.sin_family = AF_INET;
server.sin_addr.s_addr = INADDR_ANY;
if(bind(serverfd, (struct sockaddr *)&server, sizeof(server)) < 0){
perror("Bind() error: ");
fflush(stderr);
}
//"UDP message receiver" variables declarations
int bytes; //Reads how many bytes the funcion recvfrom has read
struct sockaddr_in from;
char* buffer = malloc(sizeof(char*)); //String to which save the client message
memset(buffer, 0, strlen(buffer)); //and set it to zero
socklen_t fromlen = sizeof(struct sockaddr_in);
const char stdrep[] = "Message Received: "; //This string will always be
//printed upon receiving a message
char* reply = malloc(sizeof(char*)); //This is where the return value of
//stdreply() will be stored
memset(reply, 0, strlen(reply)); //and set it zero
//This while will keep "listening" for udp messages
while((bytes = recvfrom(serverfd, buffer, 1024, 0, (struct sockaddr *)&from, &fromlen)) > 0){
//From teacher's example. Write to stdout
write(1, stdrep, strlen(stdrep));
write(1, buffer, bytes);
//Detect a basically empty string (if the client has pressed only enter)
if(buffer[0] == '\n'){
bytes = sendto(serverfd, "You pressed only enter!\n", 18, 0, (struct sockaddr *)&from, fromlen);
}
//Act according to the client message
reply = stdreply(buffer);
bytes = sendto(serverfd, reply, strlen(reply), 0, (struct sockaddr *)&from, fromlen);
if (bytes < 0){
perror("sendto: ");
fflush(stderr);
}
memset(buffer, 0, 1024);
memset(reply, 0, strlen(reply)); //The seg fault happens right here
fflush(stdout);
}
return 0;
}
There are plenty of problems in the code you are posting.
As #JonBolinger already noted, sizeof(char*) returns the size in bytes of a pointer to a char. On Intel platforms this will be either 4 or 8, depending on whether you are running on 32-bit or 64-bit. (So you end up allocating buffers of 4 or 8 bytes)
You consistently try to clear your dynamically-allocated buffers with memset(). malloc() will return memory filled with garbage, and you indicate how many bytes to clear by using strlen() on the returned buffer. strlen() will scan the buffer until it finds the first 0 character to compute the string's length. Since the buffer is filled with garbage, this can easily give you a value outside of the boundaries of your memory block and you will end up corrupting memory.
Every call to malloc() should be matched to a free() call, otherwise you will leak memory. This is especially important if your program is long-running.
When you are working with temporary local strings (strings that are not returned to the caller), it is very common practice to use a local char array instead of malloc(). This way, the buffer gets allocated on the stack and will be released automatically when your function exits scope. Just be sure to use 'safe' string functions like strncpy() that will accept as a parameter the length of the buffer, to avoid overwrites.
void Example(char* anotherString ) {
char tmpString[256]; // this will create a local buffer with capacity of 256 bytes
strncpy(tmpString, anotherString, sizeof(tmpString)); // copy string, without risk of overflowing the buffer
}
Warning: NEVER attempt to return a local temporary buffer as a result, remember that it will no longer exist when the function exits and although the returned value may initially have meaningful results, they will certainly be destroyed as soon as you call another function. Instead of this, another common practice when you need a string return value, instead of returning a string allocated with malloc() -that would need to be released with free() - you pass a local buffer that will hold the result as a parameter, like this:
void func1() {
char result[256];
func2(result, 256);
// after calling, result will carry "a returned string"
}
void func2(char* result, size_t bufferLen) {
strncpy(result, "a returned string", bufferLen);
}
I think your code would benefit greatly if you can transform it to using this style where applicable.
reply = stdreply(buffer);
This does not copy a string. It overwrites the pointer with a different one, losing the original pointer.
memset(reply, 0, strlen(reply));
This would clear the string if it were allocated with malloc. If it is a constant string like "No suitable reply" then it may be read-only, so it generates a segfault.
How can I get the interface name for the IP address in linux from C code ?
e.g. I'd like to get the interface name ( like etho , eth1 , l0 ) assigned for the IP address 192.168.0.1
Using /proc/net/arp you can match it. Here is a command line tool example.
usage: getdevicebyip 192.168.0.1
#include <stdio.h>
#include <fcntl.h>
int main(int argc, char **argv){
if (argc < 2) return 1;
FILE *fp = fopen("/proc/net/arp", "r");
char ip[99], hw[99], flags[99], mac[99], mask[99], dev[99], dummy[99];
fgets(dummy, 99, fp); //header line
while (fscanf(fp, "%s %s %s %s %s %s\n", ip, hw, flags, mac, mask, dev) != EOF)
if (!strcmp(argv[1],ip))
printf("%s\n",dev);
return 0;
}
You can use getifaddrs. See man 3 getifaddrs for usage information. This will only work on a Unix-like systems.
netlink is a way to do this on Linux. I think it might even be a proper way to do it on Linux (even though it isn't portable).
The strategy is:
Get a list of addresses on interfaces from the kernel by sending a netlink message.
Find the address you want (I have hard coded the one I want as address_dq) and record its interface (a number at this stage)
Get a list of interfaces by sending another netlink message,
Find the number of the interface matching the number you recorded in step (2).
Get the name of the interface.
The code below is not pretty, but I'm sure you could do a better job of it. I have been a especially sloppy by not checking for a multipart message (checking for the NLM_F_MULTI flag and for a message type of NLMSG_DONE is the way to do it). Instead I have just assumed the response to the first message is multipart -- it is on my machine -- and chewed up the NLMSG_DONE message which follows.
Code...
#include <asm/types.h>
#include <linux/netlink.h>
#include <linux/rtnetlink.h>
#include <sys/socket.h>
#include <string.h>
#include <stdio.h>
#include <stdlib.h>
int main(int argc, void ** argv) {
// This is the address we want the interface name for,
// expressed in dotted-quad format
char * address_dq = "127.0.0.1";
// Convert it to decimal format
unsigned int address;
inet_pton(AF_INET, address_dq, &address);
char buf[16384];
// Our first message will be a header followed by an address payload
struct {
struct nlmsghdr nlhdr;
struct ifaddrmsg addrmsg;
} msg;
// Our second message will be a header followed by a link payload
struct {
struct nlmsghdr nlhdr;
struct ifinfomsg infomsg;
} msg2;
struct nlmsghdr *retmsg;
// Set up the netlink socket
int sock = socket(AF_NETLINK, SOCK_RAW, NETLINK_ROUTE);
// Fill in the message
// NLM_F_REQUEST means we are asking the kernel for data
// NLM_F_ROOT means provide all the addresses
// RTM_GETADDR means we want address information
// AF_INET means limit the response to ipv4 addresses
memset(&msg, 0, sizeof(msg));
msg.nlhdr.nlmsg_len = NLMSG_LENGTH(sizeof(struct ifaddrmsg));
msg.nlhdr.nlmsg_flags = NLM_F_REQUEST | NLM_F_ROOT;
msg.nlhdr.nlmsg_type = RTM_GETADDR;
msg.addrmsg.ifa_family = AF_INET;
// As above, but RTM_GETLINK means we want link information
memset(&msg2, 0, sizeof(msg2));
msg2.nlhdr.nlmsg_len = NLMSG_LENGTH(sizeof(struct ifinfomsg));
msg2.nlhdr.nlmsg_flags = NLM_F_REQUEST | NLM_F_ROOT;
msg2.nlhdr.nlmsg_type = RTM_GETLINK;
msg2.infomsg.ifi_family = AF_UNSPEC;
// Send the first netlink message
send(sock, &msg, msg.nlhdr.nlmsg_len, 0);
int len;
// Get the netlink reply
len = recv(sock, buf, sizeof(buf), 0);
retmsg = (struct nlmsghdr *)buf;
// Loop through the reply messages (one for each address)
// Each message has a ifaddrmsg structure in it, which
// contains the prefix length as a member. The ifaddrmsg
// structure is followed by one or more rtattr structures,
// some of which (should) contain raw addresses.
while NLMSG_OK(retmsg, len) {
struct ifaddrmsg *retaddr;
retaddr = (struct ifaddrmsg *)NLMSG_DATA(retmsg);
int iface_idx = retaddr->ifa_index;
struct rtattr *retrta;
retrta = (struct rtattr *)IFA_RTA(retaddr);
int attlen;
attlen = IFA_PAYLOAD(retmsg);
char pradd[128];
// Loop through the routing information to look for the
// raw address.
while RTA_OK(retrta, attlen) {
if (retrta->rta_type == IFA_ADDRESS) {
// Found one -- is it the one we want?
unsigned int * tmp = RTA_DATA(retrta);
if (address == *tmp) {
// Yes!
inet_ntop(AF_INET, RTA_DATA(retrta), pradd, sizeof(pradd));
printf("Address %s ", pradd);
// Now we need to get the interface information
// First eat up the "DONE" message waiting for us
len = recv(sock, buf, sizeof(buf), 0);
// Send the second netlink message and get the reply
send(sock, &msg2, msg2.nlhdr.nlmsg_len, 0);
len = recv(sock, buf, sizeof(buf), 0);
retmsg = (struct nlmsghdr *)buf;
while NLMSG_OK(retmsg, len) {
struct ifinfomsg *retinfo;
retinfo = NLMSG_DATA(retmsg);
if (retinfo->ifi_index == iface_idx) {
retrta = IFLA_RTA(retinfo);
attlen = IFLA_PAYLOAD(retmsg);
char prname[128];
// Loop through the routing information
// to look for the interface name.
while RTA_OK(retrta, attlen) {
if (retrta->rta_type == IFLA_IFNAME) {
strcpy(prname, RTA_DATA(retrta));
printf("on %s\n", prname);
exit(EXIT_SUCCESS);
}
retrta = RTA_NEXT(retrta, attlen);
}
}
retmsg = NLMSG_NEXT(retmsg, len);
}
}
}
retrta = RTA_NEXT(retrta, attlen);
}
retmsg = NLMSG_NEXT(retmsg, len);
}
}
When run as above, returns Address 127.0.0.1 on lo.
Using "192.168.1.x" instead of "127.0.0.1" it instead returns Address 192.168.1.x on eth0.
I'm new to socketpairs and I need my children each to pass information from a structure to the parent.I was told this can be done using SOCK_DGRAM but I don't know how to do it.I looked over the internet but i couldn't find a concrete example.Can you please show for example hoe can you pass to the parent a structure made out of 2 ints and a string maybe ?I just want an example so I can understand how I could build this kind of socketpair and send information through it.Thank you
How about the following:
int sockets[2];
if (socketpair(AF_INET, SOCK_DGRAM, 0, sockets) != -1)
{
int res = fork();
if (res == 0)
{
/* In child process */
/* We only need one socket, so close the other */
close(sockets[0]);
struct some_structure my_struct;
write(sockets[1], &my_struct, sizeof(my_struct));
/* All done */
exit(0);
}
else if (res > 0)
{
/* In parent process */
/* We only need one socket, so close the other */
close(sockets[1]);
struct some_structure my_struct;
read(sockets[0], &my_struct, sizeof(my_struct));
}
}
The above code doesn't check for, or handle, errors. It can't handle structures containing pointers, structures using arrays are okay though.
Assuming that your string is represented as a char* as in
struct data {
int i, j;
char *s;
};
you need to devise some serialization format, because sending a pointer won't work; the pointee is not passed so it won't point to anything useful in the receiver (the parent). A simple format would be to put the integers end-to-end, then directly append the string including its NUL terminator, so you'd get
int senddata(int fd, struct data const *d)
{
size_t msglen = 2 * sizeof(int) + strlen(d->s) + 1;
char *msg = malloc(msglen);
if (msg == NULL)
return -1;
((int *)msg)[0] = d->i;
((int *)msg)[1] = d->j;
strcpy(msg + 2 * sizeof(int), d->s);
ssize_t r = send(fd, msg, msglen, 0);
free(msg);
return r;
}
with a corresponding receive function for the parent. You might want to put some maximum length on the string, because the parent needs to know the size of the message in advance.
I'm writing a client application in C++ to receive binary data via UDP broadcast, however I'm unable to receive anything beyond the first 4 bytes, regardless of the buffer size. I've checked the packets in Wireshark, and I can see that my machine is receiving roughly 1200 bytes of data. When I compare this to what my client is receiving, I can see that I'm getting the packets, however the remaining data is lost. Here's my code:
#define BUFFERSIZE 4096
int main()
{
struct addrinfo hints, *servinfo, *p;
int sockfd, i, nbyt;
int *buf = (int*) malloc(BUFFERSIZE);
memset(&hints, 0, sizeof hints);
hints.ai_family = AF_INET;
hints.ai_socktype = SOCK_DGRAM;
hints.ai_flags = AI_PASSIVE;
getaddrinfo(NULL, "9011", &hints, &servinfo);
sockfd = socket(servinfo->ai_family, servinfo->ai_socktype, servinfo->ai_protocol);
bind(sockfd, servinfo->ai_addr, servinfo->ai_addrlen);
FILE *file;
file = fopen("file.txt", "w+");
for (i=0;i<=45;i++)
{
nbyt = recv(sockfd, buf, BUFFERSIZE, 0);
fprintf(file, "%s %d; %s %x\n", "Bytes received:", nbyt, "Message:", *buf);
}
fclose(file);
close(sockfd);
free(buf);
printf("%s\n", "Execution ended.");
return 0;
}
An example of some of the data I'm receiving:
Bytes received: 1131; Message: 5b0
Bytes received: 1131; Message: 5b3
Bytes received: 1131; Message: 5b6
Bytes received: 1092; Message: 4e0
I've tried setting the socket to non-blocking with the MSG_DONTWAIT flag, as this fixed the problem for a similar Python application, however this only returns errors:
Bytes received: -1; Message: 0
I'm relatively new to C++ and sockets, so it's possible there's something I'm just not seeing. Hopefully somebody can help me figure out what's wrong? I can provide additional information if necessary.
You're receiving it just fine. Your debug code just doesn't do what you think it does.
The x specifier to printf prints the unsigned int argument in hex. Integers on your platform are probably 32-bits. So you're only printing the first 4 bytes.
If you want to print the entire buffer in hex, you need to write the loop to do that yourself (or use a library, of course).
For example, and I warn you my C is a little rusty (and this is by far not the best performing way to do this) ... Also, this assumes your buffer is always a multiple of sizeof(int), or it'll lose some data:
nbyt = recv(sockfd, buf, BUFFERSIZE, 0);
fprintf(file, "%s %d; %s\n", "Bytes received:", nbyt, "Message:");
for (offset = 0; offset < nbyt/sizeof(int); ++offset) {
fprintf(file, "%x ", buf[offset]);
}
fprintf(file, "\n");
*buf in your code means the first integer from the array of the received data, so you are printing just four first bytes of the received UDP payload.
Despite the already mentioned format error, if you receive a '\0' char, a formatted print with %s will cut the string there, regardless of the actual number of chars received.
For debugging plaintext, I used below code:
char escaped_char(char c)
{
char escapable[12] = {'\a','\b','\f','\n','\r','\t','\v','\\','\'','\"','\?','\0'};
char escaped[12] = { 'a', 'b', 'f', 'n', 'r', 't', 'v','\\','\'','\"', '?', '0'};
const char* escapable_end = escapable + 12;
const char* ec;
for(ec = escapable;ec != escapable_end;++ec)
{
if(c == *ec) return escaped[ec-escapable];
}
return 0;
}
/**
* #param buf input buffer to escape
* #param len length of contents in buf
* #param outlen pointer to an integer, which receives the length of the returned string
* #return A newly allocated, C style escaped string, NULL on error
* #warning A returned string must be freed with free()
*/
char* aescape(const char* buf,size_t len,size_t* outlen)
{
const char* buf_end = buf + len;
const char* c;
char ec;
char* result;
assert(buf && outlen);
(*outlen) = len;
for(c = buf;c != buf_end;++c)
{
if(escaped_char(*c))
{
++*outlen;
}
}
result = malloc((*outlen)+1);
assert(result != NULL);
if(result)
{
if((*outlen) > len)
{
char* out = result;
for(c = buf;c != buf_end;++c)
{
ec = escaped_char(*c);
if(ec)
{
*out++ = '\\';
*out++ = ec;
}
else
{
*out++ = *c;
}
}
}
else
{
memcpy(result,buf,len);
}
result[(*outlen)] = '\0';
}
else
{
(*outlen) = 0;
}
return result;
}