How to initialize three dimensional char array without pointers in c and access it?
I tried the following:
char card[1][3][15]={
{"iron","man"},
{"contagious","heide"},
{"string","middle"}
};
but I am getting
**Error:too many initializers**
**Warning: Array is only partially initialized**
Lets take a simple example...You can use your own values instead of these integers:
declaration:
int arr[2][3][4] = { { {1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4} },
{ {1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4} } };
I hope, it is clear to you.
Considering your example itself:
I think it should be
char card[1][3][15]={ {"iron","man", "contagious"}};
What this means is that you can effectively create 3 char arrays each of length 15. Your first dimension of 1 doesn't have much effect.
So, you can make it like
char card[2][3][15]={ {"iron","man", "contagious"},
{"iron","man", "contagious"}};
So, for your simple understand, the number of rows indicate the first dimension, the number of columns in each row indicates the second dimension and the number of elements(in this case chars) in each column indicates the 3rd dimension.
So, now you can see that for the data in your question, you should declare the array as char char[3][2][15]
char card[1][3][15]={ { {"iron","man"},{"contagious","heide"},{"string","middle"}}
};
You should put another braces brackets inside. I think it will be helpful to you.
Related
Let say I have Array(string, doesn't matter) of size n.
For example int array: int[] MyArr = {1, 2, 3, 4, 5};
Array length is 5, I want to know number of subsets with length of 3 elements from this array without rearranging elements of this array, it is easy for small arrays to calculate it but I would like to know general formula for array of n elements and subset of m consecutive elements.
For example above it is
{1, 2, 3}
{2, 3, 4}
{3, 4, 5}
not {1, 2, 4} or {2, 5, 1}, only consecutive elements
Note: array shouldn't be sorted
In C, is there a way to print an entire array. For example print (in full) each row from a 2D array, NOT iterating through its contents and printing them independently? Below is an example of how I imagined the code would be:
int main() {
int Numbers[4][4] = {{5, 1, 1, 6},
{2, 2},
{3, 3, 3},
{4, 4, 4}};
for (int i=0; i<=3; i++){
printf("%i \n", Numbers[i]);
}
return 0;
}
I expect the output to be along the lines of:
{5, 1, 1, 6}
{2, 2}
{3, 3, 3}
{4, 4, 4}
However, when run the code I get the following output
-414054224
-414054208
-414054192
-414054176
No, there is no way to do what you are asking. You cannot do operations on whole arrays in C; you must iterate through and print each element separately. Array expressions in C lose their "array-ness" under most circumstances.
Problem Statement
Given two arrays A[] and B[] of N and M integers respectively. The task is to count the number of unordered pairs formed by choosing an element from array A[] and other from array B[] in such a way that their sum is an even number.
Note that an element will only be a part of a single pair.
Input: A[] = {9, 14, 6, 2, 11}, B[] = {8, 4, 7, 20}
Output: 4
{9, 7}, {14, 8}, {6, 4} and {2, 20} are the valid pairs.
Source
https://www.geeksforgeeks.org/count-pairs-from-two-arrays-with-even-sum/
My Problem
I am wondering how output doesn't have so many other pairs whose sum will be even i.e. {11,7}, {2,3} etc. and many others.
As you mentioned in the question, Element will only be a part of single pair
{11,7} and {2,3} are already considered in {9, 7} and {2, 20}.
It's given in the problem statement,
Note that an element will only be a part of a single pair.
That means 7 has already been paired in {9, 7} so you can't pair {11, 7}
As I know to get Stream from 2 dimensional array but I want to know how I can get Stream from below 3 dimensional array?
int[][][] data = {
{
{1, 2, 3},
{4, 5, 6},
{7, 8, 9}
},
{
{1, 2, 3},
{4, 5, 6},
{7, 8, 9}
}
};
If you can do it with a two-dimensional array then doing it for N dimensional array is not that difficult.
The solution can be done as follows:
IntStream result = Arrays.stream(data)
.flatMap(Arrays::stream)
.flatMapToInt(Arrays::stream);
To better help understand what is going on above, you can split the method invocations as follows:
// the call to Arrays.stream yields a Stream<int[][]>
Stream<int[][]> result1 = Arrays.stream(data);
// the call to flatMap yields a Stream<int[]>
Stream<int[]> result2 = result1.flatMap(Arrays::stream);
// the call to flatMapToInt yields a IntStream
IntStream intStream = result2.flatMapToInt(Arrays::stream);
You just need to call flatMap another time to change the stream from int[][] to stream of int[].
IntStream stream = Arrays.stream(data)
.flatMap(twoDArray -> Arrays.stream(twoDArray))
.flatMapToInt(oneDArray -> Arrays.stream(oneDArray));
Say I got an array
unsigned char digit[] = {0, 1, 2, 3, 4, 5, 6, 7};
Yet I want to modify part of the array, make the array become something like:
{0, 1, 2, 3, 0, 0, 0, 0}
Enumerate every element I want to modify and alter them might take some effort. Especially when there's a large amount of elements I want to change. I know in some languages like Python I may do something using a single line of code:
a = np.array([0, 1, 2, 3, 4, 5, 6, 7])
a[4:] = [0, 0, 0, 0]
//a: array([0, 1, 2, 3, 0, 0, 0, 0])
So I wonder, is there a similar way to do that in C?
There are fewer possibilities in C, but in case of an unsigned char and setting its values to zero you could use memset:
memset(&digit[4], 0, 4);
Demo.
One options is that you could write a subroutine that would implement the interface that other languages provide "under the cover". You'll probably want to educate yourself on 'VARARGS' to make it take a variable number of arguments.
Others have already mentioned setting the array elements to a single value using memset, as a part of your follow up question you asked if some elements can be set to certain values like {1, 2, 3, 4}.
You can use memcpy here to achieve that. Since your type here is unsigned char I will keep that, but in general this method can be used for any type.
memcpy(&digit[4], ((unsigned char[4]){1, 2, 3, 4}), 4 * sizeof(unsigned char));
You can see the demo here.
I think that maybe not the shortest but something you can easy do is just:
digit[] = {0, 1, 2, 3, 4, 5, 6, 7}; %Having this
a=the number in your vector you want to start making ceros;
n=the lenght of digit;
for(i=a;i=n;i++)
{
digit[n]=0;
}
Is just a way I think you could use.
If you want to change an specific one just
b=position;
digit[b]=c; %Where c is the number you want to put in there.
I hope it works for you, good luck.