In my edit.ctp I have a select box which I don't need the user to change. So I put array(disabled=>true). But this field is not coming when
pr($this->data); and showing an error while saving.
What options are there to solve this issue.
If you know the value of the data you can edit it at the controller.
$this->request->data['ModelName']['fieldName'] = value;
UPDATE
Edit it like
echo $this->Form->input('patient_id',array('type'=>'select', 'readonly' => 'readonly'));
You could make the field readonly so that user cant change it , or use some hidden field to post the data that you want, or you could use some css, like visibility:hidden, so that user dont see it but it'll be posted.
echo this->Form->input('patient_id',array('type'=>'hidden'));
You can use some other name for the input and check in controller, or you could completely remove the select element from the view*strong text* (since, its not needed as user dont need to change it)
Related
maybe I'm blind on the point but I'm struggling for over an hour and can not find a solution.
My goal is in edit view a checkbox, which is set in the database to "yes", also to be displayed as checked.
My InputField looks like this:
<?php
echo $this->Form->checkbox(
'active',[
'value'=>'yes',
'hiddenField'=>'no'
]
);
?>
Saving the values, works.
But if the value "Yes" is saved, I call the edit view again, the checkbox is not marked as checked.
Is there any way to get around this? Would be more pleasant for the corresponding user as in the remaining input fields to get the value issued.
Do you have an idea or an approach?
Thank you in advance.
I think should be
echo $this->Form->checkbox('active', [
'checked' => $your_table->active == 'yes' ? true : false,
]);
Don't forget to use $this->set(compact('your_model')); of edited record.
I have a form that has some fields.
One field is autocomplete
.
The field is filled with information from a table
$f->addField('autocomplete','idfield','Field')->setValueList( $this->api->db->dsql()
->table('items')->field('id,name')->do_getAssoc() );
I'm trying to set the focus on that field when the page loads.
I have did this
On top of the page
$p->js()->_load('seteo_foco');
And then
seteo_foco.js
$(function(){
$("select:first").focus();
})
But this does not work.
Anybody can help ?
Thanks
Try TRUE like
$this->js(true)->_load('seteo_foco'); to load js file.
But in your js code your selector is incorrect. You need to specify you unique field. I'd use something like $form->getElement('field_name')->js(true)->focus(); on the page after the form has been initialized.
I have a Cakephp 1.3 form that allows users to edit the profile data. But some of the information in the forms needs to be read only (sometimes).
Is my only option to echo and format the field contents in the read only case or is there a flag in the Cake form that allows for read only fields. Ideally the read only fields would be greyed out similar to other interfaces.
echo $this->Form->create('User', array('url' => array('controller' => 'User', 'action'=>'editUser')));
echo $this->Form->input('id', array('type'=>'hidden'));
If (!isset($IsAdmin)) {
// Only display username - read only! Add code here
echo $this->Form->input('username', array('label' => __d('users', 'User',true)));
} else {
// Admins can edit user names
echo $this->Form->input('username', array('label' => __d('users', 'User',true)));
}
... more fields here
echo $this->Form->end(__d('users', 'Submit',true));
You can add a 'disabled' key to the options array, however realise that this is only the front-end/presentation of the form, people will be able to override the 'disabled' property of the input field and modify its value.
To prevent unwanted changes to be saved, you need to specify a 'fieldList' when saving the data using your model
To output a disabled form field;
echo $this->Form->input('fieldname', array('type'=>'hidden', 'disabled' => 'disabled'));
Then, when saving the data, specify a fieldlist (documentation: http://book.cakephp.org/1.3/en/The-Manual/Developing-with-CakePHP/Models.html#saving-your-data)
$this->MyModel->save($this->data, true, array('field1', 'field2'));
The fieldlist should include all fields that are allowed to be updated by the user
The disabled attribute is fine but actually, input fields have a 'readonly' attribute. And it sounds like you want the field to still be shown to the user so using 'hidden' isn't really addressing what you want done.
So an alternative (and actually specifically addressing your requirement for 'read only'):
echo $this->Form->input('fieldname', array('readonly' => 'readonly'));
I found that using disabled prevents jquery click triggers from firing versus readonly still fires e.g. using a bootstrap datepicker text field
Here's a link to WC3 for it: http://www.w3schools.com/tags/att_input_readonly.asp
if you really want to make a field read only why you want to use form field, just echo the value, one can easily change disable or readonly attribute of form field with simple javascript or firebug.
Okay, after having tried several approaches, here is what I like.
1) Use readonly (disabled will remove the value after hitting "save", when you are in update mode, which sucks):
echo $this->Form->input('email', array('readonly' => 'readonly'));
2) To prevent this from updating when removing 'readonly' via browser plugins, you can add this to beforeSave of your model:
if(isset($this->data[$this->alias]['id'])) // id is only set if we update
{
unset($this->data[$this->alias]['email']);
}
Field lists are not comfortable. Why should I add all the fields, when I actually only want to exclude one?
Unsetting will prevent CakePHP from updating it in the database. Of course, after hitting save with an (invalidly) updated e-mail address, this update will be shown in the form once. But as the user has manipulated the HTML form and since the database field stays unchanged, this should not matter.
You can do either of two things:
Make the field hidden
(Ex. echo $this->Form->input ('username, array ('type' => 'hidden'));
Reset the value of username to it's original value, before submitting the form or possibly in beforeSave.
How can I keep the selected value for a dropdownlist after form submission in Cakephp?
If more info (or some code) is needed just tell me please.
UPDATE
Here is part of the code in my view:
echo $this->Form->create('Chart');
echo $this->Form->input('username',
array('label'=>('Usernames List'),
'default'=>('Select username'),
'options'=>$usernames, 'selected'=>false));
echo $this->Form->end('Create Chart');
So, when I press 'Create Chart', the dropdownlist doesn't keep the username that I selected, but it goes back to the first one.
The Form helper uses the data stored in $this->data to prepopulate fields. Make sure that when you are submitting the form, the view that is rendered after has the appropriate model/key data stored in $this->data in order for the Form helper to correctly fill in the appropriate values.
Can we see your controller action possibly? That may help draw a more accurate conclusion.
you should never use the view to set defaults or values (especially selected/value is wrong as it - like your code - destroys the idea of persistent forms).
use the controller instead
#see http://www.dereuromark.de/2010/06/23/working-with-forms/ (Default Values)
add value in dropdown like this:
<?php echo $this->form->select('Schedule.showsid', array('0'=>'title', '1'=>'description'));?>
Using CakePHP's form helper to generate a checkbox is easy enough; to use the example from the documentation:
echo $this->Form->checkbox('done',array('value' => 555));
This will produce the following HTML:
<input type="hidden" name="data[User][done]" value="0" id="UserDone_" />
<input type="checkbox" name="data[User][done]" value="555" id="UserDone" />
This is all well and good, and the hidden field serves to force submission of a value for the "done" field even if the box remains unchecked.
Now, for the sake of argument, let's say the database definition of this field is ENUM('yes','no'). Of course I can easily change the value of the checkbox to "yes". However, if it's unchecked, a value of "0" is submitted from the hidden element. This produces no error or warning from mysql, as 0 is always a legal value for an enum field; it appears as an empty string.
Can I change value of the hidden field that CakePHP generates (to "no"), or do I need to suppress the auto-generation and create the hidden field myself? (An annoyance that grows with the number of checkboxes.)
I believe this all applies to radio button groups, too—at least if they don't have a default selection.
I'm using CakePHP 1.3. Thanks.
With FormHelper::checkbox, you can use hiddenField to set the default value.
<?php echo $this->Form->checkbox('done', array('value'=>'yes', 'hiddenField'=>'no');?>
With FormHelper::radio, you can only set value to default to one of the options, if the values match. This will also suppress the hidden field.
<?php echo $this->Form->radio('done', array('yes' => __('Yes')), 'no' => __('No'), array('value'=>'no');?>
Also, you should remember that CakePHP does not support enums (and I am sure this sort of scenario is one reason)
If your field data is truly binary (yes/no true/false enables/disabled etc.) then for the sake of CakePHP conventions you should just use an int(1) or tinyint(1) field and then convert the boolean value to yes/no etc in the view.
Then you don't have to worry about creating your own hidden input values and disabling the generated hidden inputs.
Another option would be to override the form->helper checkbox method that gets called by form->input to accept a new key in the options array that sets the value to something other than a 0 / false.
Unfortunately, FormHelper::checkbox allows you to disable the hidden element, but not to select its value, so you will need to do so and create the hidden field yourself. For example:
<?php echo $this->Form->hidden('done',array('value'=>'no'))?>
<?php echo $this->Form->checkbox('done',array('value'=>'yes','hiddenField'=>false))?>
With FormHelper::Radio worked for me like that
echo $this->Form->radio(
'done',
['yes' => __('Yes'), 'no' => __('No')],
['hiddenField' => false]
);