I would like to know I can count how many specific header files some files include
How many distinct specific calls some files contain (for example "#include" calls)
Thank you very much in advance
If you want to count only header files in folder and subfolder using
this,
**find . -iname "*.h" -type f | wc -l**
If you want to count only source files in folder and subfolder using
this,
**find . -iname "*.c" -type f | wc -l**
If you want to count only library files in folder and subfolder using
this,
**find . -iname "*.a" -type f | wc -l**
Use grep with the -c flag to count
For a list of files to search in like file1 and file2:
grep -c #include file1 file2 ...
Or recursively in a directory:
grep -c -r "#include" ~/MyCPrograms/
I need a shell script to remove files without an extension (like .txt or any other extension). For example, I found a file named as imeino1 (without .txt or any other thing) and I want to delete them via shell script, so if any developer know about this part, please explain how to do it.
No finds, no pipes, just plain old shell:
#!/bin/sh
for file in "$#"; do
case $file in
(*.*) ;; # do nothing
(*) rm -- "$file";;
esac
done
Run with a list of files as argument.
Assuming you mean a UNIX(-like) shell, you can use the rm command:
rm imeino1
rm -rvf `ls -lrth|grep -v ".txt"`
ls -lrth|grep -v ".txt" should be inside back-quotes `…`(or, better, inside $(…)).
If other filenames are not containing "." then instead of giving .txt for grep -v, you can give
rm -rvf `ls -lrth|grep -v "."`
This will remove all the directories and files in the path without extension.
rm -vf `ls -lrth|grep -v "."` won't remove directories, but will remove all the files without extension (if the filename does not contain the character ".").
for file in $(find . -type f | grep -v '\....$') ; do rm $file 2>/dev/null; done
Removes all files not ending in .??? in the current directory.
To remove all files in or below the current directory that contain no dot in the name, regardless of whether the names contain blanks or newlines or any other awkward characters, you can use a POSIX 2008-compliant version of find (such as found with GNU find, or BSD find):
find . -type f '!' -name '*.*' -exec rm {} +
This looks for files (not directories, block devices, …) with a name that does not match *.* (so does not contain a .) and executes the rm command on conveniently large groups of such file names.
I have multiple(more than 100) .c files and I want to change a particular text from all the file in which that text exists. I am using ubuntu!
How can I do it?(I will prefer command line rather than installing any application)
Thanks a lot!
OLD=searchtext
NEW=replacedtext
YOURFILE=/path/to/your/file
TMPFILE=`mktemp`
sed "s/$OLD/$NEW/g" $YOURFILE > $TMPFILE && mv $TMPFILE $YOURFILE
rm -rf $TMPFILE
you can also use find to find your files:
find /path/to/parent/dir -name "*.c" -exec sed 's/$OLD/$NEW/g' {} > $TMPFILE && mv $TMPFILE {} \;
find /path/to/parent/dir -name "*.c" finds all files with name *.c under /path/to/parent/dir. -exec command {} \; executes the command in the found file. {} stands for the found file.
You should check out sed, which lets your replace some text with other text (among other things)
example
sed s/day/night/ oldfile newfile
will change all occurences of "day" with "night" in the oldfile, and store the new, changed version in the newfile
to run on many files, there are a few things you could do:
use foreach in your favorite shell
use find like this
find . -name "namepattern" -exec sed -i "sed-expr" "{}" \;
use file patterns like this: sed -i "sed-expr" *pattern?.cpp
where *pattern?.cpp is just a name pattern for all files that starts with some string, then has "pattern" in them, and has any letter and a ".cpp" suffix
I am running Ubuntu. I have a folder "Project", and in that folder I have a bunch of sub-folders. In each of the sub-folders I have either a .c file, a .jar file or a .py file. I want to iterate over all the files, and for each file, compile it, and run 5 times with different input it using the "time" command to time the execution time.
I want to create a shell script for this, but I can't seem to find a good way to recurse over all the files in the sub-folders.
If you are using Bash4 you can set globstar to recurse all subdirs without caring about depth
#!/bin/bash
shopt -s globstar
for file in /path/to/your/files/**; do
case "${file##.*}" in
c)
gcc -c "$file"
;;
jar)
java -jar "$file"
;;
py)
python "$file"
;;
esac
done
If all of the subfolders are the same depth you can use for i in ./*/*/*/*.py with the appropriate number of *'s. Use one loop for each format since the actions will be different anyways.
Something like:
for folder in *
do
if [ -d $folder] then
cd $folder
for file in *.py
do
if [ -f $file ] then
do your stuff ..
fi
done
for file in *.c
do
if [ -f $file ] then
fi
done
.......
cd ..
fi
done
How do I find out the files in the current directory which do not contain the word foo (using grep)?
If your grep has the -L (or --files-without-match) option:
$ grep -L "foo" *
You can do it with grep alone (without find).
grep -riL "foo" .
This is the explanation of the parameters used on grep
-L, --files-without-match
each file processed.
-R, -r, --recursive
Recursively search subdirectories listed.
-i, --ignore-case
Perform case insensitive matching.
If you use l (lowercased) you will get the opposite (files with matches)
-l, --files-with-matches
Only the names of files containing selected lines are written
Take a look at ack. It does the .svn exclusion for you automatically, gives you Perl regular expressions, and is a simple download of a single Perl program.
The equivalent of what you're looking for should be, in ack:
ack -L foo
The following command gives me all the files that do not contain the pattern foo:
find . -not -ipath '.*svn*' -exec grep -H -E -o -c "foo" {} \; | grep 0
The following command excludes the need for the find to filter out the svn folders by using a second grep.
grep -rL "foo" ./* | grep -v "\.svn"
If you are using git, this searches all of the tracked files:
git grep -L "foo"
and you can search in a subset of tracked files if you have ** subdirectory globbing turned on (shopt -s globstar in .bashrc, see this):
git grep -L "foo" -- **/*.cpp
You will actually need:
find . -not -ipath '.*svn*' -exec grep -H -E -o -c "foo" {} \; | grep :0\$
I had good luck with
grep -H -E -o -c "foo" */*/*.ext | grep ext:0
My attempts with grep -v just gave me all the lines without "foo".
Problem
I need to refactor a large project which uses .phtml files to write out HTML using inline PHP code. I want to use Mustache templates instead. I want to find any .phtml giles which do not contain the string new Mustache as these still need to be rewritten.
Solution
find . -iname '*.phtml' -exec grep -H -E -o -c 'new Mustache' {} \; | grep :0$ | sed 's/..$//'
Explanation
Before the pipes:
Find
find . Find files recursively, starting in this directory
-iname '*.phtml' Filename must contain .phtml (the i makes it case-insensitive)
-exec 'grep -H -E -o -c 'new Mustache' {}' Run the grep command on each of the matched paths
Grep
-H Always print filename headers with output lines.
-E Interpret pattern as an extended regular expression (i.e. force grep
to behave as egrep).
-o Prints only the matching part of the lines.
-c Only a count of selected lines is written to standard output.
This will give me a list of all file paths ending in .phtml, with a count of the number of times the string new Mustache occurs in each of them.
$> find . -iname '*.phtml$' -exec 'grep -H -E -o -c 'new Mustache' {}'\;
./app/MyApp/Customer/View/Account/quickcodemanagestore.phtml:0
./app/MyApp/Customer/View/Account/studio.phtml:0
./app/MyApp/Customer/View/Account/orders.phtml:1
./app/MyApp/Customer/View/Account/banking.phtml:1
./app/MyApp/Customer/View/Account/applycomplete.phtml:1
./app/MyApp/Customer/View/Account/catalogue.phtml:1
./app/MyApp/Customer/View/Account/classadd.phtml:0
./app/MyApp/Customer/View/Account/orders-trade.phtml:0
The first pipe grep :0$ filters this list to only include lines ending in :0:
$> find . -iname '*.phtml' -exec grep -H -E -o -c 'new Mustache' {} \; | grep :0$
./app/MyApp/Customer/View/Account/quickcodemanagestore.phtml:0
./app/MyApp/Customer/View/Account/studio.phtml:0
./app/MyApp/Customer/View/Account/classadd.phtml:0
./app/MyApp/Customer/View/Account/orders-trade.phtml:0
The second pipe sed 's/..$//' strips off the final two characters of each line, leaving just the file paths.
$> find . -iname '*.phtml' -exec grep -H -E -o -c 'new Mustache' {} \; | grep :0$ | sed 's/..$//'
./app/MyApp/Customer/View/Account/quickcodemanagestore.phtml
./app/MyApp/Customer/View/Account/studio.phtml
./app/MyApp/Customer/View/Account/classadd.phtml
./app/MyApp/Customer/View/Account/orders-trade.phtml
When you use find, you have two basic options: filter results out after find has completed searching or use some built in option that will prevent find from considering those files and dirs matching some given pattern.
If you use the former approach on a high number of files and dirs. You will be using a lot of CPU and RAM just to pass the result on to a second process which will in turn filter out results by using a lot of resources as well.
If you use the -not keyword which is a find argument, you will be preventing any path matching the string on the -name or -regex argument behind from being considered, which will be much more efficient.
find . -not -regex ".*/foo/.*" -regex ".*"
Then, any path that is not filtered out by -not will be captured by the subsequent -regex arguments.
For completeness the ripgrep version:
rg --files-without-match "pattern"
You can combine with file type and search path, e.g.
rg --files-without-match -t ruby "frozen_string_literal: true" app/
another alternative when grep doesn't have the -L option (IBM AIX for example), with nothing but grep and the shell :
for file in * ; do grep -q 'my_pattern' $file || echo $file ; done
My grep does not have any -L option. I do find workaround to achieve this.
The ideas are :
to dump all the file name containing the deserved string to a txt1.txt.
dump all the file name in the directory to a txt2.txt.
make the difference between the 2 dump file with diff command.
grep 'foo' *.log | cut -c1-14 | uniq > txt1.txt
grep * *.log | cut -c1-14 | uniq > txt2.txt
diff txt1.txt txt2.txt | grep ">"
find *20161109* -mtime -2|grep -vwE "(TRIGGER)"
You can specify the filter under "find" and the exclusion string under "grep -vwE". Use mtime under find if you need to filter on modified time too.
Open bug report
As commented by #tukan, there is an open bug report for Ag regarding the -L/--files-without-matches flag:
ggreer/the_silver_searcher: #238 - --files-without-matches does not work properly
As there is little progress to the bug report, the -L option mentioned below should not be relied on, not as long as the bug has not been resolved. Use different approaches presented in this thread instead. Citing a comment for the bug report [emphasis mine]:
Any updates on this? -L completely ignores matches on the first line of the file. Seems like if this isn't going to be fixed soon, the flag should be removed entirely, as it effectively does not work as advertised at all.
The Silver Searcher - Ag (intended function - see bug report)
As a powerful alternative to grep, you could use the The Silver Searcher - Ag:
A code searching tool similar to ack, with a focus on speed.
Looking at man ag, we find the -L or --files-without-matches option:
...
OPTIONS
...
-L --files-without-matches
Only print the names of files that don´t contain matches.
I.e., to recursively search for files that do not match foo, from current directory:
ag -L foo
To only search current directory for files that do not match foo, simply specify --depth=0 for the recursion:
ag -L foo --depth 0
This may help others. I have mix of files Go and with test files. But I only need .go files. So I used
ls *.go | grep -v "_test.go"
-v, --invert-match select non-matching lines see https://stackoverflow.com/a/3548465
Also one can use this with vscode to open all the files from terminal
code $(ls *.go | grep -v "_test.go")
grep -irnw "filepath" -ve "pattern"
or
grep -ve "pattern" < file
above command will give us the result as -v finds the inverse of the pattern being searched
The following command could help you to filter the lines which include the substring "foo".
cat file | grep -v "foo"