CakePHP How do I display all table field names - cakephp

New to CakePHP, so be gentle...
I'm trying to loop through a table to display all the read-only fields (labels and values).
In my edit function, I get the table
$this->set('invoice', $this->Invoice->read(null, $id));
In my view, I want to loop through the entire table schema and output the field names and values as labels like fieldName: value
Invoice Number: SVC00158
Invoice Date: 03/03/12
There are 37 fields in this table. I would rather not have to manually code for every one. I know to retrieve the input fields like this
echo $this->Form->input('purchaseOrderNumber');
but I can't seem to find a 'read-only' attribute for the input() method. Hope that makes sense.
Thanks for your time.

You could loop through the schema and output it like that:
// assumes $result contains model data
$schema = $this->Model->schema();
foreach ($schema as $field => $attrs) {
echo $result['Model'][$field];
}

just write:
<?=$this->Form->inputs();?>

If you are a beginner I suggest you look into Cake Bake (it will "bake" all your files from the console).
I mean the views, controllers, and models based on you current db schema so that will it for you and even apply some styling to it.
I hope that helps

Related

Laravel get value of column from relation through pivot on load() after all()

I have a problem retrieving values of a column from relations in Laravel.
I have a User - Model. This model has relation to a table btw. a model named Userhobbies.
For now we have:
User ::: hasMany >>> Userhobbies
Now with User::all()->load('hobbies') I'm getting right results like
{"id":"1","username":"jdoe","first_name":"Joe","last_name":"Doe","birth":"
1992-04-11","picture_id":"f3dca65323e876026b409b9ba3d49c56","hobbies":
[{"hobby_id":"1","user_id":"1"},{"hobby_id":"2","user_id":"1"},
{"hobby_id":"3","user_id":"1"},{"hobby_id":"4","user_id":"1"}]}
As you can see Userhobbies contains only primary-key relations between hobby - table (Hobby Model) and user - table (User Model).
(Hobby model also has hasMany relation to Userhobbies)
My question now is - how to retrieve all hobby-names (from hobby - table) in my call over (after load('hobbies') ) and is it possible without writting a lot of code?
For better understanding of my idea the result which I want to retrieve:
{"id":"1","username":"jdoe","first_name":"Joe","last_name":"Doe","birth":"
1992-04-11","picture_id":"f3dca65323e876026b409b9ba3d49c56","hobbies":
["golf", "cards", "games", "football"]}
EDIT:
If I try following (I tried with belongsToMany in User and Hobby):
User::with('hobbies')->get()->first()
And I'm getting the whole values from the hobbies - table:
{user-specific data ...
hobbies:[{"id":"1","name":"golf","created_at":"2015-04-07
14:15:02","updated_at":"2015-04-07 14:15:02","pivot":
{"user_id":"1","hobby_id":"1"}},
{"id":"2","name":"cards","created_at":"2015-04-07
14:15:02","updated_at":"2015-04-07 14:15:02","pivot":
{"user_id":"1","hobby_id":"2"}},
{"id":"3","name":"games","created_at":"2015-04-07
14:15:02","updated_at":"2015-04-07 14:15:02","pivot":
{"user_id":"1","hobby_id":"3"}},
{"id":"4","name":"football","created_at":"2015-04-07
14:15:02","updated_at":"2015-04-07 14:15:02","pivot":
{"user_id":"1","hobby_id":"4"}}]}
Same try with ->load('hobbies'). I really don't know how to go on.
To explain it a bit more what I need one could imagine such query as follows:
User::all(['id', 'name'])->load(array('hobbies.id','hobbies.name'))->get();
From my knowledge, I know that it's possible to use a closure to set constraints on the query that performs the load, like so:
User::all()->load(['hobbies' => function($query)
{
$query->select('id', 'name');
}]);
By doing it, when you cast it to array, it will produce a result near to what you want. You can even add 'pivot' to your $hidden property on your Hobby model to hide this information.

CakePHP: How to write a find() query that excludes one field in the resultset?

Is there a way to write a CakePHP query to return all fields (columns) except one via find()? Or do I need to use the fields parameter and actually list all the fields, except the excluded field?
For example, if I have a database table (model), Company, with these fields:
id
name
street
city
state
zip
phone
Normally, $this->Company->find('all') would return all the fields. I want to exclude the phone field from the resultset.
$fields = array_keys($this->Company->getColumnTypes());
$key = array_search('phone', $fields);
unset($fields[$key]);
$this->Company->find('all', array('fields' => $fields));
For more info, please have a look at http://book.cakephp.org/2.0/en/models/additional-methods-and-properties.html#model-getcolumntypes
I can think of a couple ways to do this
Write out all the fields you want to include in the fields parameter. As mentioned in the comment, you can use $this->Company->schema to get all the fields programmatically rather than writing them out.
Unset the field you don't want after you get the data. You can do this in the model's afterFind function too.

CakePHP - Passing an array of record IDs to paginate - is it possible?

Due to having to having to import data from an old non cake app and oddly built database table I need to pass paginate an array of records it is allowed to display - is this possible?
Normally I would reorganise the data into proper relationships etc but due to time scales etc this is not possible.
To give you more info - in my users table I have a field that contains a list of ID's that relate to documents they are allowed to view. The field will contain something like
123,23,45,56,765,122,11.9,71,25
Each ID refers to a document the documents model. I know that normally you would create proper ACOs and AROs and let the ACL/Auth componant handle which users can access what but this isnt an option this time around. So I thought if I could do it via paginate/find it might be an option?
Any help would be really appreciated.
Thanks in advance
You wouldn't pass it a list of IDs, you'd use the IDs in your paginate conditions - something like below.
(Code written off top of my head, so pardon any syntax errors...etc. It should give you the right idea/path at least):
//Controller
$this->loadModel('User');
$this->loadModel('Document');
$user = $this->User->findById($userId);
$documentIds = explode(',', $user['User']['doc_ids']);
$this->paginate = array(
'conditions' => array(
'id' => $documentIds
)
));
$documents = $this->paginate('Document');
When you pass an array as a condtion (eg. 'id'=>$arrayOfIds), it uses MySQLs "IN" - something like:
... WHERE id IN (45, 92, 173)

pull Drupal field values with db_query() or db_select()

I've created a content type in Drupal 7 with 5 or 6 fields. Now I want to use a function to query them in a hook_view call back. I thought I would query the node table but all I get back are the nid and title. How do I get back the values for my created fields using the database abstraction API?
Drupal stores the fields in other tables and can automatically join them in. The storage varies depending on how the field is configured so the easiest way to access them is by using an EntityFieldQuery. It'll handle the complexity of joining all your fields in. There's some good examples of how to use it here: http://drupal.org/node/1343708
But if you're working in hook_view, you should already be able access the values, they're loaded into the $node object that's passed in as a parameter. Try running:
debug($node);
In your hook and you should see all the properties.
If you already known the ID of the nodes (nid) you want to load, you should use the node_load_multiple() to load them. This will load the complete need with all fields value. To search the node id, EntityFieldQuery is the recommended way but it has some limitations. You can also use the database API to query the node table for the nid (and revision ID, vid) of your nodes, then load them using node_load_multiple().
Loading a complete load can have performance impacts since it will load way more data than what you need. If this prove to be an issue, you can either try do directly access to field storage tables (if your fields values are stored in your SQL database). The schema of these tables is buld dynamicaly depedning on the fields types, cardinality and other settings. You will have to dig into your database schema to figure it out. And it will probably change as soon as you change something on your fields.
Another solution, is to build stub node entities and to use field_attach_load() with a $options['field_id'] value to only load the value of a specific field. But this require a good knowledge and understanding of the Field API.
See How to use EntityFieldQuery article in Drupal Community Documentation.
Creating A Query
Here is a basic query looking for all articles with a photo that are
tagged as a particular faculty member and published this year. In the
last 5 lines of the code below, the $result variable is populated with
an associative array with the first key being the entity type and the
second key being the entity id (e.g., $result['node'][12322] = partial
node data). Note the $result won't have the 'node' key when it's
empty, thus the check using isset, this is explained here.
Example:
<?php
$query = new EntityFieldQuery();
$query->entityCondition('entity_type', 'node')
->entityCondition('bundle', 'article')
->propertyCondition('status', 1)
->fieldCondition('field_news_types', 'value', 'spotlight', '=')
->fieldCondition('field_photo', 'fid', 'NULL', '!=')
->fieldCondition('field_faculty_tag', 'tid', $value)
->fieldCondition('field_news_publishdate', 'value', $year. '%', 'like')
->fieldOrderBy('field_photo', 'fid', 'DESC')
->range(0, 10)
->addMetaData('account', user_load(1)); // Run the query as user 1.
$result = $query->execute();
if (isset($result['node'])) {
$news_items_nids = array_keys($result['node']);
$news_items = entity_load('node', $news_items_nids);
}
?>
Other resources
EntityFieldQuery on api.drupal.org
Building Energy.gov without Views

CakePHP HABTM relationship, setting related records always adds new entry in jointable even if already exists

This is my code:
$charities = explode(',',$this->data['Charity']['charities']);
foreach ($charities as $key=>$charity){
$data['Charity'][$key] = $charity;
}
$this->Grouping->id = $this->data['Charity']['grouping_id'];
if ($this->Grouping->save($data)){
//Great!
}else{
//Oh dear
}
The code is from an action that gets called by AJAX. $this->data['Charity']['charities'] is a comma separated list of ids for the Charity model, which HABTM Grouping.
The code works fine, except that Cake doesn't seem to check whether that charity is already associated with that grouping, so I end up with lots of duplicate entries in the join table. I can see that this will be a pain later on so I'd like to get it right now.
What am I doing wrong?
Thanks
A few things I spotted:
A. Is $this->data['Charity']['charities'] an array with named keys corresponding to the table columns? Because inside the foreach() loop, you are taking the key and putting it in the $data['Charity'] array. The result could be a wrong format. The $data array for Model saves is commonly formatted as $data['Charity']['NAME_OF_COLUMN1], $data['Charity']['NAME_OF_COLUM2], and so on for each column that wants to be saved. So, if the keys are numbers, then you could be having something like: $data['Charity'][0], $data['Charity'][1], which is wrong.
B. HABTM Associations are saved differently. What I do recommend, is that you take a look at the book's section on saving HABTM. I save a HABTM relation like this (supposing a relation between users and coupons):
$this->data['Coupon'] = array('id' => 1, 'code' = 'BlaBla');
$this->data['User'] = array('id' => 33);
$this->Coupon->save($this->data, false);
So, as you can see, the $data array has a subarray named after the foreign model ('User') with the columns+values that I want to save. Then I save this array to the Coupon model.
C. Be aware that CakePHP will always delete old records and insert new ones within the join table when it is 'updating' HABTM relations. To avoid this, you set the 'unique' field to false in the Model's $HABTM configuration.

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