So, I would like to use this magic find function in my CakePHP 2.0 app:
$profile = $this->Profile->findByUserId($user['User']['id']);
However, the field in question is called userId, not user_id. The code above throws an error - column user_id is missing.
Is there a way to force Cake to try to look for camel cased column names?
Thanks for reading!
You will have to override the appropriate function for that. Cake's conventions are just that, conventions. If you stray from them, you'll need to put in more manual work. So either create the function findByUserId in the appropriate model, or override the magic __call function.
Related
I have a CakePHP project having 3 plugins: Plugin1, Plugin2, Plugin3. These are simple plugins, I've just tried to split up my project into 3 smaller & easier parts.
Plugin1 has to use a model Model1, where there is no db table for this Model1.
I know the $useTable=false thing. My problem is, I have a function func() in that model, and I am trying to use that function func() in a Controller, in Plugin1. But it shows an SQL SYNTAX error. I think, usually we use the find() function of the model, but here we are creating a function and using, may be that's the problem.
Here, table-name and Model-name are in correct convention. I don't want to create a table for this, since I don't need it. What to do now ?
sorry i was new here so this problem maybe simple.
anyone knows how to check variable content?
like xx($a);
then page shows all relate information about $a. Is CakePHP allowed to do that?
i setup a kit on my cakephp
You might be looking for either var_dump() or print_r()
You can use PHP built-in functions like
var_dump() - displays structured information about variable
print_r() - the same, but preformatted with some differences
get_defined_vars() - returns array with all defined variables
Or use true CakePHP-way
Debugger::dump() - It will print out all properties and methods (if any) of the supplied variable
For more convenience you may use CakePHP Debug Kit plugin, which provides nice toolbar and some useful tools for your purpose.
I am using the cake bake command to create my fixture and Test models. I have done it successfully with one of my models but i am having troubles with another one.
I dont know why, it tries to work with the default DB instead with the test one that i have already defined and that is the one used by the first model i tested.
Both Test models, the one which works well and this 2nd one which doesn't, have been created with cake bake and they look exactly the same.
Both of them have this in their fixture class:
public $import = array('records' => true, 'connection' => 'test');
Test defines the connection to my test database.
What can be the problem?
I have experiment something weird. In my test model if i use the singluar instead of the plural, it works with the default DB BUT if i change it to plural it works with the test DataBase. (but it can not call any method from the model, just defined methods such as find()).
For example:
public function setUp() {
parent::setUp();
//uses the default DB (i dont know why)
$this->Post = ClassRegistry::init('Post');
print_r($this->User->find('all'));
$this->Post->updatePostsStatus(1); //works well
//uses the default Test Database (i dont know why either)
$this->Post = ClassRegistry::init('Posts');
print_r($this->User->find('all'));
$this->Post->updatePostsStatus(1); //doesn't work. No function found.
/*SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'updatePostsStatus' at line 1*/
}
Thanks.
I HAVE UPDATED IT.
LAST UPDATE AND SOLUTION
The problem was the bad initialization of the Post Model constructor.
Using the plural was not relevant. It is like using any non existent model. It will always get the test database.
The answer for the good initialization of the constructor is here:
How to override model's constructor correctly in CakePHP
That sort of MySQL error can be very misleading in CakePHP.
Basically the actual problem is with the line $this->Post->updatePostsStatus(1); Specifically it's that eitherthe Post model or updatePostsStatus() method of the posts model doesn't exist.
You basically have a typo on this line, check the method name. Should it be updatePostStatus? (no plural on posts?)
For some reason, if you try to call an undefined method on a model in CakePHP, instead of reporting the method is not found, the "automagicness" of CakePHP kicks in and bizarrely it tries to push the unfound method name straight into MySQL.
Basically, because CakePHP cannot find the $this->Post->updatePostsStatus(1); method, it is actually trying to execute a MySQL query of updatePostsStatus ie mysql_query("updatePostsStatus');, which is why we are seeing this wierd database error. Chances are you've just misspelled the method name.
If the method name is still not the problem, it's something to do with the Posts model not being instantiated correctly. Although that seems doubtful as long as you got all the names right. It is definitely not a database issue, just Cakes lame way of handling unknown class methods automagically.
I use CakePHP 1.3.9 but I can't use other Models in a Controller.
I use $this->loadModel('ModelName); and $this->ModelName->find('all') - always empty.
The variable $uses also doesn't work.
Why is it not working for me?
I used i18n and must set $locale...
Do you mean the data set is empty? If the model is not loaded, you shouldn't be able to call $this->ModelName->find() as $this->ModelName would be null. Does it throw an error? Your usage is correct, as stated in the manual : http://book.cakephp.org/view/992/loadModel
You can also do
App::import('Model', 'ModelName');
$model = new Model();
But I'm guessing that your current resultset is returning empty rather than the model itself not being set.
Have you tried looking at what $this->ModelName actually contains? Do the following and post it here
pr($this->ModelName)
It's considered bad practice to put (un-associated) models in your $uses array.
Depending what you are trying to do, you may be able to make use of containable behaviour.
$this->User->Post->find('all');
If not, you should be able to use loadModel:
$this->loadModel('Article');
$recentArticles = $this->Article->find('all', array('limit' => 5));
To quote Cake:
The loadModel function comes handy when you need to use a model which is not the controller's default model or its associated model.
JohnP and Ross are correct. Controller::loadModel() is clearly working and not your problem if pr($this->ModelName) is working for you.
As they mentioned, you're probably having trouble because the data simply isn't in the database. Or maybe there's something wrong with your query. Have you tried checking the query that's produced by CakePHP and trying to query the database directly through the MySQL command line (assuming you're using MySQL)?
Or is there any chance you've overloaded the Model::find() method?
How does cakephp handle a get request? For instance, how would it handle a request like this...
http://us.mc01g.mail.yahoo.com/mc/welcome?.gx=1&.rand=9553121_pg=showFolder&fid=Inbox&order=down&tt=1732&pSize=20&.rand=425311406&.jsrand=3
Would "mc" be the controller and "welcome" be the action?
How is the rest of the information handled?
Also note that you could use named parameters as of Cake 1.2. Named parameters are in key:value order, so the url http://somesite.com/controller/action/key1:value1/key2:value2 would give a a $this->params['named'] array( 'key1' => 'value1', 'key2' => 'value2' ) from within any controller.
If you use a CNN.com style GET request (http://www.cnn.com/2009/SHOWBIZ/books/04/27/ayn.rand.atlas.shrugged/index.html), the parameters are in order of appearance (2009, SHOWBIZ, books, etc.) in the $this->params['pass'] array, indexed starting at 0.
I strongly recommend named paramters, as you can later add features by passing get params, without having to worry about the order. I believe you can also change the named parameter separation key (by default, it's ':').
So it's a slightly different paradigm than the "traditional" GET parameters (page.php?key1=value1&key2=value2). However, you could easily add some logic in the application to automatically parse traditional parameters into an array by tying into how the application parses requests.
CakePHP uses routes to determine this. By default, the routes work as you described. The remainder after the '?' is the querystring and it can be found in $this->params['url'] in the controller, parsed into an associative array.
Since I found this while searching for it, even though it's a little old.
$this->params['url']
holds GET information.
I have tested but it does work. The page in the Cakephp book for it is this link under the 'url' section. It even gives an example very similar to the one in the original question here. This also works in CakePHP 1.3 which is what I'm running.
It doesn't really use the get in the typical since.
if it was passed that long crazy string, nothing would happen. It expects data in this format: site.com/controller/action/var1/var2/var....
Can someone clarify the correct answer? It appears to me that spoulson's and SeanDowney's statements are contradicting each other?
Would someone be able to use the newest version of CakePHP and get the following url to work:
http://www.domain.com/index.php/oauth/authorize?oauth_version=1.0&oauth_nonce=c255c8fdd41bd3096e0c3bf0172b7b5a&oauth_timestamp=1249169700&oauth_consumer_key=8a001709e6552888230f88013f23d5d004a7445d0&oauth_signature_method=HMAC-SHA1&oauth_signature=0bj5O1M67vCuvpbkXsh7CqMOzD0%3D
oauth being the controller and authorize being a method AS WELL as it being able to accept the GET request at the end?