Below is my code in batchfile：
for %%f in (%~dp0*.sql) do (
sqlcmd -S %SName% -U %UName% -P %Pwd% -d %DbName% -I -i "%%f" >>TsDeploy.txt 2>&1
)
the question is there is one file in that set must be NOT Run as first one.(cause the others is script file about create Table,that one is to insert data into table ).
How Should I do to achieve the goal in ONLY ONE batchfile?
You could rename the sql file that must not run first so that it sorts to the end (prefix with z?).
Or you could do something like
for %%f in (%~dp0*.sql) do (
if "%~nxf" neq "fileNameNotToRunFirst.sql" (
sqlcmd -S %SName% -U %UName% -P %Pwd% -d %DbName% -I -i "%%f" >>TsDeploy.txt 2>&1
)
)
sqlcmd -S %SName% -U %UName% -P %Pwd% -d %DbName% -I -i "%~dp0fileNameNotToRunFirst.sql" >>TsDeploy.txt 2>&1
Or you could create a master sql script that calls each of the others in the proper order, as described in How to Run a Series of T-SQL Scripts in a Specific Order
Related
I have written a script to generate a .CSV file from an SQLCMD query, but when I open it in Notepad, there is unwanted spacing between data. When I manually paste the query results in the .csv file then there is no spacing when I open it in Notepad.
Please do let me know, what should I do to avoid the issue.
My minimal script example:
set destfolder="c:\Test"
SQLCMD -s "--Database name--" -d Audit -E -I -i "C:\Test\Mandates.sql" -s "," -o "c:\Test\tempfile.csv"
findstr /v /c:"---" "c:\Test\tempfile.csv" > "%destfolder%\%filename%"
del "%destfolder%\tempfile.csv"
Issue:
CustomerName,CustomerNumber,Value
Adam, 123456789, 0
Expected:
CustomerName,CustomerNumber,Value
Adam,123456789,0
I got the solution.
SQLCMD -s "--Database name--" -d Audit -E -I -W -i "C:\Test\Mandates.sql" -s "," -o "c:\Test\tempfile.csv"
I have used -W in the above script which resolves the issue. Thanks
I need to run about 50 scripts in a folder using sqlcmd from a batch file. Each script's query results need to be sent to its own output file. I have a working batch file that just runs each from a separate line:
sqlcmd -S %INSTANCE% -d %DATABASE% -U %USERNAME% -P "%PASSWORD%" -i "%SCRIPTFOLDER%\master_departments.sql" -s "|" -o "%OUTPUTFOLDER%\master_departments.csv" -W
sqlcmd -S %INSTANCE% -d %DATABASE% -U %USERNAME% -P "%PASSWORD%" -i "%SCRIPTFOLDER%\master_companies.sql" -s "|" -o "%OUTPUTFOLDER%\master_companies.csv" -W
sqlcmd -S %INSTANCE% -d %DATABASE% -U %USERNAME% -P %PASSWORD% -i "%SCRIPTFOLDER%\bill_history.sql" -s "|" -o "%OUTPUTFOLDER%\bill_history.csv" -W
sqlcmd -S %INSTANCE% -d %DATABASE% -U %USERNAME% -P %PASSWORD% -i "%SCRIPTFOLDER%\episodes.sql" -s "|" -o "%OUTPUTFOLDER%\episodes.csv" -W
Is there any way to run this in some kind of loop? I've seen examples that run a loop of all SQL scripts in a folder, but nothing that I've seen does it with an output file set.
Per #LotPings' suggestion I used the below code:
set INSTANCE=<someinstance>
set DATABASE=<somedb>
set USERNAME=<someuser>
set PASSWORD=<somepassword>
set "SCRIPTFOLDER=D:\<pathToScripts>\"
set "OUTPUTFOLDER=D:\<pathForOutput>\"
#Echo off
For /F "tokens=*" %%S in ('Dir /B "%SCRIPTFOLDER%*.sql" '
) do echo sqlcmd -S %INSTANCE% -d %DATABASE% -U %USERNAME% -P "%PASSWORD%" -i "%%~fS" -s "|" -o "%%~dpnS.csv" -W
#pause
I ran that in a batch file and when it paused, the last line said, "The system cannot find the file specified."
Thinking it was perhaps the backslashes in my paths, I removed them and put a slash before the .sql in the for line, but I got the same results.
Removing the backslash altogether resulted in a "File not found" message when I ran it like that.
In case your output file name matches the script name (without extension)
and your parameters are the same for all scripts
#Echo off
For /F "tokens=*" %%S in ('Dir /B "%SCRIPTFOLDER%*.sql" '
) do echo sqlcmd -S %INSTANCE% -d %DATABASE% -U %USERNAME% -P "%PASSWORD%" -i "%%~fS" -s "|" -o "%%~dpnS.csv" -W
The echo in front of sqlcmd prevents execution and allows to review the output. If all looks OK, remove the echo.
The for variable behaviour can be changed with ~ modifiers, see For /? or visit ss64.com/nt/for.html / syntax-args
To pass a folder to the batch you can input via set /P or hand over via command line arguments.
I am using widows XP OS and have batch file where I set few variable values.
when i echo those varibales i can see the values, but when i use it in some commands i get empty sting as its value.
Sample Batch file
#ECHO OFF
SET "output=select * from employee where empid='160'"
CALL SET output=%%output:'=''%%
ECHO "%output%"
sqlcmd -b -h-1 -m-1 -V1 -S testsvr -E -Q "%output%' " -d tesdb
o/p select * from employee where empid=''160''
and value of variable in sqlcmd command is empty space.
I'm not sure, what you want to do.
#ECHO OFF
SET output=select * from employee where empid="160"
ECHO %output%
ECHO sqlcmd -b -h-1 -m-1 -V1 -S testsvr -E -Q '%output%' -d tesdb
..output is:
select * from employee where empid="160"
sqlcmd -b -h-1 -m-1 -V1 -S testsvr -E -Q 'select * from employee where empid="160"' -d tesdb
Try to place the quotes as follows:
SET output="select * from employee where empid='160'"
sqlcmd -b -h-1 -m-1 -V1 -S testsvr -E -Q %output% -d tesdb
I would like to be able to shrink all log files in nested folders. I have used this same script to modify databases but I am having problems with the shrink command.
When I run this script, I get an error stating it can not find the database in the sys.database_files. So I'm guessing my database is going by a different name in sys.database_files or simply is not added. Can you help?
for /r /d %%i in (*) do (
ECHO %%i\MY_DB.mdf
osql -S LOCALHOST\SQLEXPRESS -U johan -P johan_j-d master -Q "EXEC sp_attach_db 'MY_DB', '%%i\MY_DB.mdf', '%%i\MY_DB_log.ldf';"
osql -S LOCALHOST\SQLEXPRESS -U johan -P johan_j -d MY_DB -Q "DBCC SHRINKFILE (N'MY_DB_log',0,TRUNCATEONLY);"
osql -S LOCALHOST\SQLEXPRESS -U johan -P johan_j -d master -Q "EXEC sp_detach_db 'MY_DB';"
)
Problem solved. I should have been using the logical file name not the physical file name.
We currently have a DOS batch script that performs a MySQL dump on the entire database in a single file. What I would like to do is breakup the database by tables, so that within each 'date' folder, there would be a 'db' folder containing individual table dumps. This allows us to restore selected tables rather than restoring an entire db.
#echo off
md C:\backups\%DATE:~-4%-%DATE:~4,2%-%DATE:~7,2%
cd C:\Program Files\MySQL\MySQL Workbench 5.2 CE\
mysqldump -h -u -p --databases db0 > c:\backups\%DATE:~-4%-%DATE:~4,2%-%DATE:~7,2%\db0.sql
mysqldump -h -u -p --databases db1 > c:\backups\%DATE:~-4%-%DATE:~4,2%-%DATE:~7,2%\db1.sql
I found a possible solution using shell: https://stackoverflow.com/a/134296/679449
This appears that it would allow me to export into individual tables, however I'm not sure how to/if it's possible to write in batch. Any help with that is appreciated.
My solution:
#echo off
md C:\backups\%DATE:~-4%-%DATE:~4,2%-%DATE:~7,2%\db0
md C:\backups\%DATE:~-4%-%DATE:~4,2%-%DATE:~7,2%\db1
cd C:\Program Files\MySQL\MySQL Workbench 5.2 CE\
mysql -s -e "SHOW TABLES FROM db0" -u -p --skip-column-names > C:\backups\tables.txt
for /f %%A in (C:\backups\tables.txt) DO (mysqldump -h -u -p db0 %%A > c:\backups\%DATE:~-4%-%DATE:~4,2%-%DATE:~7,2%\db0\%%A.sql)
mysql -s -e "SHOW TABLES FROM db1" -u -p --skip-column-names > C:\backups\tables.txt
for /f %%A in (C:\backups\tables.txt) DO (mysqldump -h -u -p db1 %%A > c:\backups\%DATE:~-4%-%DATE:~4,2%-%DATE:~7,2%\db1\%%A.sql)