i have a table named customer_age that loks like this:
ID 1 2 3 4 5 6 7 8 9
NAME JIM JIM JIM NICK NICK NICK Paul Paul Paul
VALUE 20 13 12 10 20 8 4 24 14
and i want to display only the first record from each name. Something like this
ID 1 4 7
NAME JIM NICK Paul
VALUE 20 10 4
So far i have not been able to work it out.
i use sql server 2005
Any help would be appreciated...
Try using a subselect to find the lowest ID for each name, and use that set of IDs to pull the records from the main table:
SELECT ID, Name, Value
FROM customer_age
WHERE ID IN
(
SELECT MIN(ID) AS ID
FROM customer_age
GROUP BY Name
)
Just select the first record for each name using cross apply:
SELECT
ca.ID, ca.NAME, ca.VALUE
FROM customer_age c
CROSS APPLY (SELECT TOP 1 ID, NAME, VALUE
FROM customer_age ca
WHERE ca.NAME = c.NAME ORDER BY ID) ca
ORDER BY ca.ID
How about using window functions??
SELECT Id, Name, Value
FROM (
SELECT Id, Name, Value, ROW_NUMBER() OVER (PARTITION BY Name ORDER BY Id ASC) AS rowNum
FROM customer_age
) AS sub
WHERE rowNum = 1
Assuming first record means highest ID, you may try your query with descending orderby ID and TOP n.
Related
How to select the value from the table based on category_id?
I have a table like this. Please help me.
Table A
ID Name category_id
-------------------
1 A 1
2 A 1
3 B 1
4 C 2
5 C 2
6 D 2
7 E 3
8 E 3
9 F 3
How to get the below mentioned output from table A?
ID Name category_id
--------------------
1 A 1
2 A 1
4 C 2
5 C 2
7 E 3
8 E 3
Give a row number for each row based on group by category_id and sort by ascending order of ID. Then select the rows having row number 1 and 2.
Query
;with cte as (
select [rn] = row_number() over(
partition by [category_id]
order by [ID]
), *
from [your_table_name]
)
select [ID], [Name], [category_id]
from cte
where [rn] < 3;
Kindly run this query It really help You Out.
SELECT tbl.id,tbl.name, tbl.category_id FROM TableA as tbl WHERE
tbl.name IN(SELECT tbl2.name FROM TableA tbl2 GROUP BY tbl2.name HAVING Count(tbl2.name)> 1)
Code select all category_id from TableA which has Name entries more then one. If there is single entry of any name group by category_id then such data will be excluded. In above example questioner want to eliminate those records that have single Name entity like wise category_id 1 has name entries A and B among which A has two entries and B has single entry so he want to eliminate B from result set.
I have 2 tables
OrderDetails:
Id Name type Quantity
------------------------------------------
2009 john a 10
2009 john a 20
2010 sam b 25
2011 sam c 50
2012 sam d 30
ValueDetails:
Id Value
-------------------
2009 300
2010 500
2011 200
2012 100
I need to get an output which displays the data as such :
Id Name type Quantity Price
-------------------------------------------------
2009 john a 10
2009 john a 20 9000
2010 sam b 25
2011 sam c 50
2012 sam d 30 25500
The price is calculated by Value x Quantity and the sum of the values is displayed in the last repeating row of the given Name.
I tired to use sum and group by but I get only two rows. I need to display all 5 rows. How can I write this query?
You can use Row_Number with max of Row_Number to get this formatted sum
;with cte as (
select od.*, sm= sum( od.Quantity*vd.value ) over (partition by Name),
RowN = row_number() over(partition by Name order by od.id)
from #yourOrderDetails od
inner join #yourValueDetails vd
on od.Id = vd.Id
)
select Id, Name, Type, Quantity,
case when max(RowN) over(partition by Name) = row_number() over(partition by Name order by Id)
then sm else null end as ActualSum
from cte
Your input tables:
create table #yourOrderDetails (Id int, Name varchar(20), type varchar(2), Quantity int)
insert into #yourOrderDetails (Id, Name, type, Quantity) values
(2009 ,'john','a', 10 )
,(2009 ,'john','a', 20 ) ,(2010 ,'sam ','b', 25 )
,(2011 ,'sam ','c', 50 ) ,(2012 ,'sam ','d', 30 )
create table #yourValueDetails(Id int, Value Int)
insert into #yourValueDetails(Id, value) values
( 2009 , 300 ) ,( 2010 , 500 )
,( 2011 , 200 ) ,( 2012 , 100 )
SELECT a.ID,
a.Name,
a.Type,
a.quantity,
price = (a.quantity * b.price)
FROM OrderDetails a LEFT JOIN
ValueDetails b on a.id = b.id
This will put the price on every row. If you want to do a SUM by Id,Name and Type it's not going to show the individual records like you show them above. If you want to put a SUM on one of the lines that share the same Id, Name and Type then you'd need a rule to figure out which one and then you could probably use a CASE statement to decide on which line you want to show the SUM total.
I am working in Excel 2013 and connecting to SQL Server with an ODBC connection
I have a table like this:
id PhoneNumber Caller
--------------------------------
1 915869850 John
2 912586985 Mary
3 963285874 John
4 915869850 Richard
5 965878965 James
6 925869753 Richard
8 963285874 James
and I need to be add a column that identifies the first time a phone number is called and ignores it on the subsequent times...
Like this:
id PhoneNumber Caller First Time
-----------------------------------------
1 915869850 John 1
2 912586985 Mary 1
3 963285874 John 1
4 915869850 Richard 0
5 965878965 James 1
6 925869753 Richard 1
8 963285874 James 0
Is it possible to do so?
Can you help me?
Use ROW_NUMBER() window function like below:
SELECT *, CASE WHEN (ROW_NUMBER() OVER
(PARTITION BY PhoneNumber ORDER BY id))=1 THEN 1 ELSE 0 END FirstTime
FROM Src
ORDER BY id
Assuming SQL Server 2005+ you can use ROW_NUMBER and then a CASE expression:
WITH CTE AS
(
SELECT *,
RN = ROW_NUMBER() OVER(PARTITION BY PhoneNumber ORDER BY id)
FROM dbo.Phones
)
SELECT id,
PhoneNumber,
[Caller],
CASE WHEN RN = 1 THEN 1 ELSE 0 END [First Time]
FROM CTE;
Another solution:
WITH FirstCallList AS
(
SELECT
MIN([id]) AS FirstIdForNumber
FROM
Calls
GROUP BY
PhoneNumber
)
SELECT
Calls.id
,Calls.PhoneNumber
,Calls.Caller
,CASE WHEN FirstCallList.FirstIdForNumber IS NULL THEN 0 ELSE 1 END AS FirstTime
FROM
Calls
LEFT OUTER JOIN FirstCallList ON Calls.id = FirstCallList.FirstIdForNumber
ORDER BY
Calls.id
;
The classic approach to this was a self join or a scalar subquery like this:
select id, PhoneNumber,
case
when id = (
select min(p2.id) from <Phones> p2
where p2.PhoneNumber = p.PhoneNumber
) then 1 else 0
end as [First Time]
from <Phones> p
I have a select * query which gives lots of row and lots of columns of results. I have an issue with duplicates of one column A when given the same value of another column B that I would like to only include one of.
Basically I have a column that tells me the "name" of object and another that tells me the "number". Sometimes I have an object "name" with more than one entry for a given object "number". I only want distinct "numbers" within a "name" but I want the query to give the entire table when this is true and not just these two columns.
Name Number ColumnC ColumnD
Bob 1 93 12
Bob 2 432 546
Bob 3 443 76
This example above is fine
Name Number ColumnC ColumnD
Bob 1 93 12
Bob 2 432 546
Bill 1 443 76
Bill 2 54 1856
This example above is fine
Name Number ColumnC ColumnD
Bob 1 93 12
Bob 2 432 546
Bob 2 209 17
This example above is not fine, I only want one of the Bob 2's.
Try it if you are using SQL 2005 or above:
With ranked_records AS
(
select *,
ROW_NUMBER() OVER(Partition By name, number Order By name) [ranked]
from MyTable
)
select * from ranked_records
where ranked = 1
If you just want the Name and number, then
SELECT DISTINCT Name, Number FROM Table1
If you want to know how many of each there are, then
SELECT Name, Number, COUNT(*) FROM Table1 GROUP BY Name, Number
By using a Common Table Expression (CTE) and the ROW_NUMBER OVER PARTION syntax as follows:
WITH
CTE AS
(
SELECT
*,
ROW_NUMBER() OVER (PARTITION BY Name, Number ORDER BY Name, Number) AS R
FROM
dbo.ATable
)
SELECT
*
FROM
CTE
WHERE
R = 1
WITH
CTE AS
(
SELECT
*,
ROW_NUMBER() OVER (PARTITION BY Plant, BatchNumber ORDER BY Plant, BatchNumber) AS R
FROM dbo.StatisticalReports WHERE dbo.StatisticalReports. \!"FermBatchStartTime\!" >= DATEADD(d,-90, getdate())
)
SELECT
*
FROM
CTE
WHERE
R = 1
ORDER BY dbo.StatisticalReports.Plant, dbo.StatisticalReports.FermBatchStartTime
that my problem:
I have database table like that:
id (AI) market_id
1 6
2 10
3 6
4 10
5 11
How to select last inserted market_id by id?
You could do something like this:
SELECT * FROM <your_table> ORDER BY id DESC LIMIT 1;
If you only are interested in the market_id you could change the * in the above query to market_id.
You can use LAST_INSERT_ID():
SELECT market_id FROM <table> where id=LAST_INSERT_ID();
For SQL Server,
Select TOP 1 ID, market_I'd from table order by ID desc