first of all I am a complete programming newbie, so I am sorry if there is something that does this really easily and I don't know of it, it is in no way my intention to be dumb.
[Also, sorry the programs are in spanish but I don't think the printf's really affect the whole logic thing.
Anyhow:
I made a program that evaluated a number and then got it as near as possible to the closest multiple of three, then I did the same for 5:
//cambia un numero al multiplo de 3 mas cercano
#include <stdio.h>
#include <stdlib.h>
int main(){
int a;
printf("Escribe el numero que deseas redondear: ");
scanf(" %d", &a);
while(a%3 != 0){
--a;
if (a%3 == 0)
break;
a++;
a++;
}
printf("El multiplo de 3 mas cercano es: %d\n", a);
}
//cambia un numero al multiplo de 5 mas cercano
#include <stdio.h>
#include <stdlib.h>
int main(){
int a;
printf("Escribe el numero que deseas redondear: ");
scanf(" %d", &a);
while(a%5 != 0){
--a;
if (a%5 == 0)
break;
--a;
if (a%5 == 0)
break;
a++;
a++;
a++;
if (a%5 == 0)
break;
a++;
if (a%5 == 0)
break;
if (a%5 == 0)
break;
a++;
}
printf("El multiplo de 5 mas cercano es: %d\n", a);
}
Now I want to write a program that does the same, but takes the number of the multiple from the user. I wrote this:
//cambia un numero al multiplo de n (input) más cercano
#include <stdio.h>
#include <stdlib.h>
int main(){
int a, n;
printf("Escribe el numero que deseas redondear: ");
scanf(" %d", &a);
printf("Escribe el numero base para redondear: ");
scanf(" %d", &n);
for(a, n; a%n != 0; a++);
printf("El multiplo de %d mas cercano (A la derecha) es: %d\n",n, a);
}
But of course this only makes it as near as possible from the right, and I don't know how (With n cases) to make it go to the closest number. The idea is this:
5 6 7 8 9 10
If we want it to go to the closest multiple of 5 and the input is 6-7 then it goes to 5, because that is the closest multiple of 5. If the input is 8-9 then it sends it to 10. The idea is always getting to the "closest" number. But I don't really see how to do it. Any help would be greatly appreciated.
If you could alternatively post the help in Java that would be more than sufficient as well. Since I know a bit java as well.
Thanks!
The classic way to do this is divide, round, multiply.
Related
I have a problem with my code:
When I write any input different from 1,2,3,4 the output is
Inserire il numero dei giocatori
inserire un numero valido
Inserire il numero dei giocatori
inserire un numero valido
Inserire il numero dei giocatori
How can I fix it?
#include <stdio.h>
#include <stdlib.h>
#include <memory.h>
#include <time.h>
int controll_num(){
int controll=0;
int players;
char c;
do{
printf("Inserire il numero dei giocatori \n");
c=getc(stdin);
switch (c){
case 49:
players=1;
controll=1;
break;
case 50:
players=2;
controll=1;
break;
case 51:
players = 3;
controll=1;
break;
case 52:
players = 4;
controll=1;
break;
default:
printf("inserire un numero valido\n");
}
}while(controll==0);
return players;
}
int main(){
controll_num();
return 0;
}
Instead of getc use scanf as for example
scanf( " %c", &c );
Pay attention to the leading space in the format string. It allows to skip white space characters as for example the new line character '\n' that is placed in the input buffer by pressing the Enter key.
As for getc then it can read white space characters.
Also instead of using magic numbers like 49 as case labels
case 49:
use characters like
case '1':
This will make your code more readable.
You need to check if the value is digit and your switch case is not needed at all.
int controll_num(void){
int players;
char c;
while(1)
{
printf("Inserire il numero dei giocatori \n");
c=getc(stdin);
if(isdigit((unsigned char)c))
{
players = c - '0';
break;
}
printf("inserire un numero valido\n");
};
return players;
}
int main(void)
{
printf("Number of players %d\n", controll_num());
}
https://godbolt.org/z/sf7nxE7cx
Basically, I have to make a currency prices conversion with a menu (Im in first year) but the second scanf that executes when you select the 0) is totally skipped; after that the program prints the menu again around 5 times and then it lets you select an option again. This is the only part that is not working, the rest is fine.
You may think that the problem is that the buffer has a newline stored from the previous scanf, but that is not the case as I am making sure to clean it. Also, don't mind the strings, they are just in spanish.
Thanks for your time!
'''
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
int main(void) {
char e = ' ';
float le = 1.1, de = 0.9, din = 1, c1, c2;
while (e != 's') {
puts("\n ================================================================");
puts(" CONVERSION DE DIVISAS");
puts(" ================================================================");
puts("0) Introducir valores de cotizacion de monedas");
puts("a) Convertir euros a dolares y libras");
puts("b) Convertir dolares a euros y libras");
puts("c) Convertir libras a euros y dolares");
puts("s) Salir");
printf("\nIntroduzca su eleccion: ");
scanf(" %c", &e);
e = tolower(e);
fflush(stdin);
switch (e) {
case '0':
printf("\nIntroduzca cuantas libras son un euro: ");
scanf(" %9.4f ", &le);
fflush(stdin);
printf("Introduzca cuantos dolares son un euro: ");
scanf(" %9.4f ", &de);
fflush(stdin);
break;
default:
printf("\nOpcion incorrecta");
break;
}
}
return 0;
}
'''
I was trying to make a program in C that basically asks the user some information about the people they live with. The code is in Spanish, but I will show you the problem.
/*Miembros de la familia*/
#include<stdio.h>
#include<stdbool.h>
#define TRUE 1
#define FALSE 0
int main(){
int personas,i,varones=0,hembras=0,opcion;
bool mayoredad=false;
printf("Indique cuantas personas viven en su casa:\n");
scanf("%i", &personas);
struct nombre{
char primer[30];
char segundo[30];
char apellido[30];
}minombre;
struct fecha{
int dia;
int mes;
int anio;
}nacimiento, actual;
printf("\nIngrese la fecha actual:\n");
scanf("%i %i %i", &actual.dia, &actual.mes, &actual.anio);
struct familia{
struct nombre minombre;
char cedula[10];
struct fecha nacimiento;
char genero;
int edad;
}familia[personas];
for(i=0;i<personas;i++){
printf("\nIndique su primer nombre, segundo nombre y apellido:\n");
scanf("%s %s %s", &familia[i].minombre.primer, &familia[i].minombre.segundo, &familia[i].minombre.apellido);
printf("\nPor favor escriba su numero de cedula:\n");
scanf("%s", &familia[i].cedula);
do{
printf("\nIngrese la fecha de su nacimiento: (DD)(MM)(AAAA):\n");
scanf("%i %i %i", &familia[i].nacimiento.dia, &familia[i].nacimiento.mes, &familia[i].nacimiento.anio);
if(familia[i].nacimiento.anio>actual.anio){
printf("Dato invalido, por favor intente nuevamente.");
}
}while(nacimiento.anio>actual.anio);
familia[i].edad=actual.anio-familia[i].nacimiento.anio;
if(familia[i].nacimiento.mes>=actual.mes && familia[i].nacimiento.dia>actual.dia){
familia[i].edad--;
}
if(familia[i].edad>=18){
mayoredad=true;
}
do{
printf("Indique su genero: (f) o (m):");
scanf(" %c", &familia[i].genero);
if(familia[i].genero=='f'){
hembras++;
}else if(familia[i].genero=='m'){
varones++;
}
}while(familia[i].genero!='f' && familia[i].genero!='m');
}
do{
printf("Registro concluido. Desea ver las estadisticas? 1(si) 2(no)");
scanf("%i", &opcion);
if(opcion!=1 && opcion!=2){
printf("DATO INVALIDO, INTENTE NUEVAMENTE");
}else if(opcion==1){
for(i=0;i<personas;i++){
printf("Nombre: %s %s %s\n", familia[i].minombre.primer, familia[i].minombre.segundo, familia[i].minombre.apellido);
printf("Cedula:%s\n", familia[i].cedula);
printf("Edad:%i\n", familia[i].edad);
printf("Mayor de edad:\n");
switch(mayoredad){
case true:printf("Si");break;
case false:printf("No");
}
}
printf("Cantidad de personas en el hogar: %i\n", personas);
printf("Varones: %i Hembras: %i\n", varones, hembras);
}
}while(opcion>=2 && opcion<0);
printf("Presione una tecla para salir.");
getchar();
return 0;
}
In the last do-while loop that requests the person's gender (familia[i].genero)
It is supposed to ask just once, but in the last iteration of the for loop, it displays the same question four times:enter image description here
How can I fix this?
The format specifier %i will treat input whose suffix is 0 (and not 0x nor 0X) as octal number.
Therefore, 09 in your input is invalid as octal number and it will leave 9 in the stream.
This 9 is read to familia[i].nacimiento.anio by the next specifier.
Then, following scanf(" %c", &familia[i].genero); will read 2003 from the input and this will lead to the 4 extra asking.
To fix this, use %d specifier to read integers. %d spcifier will treat input as decimal number regardless of the suffix.
I cant seem to loop this code. Its a simple code to display the smallest number typed, the biggest one, and how many numbers were typed by the user. Its also supose to quit if the user types in 0. Its in portuguese so look at the side of the commands for descriptions. It seems to be working properly but it only does it once and I cant figure out how to make it loop.
CODE:
#include <stdio.h>
int main()
{
int x,
y,
soma,
maior;
printf("Digite o proximo numero ou digite 0 para sair\n ");\\\Type the next number or type 0 to exit.
scanf("%d", &x);
y=x;
maior=x; \\\maior = the biggest number. soma = amount of numbers and y the smallest number.
soma=1;
if(x==0)
return(0);
else
printf("Digite o proximo numero\n");\\\type the next number.
scanf("%d", &x);
if (x>maior)\\\If X is bigger then the biggest number so far.
{
maior=x;
soma=soma+1;
printf("O maior numero eh: %d\n",maior);\\\prints current biggest number
printf("O menor numero eh: %d\n", y);\\\prints smaller number
printf("A quantidade de numeros digitados foi %d", soma);\\\How many numbers were typed in
}
else
if (x==0)
{
return(0);
}
else
if (x<y)\\If x is smaller then the smallest number so far.
{
y=x;
soma=soma+1;
printf("O maior numero eh: %d\n",maior);
printf("O menor numero eh: %d", y);
printf("A quantidade de numeros digitados foi %d", soma);
}
}
I don't see a looping statement in your code, you need to surround the part that you want to loop with while(true) or for(;;) block. Normally, when it gets to the end of the main function, the program simply terminates.
I have a little problem, my program works well until it arrives to the final step, a scanf which asks for continuation of the loop. The problem is that this scan isn't working, but the following system("cls") works. Looks like javascript when async.
Here is the code.
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
char elegir_dificultad;
int dificil = 1;
printf("Desea que se le indique si el numero es menor o mayor? \n s/n \n");
scanf("%c",&elegir_dificultad);
if(elegir_dificultad == 's'){
dificil = 0;
}
while(1){
int aleatorio, cont, introducido;
cont = 1;
aleatorio = rand()%101;
printf("%d",aleatorio);
int fallo = 1;
while(fallo){
printf("Introduce el numero, intento numero %d \n", cont);
scanf("%d",&introducido);
if(introducido == aleatorio){
fallo = 0;
}
if(cont == 10){
break;
}
if(!dificil){
if(introducido < aleatorio){
printf("El numero introducido es menor que el aleatorio \n");
}
if(introducido > aleatorio){
printf("El numero introducido es mayor que el aleatorio \n");
}
}
if(fallo){
cont++;
}
}
char continuar;
if(fallo){
printf("Has perdido... el numero era %d \n Quieres repetirlo? s/n \n",aleatorio);
scanf("%c",&continuar);
if(continuar=='n'){
break;
}
system("cls");
}else{
printf("°Has ganado! el numero era %d \n Quieres repetirlo? s/n \n",aleatorio);
scanf("%c",&continuar);
if(continuar=='n'){
break;
}
system("cls");
}
}
system("PAUSE");
return 0;
}
This problem is because of \n character left behind by the previous scanf. Place a space before each %c specifier in scanf to eat up \n. .
scanf(" %c", &introducido);
...
scanf(" %c",&continuar);