SQL SERVER 2008 R2 string split - sql-server

Question

I want to split a column of strings say "99 crystal springs road" and get only 2 words (99 and crystal) respectively and update 99 to one column and crystal to another column of another table. How can I do it using charindex and substring?

Answer 1

Here is some sample code on how to do it ...
First, create this function:
CREATE FUNCTION [dbo].[GetStringPart]
(#fullString varchar(200), #pos tinyint)
RETURNS VARCHAR(200) -- return_data_type.
AS
BEGIN
IF #pos IS NULL OR #pos <= 0
SET #pos = 1
declare #secondPart varchar(200),#firstPart varchar(200),#output varchar(200)
declare #firstSpace int, #secondSpace int
set #firstSpace = CHARINDEX(' ', #fullString)
IF #firstSpace <= 0
RETURN ''
ELSE IF #pos = 1
BEGIN
SET #output = LTRIM(RTRIM(SUBSTRING(#fullString, 1, #firstSpace)))
END
ELSE
BEGIN
SET #secondSpace = CHARINDEX(' ', #fullString, CHARINDEX(' ', #fullString)+1) - CHARINDEX(' ', #fullString)+1
IF #secondSpace <= 0
SET #secondSpace = LEN(#fullString) - #firstSpace + 1
SET #output = LTRIM(RTRIM(SUBSTRING(#fullString, #firstSpace, #secondSpace)))
END
RETURN #Output
END
GO
Then you can use it like this:
declare #origTable table(name varchar(100))
insert into #origTable (name) values ('99 crystal springs road')
declare #newTable table(col1 varchar(100), col2 varchar(100))
INSERT INTO #newTable (col1, col2)
SELECT dbo.GetStringPart(name, 1), dbo.GetStringPart(name, 2) FROM #origTable
select * from #newTable

Answer 2

Assuming that you are selecting "99" and "crystal" just because they're the first two words...
You can do this in a single step but for ease of reading the solution I've separated it out
declare #sourceAddresses table
(
address varchar(100)
)
declare #split table
(
address varchar(100),
firstDelimiter int,
secondDelimiter int
)
declare #table table
(
part1 varchar(20),
part2 varchar(20)
)
insert into #sourceAddresses (address) values ('99 crystal springs road')
insert into #sourceAddresses (address) values ('100 elsewhere road')
insert into #split (address, firstDelimiter)
select address, charindex(' ', address)
from #sourceAddresses
update #split
set secondDelimiter = charindex(' ', address, (firstDelimiter+1))
where firstDelimiter > -1
insert into #table (part1, part2)
select substring(address, 0, firstDelimiter), substring(address, (firstDelimiter+1), (secondDelimiter-firstDelimiter))
from #split
where firstDelimiter > -1
and secondDelimiter > -1
select * from #table

Answer 3

Maybe something like this:
First create a function that gets part of the strings:
CREATE FUNCTION dbo.GetStringPart (#sep char(1), #s varchar(512),#pos int)
RETURNS VARCHAR(200)
AS
BEGIN
DECLARE #output VARCHAR(200)
;WITH Pieces(pn, start, stop) AS (
SELECT 1, 1, CHARINDEX(#sep, #s)
UNION ALL
SELECT pn + 1, stop + 1, CHARINDEX(#sep, #s, stop + 1)
FROM Pieces
WHERE stop > 0
)
SELECT
#output=SUBSTRING(#s, start, CASE WHEN stop > 0 THEN stop-start ELSE 512 END)
FROM Pieces
WHERE pn=#pos
RETURN #Output
END
GO
Then you can easy do this:
DECLARE #origalTable TABLE(name VARCHAR(100))
INSERT INTO #origalTable
VALUES('99 crystal springs road')
DECLARE #newTable TABLE(col1 VARCHAR(100), col2 VARCHAR(100))
INSERT INTO #newTable (col1, col2)
SELECT dbo.GetStringPart(' ',name, 1), dbo.GetStringPart(' ',name, 2) FROM #origalTable
SELECT * FROM #newTable
DROP FUNCTION dbo.GetStringPart