character strings into arrays - c

This is/isn't homework...the printing of the list IS homework and that works great, the iscntrl() and Array stuff is 6 weeks from now stuff and giving me grief.
I want to create an array filled with the first 32 TLAs of the Ascii table so that when I print out a column / row chart of Decimal to Ascii code I can use iscntrl() to flag that it's an un-printable character. In its place I want to grab the next TLA in the array and print that instead of the non-graphical character.
I have the iscntrl() working fine. Just can't figure out the array thing. All the examples in the books I have and online want to demo grabbing input from the user and tossing it into the array. I want to give the array a list at the beginning in the code and pull from that.
Can someone either give me a good link for what I need or just tell me how to do the whole process?
I've got 32 three letter items and I need to populate the array and pull them out via a for loop.
Thanks.

You can declare an array like this, and pre-fill its values:
const char *ControlCharacterNames[] = {
"NUL",
"SOH",
"STX",
"ETX",
// etc
};
Then, you can access ControlCharacterNames as an array in your code.

http://publications.gbdirect.co.uk/c_book/chapter6/initialization.html, chapter "6.7.2. More initialization".
Long story short, you probably need something like
char *TLAs[] = { "TL1", "TL2", "TL3", "FYI", "WTH", /* ...and so on...*/ };
and then pull the one you need using it's index
printf(TLAs[3]); // print "FYI", the 4th TLA
Hope I understood your question right.

Related

What does &array[element] means and why?

I was coding in MPI using C. I don't understand how the MPI_Send() works or if maybe &array[element] works.
MPI_Send(&array[element],element_left,MPI_INT,i,0,MPI_COMM_WORLD);
here array[]={1,2,3,4,5,6,7,8,9,10} and element = 6 and element_left = 4. I understand array[element]=array[6]=7 but why this function picks 7,8,9,10? I know it will pick 4 elements from the array but why do we need & here and by only giving starting entry array[6] how is this function able to pick the next 3 as well?
I thought I have to add one after another using a for loop or something, but when I searched something on Google I got this code and after going through so much I still didn't understand. Please help me understand the backwardness of this code.
&array[element] is the same expression as array + element and means the address of the elementth element of the array array.
The function you call wants this address as the first argument, and takes the number of elements to process as the second argument.
Most MPI routines take a trio of arguments:
address of buffer
count of elements
datatype of elements
So by &array[element],element_left,MPI_INT you specify the elements element as the start of the buffer, and then you take element_left many integers to send. Kinda strange that you name the count element_left which is more like a name for an index, but that's what happens.

Is there a way to sort a no. of character arrays in alphabetical order without using the #include<string.h> or #include<stdlib.h>?

So, I have tried to do the same in a case of array of structures where 'char name[100]' is the only data member.
1st part of the code
2nd part of the code
The problem that I have encountered here is that once I provide a no. of names during program runtime, the output screen either does not print anything afterwards, or, prints the data without sorting it.
output screen
I did not get any compile time errors so I believe that there is a flaw in the logic.
There's this another method I tried hoping to get positive results. I type-casted characters to integers hoping that ASCII values could be used to compare. But, the results are exactly the same (undesired results).
updated logic of the 2nd part of the code
I hope somebody helps me find a way to correct this logic or provide another logic that is efficient.
the sorting logic you used is good , but from what is see the use of function's in C need's to be provided by pointers. other wise all the data inside the function will born and die inside the function , and the all the variables in the Main will stay the same as given, that explains why the output is the same as the input
try to print inside the sorting function's to see if this is the problem.

How do I replace an array element in LabView? (2d array of pictures)

so I have a final project for a class where I need to make a video game in LabView. The issue I'm having at the moment is that I can't figure out the 'right' way to put 'yourShip.png' into the 2d array of 2d pictures at [0,0]. Every tutorial I can find basically has exactly what I have down below in the screenshot, and it makes sense to me. However, running the program quickly shows that it does nothing.
To describe the code, I have a path constant that leads to the picture, which feeds to a draw flattened pixelmap function. Up to this point I know the code works, since creating a test indicator reveals as such. However, next I try to use the replace array subset function to replace the (default blank) 2d picture at [0,0] with yourShip.png. 'screen' is a 5x5 2d array of 2d pictures. The local variable of the same name being outputted to is indeed the very same array.
My main guess with why my code doesn't work is because of the way I'm taking screen as the input variable and then outputting to it via a local variable. However, if this is wrong, I'm confused with how I should do it. All I want to do is 'spawn' the image at the correct index.
The replace array subset works quite literally, i.e. it can only replace existing elements.
If there is no element at the specified index because the array is smaller, the function will do just nothing.
I guess your array is empty, so, initialize your screen array first to a size of at least 1x1.

Array (class) filled with non nil values stays empty

I am currently having trouble filling up an array of customClass.
I try to fill it with a jsonFile. During my json parsing (using swiftyJSON) i loop and fill my array.
The problem is, at the end of my loop, it is still empty. I tested it in different ways, and here is my code:
That's the file where the problem is. In my loop I fill an Annotation, that I add with append to my array. The problem is what my print return. Here is a part of it:
It's just a small part of a huge jsonfile. And, my tmpAnnot.name is correctly printed every iteration. But when it comes to my Array, nothing.
So I'm completly lost and hope you could help me ^^
(And for the information, here is my custom class) :
And btw, I tried to print my array.count, and it's nil too
Im so sorry if the question has been posted. I couldn't find it in the entire website.
Change your JSONAnnotationList declaration to be an non-optional and assign it an empty array
var JSONAnnotationList: [UGOAnnotation] = []
You see, you have never created an array so there was nothing to be printed.
The whole point of optionals is to use them sparingly, not everywhere.

Perl: Reading from file and saving into an array

I had got a script in Perl and my task is to do some changes in it. This of course means to understand which part does exactly what. I am not familiar with Perl language but I tried to read through some tutorials, but still some things are confusing me. And I got stuck in following part:
while (<KOEFICIENTYfile>) {
#_=(split(/\s+/, $_));
push(#ZAID,shift(#_));
$KOEFICIENTY{$ZAID[-1]}=[#_];
}
As I understands this part then it:
Reads line from filehandle KOEFICIENTYfile
Separates them by spaces (one or more)
Loads first item from this separated array into array ZAID (and in the process, removes it from #_)
??? Adds a rest of a separated array into array KOEFICIENTY? I am confused by curly brackets part and by square brackets after equals sign.
I think that I understood the meaning of #, $, #_ or negative indexing but this is beyond me. Can you please advice me on meaning of this?
[-1] indexing is just a shortcut way to say "last element of the array".
KOEFICIENTY is actually a hash (you can tell this because it is using curly braces, instead of square ones, around the index), so you're putting the rest of the array #_ into a hash called KOEFICIENTY with a key of the last element of the array.
If you include:
use Data::Dumper
at the top of the script and do
print Dumper(%KOEFICIENTY)
it will nicely format the output for you, which may help
The original coder was trying to be too clever using the negative offset. It would have been much more obvious if the code had been written with a simple temporary variable thus:
while (<KOEFICIENTYfile>) {
#_ = (split(/\s+/, $_));
my $key = shift(#_);
push(#ZAID, $key);
$KOEFICIENTY{$key} = [#_];
}
The braces on $KOEFICIENTY show that this is a "hash" of key/value pairs named %KOEFICIENTY, and not a normal array.
If you don't actually need to preserve the sort order of the keys you could just use keys %KOEFICIENTY to retrieve them instead of storing them in #ZAID.
#zaid is a list, into which the first part of the split is added.
%KOEFICIENTY is a hash, in which a reference to the rest of the split is stored as a list reference under the key of the first part.
So if the line is a b c, #zaid will get a and %KOEFICIENTY{'a'} will hold a reference to a list containing b and c.

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