Add row in multiple-column listview? - wpf

Question

I am having trouble adding a row that displays all the values of the member of an object.
Here is how I have set up my listview:
<ListView Height="178" HorizontalAlignment="Left" Margin="238,31,0,0" Name="SpoolSheetListView" VerticalAlignment="Top" Width="555" HorizontalContentAlignment="Stretch" SelectionMode="Single">
<ListView.View>
<GridView>
<GridViewColumn Width="85" Header="Column 1" />
<GridViewColumn Width="120" Header="Column 2" />
<GridViewColumn Width="120" Header="Column 3" />
<GridViewColumn Width="120" Header="Column 4" />
<GridViewColumn Width="115" Header="Column 5" />
</GridView>
</ListView.View>
</ListView>
say, myObject has 5 members: member1 to member5, which are all of type string. How do I add a single row in the ListView for that object?
Thanks again people!

Answer 1

WPF list controls work best when you use them with data binding; you should bind the ItemsSource of the ListView to a list of objects, and bind each column to a property of these objects.
<ListView ItemsSource="{Binding Items}" Height="178" HorizontalAlignment="Left" Margin="238,31,0,0" Name="SpoolSheetListView" VerticalAlignment="Top" Width="555" HorizontalContentAlignment="Stretch" SelectionMode="Single">
<ListView.View>
<GridView>
<GridViewColumn Width="85" Header="Column 1" DisplayMemberBinding="{Binding Member1}" />
<GridViewColumn Width="120" Header="Column 2" DisplayMemberBinding="{Binding Member2}" />
<GridViewColumn Width="120" Header="Column 3" DisplayMemberBinding="{Binding Member3}" />
<GridViewColumn Width="120" Header="Column 4" DisplayMemberBinding="{Binding Member4}" />
<GridViewColumn Width="115" Header="Column 5" DisplayMemberBinding="{Binding Member5}" />
</GridView>
</ListView.View>
</ListView>
(Items being a property of the DataContext that returns a collection of objects)
To add a row to the ListView, you just need to add an item to the Items collection (note that the collection should implement INotifyCollectionChanged so that the ListView is notified; the ObservableCollection<T> class works fine for most cases)