I want to create two DATETIME variables I can use to check with BETWEEN AND when given just one DATETIME in a stored procedure on SQL Server 2008.
So, when I get 2012/12/31 15:32:12 as input, I want to generate two new variables out of that, being #from = 2012/12/31 00:00:00 and #to = 2012/12/31 23:59:59.
These two variables are used to check if the records lie between them - that is, are on the same day as the input date.
I fooled around using CAST and CONVERT, but I don't really konw how to manipulate the dates in the way I want.
Should I do this another way? Or are there functions I'm not aware of?
Now it is version independedt
declare #from datetime, #to datetime
SET #from = convert(varchar, convert(datetime, '2012/12/31 15:32:12', 111), 112)
SET #to = DATEADD(day, 1, #from)
select * from yourtable where test date >= #from AND date < #to
You can;
declare #input datetime = '2012/12/31 15:32:12'
declare #from datetime = dateadd(day, 0, datediff(day, 0, #input))
declare #to datetime = dateadd(second, -1, dateadd(day, 1, #from))
>>>
2012-12-31 00:00:00.000 2012-12-31 23:59:59.000
Be careful of accuracy on your #to. 23:59:59.001 is a valid date but won't show up in your range if you subtract an entire second.
It is more common to set your #from and then use < #from + 1 instead of BETWEEN. (The plus adds whole days in SQL).
First convert your input date to a varchar using the appropriate date format(111 in this case), For the to date, append the midnight hour
Then cast your varchar back to datetime.
Example :
SELECT #from = CAST(CONVERT(VARCHAR(10), GETDATE(), 111) AS DATETIME)
,#to = CAST(CONVERT(VARCHAR(10), GETDATE(), 111)+' 23:59:59:997' AS DATETIME)
Here is a useful chart of datetime formats with brief explanations.
http://www.sql-server-helper.com/tips/date-formats.aspx
Related
I have a query that takes two datetime variables (Start date and end date) and appends two differing fixed times to allow for a business trading time offset.
An example of a test query using this logic is:
DECLARE #startdate datetime;
DECLARE #enddate datetime;
SET #startdate = convert(datetime,'2017-01-01')
SET #enddate = convert(datetime,'2017-01-02')
SELECT *
FROM ig_Business..Check_Item_Detail CID (NOLOCK)
JOIN ig_business..Check_Sales_Detail CSD (NOLOCK) ON CSD.transaction_data_id = CID.transaction_data_id
WHERE csd.tendered_date_time BETWEEN DATEADD(m, DATEDIFF(m, 0, convert(date, #STARTDATE)), 0) + '06:00:00'
AND DATEADD(m, DATEDIFF(m, 0, convert(date, #ENDDATE)), 0) + '05:59:59'
However, the result set for this query is empty, and I am unsure why, because when I run
select DATEADD(m, DATEDIFF(m, 0, convert(date, #STARTDATE)), 0) + '06:00:00'
i get back a seemingly valid datetime : 2017-01-01 06:00:00.000
An example of what is returned when I remove the time restriction:
i get back a seemingly valid datetime : 2017-01-01 06:00:00.000
You're not.
You're getting back a date that has been automatically cast to a string, and have glued another string on the end, giving you a string that looks like a datetime.
If you want to add something to the date, use another dateadd(). This will give you a BETWEEN comparison with actual datetimes.
Right now you are doing a "between" with a datetime and a string.
I'm surprised it doesn't throw an error.
If 2012+, you can use format() to append a time to a date/datetime value
Example
Declare #startdate date = '2017-01-01'
Select format(#startdate,'yyyy-MM-dd 06:00:00')
Returns
2017-01-01 06:00:00
This format() can be included in your where
...
Where SomeDateTime between format(#startdate,'yyyy-MM-dd 06:00:00')
and format(#enddate,'yyyy-MM-dd 17:00:00')
This question may be duplicate sorry for it,As I could not able to find any solution in web till now so am Posting this
I need to create a SQL server functions where I need to replace only the date part from the actual date ..
For example if the actual date is 01/10/2016 means I need to update the actual date to 15/10/2016 the date part alone is replaced from 01 to 15 I need to achieve this, please help me in solving this as am very new to SQL SERVER
DECLARE #actual_due_date INT = 5;
DECLARE #invoice_date DATETIME = '20161210';
DECLARE #due_date DATETIME;
SET #due_date=DATEADD(DAY,#actual_due_date-DATEPART(DAY,#invoice_date),#invoice_date);
SELECT #due_date;
This prints out
2016-12-05 00:00:00.000
Here's another way to do it:
DECLARE #oldDate DATETIME = '2016-10-17 10:29:22'
DECLARE #replacingDate DATE = '2016-10-15'
DECLARE #newDate DATETIME
SET #newDate = CONVERT(datetime, CONVERT(varchar, #replacingDate)+' '+ LEFT(CONVERT(varchar, CONVERT(time, #oldDate)), 8))
SELECT #newDate
--UPDATE TableA
--SET FieldX = CONVERT(datetime, CONVERT(varchar, #replacingDate)+' '+ LEFT(CONVERT(varchar, CONVERT(time, #oldDate)), 8))
--WHERE SomeCondition
Don't know, what you really try to achieve, but you could try this:
DECLARE #OtherDate DATETIME = {ts'2016-02-05 12:00:00'}; --Some day in February, 12 o'clock
DECLARE #actualDate DATETIME = GETDATE(); --current day and time
--This comes back with the other date, but the actual time
SELECT CAST(CAST(#OtherDate AS date) AS datetime) + CAST(CAST(#actualDate AS time) AS datetime);
Not sure of the purpose, why you are replacing it.
Here is one way:
Declare #date date = '01/10/2016'
Select Replace(Convert(varchar(20), #date, 101), '01/', '15/') AS ReplacedDate
-- 15/10/2016
I want to get date from yyyy-mm-dd to yyyy-mm-dd in SQL.
Example: I have two parameter #startdate : 2015-12-28 and #enddate : 2016-01-02, and database in SQLServer, datatype is varchar(10)
DATE_ORDER
28-12-2015
30-12-1996
29-12-2016
30-12-1997
24-12-2015
27-12-1993
03-01-2016
01-01-1992
02-01-2016
etc...
Ok,now I want to get data from #startdate : 2015-12-28 and #enddate : 2016-01-02. I use SELECT * FROM TABLE_X WHERE DATE_ORDER >= #startdate AND DATE_ORDER <= #enddate . But the results are not what I expected. Here are the results I want
28-12-2015
30-12-1996
29-12-2016
30-12-1997
01-01-1992
02-01-2016
I think to solve this problem, I need to do two things :
First, get date range from #startdate to #enddate , in here 28/12/2015, 29/12/2015, 30/12/2015, 31/12/2015, 01/01/2016, 02/01/2016.
The second: get the date in database same in range 28/12, 29/12, 30/12, 31/12, 01/01, 02/01, ignoring the year.
Can you give me some ideas about this ?
Your actual format is "105-italian" find details here.
You can convert your existing VARCHAR(10)-values with this line to real datetime
SELECT CONVERT(DATETIME,YourColumn,105)
Next thing to know is, that you should not use BETWEEN but rather >=StartDate AND < NakedDateOfTheFollowingDay to check date ranges
So to solve your need Get date-range from 2015-12-28 to 2016-01-02 you might do something like this:
DECLARE #Start DATETIME={d'2015-12-28'};
DECLARE #End DATETIME={d'2016-01-02'};
SELECT *
FROM YourTable
WHERE CONVERT(DATETIME,YourDateColumn,105)>=#Start AND CONVERT(DATETIME,YourDateColumn,105)<#End+1
Attention Be aware, that the conversion lets your expression be not sargable. No index will be used.
Better was to store your date as correctly typed data to avoid conversions...
Try this query
SET DATEFIRST 1
DECLARE #wk int SET #wk = 2
DECLARE #yr int SET #yr = 2011
--define start and end limits
DECLARE #todate datetime, #fromdate datetime
SELECT #fromdate = dateadd (week, #wk, dateadd (YEAR, #yr-1900, 0)) - 4 -
datepart(dw, dateadd (week, #wk, dateadd (YEAR, #yr-1900, 0)) - 4) + 1
SELECT #todate = #fromdate + 6
;WITH DateSequence( Date ) AS
(
SELECT #fromdate AS Date
UNION ALL
SELECT dateadd(DAY, 1, Date)
FROM DateSequence
WHERE Date < #todate
)
--select result
SELECT * FROM DateSequence OPTION (MaxRecursion 1000)
So, after the 2nd or 3rd edit, it slowly becomes clear, what you want (i hope).
So you REALLY WANT to get the dates with the year beeing ignored.
As someone pointed out already, date-values are stored internally not as string, but as internal datatype date (whatever that is in memory, i don't know).
If you want to compare DATES, you cannot do that with ignorance of any part. If you want to, you have to build a NEW date value of day and month of given row and a hard coded year (2000 or 1 or whatever) for EVERY row.
SELECT * FROM TABLE_X WHERE convert(date,'2000' + substring(convert(char(8),convert(datetime, 'DATE_ORDER', 105),112),5,4),112) >= #startdate AND convert(date,'2000' + substring(convert(char(8),convert(datetime, 'DATE_ORDER', 105),112),5,4),112) <= #enddate
If your startdate and enddate go OVER sylvester, you have to do 2 queries, on from startdate to 1231, one from 0101 to enddate.
I am using the following way to compare two dates:
if CONVERT(varchar(20), #ScheduleDate, 101) >= CONVERT(varchar(20), #CurrentDateTime, 101)
This is working fine for the current year, but when the comes in yearly like one date is 12/31/2012 and 1/1/2013 then its not working.
Please help me how can I resolve this.
why do you comparing strings?
you can compare dates
if #ScheduleDate >= #CurrentDateTime
but if your date contains time, I usually do
if convert(nvarchar(8), #ScheduleDate, 112) >= convert(nvarchar(8), #CurrentDateTime, 112)
112 datetime format is YYYYMMDD so it's good for compare dates
You have to remember that string comparison is from left to right, so "1/...." is smaller than "12/...".
You need to use DATETIME comparisons, not string comparison.
Something like
DECLARE #ScheduleDate DATETIME = '1/1/2013',
#CurrentDateTime DATETIME = '12/31/2012'
IF (#ScheduleDate >= #CurrentDateTime)
BEGIN
SELECT #ScheduleDate, #CurrentDateTime
END
DECLARE #ScheduleDateString VARCHAR(20) = '1/1/2013',
#CurrentDateTimeString VARCHAR(20) = '12/31/2012'
IF (CONVERT(DATETIME,#ScheduleDateString,101)>=CONVERT(DATETIME,#CurrentDateTimeString,101))
BEGIN
SELECT CONVERT(DATETIME,#ScheduleDateString,101),CONVERT(DATETIME,#CurrentDateTimeString,101)
END
SQL Fiddle DEMO
Note that if the variables are already datetimes, you do not need to convert them.
Assuming that both variables are currently DateTime variables, can't you just compare them without converting to strings?
declare #ScheduleDate DATETIME, #CurrentDateTime DATETIME
SET #ScheduleDate = '1 Jan 2013'
SET #CurrentDateTime = GetDate()
IF (#ScheduleDate >= #CurrentDateTime)
BEGIN
SELECT 'Do Something'
END
ELSE
BEGIN
SELECT 'Do Something Else'
END
when you use CONVERT(nvarchar(8), #ScheduleDate, 112) function it's return string instead of date.
so,
Use "112" DateFormat in Sql Server it's return string in "YMD" format without any sepration.
compare that string in your query and get desire output.
Such as "if CONVERT(nvarchar(8), #ScheduleDate, 112) >= CONVERT(nvarchar(8), #CurrentDateTime, 112)"
I would not use CONVERT to compare formatted strings. It is slow (well, more like microseconds, but still)
I use a UDF for SQL prior to version 2008
CREATE FUNCTION [dbo].[DateOnly] (#Date DateTime)
RETURNS Datetime AS
BEGIN
Return cast (floor (cast (#Date as float)) as DateTime)
END
and for versions >=2008 this approach
select convert(#MyDateTime as DATE)
Of course, you can compare datetime values directly, but to know whether two datetime values are on the same date (ignoring the time component), the above versions have proven to be effectivy.
Date : From and To with following format
from_Date# = #dateformat("#form.from#", "mm/dd/yyyy")
to_Date# = #dateformat("#now()#" + 1, "mm/dd/yyyy")
In SQL Statement
WHERE a.DateCreated >= CAST ('#from_date#' AS DATE) and a.DateCreated <= CAST('#to_date#' AS DATE)
This is working fine without any cast of original date time column
What would be the sql for the following,
I have a date of birth in an int field,
ie YYYYMMDD = 19600518
I would like to get the age.
None of the other answers are actually calculating age. They're calculating the number of year boundaries and not taking the birthday into account.
To calculate the age, you'll need to do something like this:
DECLARE #d DATETIME
SET #d = CONVERT(DATETIME, CONVERT(VARCHAR(8), 19600518), 112)
SELECT DATEDIFF(year, #d, GETDATE())
- CASE WHEN DATEADD(year, DATEDIFF(year, #d, GETDATE()), #d) <= GETDATE()
THEN 0 ELSE 1 END AS Age
Most of the other answers are not calculating age - just whole years (e.g. Jan 1 2009 is one "year" after Dec 31 2008). Thus, if you use most of the calculations on this page, you will return an incorrect age for half of the year, on average. Luke is the only person who has seen this but his answer strikes me as too complicated - there is an easier way:
Select CAST(DATEDIFF(hh, [birthdate], GETDATE()) / 8766 AS int) AS Age
(NOTE: Thanks go to 'Learning' for making a great catch on my original algorithm - this is a revision that uses hours instead of days)
Because the rounding here is very granular, this is almost perfectly accurate for every day of every year. The exceptions are so convoluted that they are almost humorous: every fourth year the age returned will be one year too young if we A) ask for the age before 6:00 AM, B) on the person's birthday and C) their birthday is after February 28th. Of course, depending on what time someone was born this might 'technically' be correct! In my setting, this is a perfectly acceptable compromise.
Here is a loop that prints out ages to show that this works.
Declare #age int;
Declare #BirthDate datetime;
Declare #Year int;
Set #Year = 2008;
WHILE (#Year > 1930)
BEGIN
-- Put today's date where you see '-03-18'
SET #BirthDate = CAST(Cast(#Year as varchar(4)) + '-03-18' AS DATETIME)
SELECT #age=CAST(DATEDIFF(hh, #BirthDate, GETDATE()) / 8766 AS int);
Print Cast(#Year as varchar) + ' Age: ' + Cast(#age as varchar);
Set #Year = #Year - 1;
END;
Finally, this is the version that will also convert Paul's integer date to a real date:
CAST(DATEDIFF(hh, Convert(Datetime, Convert(varchar(8), [birthdate]), 112), GETDATE()) / 8766 AS int) AS Age
DECLARE #dateSt VARCHAR(8)
DECLARE #startDt DATETIME
-- Set the start date string
SET #dateSt = '19600518'
-- Make it a DATETIME (the ISO way)
SET #startDt = CAST(SUBSTRING(#dateSt, 1, 4) + '-' +
SUBSTRING(#dateSt, 5, 2) + '-' +
SUBSTRING(#dateSt, 7, 2) AS DATETIME)
-- Age in Days
SELECT DATEDIFF(D, #startDt, getdate())
Age in years :
select datediff(YY, convert(datetime, convert(varchar, 19600518)), getdate())
[EDIT]
-- I forgot to declare the variables
declare #birthday datetime;
set #birthday = convert(datetime,convert(varchar, 19600518), 112);
declare #datetoday datetime;
set #datetoday = getdate();
select
(
CASE
WHEN dateadd(year, datediff (year, #birthday, #datetoday), #birthday) <= #datetoday
THEN datediff (year, #birthday, #datetoday)
ELSE datediff (year, #birthday, #datetoday) - 1
END) as age;
Here's a one-liner way to do it:
CONVERT(DATETIME, CONVERT(VARCHAR(8),19600518), 112)
But beware! This relies on T-SQL, and probably won't work in other SQL environments.
Please note that the "style" of 112 is simply the "ISO" date format of yyyymmdd. (Something I found in some CONVERT documentation.)
This is a reason why you should NOT ever store dates as anything except a datetime datatype. The best fix is to change your datatype and convert all the dates once (wouldn't be surprised if there are few invalid ones in there either). then you never have to do these workarounds again.
I worked it out and got same as #Learning
select dob, datediff(year, convert(datetime, convert(varchar(8),[dob])) ,getdate()) as age
from [mytable]
where IsDate(convert(varchar(8),[dob])) = 1
NB. I needed the IsDate as well as there were some invalid dates in the data.
Edit. Here is an article from SQLServerCentral on calculating age.