Can't assign wide char into wide char field. - c

Question

I have been given this school project. I have to alphabetically sort list of items by Czech rules. Before I dig deeper, I have decided to test it on a 16 by 16 matrix so I did this:
typedef struct {
wint_t **field;
}LIST;
...
setlocale(LC_CTYPE,NULL);
....
list->field=(wint_t **)malloc(16*sizeof(wint_t *));
for(int i=0;i<16;i++)
list->field[i]=(wint_t *)malloc(16*sizeof(wint_t));
In another function I am trying to assign a char. Like this:
sorted->field[15][15] = L'C';
wprintf(L"%c\n",sorted->field[15][15]);
Everything is fine. Char is printed. But when I try to change it to
sorted->field[15][15] = L'Č';
It says: Extraneous characters in wide character constant ignored. (Xcode) And the printing part is skipped. The main.c file is in UTF-8. If I try to print this:
printf("ěščřžýááíé\n");
It prints it out as written. I am not sure if I should allocate mem using wint_t or wchar_t or if I am doing it right. I tested it with both but none of them works.

Answer 1

clang seems to support entering arbitrary byte sequences into to wide strings with the \x notation:
wchar_t c = L'\x2126';
This compiles without notice.
Edit: Adapting what I find on wikipedia about wide characters, the following works for me:
#include <stdio.h>
#include <wchar.h>
#include <stdlib.h>
#include <locale.h>
int main(void)
{
setlocale(LC_ALL,"");
wchar_t myChar1 = L'\x2126';
wchar_t myChar2 = 0x2126; // hexadecimal encoding of char Ω using UTF-16
wprintf(L"This is char: %lc \n",myChar1);
wprintf(L"This is char: %lc \n",myChar2);
}
and prints nice Ω characters in my terminal. Make sure that your teminal is able to interpret utf-8 characters.