select between years case when statement - sql-server

Question

I wrote a query
WITH sample AS (
SELECT CAST('2010-01-01' AS DATETIME) AS d
UNION ALL
SELECT DATEADD(dd, 1, i.vrp_notificationdate) as deneme
FROM Incident i
WHERE DATEADD(dd, 1, i.vrp_notificationdate) <= CAST('2011-11-01' AS DATETIME))
SELECT count(DATENAME(mm,l.vrp_notificationdate) +' '+DATENAME(yy,l.vrp_notificationdate)) as Toplam,DATENAME(mm,l.vrp_notificationdate) +' '+DATENAME(yy,l.vrp_notificationdate)
FROM Incident as l
group by
DATENAME(mm,l.vrp_notificationdate) +' '+DATENAME(yy,l.vrp_notificationdate)
the query show
10 November 2011
101 October 2011
4 September 2011
but i want to show this .
0 january 2010
0 february 2010
-
-
-
10 November 2011
101 October 2011
4 september 2011
0 december 2011
0 february 2011
i tried case when statement,but query show same result
How to solve what i use
Best regards.

Answer 1

You are trying to show data that doesn't exist. The idea of this solution is to
Add dummy dates
Assign a count of 0 to each dummy date
Union your original results with this dummy dates
Group into a final result
SQL Statement
DECLARE #StartDate DATE = '01-01-2010'
;WITH Dates(d) AS (
SELECT #StartDate
UNION ALL
SELECT DATEADD(mm, 1, d) AS Date
FROM Dates
WHERE d < '12-01-2012'
)
,WITH sample AS (
SELECT CAST('2010-01-01' AS DATETIME) AS d
UNION ALL
SELECT DATEADD(dd, 1, i.vrp_notificationdate) as deneme
FROM Incident i
WHERE DATEADD(dd, 1, i.vrp_notificationdate) <= CAST('2011-11-01' AS DATETIME)
)
SELECT SUM(Toplam) AS Toplam
, DateFormat
FROM (
SELECT COUNT(DATENAME(mm,l.vrp_notificationdate) + ' ' + DATENAME(yy,l.vrp_notificationdate)) AS Toplam
, DATENAME(mm,l.vrp_notificationdate) + ' ' + DATENAME(yy,l.vrp_notificationdate) AS DateFormat
, CONVERT(VARCHAR(6), l.vrp_notificationdate, 112) as orderDate
FROM Incident as l
GROUP BY
DATENAME(mm,l.vrp_notificationdate) + ' ' + DATENAME(yy,l.vrp_notificationdate)
, CONVERT(VARCHAR(6), l.vrp_notificationdate, 112)
UNION ALL
SELECT 0 AS Toplam
, DATENAME(mm, d) + ' ' + DATENAME(yy, d)
, CONVERT(VARCHAR(6), d.d, 112) as orderDate
FROM Dates d
) g
GROUP BY
DateFormat
ORDER BY
g.orderDate

Answer 2

Well, if the date doesn't appear, it means that there isn't any value present for that date. So, it's impossible to get that date to appear in the result.
To pass this the simplest solution is to:
Create a table with all the possible dates and another column that will start with zero.
Update that table with the results of the query that you made (update the column that start with zero to have the count values).
Display the end results from the new table:
select countValues + ' ' + dateValues from newTable
If you have any doubt, just ask :)

Answer 3

Why do you provide "WITH sample AS" when you do not use sample?
I'ld use this recursive query to build all dates for your result table.
WITH sample (d) AS (
SELECT CAST('2010-01-01' AS DATETIME)
UNION ALL
SELECT DATEADD(mm, 1, d) FROM sample WHERE DATEADD(mm, 1, d) <= CAST('2011-11-01' AS DATETIME)
)
select * from sample
You could then outer join this table with your Incident table to get the count of incidents for each month.
If you want to see a lot of months or even days, you might get an MSG 530 because of too much recursion. In this case you need the add OPTION (MAXRECURSION ) after "select * from sample".