Related
This question already has answers here:
Capture characters from standard input without waiting for enter to be pressed
(21 answers)
Closed last year.
I'm trying to write a "more"(just like "more" instruction in Linux) program in C.
Quit when "q" is pressed and show one more page when " " is pressed.
But everytime I have to press Enter after the command.
I tried to use setbuf() and setvbuf() but it doesn't work.Why?How should I do?
FILE *fp_tty; //read from keyboard
fp_tty = fopen("/dev/tty", "r");
setbuf(fp_tty, NULL);
see_more(fp_tty);
......
int see_more(FILE *cmd) {
int c;
printf("\033[7m more? \033[m");
while ((c = getc(cmd)) != EOF) {
if (c == 'q') {
return 0; //quit
}
if (c == ' ') {
return PAGELEN; //next page
}
if (c == '\n') {
return 1; //1 line
}
}
return 0;
}
Linux shares the tty rules of most Unix systems. When a device is seen as a terminal input meaning here something that receive key presses from a human being, the input is by default line oriented. The rationale is that the user is allowed to press a wrong key, cancel it, and finaly press the correct key. In that case, the tty driver handles the fix and only present the final string to the application.
That works fine for line oriented application, but would be foolish for plain screen ones like emacs or vi (yeah, they are from the 70's too...), so the tty driver can be set in raw mode to immediately pass any character to the application (other options exist...). That what the curses library use under the hood to be able to immediately react to any key press.
TL/DR: you must put the tty driver in raw mode to be able to immediately process a character. The details are on the tcflush man page.
As pointed out by #rici in comments, termios can help switching the terminal to non-canonical mode.
In your case you can handle those keys using:
#include <stdio.h>
#include <string.h>
#include <termios.h>
#include <unistd.h>
#define KEY_ESCAPE 0x001b
#define KEY_ENTER 0x000a
static struct termios term, oterm;
static int getch(void);
static int kbhit(void);
static int kbesc(void);
static int kbget(void);
static int getch(void)
{
int c = 0;
tcgetattr(0, &oterm);
memcpy(&term, &oterm, sizeof(term));
term.c_lflag &= ~(ICANON | ECHO);
term.c_cc[VMIN] = 1;
term.c_cc[VTIME] = 0;
tcsetattr(0, TCSANOW, &term);
c = getchar();
tcsetattr(0, TCSANOW, &oterm);
return c;
}
static int kbhit(void)
{
int c = 0;
tcgetattr(0, &oterm);
memcpy(&term, &oterm, sizeof(term));
term.c_lflag &= ~(ICANON | ECHO);
term.c_cc[VMIN] = 0;
term.c_cc[VTIME] = 1;
tcsetattr(0, TCSANOW, &term);
c = getchar();
tcsetattr(0, TCSANOW, &oterm);
if (c != -1) ungetc(c, stdin);
return ((c != -1) ? 1 : 0);
}
static int kbesc(void)
{
int c;
if (!kbhit()) return KEY_ESCAPE;
c = getch();
while (kbhit()) getch();
return c;
}
static int kbget(void)
{
int c;
c = getch();
return (c == KEY_ESCAPE) ? kbesc() : c;
}
int main(void)
{
int c;
while (1) {
c = kbget();
if (c == 'q')
{
return 0; //quit
}
if (c == ' ') {
return PAGELEN; //next page
}
if (c == '\n') {
return 1; //1 line
}
}
return 0;
}
I want to mask my password while writing it with *.
I use Linux GCC for this code.
I know one solution is to use getch() function like this
#include <conio.h>
int main()
{
char c,password[10];
int i;
while( (c=getch())!= '\n');{
password[i] = c;
printf("*");
i++;
}
return 1;
}
but the problem is that GCC does not include conio.h file so, getch() is useless for me.
Does anyone have a solution?
In the Linux world, masking isn't usually done with asterisks, normally echoing is just turned off and the terminal displays blanks E.g. if you use su or log into a virtual terminal etc.
There is a library function to handle getting passwords, it won't mask the password with asterisks but will disable echoing of the password to terminal. I pulled this out of a linux book I have. I believe its part of the posix standard
#include <unistd.h>
char *getpass(const char *prompt);
/*Returns pointer to statically allocated input password string
on success, or NULL on error*/
The getpass() function first disables echoing and all processing of
terminal special characters (such as the interrupt character, normally
Control-C).
It then prints the string pointed to by prompt, and reads a line of
input, returning the null-terminated input string with the trailing
newline stripped, as its function result.
A google search for getpass() has a reference to the GNU implementation (should be in most linux distros) and some sample code for implementing your own if need be
http://www.gnu.org/s/hello/manual/libc/getpass.html
Their example for rolling your own:
#include <termios.h>
#include <stdio.h>
ssize_t
my_getpass (char **lineptr, size_t *n, FILE *stream)
{
struct termios old, new;
int nread;
/* Turn echoing off and fail if we can't. */
if (tcgetattr (fileno (stream), &old) != 0)
return -1;
new = old;
new.c_lflag &= ~ECHO;
if (tcsetattr (fileno (stream), TCSAFLUSH, &new) != 0)
return -1;
/* Read the password. */
nread = getline (lineptr, n, stream);
/* Restore terminal. */
(void) tcsetattr (fileno (stream), TCSAFLUSH, &old);
return nread;
}
If need be you could use this as the basis as modify it to display asterisks.
Without getch to rely on and avoiding the obsolete getpass, the recommended approach is to disable terminal ECHO through termios use. After a few searches to find a canned flexible password routine, I was surprised that very few for stand-alone use with C. Rather than simply recoding getch with termios c_lflag options, slightly more generalized approach takes just a few additions. Beyond replacing getch any routine should enforce a specified maximum length to prevent overflow, truncate if the user attempt to enter beyond the maximum, and warn if truncation occurs in some manner.
Below, the additions will allow reading from any FILE * input stream, limiting the length to a specified length, provide minimal editing (backspace) ability when taking input, allow the character mask to be specified or disabled completely, and finally return the length of the password entered. A warning was added when the password entered was truncated to the maximum or specified length.
Hopefully it will prove useful to others with this question looking for a similar solution:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <termios.h>
#define MAXPW 32
/* read a string from fp into pw masking keypress with mask char.
getpasswd will read upto sz - 1 chars into pw, null-terminating
the resulting string. On success, the number of characters in
pw are returned, -1 otherwise.
*/
ssize_t getpasswd (char **pw, size_t sz, int mask, FILE *fp)
{
if (!pw || !sz || !fp) return -1; /* validate input */
#ifdef MAXPW
if (sz > MAXPW) sz = MAXPW;
#endif
if (*pw == NULL) { /* reallocate if no address */
void *tmp = realloc (*pw, sz * sizeof **pw);
if (!tmp)
return -1;
memset (tmp, 0, sz); /* initialize memory to 0 */
*pw = (char*) tmp;
}
size_t idx = 0; /* index, number of chars in read */
int c = 0;
struct termios old_kbd_mode; /* orig keyboard settings */
struct termios new_kbd_mode;
if (tcgetattr (0, &old_kbd_mode)) { /* save orig settings */
fprintf (stderr, "%s() error: tcgetattr failed.\n", __func__);
return -1;
} /* copy old to new */
memcpy (&new_kbd_mode, &old_kbd_mode, sizeof(struct termios));
new_kbd_mode.c_lflag &= ~(ICANON | ECHO); /* new kbd flags */
new_kbd_mode.c_cc[VTIME] = 0;
new_kbd_mode.c_cc[VMIN] = 1;
if (tcsetattr (0, TCSANOW, &new_kbd_mode)) {
fprintf (stderr, "%s() error: tcsetattr failed.\n", __func__);
return -1;
}
/* read chars from fp, mask if valid char specified */
while (((c = fgetc (fp)) != '\n' && c != EOF && idx < sz - 1) ||
(idx == sz - 1 && c == 127))
{
if (c != 127) {
if (31 < mask && mask < 127) /* valid ascii char */
fputc (mask, stdout);
(*pw)[idx++] = c;
}
else if (idx > 0) { /* handle backspace (del) */
if (31 < mask && mask < 127) {
fputc (0x8, stdout);
fputc (' ', stdout);
fputc (0x8, stdout);
}
(*pw)[--idx] = 0;
}
}
(*pw)[idx] = 0; /* null-terminate */
/* reset original keyboard */
if (tcsetattr (0, TCSANOW, &old_kbd_mode)) {
fprintf (stderr, "%s() error: tcsetattr failed.\n", __func__);
return -1;
}
if (idx == sz - 1 && c != '\n') /* warn if pw truncated */
fprintf (stderr, " (%s() warning: truncated at %zu chars.)\n",
__func__, sz - 1);
return idx; /* number of chars in passwd */
}
A simple program showing the use would be as follows. If using a static array of character for holding the password, just insure a pointer is passed to the function.
int main (void ) {
char pw[MAXPW] = {0};
char *p = pw;
FILE *fp = stdin;
ssize_t nchr = 0;
printf ( "\n Enter password: ");
nchr = getpasswd (&p, MAXPW, '*', fp);
printf ("\n you entered : %s (%zu chars)\n", p, nchr);
printf ( "\n Enter password: ");
nchr = getpasswd (&p, MAXPW, 0, fp);
printf ("\n you entered : %s (%zu chars)\n\n", p, nchr);
return 0;
}
Example Output
$ ./bin/getpasswd2
Enter password: ******
you entered : 123456 (6 chars)
Enter password:
you entered : abcdef (6 chars)
The functionality of getch (which is a non-standard, Windows function) can be emulated with this code:
#include <termios.h>
#include <unistd.h>
int getch() {
struct termios oldt, newt;
int ch;
tcgetattr(STDIN_FILENO, &oldt);
newt = oldt;
newt.c_lflag &= ~(ICANON | ECHO);
tcsetattr(STDIN_FILENO, TCSANOW, &newt);
ch = getchar();
tcsetattr(STDIN_FILENO, TCSANOW, &oldt);
return ch;
}
Note that your approach is not perfect - it's better to use something like ncurses or another terminal library to handle these things.
You can create your own getch() function on Linux in this manner.
int getch() {
struct termios oldtc, newtc;
int ch;
tcgetattr(STDIN_FILENO, &oldtc);
newtc = oldtc;
newtc.c_lflag &= ~(ICANON | ECHO);
tcsetattr(STDIN_FILENO, TCSANOW, &newtc);
ch=getchar();
tcsetattr(STDIN_FILENO, TCSANOW, &oldtc);
return ch;
}
Demo code:
int main(int argc, char **argv) {
int ch;
printf("Press x to exit.\n\n");
for (;;) {
ch = getch();
printf("ch = %c (%d)\n", ch, ch);
if(ch == 'x')
break;
}
return 0;
}
Your method is correct, however you'll need to turn off terminal echo while the password is being entered:
#include <sgtty.h>
void echo_off()
{
struct sgttyb state;
(void)ioctl(0, (int)TIOCGETP, (char *)&state);
state.sg_flags &= ~ECHO;
(void)ioctl(0, (int)TIOCSETP, (char *)&state);
}
void echo_on()
{
struct sgttyb state;
(void)ioctl(0, (int)TIOCGETP, (char *)&state);
state.sg_flags |= ECHO;
(void)ioctl(0, (int)TIOCSETP, (char *)&state);
}
Instead of getch(), why not just use getc() instead?
Thanks all of you whose help & support to solve my problem.
I find a best way to hide my password in linux that fits me best.
To use getpass() function. It just need to include "unistd.h" file.
syntex of getpass function:
char * getpass (const char *prompt)
Parameters:
prompt: string pointer to print while asking for Password
Return Value:
string pointer of password
Example:
#include <stdio.h>
#include <unistd.h>
int main()
{
char *password; // password string pointer
password = getpass("Enter Password: "); // get a password
printf("%s\n",password); // this is just for conformation
// that password stored successfully
return 1;
}
output:
Enter Password:
heet
You might use ncurses.h if it is not necessary to be portable onto Windows for that, but here is some kind of a more "portable" version:
If it is not necessery to be portable ill point you to a ncurses solution
portablegetch.h
/*portablegetch.h*/
#ifndef PGETCH
#define PGETCH
#ifdef __unix__
#include <termios.h>
#include <unistd.h>
static struct termios n_term;
static struct termios o_term;
static int
cbreak(int fd)
{
if((tcgetattr(fd, &o_term)) == -1)
return -1;
n_term = o_term;
n_term.c_lflag = n_term.c_lflag & ~(ECHO|ICANON);
n_term.c_cc[VMIN] = 1;
n_term.c_cc[VTIME]= 0;
if((tcsetattr(fd, TCSAFLUSH, &n_term)) == -1)
return -1;
return 1;
}
int
getch()
{
int cinput;
if(cbreak(STDIN_FILENO) == -1) {
fprintf(stderr, "cbreak failure, exiting \n");
exit(EXIT_FAILURE);
}
cinput = getchar();
tcsetattr(STDIN_FILENO, TCSANOW, &o_term);
return cinput;
}
#elif _MSC_VER || __WIN32__ || __MS_DOS__
#include <conio.h>
#endif
#endif
And the c-file
whatever.c
#include <stdio.h>
#include <stdlib.h>
#include "portablegetch.h"
int
main(int argc, char **argv)
{
int input;
printf("Please Enter your Password:\t");
while(( input=getch() ) != '\n')
printf("*");
printf("\n");
return EXIT_SUCCESS;
}
That should fit to your problem.
Hope that helps.
#include <termios.h>
#include <stdio.h>
static struct termios old, new;
void initTermios(int echo) {
tcgetattr(0, &old);
new = old;
new.c_lflag &= ~ICANON;
new.c_lflag &= echo ? ECHO : ~ECHO;
tcsetattr(0, TCSANOW, &new);
}
void resetTermios(void) {
tcsetattr(0, TCSANOW, &old);
}
char getch_(int echo) {
char ch;
initTermios(echo);
ch = getchar();
resetTermios();
return ch;
}
char getch(void) {
return getch_(0);
}
int main(void) {
char c;
printf("(getch example) please type a letter...");
c = getch();
printf("\nYou typed: %c\n", c);
return 0;
}
Just copy these snippet and use it. Hope it helped
Just pass for it the char* that you want to set password in and its size and the function will do its job
void set_Password(char *get_in, int sz){
for (int i = 0; i < sz;) {
char ch = getch();
if (ch == 13) {
get_in[i] = '\0';
break;
}
else if(ch != 8){
get_in[i++] = ch;
putch('*');
}
else if(i > 0)
cout << "\b \b",get_in[i--] = '\0';
}
cout << "\n";
}
This is an example, run it on your compiler
Unfortunately in the C standard library there is no such function out of the box. Maybe in third party library.
One option is use ANSI escape sequences to set the background color to foreground color in the console to conceal the password. Try this link.
With scanning the characters you can take it into a buffer. Also you need to write code if backspace is pressed, and appropriately correct the inserted password.
Here is a code which once i wrote with the curses. Compile with gcc file.c -o pass_prog -lcurses
#include <stdio.h>
#include <stdlib.h>
#include <curses.h>
#define ENOUGH_SIZE 256
#define ECHO_ON 1
#define ECHO_OFF 0
#define BACK_SPACE 127
char *my_getpass (int echo_state);
int main (void)
{
char *pass;
initscr ();
printw ("Enter Password: ");
pass = my_getpass (ECHO_ON);
printw ("\nEntered Password: %s", pass);
refresh ();
getch ();
endwin ();
return 0;
}
char *my_getpass (int echo_state)
{
char *pass, c;
int i=0;
pass = malloc (sizeof (char) * ENOUGH_SIZE);
if (pass == NULL)
{
perror ("Exit");
exit (1);
}
cbreak ();
noecho ();
while ((c=getch()) != '\n')
{
if (c == BACK_SPACE)
{
/* Do not let the buffer underflow */
if (i > 0)
{
i--;
if (echo_state == ECHO_ON)
printw ("\b \b");
}
}
else if (c == '\t')
; /* Ignore tabs */
else
{
pass[i] = c;
i = (i >= ENOUGH_SIZE) ? ENOUGH_SIZE - 1 : i+1;
if (echo_state == ECHO_ON)
printw ("*");
}
}
echo ();
nocbreak ();
/* Terminate the password string with NUL */
pass[i] = '\0';
endwin ();
return pass;
}
In C you can use getpasswd() function which pretty much doing similar thing as stty in shell, example:
#include <stdio.h>
#include <string.h>
#include <pwd.h>
#include <unistd.h>
int main()
{
char acct[80], password[80];
printf(“Account: “);
fgets(acct, 80, stdin);
acct[strlen(acct)-1] = 0; /* remove carriage return */
strncpy(password, getpass(“Password: “), 80);
printf(“You entered acct %s and pass %s\n”, acct, password);
return 0;
}
Here is equivalent shell script which use stty (which changes the settings of your tty):
save_state=$(stty -g)
/bin/echo -n “Account: “
read acct
/bin/echo -n “Password: “
stty -echo
read password # this won’t echo
stty “$save_state”
echo “”
echo account = $acct and password = $password
Source: How can I read a password without echoing it in C?
man getpass
This function is obsolete. Do not use it. If you want to read input
without terminal echoing enabled, see the description of the ECHO flag
in termios(3)
# include <termios.h>
# include <unistd.h> /* needed for STDIN_FILENO which is an int file descriptor */
struct termios tp, save;
tcgetattr( STDIN_FILENO, &tp); /* get existing terminal properties */
save = tp; /* save existing terminal properties */
tp.c_lflag &= ~ECHO; /* only cause terminal echo off */
tcsetattr( STDIN_FILENO, TCSAFLUSH, &tp ); /* set terminal settings */
/*
now input by user in terminal will not be displayed
and cursor will not move
*/
tcsetattr( STDIN_FILENO, TCSANOW, &save); /* restore original terminal settings */
If you notice, most current linux distro's do not mask a password with asterisks. Doing so divulges the length of the password which is no way beneficial. It is easier and better to simply make the cursor not move when a password is typed in. If for whatever reason you require a * to be printed for every character that's typed then you would have to grab every keypress before Enter is hit and that's always been problematic.
printf("\nENTER PASSWORD: ");
while (1)
{
ch=getch();
if(ch==13) //ON ENTER PRESS
break;
else if(ch==8) //ON BACKSPACE PRESS REMOVES CHARACTER
{
if(i>0)
{
i--;
password[i]='\0';
printf("\b \b");
}
}
else if (ch==32 || ch==9) //ON PRESSING TAB OR SPACE KEY
continue;
else
{
password[i]=ch;
i++;
printf("*");
}
}
password[i]='\0';
Here is my idea, adapted from that of the C++ official site.
#include <termios.h>
#include <unistd.h>
#include <stdio.h>
#include <iostream>
#include <string>
using namespace std;
string getpass(const char *prompt, bool showchar = false, char echochar = '*')
{
struct termios oi, ni;
tcgetattr(STDIN_FILENO, &oi);
ni = oi;
ni.c_lflag &= ~(ICANON | ECHO);
const char DELETE = 127;
const char RETURN = 10;
string password;
unsigned char ch = 0;
cout << prompt;
tcsetattr(STDIN_FILENO, TCSANOW, &ni);
while (getchar() != RETURN) {
if (ch == DELETE) {
if(password.length != 0){
if (showchar) cout << "\b \b";
password.resize(password.length() - 1);
}
}else {
password += getchar();
if (showchar) cout << echochar;
}
}
tcsetattr(STDIN_FILENO,TCSANOW,&oi)
cout << endl;
return password;
}
It will read one character at once and add it to the string and supports showing another character.
note that the ICANON termios lflag turns off the processing carriagereturn/linefeed, and the negative ECHO termios setting turns off echo for STDIN.
when using this (with or without the echo being on) to read a password and print '*' for entered characters, it's not just a matter of reading characters until a newline/carriage return is encountered, you also have to process backspace in your 'string building routine' (else the backspaces end up in the actual string, and do not cause characters to be removed from it such as would be the case with the various string based input functions).
the same would happen in C in DOS with getch tho. that would also happily return 0x08 for backspace (or 127 or whatever your specific os uses as backspace)
keeping track of 'not deleting -before- the start of the string', replacing the 'new end of the string' with 0 and moving the current position counter back by one (unless you are at position 0) is up to the programmer with any of these functions (even the getch on dos C).
getpass() doesn't do what the user originally asked for btw, he wants *'s (which still disclose the length of the password to people standing behind him and looking at his screen, as well as in the scrollbuffer of the terminal if he doesn't close it after use). but without *'s is probably a better idea in 'non closed environments'.
#include <stdio.h>
/* copy input to output */
main()
{
int c;
c = getchar();
while(c != EOF)
{
putchar(c);
c = getchar();
}
return 0;
}
In the given code, the program displays the input character.
It reads every character one by one (into the variable 'c') and outputs the same read characters simultaneously. The program terminates when the EOF character is given as input.
When I ran the code in my IDE (Code::Blocks 16.01) and input a string,
eg: Hi! My name is C.\n
The output is displayed after '\n' and not simultaneously.
Isn't the output supposed to be as - "HHii!! MMyy nnaammee iiss CC.."?
Bold letters indicate the output.
include:
#include <unistd.h>
#include <termios.h>
before your code in main insert:
struct termios term, term_orig;
if(tcgetattr(STDIN_FILENO, &term_orig)) {
printf("tcgetattr failed\n");
return -1;
}
term = term_orig;
term.c_lflag &= ~ICANON;
if (tcsetattr(STDIN_FILENO, TCSANOW, &term)) {
printf("tcsetattr failed\n");
return -1;
}
after your code insert:
if (tcsetattr(STDIN_FILENO, TCSANOW, &term_orig)) {
printf("tcsetattr failed\n");
return -1;
}
Because by default, input from terminal is line-buffered. So your program get a whole line after you press Enter.
To disable buffering in Unix & Linux systems, try this:
#include <unistd.h>
#include <termios.h>
int disableLineBuffer(void){
struct termios term, oldterm;
if (tcgetattr(STDIN_FILENO, &term)) return -1;
oldterm = term;
term.c_lflag &= ~(ECHO | ICANON);
if (tcsetattr(STDIN_FILENO, TCSANOW, &term)) return -1;
return 0;
}
In Windows, go and do this instead:
#include <windows.h>
BOOL WINAPI DisableLineBuffer(void){
HANDLE hInput = GetStdHandle(STD_INPUT_HANDLE);
DWORD mode;
if (!GetConsoleMode(hInput, &mode)) return FALSE;
mode &= ~ENABLE_LINE_INPUT;
if (!SetConsoleMode(hInput, mode)) return FALSE;
return TRUE;
}
Be sure to revert changes to the console before your program exits, or you may have trouble doing anything else in your terminal.
I need to write a program in C language which will be doing something like this:
For example, when I will press "a", terminal will be writing that typed character in the unending loop like this: aaaaaaaaaaaaaaaa...until another key, for example "b" will be pressed. Final output should look like this: aaaaaaaaabbbbbbq (q should terminate the program).
My code here:
int main(int argc, char** argv) {
int c;
static struct termios staryTermios, novyTermios;
tcgetattr(STDIN_FILENO, &staryTermios);
novyTermios = staryTermios;
novyTermios.c_lflag &= ~(ICANON);
tcsetattr(STDIN_FILENO, TCSANOW, &novyTermios);
while ((c = getchar()) != 'q') {
putchar(c);
}
tcsetattr( STDIN_FILENO, TCSANOW, &staryTermios);
return 0;
}
this version writes the typed characters only once and then it waits for another keypress
To achieve the result you want, you need to make the standard input non-blocking. You can do that with this minor adaptation of your code. It worked fine on Mac OS X 10.7.5. Note that getchar() returns EOF when there's no character ready to read (which will be most of the time; neither you nor I can type fast enough to matter to a modern computer). I'm mildly concerned that on some systems, once getchar() has returned EOF once when there was no character to read, it might never return anything other than EOF again, but that wasn't a problem for Mac OS X.
#include <stdio.h>
#include <termios.h>
#include <unistd.h>
#include <fcntl.h>
#include <stdlib.h>
static void err_exit(const char *msg);
int main(void)
{
int c;
int oc = '\0';
struct termios staryTermios, novyTermios;
int oflags, nflags;
if (tcgetattr(STDIN_FILENO, &staryTermios) != 0)
err_exit("tcgetattr() failed");
novyTermios = staryTermios;
novyTermios.c_lflag &= ~(ICANON);
if (tcsetattr(STDIN_FILENO, TCSANOW, &novyTermios) != 0)
err_exit("tcsetattr() failed to set standard input");
oflags = fcntl(STDIN_FILENO, F_GETFL);
if (oflags < 0)
err_exit("fcntl() F_GETFL failed");
nflags = oflags;
nflags |= O_NONBLOCK;
if (fcntl(STDIN_FILENO, F_SETFL, nflags) == -1)
err_exit("fcntl() F_SETFL failed");
while ((c = getchar()) != 'q')
{
if (c != EOF)
oc = c;
if (oc != '\0')
putchar(oc);
}
if (tcsetattr(STDIN_FILENO, TCSANOW, &staryTermios) != 0)
err_exit("tcsetattr() failed to reset standard input");
putchar('\n');
return 0;
}
static void err_exit(const char *msg)
{
fprintf(stderr, "%s\n", msg);
exit(1);
}
I guess you will need two threads which will both be accessing a common variable. The job of one thread would be to continuously print the common variable. The job of the second would be to wait for input from the keyboard and update the variable accordingly.
I want to mask my password while writing it with *.
I use Linux GCC for this code.
I know one solution is to use getch() function like this
#include <conio.h>
int main()
{
char c,password[10];
int i;
while( (c=getch())!= '\n');{
password[i] = c;
printf("*");
i++;
}
return 1;
}
but the problem is that GCC does not include conio.h file so, getch() is useless for me.
Does anyone have a solution?
In the Linux world, masking isn't usually done with asterisks, normally echoing is just turned off and the terminal displays blanks E.g. if you use su or log into a virtual terminal etc.
There is a library function to handle getting passwords, it won't mask the password with asterisks but will disable echoing of the password to terminal. I pulled this out of a linux book I have. I believe its part of the posix standard
#include <unistd.h>
char *getpass(const char *prompt);
/*Returns pointer to statically allocated input password string
on success, or NULL on error*/
The getpass() function first disables echoing and all processing of
terminal special characters (such as the interrupt character, normally
Control-C).
It then prints the string pointed to by prompt, and reads a line of
input, returning the null-terminated input string with the trailing
newline stripped, as its function result.
A google search for getpass() has a reference to the GNU implementation (should be in most linux distros) and some sample code for implementing your own if need be
http://www.gnu.org/s/hello/manual/libc/getpass.html
Their example for rolling your own:
#include <termios.h>
#include <stdio.h>
ssize_t
my_getpass (char **lineptr, size_t *n, FILE *stream)
{
struct termios old, new;
int nread;
/* Turn echoing off and fail if we can't. */
if (tcgetattr (fileno (stream), &old) != 0)
return -1;
new = old;
new.c_lflag &= ~ECHO;
if (tcsetattr (fileno (stream), TCSAFLUSH, &new) != 0)
return -1;
/* Read the password. */
nread = getline (lineptr, n, stream);
/* Restore terminal. */
(void) tcsetattr (fileno (stream), TCSAFLUSH, &old);
return nread;
}
If need be you could use this as the basis as modify it to display asterisks.
Without getch to rely on and avoiding the obsolete getpass, the recommended approach is to disable terminal ECHO through termios use. After a few searches to find a canned flexible password routine, I was surprised that very few for stand-alone use with C. Rather than simply recoding getch with termios c_lflag options, slightly more generalized approach takes just a few additions. Beyond replacing getch any routine should enforce a specified maximum length to prevent overflow, truncate if the user attempt to enter beyond the maximum, and warn if truncation occurs in some manner.
Below, the additions will allow reading from any FILE * input stream, limiting the length to a specified length, provide minimal editing (backspace) ability when taking input, allow the character mask to be specified or disabled completely, and finally return the length of the password entered. A warning was added when the password entered was truncated to the maximum or specified length.
Hopefully it will prove useful to others with this question looking for a similar solution:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <termios.h>
#define MAXPW 32
/* read a string from fp into pw masking keypress with mask char.
getpasswd will read upto sz - 1 chars into pw, null-terminating
the resulting string. On success, the number of characters in
pw are returned, -1 otherwise.
*/
ssize_t getpasswd (char **pw, size_t sz, int mask, FILE *fp)
{
if (!pw || !sz || !fp) return -1; /* validate input */
#ifdef MAXPW
if (sz > MAXPW) sz = MAXPW;
#endif
if (*pw == NULL) { /* reallocate if no address */
void *tmp = realloc (*pw, sz * sizeof **pw);
if (!tmp)
return -1;
memset (tmp, 0, sz); /* initialize memory to 0 */
*pw = (char*) tmp;
}
size_t idx = 0; /* index, number of chars in read */
int c = 0;
struct termios old_kbd_mode; /* orig keyboard settings */
struct termios new_kbd_mode;
if (tcgetattr (0, &old_kbd_mode)) { /* save orig settings */
fprintf (stderr, "%s() error: tcgetattr failed.\n", __func__);
return -1;
} /* copy old to new */
memcpy (&new_kbd_mode, &old_kbd_mode, sizeof(struct termios));
new_kbd_mode.c_lflag &= ~(ICANON | ECHO); /* new kbd flags */
new_kbd_mode.c_cc[VTIME] = 0;
new_kbd_mode.c_cc[VMIN] = 1;
if (tcsetattr (0, TCSANOW, &new_kbd_mode)) {
fprintf (stderr, "%s() error: tcsetattr failed.\n", __func__);
return -1;
}
/* read chars from fp, mask if valid char specified */
while (((c = fgetc (fp)) != '\n' && c != EOF && idx < sz - 1) ||
(idx == sz - 1 && c == 127))
{
if (c != 127) {
if (31 < mask && mask < 127) /* valid ascii char */
fputc (mask, stdout);
(*pw)[idx++] = c;
}
else if (idx > 0) { /* handle backspace (del) */
if (31 < mask && mask < 127) {
fputc (0x8, stdout);
fputc (' ', stdout);
fputc (0x8, stdout);
}
(*pw)[--idx] = 0;
}
}
(*pw)[idx] = 0; /* null-terminate */
/* reset original keyboard */
if (tcsetattr (0, TCSANOW, &old_kbd_mode)) {
fprintf (stderr, "%s() error: tcsetattr failed.\n", __func__);
return -1;
}
if (idx == sz - 1 && c != '\n') /* warn if pw truncated */
fprintf (stderr, " (%s() warning: truncated at %zu chars.)\n",
__func__, sz - 1);
return idx; /* number of chars in passwd */
}
A simple program showing the use would be as follows. If using a static array of character for holding the password, just insure a pointer is passed to the function.
int main (void ) {
char pw[MAXPW] = {0};
char *p = pw;
FILE *fp = stdin;
ssize_t nchr = 0;
printf ( "\n Enter password: ");
nchr = getpasswd (&p, MAXPW, '*', fp);
printf ("\n you entered : %s (%zu chars)\n", p, nchr);
printf ( "\n Enter password: ");
nchr = getpasswd (&p, MAXPW, 0, fp);
printf ("\n you entered : %s (%zu chars)\n\n", p, nchr);
return 0;
}
Example Output
$ ./bin/getpasswd2
Enter password: ******
you entered : 123456 (6 chars)
Enter password:
you entered : abcdef (6 chars)
The functionality of getch (which is a non-standard, Windows function) can be emulated with this code:
#include <termios.h>
#include <unistd.h>
int getch() {
struct termios oldt, newt;
int ch;
tcgetattr(STDIN_FILENO, &oldt);
newt = oldt;
newt.c_lflag &= ~(ICANON | ECHO);
tcsetattr(STDIN_FILENO, TCSANOW, &newt);
ch = getchar();
tcsetattr(STDIN_FILENO, TCSANOW, &oldt);
return ch;
}
Note that your approach is not perfect - it's better to use something like ncurses or another terminal library to handle these things.
You can create your own getch() function on Linux in this manner.
int getch() {
struct termios oldtc, newtc;
int ch;
tcgetattr(STDIN_FILENO, &oldtc);
newtc = oldtc;
newtc.c_lflag &= ~(ICANON | ECHO);
tcsetattr(STDIN_FILENO, TCSANOW, &newtc);
ch=getchar();
tcsetattr(STDIN_FILENO, TCSANOW, &oldtc);
return ch;
}
Demo code:
int main(int argc, char **argv) {
int ch;
printf("Press x to exit.\n\n");
for (;;) {
ch = getch();
printf("ch = %c (%d)\n", ch, ch);
if(ch == 'x')
break;
}
return 0;
}
Your method is correct, however you'll need to turn off terminal echo while the password is being entered:
#include <sgtty.h>
void echo_off()
{
struct sgttyb state;
(void)ioctl(0, (int)TIOCGETP, (char *)&state);
state.sg_flags &= ~ECHO;
(void)ioctl(0, (int)TIOCSETP, (char *)&state);
}
void echo_on()
{
struct sgttyb state;
(void)ioctl(0, (int)TIOCGETP, (char *)&state);
state.sg_flags |= ECHO;
(void)ioctl(0, (int)TIOCSETP, (char *)&state);
}
Instead of getch(), why not just use getc() instead?
Thanks all of you whose help & support to solve my problem.
I find a best way to hide my password in linux that fits me best.
To use getpass() function. It just need to include "unistd.h" file.
syntex of getpass function:
char * getpass (const char *prompt)
Parameters:
prompt: string pointer to print while asking for Password
Return Value:
string pointer of password
Example:
#include <stdio.h>
#include <unistd.h>
int main()
{
char *password; // password string pointer
password = getpass("Enter Password: "); // get a password
printf("%s\n",password); // this is just for conformation
// that password stored successfully
return 1;
}
output:
Enter Password:
heet
You might use ncurses.h if it is not necessary to be portable onto Windows for that, but here is some kind of a more "portable" version:
If it is not necessery to be portable ill point you to a ncurses solution
portablegetch.h
/*portablegetch.h*/
#ifndef PGETCH
#define PGETCH
#ifdef __unix__
#include <termios.h>
#include <unistd.h>
static struct termios n_term;
static struct termios o_term;
static int
cbreak(int fd)
{
if((tcgetattr(fd, &o_term)) == -1)
return -1;
n_term = o_term;
n_term.c_lflag = n_term.c_lflag & ~(ECHO|ICANON);
n_term.c_cc[VMIN] = 1;
n_term.c_cc[VTIME]= 0;
if((tcsetattr(fd, TCSAFLUSH, &n_term)) == -1)
return -1;
return 1;
}
int
getch()
{
int cinput;
if(cbreak(STDIN_FILENO) == -1) {
fprintf(stderr, "cbreak failure, exiting \n");
exit(EXIT_FAILURE);
}
cinput = getchar();
tcsetattr(STDIN_FILENO, TCSANOW, &o_term);
return cinput;
}
#elif _MSC_VER || __WIN32__ || __MS_DOS__
#include <conio.h>
#endif
#endif
And the c-file
whatever.c
#include <stdio.h>
#include <stdlib.h>
#include "portablegetch.h"
int
main(int argc, char **argv)
{
int input;
printf("Please Enter your Password:\t");
while(( input=getch() ) != '\n')
printf("*");
printf("\n");
return EXIT_SUCCESS;
}
That should fit to your problem.
Hope that helps.
#include <termios.h>
#include <stdio.h>
static struct termios old, new;
void initTermios(int echo) {
tcgetattr(0, &old);
new = old;
new.c_lflag &= ~ICANON;
new.c_lflag &= echo ? ECHO : ~ECHO;
tcsetattr(0, TCSANOW, &new);
}
void resetTermios(void) {
tcsetattr(0, TCSANOW, &old);
}
char getch_(int echo) {
char ch;
initTermios(echo);
ch = getchar();
resetTermios();
return ch;
}
char getch(void) {
return getch_(0);
}
int main(void) {
char c;
printf("(getch example) please type a letter...");
c = getch();
printf("\nYou typed: %c\n", c);
return 0;
}
Just copy these snippet and use it. Hope it helped
Just pass for it the char* that you want to set password in and its size and the function will do its job
void set_Password(char *get_in, int sz){
for (int i = 0; i < sz;) {
char ch = getch();
if (ch == 13) {
get_in[i] = '\0';
break;
}
else if(ch != 8){
get_in[i++] = ch;
putch('*');
}
else if(i > 0)
cout << "\b \b",get_in[i--] = '\0';
}
cout << "\n";
}
This is an example, run it on your compiler
Unfortunately in the C standard library there is no such function out of the box. Maybe in third party library.
One option is use ANSI escape sequences to set the background color to foreground color in the console to conceal the password. Try this link.
With scanning the characters you can take it into a buffer. Also you need to write code if backspace is pressed, and appropriately correct the inserted password.
Here is a code which once i wrote with the curses. Compile with gcc file.c -o pass_prog -lcurses
#include <stdio.h>
#include <stdlib.h>
#include <curses.h>
#define ENOUGH_SIZE 256
#define ECHO_ON 1
#define ECHO_OFF 0
#define BACK_SPACE 127
char *my_getpass (int echo_state);
int main (void)
{
char *pass;
initscr ();
printw ("Enter Password: ");
pass = my_getpass (ECHO_ON);
printw ("\nEntered Password: %s", pass);
refresh ();
getch ();
endwin ();
return 0;
}
char *my_getpass (int echo_state)
{
char *pass, c;
int i=0;
pass = malloc (sizeof (char) * ENOUGH_SIZE);
if (pass == NULL)
{
perror ("Exit");
exit (1);
}
cbreak ();
noecho ();
while ((c=getch()) != '\n')
{
if (c == BACK_SPACE)
{
/* Do not let the buffer underflow */
if (i > 0)
{
i--;
if (echo_state == ECHO_ON)
printw ("\b \b");
}
}
else if (c == '\t')
; /* Ignore tabs */
else
{
pass[i] = c;
i = (i >= ENOUGH_SIZE) ? ENOUGH_SIZE - 1 : i+1;
if (echo_state == ECHO_ON)
printw ("*");
}
}
echo ();
nocbreak ();
/* Terminate the password string with NUL */
pass[i] = '\0';
endwin ();
return pass;
}
In C you can use getpasswd() function which pretty much doing similar thing as stty in shell, example:
#include <stdio.h>
#include <string.h>
#include <pwd.h>
#include <unistd.h>
int main()
{
char acct[80], password[80];
printf(“Account: “);
fgets(acct, 80, stdin);
acct[strlen(acct)-1] = 0; /* remove carriage return */
strncpy(password, getpass(“Password: “), 80);
printf(“You entered acct %s and pass %s\n”, acct, password);
return 0;
}
Here is equivalent shell script which use stty (which changes the settings of your tty):
save_state=$(stty -g)
/bin/echo -n “Account: “
read acct
/bin/echo -n “Password: “
stty -echo
read password # this won’t echo
stty “$save_state”
echo “”
echo account = $acct and password = $password
Source: How can I read a password without echoing it in C?
man getpass
This function is obsolete. Do not use it. If you want to read input
without terminal echoing enabled, see the description of the ECHO flag
in termios(3)
# include <termios.h>
# include <unistd.h> /* needed for STDIN_FILENO which is an int file descriptor */
struct termios tp, save;
tcgetattr( STDIN_FILENO, &tp); /* get existing terminal properties */
save = tp; /* save existing terminal properties */
tp.c_lflag &= ~ECHO; /* only cause terminal echo off */
tcsetattr( STDIN_FILENO, TCSAFLUSH, &tp ); /* set terminal settings */
/*
now input by user in terminal will not be displayed
and cursor will not move
*/
tcsetattr( STDIN_FILENO, TCSANOW, &save); /* restore original terminal settings */
If you notice, most current linux distro's do not mask a password with asterisks. Doing so divulges the length of the password which is no way beneficial. It is easier and better to simply make the cursor not move when a password is typed in. If for whatever reason you require a * to be printed for every character that's typed then you would have to grab every keypress before Enter is hit and that's always been problematic.
printf("\nENTER PASSWORD: ");
while (1)
{
ch=getch();
if(ch==13) //ON ENTER PRESS
break;
else if(ch==8) //ON BACKSPACE PRESS REMOVES CHARACTER
{
if(i>0)
{
i--;
password[i]='\0';
printf("\b \b");
}
}
else if (ch==32 || ch==9) //ON PRESSING TAB OR SPACE KEY
continue;
else
{
password[i]=ch;
i++;
printf("*");
}
}
password[i]='\0';
Here is my idea, adapted from that of the C++ official site.
#include <termios.h>
#include <unistd.h>
#include <stdio.h>
#include <iostream>
#include <string>
using namespace std;
string getpass(const char *prompt, bool showchar = false, char echochar = '*')
{
struct termios oi, ni;
tcgetattr(STDIN_FILENO, &oi);
ni = oi;
ni.c_lflag &= ~(ICANON | ECHO);
const char DELETE = 127;
const char RETURN = 10;
string password;
unsigned char ch = 0;
cout << prompt;
tcsetattr(STDIN_FILENO, TCSANOW, &ni);
while (getchar() != RETURN) {
if (ch == DELETE) {
if(password.length != 0){
if (showchar) cout << "\b \b";
password.resize(password.length() - 1);
}
}else {
password += getchar();
if (showchar) cout << echochar;
}
}
tcsetattr(STDIN_FILENO,TCSANOW,&oi)
cout << endl;
return password;
}
It will read one character at once and add it to the string and supports showing another character.
note that the ICANON termios lflag turns off the processing carriagereturn/linefeed, and the negative ECHO termios setting turns off echo for STDIN.
when using this (with or without the echo being on) to read a password and print '*' for entered characters, it's not just a matter of reading characters until a newline/carriage return is encountered, you also have to process backspace in your 'string building routine' (else the backspaces end up in the actual string, and do not cause characters to be removed from it such as would be the case with the various string based input functions).
the same would happen in C in DOS with getch tho. that would also happily return 0x08 for backspace (or 127 or whatever your specific os uses as backspace)
keeping track of 'not deleting -before- the start of the string', replacing the 'new end of the string' with 0 and moving the current position counter back by one (unless you are at position 0) is up to the programmer with any of these functions (even the getch on dos C).
getpass() doesn't do what the user originally asked for btw, he wants *'s (which still disclose the length of the password to people standing behind him and looking at his screen, as well as in the scrollbuffer of the terminal if he doesn't close it after use). but without *'s is probably a better idea in 'non closed environments'.