Program which count chars of selected word - c

Question

Its a homework, sorry for that.
I can't make working program for counting chars in word, for an example:
I enter the String : My name is peter
The program asks which word to process..
I enter the number : 3
Program says : Count of the Third word is 2.
#include <stdio.h>
#include <conio.h>
#include <string.h>
int main()
{
char text[200],vards[20];
int i, length,lengthv, count=0,x;
printf("insert txt\n");
gets(text);
length=strlen(text);
for(i=0; i<length; i++)
{
if(text[i]!=' ' && text[i]!='.' && text[i]!=',')
{
printf("%c", text[i]);
if (text[i+1]=='\0')
count++;
}
else
{
if(text[i-1]!=' ' && text[i-1]!='.' && text[i-1]!=',')
{
count++;
printf("\n");
}
}
}
printf("detect lenght of wich name\n");
for(i=0;i<x;i++);
scanf("%s", &text);
lengthv=strlen(vards);
printf("\n The lenght of name is %d", lengthv);
getch();
return 0;
}

Answer 1

I can't really understand your code, but here is how I would do it:
#include <stdlib.h>
#include <stdio.h>
int main() {
char text[200], whichText[200];
int i=0, length, countWord=0, currWord=1, wordChars=0;
// Get text input:
printf("insert txt\n");
gets(text);
length=strlen(text);
// Get word to count:
while(countWord == 0) {
printf("Count which word?\n");
gets(whichText);
sscanf(whichText, "%i", &countWord);
}
// Iterate through each character of the text input:
for( i=0; i < length; i++ ) {
// Keep track of which word we are on, by counting spaces:
if( text[i] == ' ' ) {
currWord ++;
continue;
}
// While we are on the desired word, count the characters:
if( currWord == countWord )
wordChars ++;
}
printf("Count of word %i is %i.\n", countWord, wordChars);
return 0;
}