search array for string - c

Question

How would i implement this?Im trying to compare a array of c strings to a single string and if there is no match append it to the 2d array.
char*mprt,uni[100][16];
mprt = &uni[0][0];
for (int s = 0;s <= 99;s++)
{
for (int z = 0;z <= 15;z++)
{
if (strcmp(mprt++, string1) != 0)
{
uni[s][z] = string1[z];
}
}
}

Answer 1

Ok ... from your comments I now get what you're trying to do. You'd want to make this into a function so you could feed words to it, but it should get you pointed in the right direction.
Note that you can use char[][], but this way your strings can be of any length because we dynamically allocate them when we put them in the list.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
/* space for 100 strings */
char **uni = calloc(100, sizeof(char*));
char **i;
/* Put one word in the list for test */
*uni = calloc(5, sizeof(char*));
strncpy(*uni, "this", 5);
/* here's the string we're going to search for */
char * str2 = "that";
/* go through the first dimension looking for the string
note we have to check that we don't exceed our list size */
for (i = uni; *i != NULL && i < uni+100; i++)
{
/* if we find it, break */
if (strcmp(*i,str2) == 0)
break;
}
/* if we didn't find the string, *i will be null
* or we will have hit the end of our first dimension */
if (i == uni + 100)
{
printf("No more space!\n");
}
else if (*i == NULL)
{
/* allocate space for our string */
*i = calloc(strlen(str2) + 1, sizeof(char));
/* copy our new string into the list */
strncpy(*i, str2, strlen(str2) + 1);
}
/* output to confirm it worked */
for (i = uni; *i != NULL && i < uni+100; i++)
printf("%s\n",*i);
}
For completeness, the char[][] version:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
char uni[100][16];
int i,j;
/* init our arrays */
for (i=0;i<100;i++)
for (j=0;j<16;j++)
uni[i][j] = '\0';
/* Put one word in the list for test */
strncpy(uni[0], "this",15);
/* here's the string we're going to search for */
char * str2 = "that";
/* go through the first dimension looking for the string */
for (i = 0; uni[i][0] != '\0' && i < 100; i++)
{
/* if we find it, break */
if (strcmp(uni[i],str2) == 0)
break;
}
/* if we didn't find the string, uni[i][0] will be '\0'
* or we will have hit the end of our first dimension */
if (i == 100)
{
printf("No more space!\n");
}
else if (uni[i][0] == '\0')
{
/* copy our new string into the array */
strncpy(uni[i], str2, 15);
}
/* output to confirm it worked */
for (i = 0; uni[i][0] != '\0' && i < 100; i++)
printf("%s\n",uni[i]);
}
Edit to explain C pointers and arrays from comments below:
In C, arrays degrade to pointers. This is actually really confusing when you first start.
If I have char myArray[10] and I want to pass that to a function that takes a char * argument, I can use either &myArray[0] or just myArray. When you leave off the index, it degrades to a pointer to the first element in the array.
In a multidimensional array like yours, &uni[5][0] == uni[5] - both are pointers to the first element in the second dimension at index 5 in the first. It degrades to char* pointed at the beginning of the 6th word in your list.

Answer 2

In your for loop, you need to copy the whole string to append it,
Replace the line by this,
strcpy(uni[s], string1[z]);
Considering string1[z] is an element of an array of char pointers.
Edit:
Not sure if this is what you're trying to do, but you'll end up with all elements set to string1
char string1[] = "String";
char uni[100][16] = {};
for (int s = 0; s < 100; s++)
{
if (strcmp(uni[s], string1) != 0)
{
strcpy(uni[s], string1);
}
}
Or this, without strcpy()
char string1[] = "String";
char uni[100][16] = {};
for (int s = 0; s < 100; s++)
{
for (int r = 0; r < sizeof(string1); r++)
{
uni[s][r] = string1[r];
}
}

Answer 3

to append to the end of the 2D array you need to use dynamic memory allocation
const int row_max = 100, col_max = 16;
char** uni = NULL;
char searchString[col_max] = "xyz";
int currentLength = 0;
uni = (char**) malloc (row_max * sizeof(char*)); //TODO:error handling code to be added
for (int row = 0; row < row_max; row++)
{
uni[row] = (char*)malloc(col_max * sizeof(char));//TODO:error handling code to be added
currentLength = row;
}
for (int row = 0; row < row_max; row++) //fill array uni with data here
{
uni[row] = "abc";
}
for (int row = 0; row < row_max; row++)
{
for (int col = 0; col < col_max; col++)
{
if (strcmp(&uni[row][col], searchString) != 0 )
{//string not found
uni = (char**)realloc(uni, (currentLength + 1) * sizeof(char*));//TODO:error handling code to be added
uni[currentLength + 1] = (char*)malloc(col_max);//TODO:error handling code to be added
currentLength++;
strcpy(uni[currentLength],searchString); //append at end of 2D array
goto stop;
}
}
}
stop:
for (int row = 0; row <= currentLength; row++)
free(uni[row]);
free(uni);
return 0;