I don’t know if this is possible but I would like to make a batch, which replaces all, the backslashes contained in a txt file (C:\locations) with forward slashes.
THX..
EDIT:
Im trying to loop:
set str1=!Var1!
echo.%str1%
set str1=%str1:\=/%
to work together with:
set file=C:\text1.txt
FOR /F %%i IN (%file%) DO (
set username=%%i
echo (load "%%i") >> C:\text.txt
)
what I have so far is:
ECHO Retreving list of files...
dir /s /b c:\ICT\AUTOCAD_2010\*.LSP > C:\BART1.txt
Echo Looping variables...
set file=C:\text1.txt
FOR /F %%1 IN (%file%) DO (
set fred=%%1
echo %%1 > C:\tempme.txt
)
set fred=C:\tempme.txt
set fred=%fred:\=/%
echo (load "%fred%") >> C:\text2.txt
however this returns:
(load "C:/tempme.txt")
which is incorect.
Windows' PowerSheel is too limited for that. I suggest you using a scripting language like Perl. Here's a quick script that does that:
my #file = <STDIN>;
my $text = join('', #file);
$text =~ s/\\/\//g;
print($text);
You can launch it like
perl foo.pl < example.txt > result.txt
Using sed as suggested by Tichodroma is another very good option.
I'm a little confused as to what you really want. Your sample code has a FOR ... IN that only has one file in the IN (), i.e. the content of %fred%. Then you write that one filename into a temporary file. Afterwards you have SET that replaces the backslash with a forward slash in the name of the temporary file. But this never touches any file.
However, in your opening segment you want to replace backslashes with forward slashes in a file. So I'm focusing on that part. That would be done this way:
#ECHO OFF
SETLOCAL EnableDelayedExpansion
REM Here's a backslash: \
FOR /F "delims=" %%a IN ('TYPE %0') DO (
SET line=%%a
ECHO !line:\=/!
)
Please note that for simplicity this little batch file parses itself (%0) and, therefore, only replaces that one backslash. However, feel free to put whichever file next to TYPE.
EnableDelayedExpansion makes the syntax with the ! work (see SET /? for more info about delayed expansion). TYPE obviously writes a file to the console. The FOR /F "delims=" now grabs the output of that line per line (since delims= defines no delimiter for the tokenizer of FOR). The line-variable is necessary, because I don't think that there is a proper way to make the ECHO-line work with %%a.
The only downside is that this will remove all empty lines from the original file. I don't know if that's a problem for you.
Related
I've set up an app for a couple of friends and me in batch with a auto-updating system, but I need to add a line of code in the auto-updating system. I decided to completely rewrite the file, it takes a long time to add 'echo' in from to every line and, '>>text.txt' at the end of every line and added '^' when needed, so I was wondering if there was an easier way of writing lot's of code to a file in batch.
Example:
#echo off
rem I need a way to do the following without adding 'echo' and '>>text.txt'
echo echo Checking for updates... >text.txt
echo echo 1.4 ^>^>new.txt >>text.txt
echo ping localhost -n 2 ^>nul >>text.txt
rem and so on and so on.
Or if there is a way to simply add a new line of code in a specific place in the file, that would also help!
Thanks in advance!
The following is how you can more easily and efficiently do what your current code does, by removing all of those individual write processes.
#( Echo #Echo Checking for updates...
Echo #(Echo 1.4^)^>^>"new.txt"
Echo #(%__AppDir__%ping.exe LocalHost -n 2^)^>NUL
)>"text.txt"
There are other possibilities, but at this time, based on the lack of information in your question, I'm reluctant to expand further at this time.
If I understand correctly, then you could do the following:
in the batch file, prepend each line of text that you want to output with :::: (this constitutes an invalid label that is going to be ignored);
then use the following code:
rem // Redirect to file:
> "text.txt" (
rem // Find all lines that begin with `::::` and loop over them:
for /F "delims=" %%T in ('findstr "^::::" "%~f0"') do (
rem // Store currently iterated line:
set "TEXT=%%T"
rem // Toggle delayed expansion to avoid loss of `!`:
setlocal EnableDelayedExpansion
rem // Remove `::::` prefix and output remaining line:
echo(!TEXT:*::::=!
endlocal
)
)
replace set "TEXT=%%T" by call set "TEXT=%%T" if you want to enable percent expansion within the returned text (so it could, for example, contain %~nx0, which would then be expanded to the file name of the script).
I am using this technique a lot (without the output redirection) for help systems in my batch files (/?).
Your asked
I need a way to do the following without adding echo and >>text.txt
The script takes advantage of the line continuation character, the caret ^.
The first character after the caret ^ is always escaped, so do linefeed characters:
#echo off
SETLOCAL EnableDelayedExpansion
call :init
>text.txt (
echo #echo off%NL%
Checking for updates...%NL%
>^>new.txt echo 1.4%NL%
>NUL ping localhost -n 2
)
ENDLOCAL
exit /b
:init
( set LF=^
%= 0X0D FORM FEED =%
)
::0X0A Carriage Return
FOR /F %%a in ('copy /Z "%~f0" nul') do set "CR=%%a"
::Create newline/line continuation character
set ^"NL=^^^%LF%%LF%^%LF%%LF%^^" %= Unix-Style Endings \n =%
::set ^"NL=%CR%^^^%LF%%LF%^%LF%%LF%^^" %= Windows-Style Endings \r\n =%
exit /b
The variable %LF% is a escaped linefeed, and %NL% is a escaped %LF% plus a escaped caret ^ for line continuation.
The code
>^>new.txt echo 1.4%NL%
>NUL ping localhost -n 2
might seem strange. Why isn't the first caret ^ escaped?
Because %NL% already escaped it.
Sources:
Explain how Windows batch newline variable hack works
https://stackoverflow.com/a/5642300/12861751
https://www.dostips.com/forum/viewtopic.php?t=6369
I wanted to take list of files to delete from user as a argument. One line per argument.
How can store the list of files separated by new line in a variable.
I am using below command.
Set DeletionFiles=${p:DeleteFiles}"
for %%i in (%DeletionFiles%) do (
echo %%i
)
Then i wanted to iterated them on a loop.
${p:DeleteFiles} will get replaced by it's value from external app, which will contain list of files separated by new line.I can not change it.
#ECHO OFF
SETLOCAL
SET "deletionfiles="
:dloop
SET "deleteme="
SET /p "deleteme=Which file to delete ? "
IF DEFINED deleteme SET "deleteme=%deleteme:"=%"
IF DEFINED deleteme SET "deletionfiles=%deletionfiles%,"%deleteme%""&goto dloop
ECHO delete %deletionfiles:~1%
GOTO :EOF
There is no need to use a newline. Your for command (or a del command) will operate perfectly happily on a comma-(or space-)separated list.
Note that there are certain characters that batch uses for special purposes and batch string-processing may not process them in the expected manner. These characters include % ^ and &.
${p:DeleteFiles} will get replaced by it's value from external app,
which will contain list of files separated by new line.I can not
change it.
After the replacement the batch file looks like:
Set DeletionFiles=file1.jpg
file2.jpg
file3.jpg
"
This isn't a valid batch file anymore.
Furthermore it's a bad idea to modify the batch file itself, as this works only once.
You could place the ${p:DeleteFiles} into another file, like input.txt.
Your batch would look like
echo ${p:DeleteFiles} > input.txt
<external program for replacing the DeleteFiles> input.txt
for /F "tokens=*" %%A in (input.txt) do (
echo File: %%A
)
If I understand you correctly, your external program will generate a list of files. You then want to store this multi-line list to a variable. What do you want to do with the variable once you have it? I assume you want to delete the files, but your question isn't clear on that point, so I'll try to over-answer to cover it.
for /f "delims=" %%a in ('{command that generates your list}') do (
echo Doing stuff to %%a...
echo %%a>>listOfFilesToDelete.txt
set var=%%a
if "%var:~0,7%"="DoNotDelete" copy "%%a" \someArchiveFolder\
del "%%a"
)
This will read each line in your generated list as variable %%a. It will then do whatever command(s) you specify. This way, you can run a command on each of the files in the list. In the above code it's
Printing each line to the console embedded in some text
Outputting it to a file
Checking the first 7 characters of the line against a specified string and then copying it to a folder if it matches
And then deleting it
If you still need to reference each line from your generated list, you can even setup an array-like structure. (See Create list or arrays in Windows Batch)
setlocal EnableDelayedExpansion
:: Capture lines in an 'array'
set /a i=0
for /f "delims=" %%a in ('dir /b') do (
set /a i+=1
set var!i!=%%a
)
:: Loop through the 'array'
for /L %%a in (1,1,%i%) do (
echo Do more stuff with !var%%a!
)
Just like above, this will read each line in your generated list as variable %%a. It will then set a variable var!i! equal to the value of the current line. You can then reference each line as var1, var2, and so on, or, as the second section shows, you can loop through them all using for /L. You'll need to get a grasp on working with delayed expansion variables, though.
Okay I have several lines in a text file. I want to get the first line and save it in another file. For example this is the text file:
put returns between paragraphs
for linebreak add 2 spaces at end
for linebreak add 2 spaces at end2
for linebreak add 2 spaces at end3
I want put returns between paragraphs to be saved into another file.
I used
for /f "tokens=" %%A in ('findstr /r "^[0-9][0-9]*$" <"C:\Users\Sherlock\Desktop\AbcImport\123.txt"') do echo 123>>1234.txt
pause
But it doesn't work at all.
How to get just the first line of a text file written into a new text file using a batch file?
Option 1 - SET /P : This is the simplest and fastest pure batch solution, provided the line does not exceed 1021 bytes, and it does not end with control characters that must be preserved. The size of the file does not matter - it will always read and write the first line very quickly.
#echo off
setlocal enableDelayedExpansion
set "ln="
<"input.txt" set /p "ln="
>"output.txt" (echo(!ln!)
Option 2 - FOR /F : This will work with lines up to ~8191 bytes long, but it can be slow if the file is really large because the FOR /F loop must read the entire file before it processes the first line. This solution is basically the same as the Mofi answer, except it disables the EOL option, so it never ignores the first line, regardless what the first character is. It does have a limitation that it will skip empty lines, so technically it does not give the correct result if the first line is empty:
#echo off
for /f usebackq^ delims^=^ eol^= %%A in ("input.txt") do echo(%%A>"output.txt"&goto :break
:break
There is a way to preserve the first line if it is empty using pure batch, but I would not bother. I would move on to ...
Option 3 - JREPL.BAT, or some other non-batch solution : Batch is quite poor at manipulating text files. You are much better off using some other scripting language like VBScript, JScript, or Powershell. Or a Windows port of any number of unix utilities.
I would use JREPL.BAT - a hybrid JScrpit/batch regular expression text processing utility that runs natively on any Windows machine from XP onward. It is way overkill for such a simple task, but it is an extremely handy, powerful, and efficient tool to have in your arsenal. Once you have it, then it can be used for many text processing tasks. Full documentation is embedded within the script.
jrepl "^.*" "$&" /jendln "quit=true" /f "input.txt" /o "output.txt"
Use CALL JREPL if you put the command within a batch script.
Here is the batch code to write just first non blank/empty line of a text file into another text file.
#echo off
for /F "usebackq delims=" %%I in ("InputTextFile.txt") do (
echo %%I>"OutputTextFile.txt"
goto ContinueAfterLoop
)
:ContinueAfterLoop
InputTextFile.txt is the file in current directory containing the first line to copy.
OutputTextFile.txt is the file created in current directory with first line from input file copied into this output file.
The command GOTO is used to exit the loop after first line is processed and continue the batch file below the loop.
For understanding the used commands and how they work, open a command prompt window, execute there the following commands, and read entirely all help pages displayed for each command very carefully.
echo /?
for /?
goto /?
Read also the Microsoft article about Using Command Redirection Operators.
You can use use this command:
SetLocal EnableDelayedExpansion
for /f "tokens=* delims=;" %%m in ("C:\Users\Sherlock\Desktop\AbcImport\123.txt") do (
set /p FirstLine=<%%m
echo !FirstLine!>>1234.txt
)
and for multiple file:
SetLocal EnableDelayedExpansion
for %%a in ("*") do (
for /f "tokens=* delims=;" %%m in ("%%a") do (
set /p FirstLine=<%%m
echo !FirstLine!>>1234.txt
)
)
rem Get the first line of a text file:
set /P "line=" < "C:\Users\Sherlock\Desktop\AbcImport\123.txt"
rem Write it into a new text file:
echo %line%> 1234.txt
I've got some *.Xml files in a directory and its sub-directories. I need to loop through the XML files which have a specific constant at the end of their file name, and then echo/print their names without the constant part nor the extension (.Xml).
For example: these are the file names I have:
FileAAA_Constant.Xml
FileBBB.Xml
FileCCC.Xml
FileDDD_Constant.Xml
And this is the output I need:
FileAAA
FileDDD
I've tried this command:
For /R %%X in (*_Constant.Xml) do echo %%~nX
Which outputs this:
FileAAA_Constant
FileDDD_Constant
As you can see, it has removed the extension only, while I need to remove "_Constant.Xml" as well.
This works if the file names contains only one underscore, as indicated in your example:
for /F "delims=_" %%X in ('dir /S /B *_Constant.Xml') do echo %%X
If the desired file names may contain more than one underscore, use Pokechu22's answer.
Fairly easy if the exact length of the phrase is known; you just need to use the %var:~0,-3% syntax. Since "_Constant" is 9 chars long, you would want %var:~0,-9%, which takes text from the start (0) to 9 chars from the end (-9). Aditionally, delayed variable expansion also must be enabled with setlocal ENABLEDELAYEDEXPANSION for this to be run inside of your For loop.
Here's a full example:
#Echo off
setlocal ENABLEDELAYEDEXPANSION
for /R %%X in (*_Constant.Xml) do (
set FileNameTemp=%%~nX
echo !FileNameTemp:~0,-9!
)
Note that if you have a file named just _Constant.xml, this will produce "ECHO is off." rather than "" (no output). This can be solved by changing echo !FileNameTemp:~0,-9! to echo. !FileNameTemp:~0,-9!, but that puts a space before each output.
Here's the loop alone:
for /R %%X in (*_Constant.Xml) do (
set FileNameTemp=%%~nX
echo !FileNameTemp:~0,-9!
)
This question already has answers here:
Set output of a command as a variable (with pipes) [duplicate]
(6 answers)
Closed 7 years ago.
I need to run a simple find command and redirect the output to a variable in a Windows Batch File.
I have tried this:
set file=ls|find ".txt"
echo %file%
But it does not work.
If I run this command it works without problems:
set file=test.txt
echo %file%
So obviously my command output is not being set to my variable. Can anyone help? Thanks
I just find out how to use commands with pipes in it, here's my command (that extracts the head revision of an svn repo) :
SET SVN_INFO_CMD=svn info http://mySvnRepo/MyProjects
FOR /f "tokens=1 delims=" %%i IN ('%SVN_INFO_CMD% ^| find "Revision"') DO echo %%i
First of all, what you seem to expect from your question isn't even possible in UNIX shells. How should the shell know that ls|find foo is a command and test.txt is not? What to execute here? That's why UNIX shells have the backtick for such things. Anyway, I digress.
You can't set environment variables to multi-line strings from the shell. So we now have a problem because the output of ls wouldn't quite fit.
What you really want here, though, is a list of all text files, right? Depending on what you need it's very easy to do. The main part in all of these examples is the for loop, iterating over a set of files.
If you just need to do an action for every text file:
for %%i in (*.txt) do echo Doing something with "%%i"
This even works for file names with spaces and it won't erroneously catch files that just have a .txt in the middle of their name, such as foo.txt.bar. Just to point out that your approach isn't as pretty as you'd like it to be.
Anyway, if you want a list of files you can use a little trick to create arrays, or something like that:
setlocal enabledelayedexpansion
set N=0
for %%i in (*.txt) do (
set Files[!N!]=%%i
set /a N+=1
)
After this you will have a number of environment variables, named Files[0], Files[1], etc. each one containing a single file name. You can loop over that with
for /l %%x in (1,1,%N%) do echo.!Files[%%x]!
(Note that we output a superfluous new line here, we could remove that but takes one more line of code :-))
Then you can build a really long line of file names, if you wish. You might recognize the pattern:
setlocal enabledelayedexpansion
set Files=
for %%i in (*.txt) do set Files=!Files! "%%i"
Now we have a really long line with file names. Use it for whatever you wish. This is sometimes handy for passing a bunch of files to another program.
Keep in mind though, that the maximum line length for batch files is around 8190 characters. So that puts a limit on the number of things you can have in a single line. And yes, enumerating a whole bunch of files in a single line might overflow here.
Back to the original point, that batch files have no way of capturing a command output. Others have noted it before. You can use for /f for this purpose:
for /f %%i in ('dir /b') do ...
This will iterate over the lines returned by the command, tokenizing them along the way. Not quite as handy maybe as backticks but close enough and sufficient for most puposes.
By default the tokens are broken up at whitespace, so if you got a file name "Foo bar" then suddenly you would have only "Foo" in %%i and "bar" in %%j. It can be confusing and such things are the main reason why you don't ever want to use for /f just to get a file listing.
You can also use backticks instead of apostrophes if that clashes with some program arguments:
for /f "usebackq" %%i in (`echo I can write 'apostrophes'`) do ...
Note that this also tokenizes. There are some more options you can give. They are detailed in the help for command.
set command has /p option that tells it to read a value from standard input. Unfortunately, it does not support piping into it, but it supports reading a value from a first line of existing file.
So, to set your variable to the name of a first *.txt file, you could do the following:
dir /b *.txt > filename.tmp
set /p file=< filename.tmp
del /q filename.tmp
It is important not to add a space before or even after =.
P. S. No fors, no tokens.
Here's a batch file which will return the last item output by find:
#echo off
ls | find ".txt" > %temp%\temp.txt
for /f %%i in (%temp%\temp.txt) do set file=%%i
del %temp%\temp.txt
echo %file%
for has a syntax for parsing command output, for /f "usebackq", but it cannot handle pipes in the command, so I've redirected output to a temporary location.
I strongly recommend, given that you have access to ls, that you consider using a better batch language, such as bash or even an scripting language like python or ruby. Even bash would be a 20x improvement over cmd scripting.
The short answer is: Don't!
A windows shell env var can hold a max of 32 Kb and it isn't safe to save output from programs in them.
That's why you can't. In batch script you must adopt another programming style. If you need all of the output
from the program then save it to file. If you only need to check for certain properties then pipe the output into
a program that does the checking and use the errorlevel mechanism:
#echo off
type somefile.txt | find "somestring" >nul
if %errorlevel% EQU 1 echo Sorry, not found!
REM Alternatively:
if errorlevel 1 echo Sorry, not found!
However, it's more elegant to use the logical operators Perl style:
#echo off
(type somefile.txt | find "somestring" >nul) || echo Sorry, not found!
It's not available in DOS, but in the Windows console, there is the for command. Just type 'help for' at a command prompt to see all of the options. To set a single variable you can use this:
for /f %%i in ('find .txt') do set file=%%i
Note this will only work for the first line returned from 'find .txt' because windows only expands variable once by default. You'll have to enable delayed expansion as shown here.
what you are essentially doing is listing out .txt files. With that, you can use a for loop to over dir cmd
eg
for /f "tokens=*" %%i in ('dir /b *.txt') do set file=%%i
or if you prefer using your ls, there's no need to pipe to find.
for /f "tokens=*" %%i in ('ls *.txt') do set file=%%i
Example of setting a variable from command output:
FOR /F "usebackq" %%Z IN ( `C:\cygwin\bin\cygpath "C:\scripts\sample.sh"` ) DO SET BASH_SCRIPT=%%Z
c:\cygwin\bin\bash -c '. ~/.bashrc ; %BASH_SCRIPT%'
Also, note that if you want to test out the FOR command in a DOS shell, then you need only use %Z instead of %%Z, otherwise it will complain with the following error:
%%Z was unexpected at this time.