Get only the files included in a directory in c / Ubuntu - c

Question

I have to create a listing of the files contained inside a specific directory, I have done the code below(part of a bigger programm), but I would like my programm to ignore any possible folders that could be included inside the directory.
#include <stdio.h>
#include <sys/types.h>
#include <dirent.h>
int main ()
{
DIR *dirptr;
struct dirent *entry;
dirptr = opendir ("synchedFolder");
if (dirptr != NULL)
{
while (entry = readdir (dirptr))
{
if(strcmp(entry->d_name,"..")!=0 && strcmp(entry->d_name,".")!=0)
puts (entry->d_name);
}
(void) closedir (dirptr);
}
else
perror ("ERROR opening directory");
}

Answer 1

If you want to list only files, but no directories, you have to add the following check:
entry->d_type == DT_REG
or
entry->d_type != DT_DIR

Answer 2

There's stat() and lstat() and the return value for stat. In the latter, look out for the S_ISDIR macro.

Answer 3

Short answer is the dirent structure includes the necessary information:
if ( entry->d_type == DT_REG)

Answer 4

Check stat (or lstat)
#include <stdio.h>
#include <stdlib.h>
#include <sys/types.h>
#include <sys/stat.h>
/* int main (void){ */
int main (int argc, char **argv){
int i,result=0;
struct stat buf;
/* print_S_I_types(); */
for (i=1; i < argc; i++){
if (lstat(argv[i], &buf) < 0) {
fprintf(stderr, "something went wrong with %s, but will continue\n",
argv[i]);
continue;
} else {
if S_ISREG(buf.st_mode){
printf("argv[%d] is normal file\n",i);
}else {
printf("argv[%d] is not normal file\n",i);
}
}
}
return 0;
}

Answer 5

Working code for listing files (without directories):
#include <stdio.h>
#include <dirent.h>
#include <stdlib.h>
int main()
{
DIR *dir;
struct dirent *ent;
if ((dir = opendir ("/home/images")) != NULL)
{
/* print all the files and directories within directory */
while ((ent = readdir (dir)) != NULL)
{
if(ent->d_type!= DT_DIR)
{
printf ("%s\n", ent->d_name);
}
}
closedir (dir);
}
else
{
/* could not open directory */
perror ("");
return EXIT_FAILURE;
}
}