I am implementing an application, and if I click on a menu item:
<MenuItem Name="menuAlgemeneGeg" Header="Algemene gegevens" Click="AlgemeneGegevensClick" />
the method is :
private void AlgemeneGegevensClick(object sender, RoutedEventArgs e)
{
ToetsBeheerViewModel vm = (ToetsBeheerViewModel)this.DataContext;
EditAlgemeneGegevens window = new EditAlgemeneGegevens(vm.Examination);
window.ShowDialog();
menuAlgemeneGeg.IsEnabled = false;
}
Now what I want is, that when you click on it the menuitem is disabled. But from the moment the user closes this window it must be enabled again. I can disable the menuitem but can't change this back to enable it.
Someone who can help me out please?
you can handle window closed event.. and enable menu in even handler
private void AlgemeneGegevensClick(object sender, RoutedEventArgs e)
{
ToetsBeheerViewModel vm = (ToetsBeheerViewModel)this.DataContext;
EditAlgemeneGegevens window = new EditAlgemeneGegevens(vm.Examination);
window.Closed += new EventHandler(Window_Closed);
window.ShowDialog();
menuAlgemeneGeg.IsEnabled = false;
}
void Window_Closed(object sender, EventArgs e)
{
menuAlgemeneGeg.IsEnabled = true;
}
Related
I know how to subscribe to the CoreWebview2.DownloadStarting event and use handled = true to stop the Download dialog from showing while a download (i.e. an image) is being made, but the problem is the DownloadStarting event never fires if you right click on a web page and choose "Save as" or "Print > Save as PDF", even though the Download dialog will appear as if a regular download was being made. Does anyone know any workaround for this?
My code:
public Form1()
{
InitializeComponent();
}
private async void button1_Click(object sender, EventArgs e)
{
if (webView != null)
webView.Dispose();
webView = new WebView2();
await webView.EnsureCoreWebView2Async();
webView.CoreWebView2.DownloadStarting += CoreWebView2_DownloadStarting;
panel1.Controls.Add(webView);
webView.Dock = DockStyle.Fill;
webView.Source = new Uri("https://www.microsoft.com");
}
private void CoreWebView2_DownloadStarting(object sender, CoreWebView2DownloadStartingEventArgs e)
{
e.Handled = true;
}
I just found a solution:
subscribe to CoreWebView2.IsDefaultDownloadDialogOpenChanged event:
webView.CoreWebView2.IsDefaultDownloadDialogOpenChanged += webView_CoreWebView2_IsDefaultDownloadDialogOpenChanged;
Close the Download dialog if it's open:
private void webView_CoreWebView2_IsDefaultDownloadDialogOpenChanged(object sender, object e)
{
if (webView.CoreWebView2.IsDefaultDownloadDialogOpen) webView.CoreWebView2.CloseDefaultDownloadDialog();
}
I am developing windows form chat application and i am writing message in richtextbox but when i click on send button and every message show in webbrowser control. .i want to add webbrowser control dynamically for individual message is send.i am using following code:
namespace WindowsFormsApplication1
{
[ComVisible(true)]
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
// this.w1.DocumentCompleted += new WebBrowserDocumentCompletedEventHandler(w1_DocumentCompleted);
}
WebBrowser w1 = new WebBrowser();
private void button1_Click(object sender, EventArgs e)
{
this.Controls.Add(w1);
HtmlElement div = w1.Document.GetElementById("abc");
div.InnerHtml = richTextBox1.Text;
}
private void Form1_Load(object sender, EventArgs e)
{
w1.Navigate(Path.Combine(Environment.CurrentDirectory, "HTMLPageForScripting.htm"));
}
}
}
Here is the case you asked for:
Add a Panel to form to put browser in and set its autoscroll property to true;
In button1 Click event, create browser, set its width and height, and navigate to the document you want.
In button1 Click event subscribe for DocumentCompleted event and add content there. We do add here because we should be sure all contents containing <div id="abc"></div>has been loaded.
Here is code:
private void button1_Click(object sender, EventArgs e)
{
var browser = new WebBrowser();
browser.Height = 100;
browser.Dock = DockStyle.Top;
browser.Navigate(#"D:\test.html");
browser.DocumentCompleted += browser_DocumentCompleted;
this.panel1.Controls.Add(browser);
//Just do it to put it at the end of list and scroll to it
browser.BringToFront();
this.panel1.ScrollControlIntoView(browser);
}
void browser_DocumentCompleted(object sender, WebBrowserDocumentCompletedEventArgs e)
{
var browser = (WebBrowser)sender;
HtmlElement div = browser.Document.GetElementById("abc");
div.InnerHtml = richTextBox1.Text;
}
How would I be able to submit events manually to be received by InkCanvas ?
What I need to do, is to set the mode of InkCanvas to ink mode, and then, send virtual events to InkCanvas so that I get a drawing behavior as if user used the real mouse.
Thanks
The following code snippet shows an example of drawing a shape in InkCanvas:
StylusPointCollection stroke1Points = new StylusPointCollection();
stroke1Points.Add(new StylusPoint(50,10));
stroke1Points.Add(new StylusPoint(90,50));
stroke1Points.Add(new StylusPoint(10,50));
stroke1Points.Add(new StylusPoint(50,10));
Stroke stroke1 = new Stroke(stroke1Points);
canvas.Strokes.Add(stroke1);
Where canvas is of type InkCanvas. The above generates a triangle in the canvas.
"And yes, you may accept the answer if it helps you."
Something like this?
private void inkSurface_MouseLeftButtonDown(object sender, MouseButtonEventArgs e)
{
inkSurface.CaptureMouse();
_inkStroke = new Stroke(
e.StylusDevice.GetStylusPoints(inkSurface));
_inkStroke.DrawingAttributes.Width = 5;
_inkStroke.DrawingAttributes.Height = 5;
_inkStroke.DrawingAttributes.Color = Colors.Black;
inkSurface.Strokes.Add(_inkStroke);
e.Handled = true;
}
private void inkSurface_MouseMove(object sender, MouseEventArgs e)
{
if (_inkStroke != null)
{
_inkStroke.StylusPoints.Add(
e.StylusDevice.GetStylusPoints(inkSurface));
}
e.Handled = true;
}
private void inkSurface_MouseLeftButtonUp(object sender, MouseButtonEventArgs e)
{
inkSurface.ReleaseMouseCapture();
e.Handled = true;
}
I have a problem again. when I click button, window appears. when I click button again same window appears again. I want when I click button first time, page appears. but I want to prevent second click. can anyone help me with this problem? thanks in advance.
private void Dictionary_Click(object sender, RoutedEventArgs e)
{
Dictionary dic = new Dictionary();
dic.Show();
dic.Topmost = true;
}
set a simple boolean value to check if the window is already open?
private bool isWindowAlreadyOpen = false;
private void Dictionary_Click(object sender, RoutedEventArgs e)
{
if (!isWindowAlreadyOpen)
{
Dictionary dic = new Dictionary();
dic.Show();
dic.Topmost = true;
isWindowAlreadyOpen = true;
}
}
Should do the trick.
EDIT
You'll have to register the closed event of the window to unset the boolean:
private bool isWindowAlreadyOpen = false;
private void Dictionary_Click(object sender, RoutedEventArgs e)
{
if (!isWindowAlreadyOpen)
{
Dictionary dic = new Dictionary();
dic.Show();
dic.Topmost = true;
dic.Closed += Dictionary_Closed;
isWindowAlreadyOpen = true;
}
}
private void Dictionary_Closed(object sender, EventArgs e)
{
isWindowAlreadyOpen = false;
}
EDIT2
Alternatively, you can use dic.ShowDialog() if you want this window to be topmost and only one instance.
I have to handle both the single click and the double click of a button in a WPF application with different reaction.
Unfortunately, on a doubleclick, WPF fires two click event and a double click event, so it's hard to handle this situation.
It tried to solve it using a timer but without success...I hope you can help me.
Lets see the code:
private void delayedBtnClick(object statInfo)
{
if (doubleClickTimer != null)
doubleClickTimer.Dispose();
doubleClickTimer = null;
this.Dispatcher.Invoke(System.Windows.Threading.DispatcherPriority.Normal, new VoidDelegate(delegate()
{
// ... DO THE SINGLE CLICK ACTION
}));
}
private void btn_Click(object sender, RoutedEventArgs e)
{
if (doubleClickTimer == null)
doubleClickTimer = new Timer(delayedBtnClick, null, System.Windows.Forms.SystemInformation.DoubleClickTime, Timeout.Infinite);
}
}
}
private void btnNext_MouseDoubleClick(object sender, MouseButtonEventArgs e)
{
if (doubleClickTimer != null)
doubleClickTimer.Change(Timeout.Infinite, Timeout.Infinite); // disable it - I've tried it with and without this line
doubleClickTimer.Dispose();
doubleClickTimer = null;
//.... DO THE DOUBLE CLICK ACTION
}
The problem is that the 'SINGLE CLICK ACTION' called after the 'DOUBLE CLICK ACTION' on doubleclick. It's strange that I set thedoubleClickTimer to null on double click but in the delayedBtnClick it's true :O
I've already tried to use longer time, a bool flag and lock...
Do you have any ideas?
Best!
If you set the RoutedEvent's e.Handled to true after handling the MouseDoubleClick event then it will not call the Click Event the second time after the MouseDoubleClick.
There's a recent post which touches on having different behaviors for SingleClick and DoubleClick which may be useful.
However, if you are sure you want separate behaviors and want/need to block the first Click as well as the second Click, you can use the DispatcherTimer like you were.
private static DispatcherTimer myClickWaitTimer =
new DispatcherTimer(
new TimeSpan(0, 0, 0, 1),
DispatcherPriority.Background,
mouseWaitTimer_Tick,
Dispatcher.CurrentDispatcher);
private void Button_MouseDoubleClick(object sender, MouseButtonEventArgs e)
{
// Stop the timer from ticking.
myClickWaitTimer.Stop();
Trace.WriteLine("Double Click");
e.Handled = true;
}
private void Button_Click(object sender, RoutedEventArgs e)
{
myClickWaitTimer.Start();
}
private static void mouseWaitTimer_Tick(object sender, EventArgs e)
{
myClickWaitTimer.Stop();
// Handle Single Click Actions
Trace.WriteLine("Single Click");
}
You could try this:
Button.MouseLeftButtonDown += Button_MouseLeftButtonDown;
private void Button_MouseLeftButtonDown(object sender, MouseButtonEventArgs e)
{
e.Handled = true;
if (e.ClickCount > 1)
{
// Do double-click code
}
else
{
// Do single-click code
}
}
If neccessary, you could require mouse click and wait until mouse up to perform the action.