#include < stdio.h >
int main() {
char *s;
s=call();
printf(s);
}
char* call() {
return("hello");
}
Why these code not working. It's generating an error. How do I make it work?
Two things:
You can't put spaces inside the angle brackets when including a system header (e.g. #include <stdio.h>
You need a prototype for call()
Related
I'm attempting to learn the remove() function in C, and I want to make a program with first gets the environmental variable with getenv() function, then uses it inside the code.
However, I get the error
"too many arguments to function remove()".
#include <stdio.h>
#include <stdlib.h>
int main()
{
char* a = getenv("USERPROFILE");
remove("%s/Desktop/remove.txt", a);
return 0;
}
If you are simply trying to combine them this should work.
I commented out some lines and put a printf so you can run it to see the result.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAXPATH 256
int main()
{
//char* a = getenv("USERPROFILE");
char* a = "userprofile";
char path[MAXPATH];
strcpy(path,a);
strcat(path,"/Desktop/remove.txt");
//remove(path);
printf("PATH: %s",path);
return 0;
}
Say I have a library I am making and I want to call a function rename or puts, how can I keep the original rename and puts from stdlib or stdio or whatever, and yet have my own function be puts?
#include <stdio.h>
alias puts original_puts;
void
puts(char *c) {
original_puts(c);
}
How can I accomplish something to this effect?
You can't alias library functions, but you can alias your own using preprocessor directives.
For example:
mylib.h:
#include <stdio.h>
void my_puts(char *c);
#define puts(arg) my_puts(arg)
mylib.c:
void my_puts(char *c)
{
(puts)(c);
}
Now, anytime someone calls puts, it substitutes a call to my_puts instead. Also, when you want to call the "real" function in your wrapper, you can put the function name in quotes. Because the macro that does the substitution is a function-like macro, the parenthesis prevent the substitution from happening.
If compiling with gcc or clang, you can wrap the symbol with -Wl,--wrap:
#include <stdio.h>
#include <time.h>
#include <stdlib.h>
int __real_puts(const char *c);
int __wrap_puts(const char *c) {
__real_puts("Hello");
__real_puts(c);
return 0;
}
int main(int argc, char const *argv[]) {
puts("world");
}
$ gcc src.c -Wl,--wrap=puts && ./a.out
Hello
world
Hello folks out there,
this is my code:
main.c
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "sqlite3.h"
#include "db_typedefs.h"
#include "operations.h"
int main(){
printf("Text\n");
int f = 3;
void add_mini(3);
}
operations.h
#ifndef ADD_OPERATIONS_H_INCLUDED
#define ADD_OPERATIONS_H_INCLUDED
void add_mini(int flag);
#endif // ADD_OPERATIONS_H_INCLUDED
operations.c
void add_mini(int flag)
{
int rc;
rc = flag;
printf("%i\n", rc);
}
Operations.c has also libraries included similar to main.c.
Compiler Error
error: expected declaration specifiers or '...' before numeric constant
regarding to void add_mini(3)
It seems like I'm unable to pass a simple integer value. While debugging it's even skipping the add_mini line.
Do you have any idea what's going on?
The whole code is embedded in a larger query to determine typed orders but this works fine. I just can't pass this simple integer value.
Thanks in advance.
When you use
void add_mini(3);
the compiler thinks it is a function declaration, not a function call. The argument 3 is not valid for a function declaration. Hence, the compiler complains.
Remove the void part to call the function.
int main(){
printf("Text\n");
int f = 3;
add_mini(3);
}
or, since you have initialized f to 3,
int main(){
printf("Text\n");
int f = 3;
add_mini(f);
}
Call the function like so: add_mini(3); rather than void add_mini(3);
Remove the word void for calling add_mini from main.c :
add_mini(3);
Or
(void)add_mini(3);
Eclipse tells me that I have mutliple Definitions of a function.
I just can't spot the mistake.
This is my main.c
#include <stdio.h>
#include "kontaktverzeichnis.h"
int main(){
kontakt_hinzufuegen();
return 0;
}
This is the header:
#ifndef KONTAKTVERZEICHNIS_H_
#define KONTAKTVERZEICHNIS_H_
#include "kontaktfunktionen.c"
int kontakt_hinzufuegen();
#endif /* KONTAKTVERZEICHNIS_H_ */
and this is kontaktfunktionen.c
#include <stdio.h>
kontakt[];
kontakt_hinzufuegen(){
int i = 0;
printf("Bisher sind %i Kontakte angelegt.",kontakt[i]);
kontakt[i++];
}
struct kontaktname{
char* name;
char* vorname;
};
struct kontaktanschrift{
char* strasse;
int hausnummer;
int plz;
char* ort;
char* land;
};
Where is my error?
You're not supposed to #include C files, that's not the proper way to organize your code.
You should compile the C files separately and then link them together, or compile them all at once with a single compiler invocation.
Do not #include anything in your header file. And do a #include "kontaktverzeichnis.h" in the kontaktfunktionen.c file.
As #StoryTeller commented, define your kontakt_hinzufuegen() as int kontakt_hinzufuegen() in the kontaktfunktionen.c file and return an int value from the function kontakt_hinzufuegen as for ex::
#include <stdio.h>
#include "kontaktverzeichnis.h"
// define the type for this array as below
int kontakt[];
int kontakt_hinzufuegen(){
int i = 0;
printf("Bisher sind %i Kontakte angelegt.",kontakt[i]);
kontakt[i++];
// Return an int value
return 0 ;
}
Your error is that in kontaktfunktionen.h you are including kontaktfunktionen.c. This will include all the definitions and declarations from kontaktfunktionen.c which are already declared when you use kontaktfunktionen.c
As others have said: You should not include .c files in your header files.
I am trying to learn creating header file in C and including it in my main.c func() . I created a simple tut1.c file with function named call() and a tut1.h header file which externs tut1.c function named call(). Thats it, now i am using eclipse Juno for C/C++ on linux fedora. I dont get any compile error but the code wont output? I tried on console and eclipse in vain. Can you check please? Thanks
---main.c-----
#include <stdlib.h>
#include <string.h>
#include <stdio.h>
#include "tut1.h"
int main (void)
{
int tut1(void);
return 0;
}
-----tut1.c------
#include <stdio.h>
#include <stdlib.h>
#include "tut1.h"
int call (void)
{
int *ptr;
int i;
ptr = &i;
*ptr = 10;
printf ("%d we are printing the value of &i\n", &i);
printf ("%d we are printing the value of *ptr\n", *ptr);
printf ("%d we are printing the value of ptr\n", ptr);
printf ("%d we are printing the value of &ptr\n", &ptr);
getchar();
return 0;
}
----tut1.h----
#ifndef TUT1_H_
#define TUT1_H_
extern int call (void);
#endif
You're not seeing anything because you're not calling the call() function from your main() function.
The main() function is the default entry point when you run the program, i.e. the first function that gets called during execution.
To execute the function call() you would need to call this from main() as follows :
int main (void)
{
int result = call();
return 0;
}
BTW, this line int tut1(void); within your main() just declares a function, which you do not seem to have defined anywhere. So I have removed it in the above shown code.