I need to retrieve the mysql connection settings and store them as variables. I know that the file configuration.php contains what I need. I just don't know how to call it accurately. Here are the 4 variables (and associate values) that I need:
1) $host = public $host from config file
2) $user = public $user from config file
3) $password = public $password from config file
4) $db_name = public $db from config file
$info =& JFactory::getApplication();
$info->getCfg('host');
$info->getCfg('user');
$info->getCfg('db');
// defined in libraries/joomla/application/application.php (380)
function getCfg( $varname ) {
$config =& JFactory::getConfig();
return $config->getValue('config.' . $varname);
}
looking at the code in joomla application you can also do the following :
$config =& JFactory::getConfig();
and get most if the info you want .
Related
Using Cake version 2.4.3 stable
So I am having a time here, I have modified this plug in to save files to the app folder https://github.com/srs81/CakePHP-AjaxMultiUpload/
The uploaded files are being saved to /public_html/app/files
Now the strange thing is, when trying to serve these files to the view, I can read the file name, the file size, but not the file itself, image, pdf, etc.
When I try to access the file via direct url, i get this error :
Error: FilesController could not be found.
How can it be that I can read the file name, the file size, but not the file itself?
There is a need to save the files in the app folder. These files should be protected and therefore only be accessed by users who are logged into the application. I have tried to use cake send file response with no outcome.
Edit : I guess the real question at hand here is how can I read files from APP . DS . 'files' ?
View code :
public function view ($model, $id, $edit=false) {
$results = $this->listing ($model, $id);
$directory = $results['directory'];
$baseUrl = $results['baseUrl'];
$files = $results['files'];
$str = "<dt>" . __("Pictures") . "</dt>\n<dd>";
$count = 0;
$webroot = Router::url("/") . "ajax_multi_upload";
foreach ($files as $file) {
$type = pathinfo($file, PATHINFO_EXTENSION);
$filesize = $this->format_bytes (filesize ($file));
$f = basename($file);
$url = $baseUrl . "/$f";
if ($edit) {
$baseEncFile = base64_encode ($file);
$delUrl = "$webroot/uploads/delete/$baseEncFile/";
$str .= "<a href='$delUrl'><img src='" . Router::url("/") .
"ajax_multi_upload/img/delete.png' alt='Delete' /></a> ";
}
$str .= "<img src='$url' /> ";
$str .= "<a href='$url'>" . $f . "</a> ($filesize)";
$str .= "<br />\n";
}
$str .= "</dd>\n";
return $str;
}
And the upload / save
public function upload($dir=null) {
// max file size in bytes
$size = Configure::read ('AMU.filesizeMB');
if (strlen($size) < 1) $size = 20;
$relPath = Configure::read ('AMU.directory');
if (strlen($relPath) < 1) $relPath = "files";
$sizeLimit = $size * 1024 * 1024;
$this->layout = "ajax";
Configure::write('debug', 0);
$directory = APP . DS . $relPath;
if ($dir === null) {
$this->set("result", "{\"error\":\"Upload controller was passed a null value.\"}");
return;
}
// Replace underscores delimiter with slash
$dir = str_replace ("___", "/", $dir);
$dir = $directory . DS . "$dir/";
if (!file_exists($dir)) {
mkdir($dir, 0777, true);
}
$uploader = new qqFileUploader($this->allowedExtensions,
$sizeLimit);
$result = $uploader->handleUpload($dir);
$this->set("result", htmlspecialchars(json_encode($result), ENT_NOQUOTES));
}
The only real change from the original plug in is changing WWWROOT to APP to make the switch. Saving works fine and lovely. But its just weird that I can read the file name, file size in the view no problem but cannot view an image, pdf, etc.
The problem:
You cannot display files that are outside the webroot via a direct URL - that's the whole point in putting them above the webroot in the first place - to make them NOT directly accessible.
So building the image src path in the controller first (not good practice anyway) won't change the fact that when that path gets to the browser, and it reads the source of the image as trying to pull an image from above webroot, it won't/can't.
The Solution:
The solution is to use a CakePHP's Sending files (what used to be Media Views). Then, you set your img's "src" to a controller/action. In that action, it basically says "display this action as an image" (or pdf, or whatever else).
Path to use in Controller:
took this from one of my apps which is doing exactly the above, and here's the path I used for a file in 'files' (same level as webroot):
file_exists(APP . 'files' . DS . $your_filename)
Create a symbolic link to your folder inside of the webroot ;-)
Ok, I'm trying to File & Folder classes as specified here:
http://book.cakephp.org/2.0/en/core-utility-libraries/file-folder.html#
My Folder Controller looks like this:
<?php
App::uses('AppController', 'Controller');
App::uses('Folder', 'Utility');
App::uses('File', 'Utility');
class FolderController extends AppController {
public $uses = array();
public function display() {
$dir = '/var/www/html/letters/pdfdir/';
$files = $dir->find('.*\.pdf', true);
foreach ($files as $file) {
$file = new File($dir->pwd() . DS . $file);
$contents = $file->read();
echo 'CONTENT: '.$contents;
// $file->write('I am overwriting the contents of this file');
// $file->append('I am adding to the bottom of this file.');
// $file->delete(); // I am deleting this file
$file->close(); // Be sure to close the file when you're done
}
}
}
but I get the following error:
Error: Call to a member function find() on a non-object
File: /var/www/html/letters/app/Controller/FolderController.php
Line: 13
Any help appreciated.
Regards
You have a mistake
$dir = '/var/www/html/letters/pdfdir/';
should be
$dir = new Folder('/var/www/html/letters/pdfdir');
In your original code $dir is just a variable of string type. However, it should be an object of Folder class.
Another note: you have to remove the trailing slash.
$dir is still a string, you need to pass it to a File or Folder object to become usable as an object.
I understand there are MANY ways to do all of this, but trying to do it the best way.
I have created the db parameters, dns, dbh, sth, sql and generally quite happy with the result up to ... well ... the result part.
<?php
// db parameters
$dbhost = "localhost";
$dbname = "x";
$dbuser = "y";
$dbpass = "z";
// driver invocation (dsn is short for data source name)
$dsn = "mysql:host=$dbhost;dbname=$dbname";
// create db object (dbh is short for database handle)
$dbh = new PDO($dsn, $dbuser, $dbpass);
// execution of database query (sth is short for statement handle)
$sql = "SELECT * FROM a_aif_remaining";
$sth = $dbh->prepare($sql);
$sth->execute();
NOT SURE WHAT TO PUT BELOW.... (A) or (B)
I just want to present a simple array of the data. One row from the table per line.
Option A
echo $_POST['fieldname1'];
echo $_POST['fieldname2'];
echo $_POST['fieldname3'];
Option B
while ($rows = $sth->fetch(PDO::FETCH_ASSOC)) {
echo $row[fieldname1],'<br>';
}
AND I AM CONFIDENT WITH THE ENDING
$dbh = NULL;
?>
Any advise would be GREATLY appreciated.
UPDATED CODE: (Produces nothing on the page)
<?php
// db parameters
$dbhost = "localhost";
$dbname = "theaudit_db1";
$dbuser = "theaudit_user";
$dbpass = "audit1999";
$dsn = "mysql:host=$dbhost;dbname=$dbname"; // driver invocation (dsn is short for Data Source Name)
try {
$dbh = new PDO($dsn, $dbuser, $dbpass); // connect to new db object (dbh is short for Database Handle)
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); // set the PDO error mode to enable exceptions
$dbh->setAttribute(PDO::ATTR_EMULATE_PREPARES, false); // set the PDO emulate prepares to false
// execute query to database (sth is short for Statement Handle)
$sql = "SELECT * FROM a_aif_remaining";
$sth = $dbh->prepare($sql);
$sth->execute();
$data = $sth->fetchAll(PDO::FETCH_ASSOC);
$dbh = NULL;
}
catch(PDOException $e)
{
echo $e->getMessage();
}
?>
Though I can't get what's the connection between A anb B, I can answer the
I just want to present a simple array of the data. One row from the table per line.
question.
$sql = "SELECT * FROM a_aif_remaining";
$sth = $dbh->prepare($sql);
$sth->execute();
$data = $sth->fetchAll(PDO::FETCH_ASSOC);
where $data is a sought-for array.
The problem with your updated code is simple - you arent echo'ing your data out. You need to add something like..
foreach($data as $arKey=>$dataRow){
foreach($dataRow as $arKey=>$rowField){
echo $rowField.','; //concat with a ',' to give csv like output
}
echo '<br>'; //to get to next line for each row (may want to trim the last ','
}
I am also confused by the reference to $_POST. It is true both are associate arrays but that does not mean that the $_POST option is viable - the data would only be available in the $_POST if you put it there (eg $_POST = $data) which would be pointless. Or if you had posted the data from somewhere else. Neither seem to fit what you are asking so I would forget about the $_POST and just figure out how you access your multi dimensional $data array. There is endless tut's on this subject. Try using
var_dump($data)
to see whats inside that should help you visualise what is going on.
NOTE: in option B you are not correctly concatenating or referencing your array it should be:
while ($rows = $sth->fetch(PDO::FETCH_ASSOC)) {
echo $rows[fieldname1].'<br>'; //$row doesnt exist its $rows and you use . to concat not ,
}
Ah yes and probably better to use unset rather than setting $dbh to equal null
unset($dbh);
I'm trying to make a query to a database in Joomla 2.5. I have a db named 'example', and I'm trying to get certain value named 'value' (very original) for a user whose id is 949:
$db =& JFactory::getDBO();
$query = $db->getQuery(true);
$user = 949;
$db->setQuery( 'SELECT value FROM example WHERE user_id = ' . $user );
$result = $db->loadObjectList();
echo $result;
However, I'm just getting 'Array' as result (the expected value is a decimal, e.g. 4.5).
Could someone please tell me what am I doing wrong?
$db =& JFactory::getDBO();
$query = $db->getQuery(true);
$user = 949;
$db->setQuery( "SELECT value FROM example WHERE user_id = '" . $user."'" );
$result = $db->loadObjectList();
echo $result;
try this one
$db->loadObjectList() returns an array of objects, which echo can't display. If you want to just return one value from one row, user $db->loadResult() instead.
# Cron Job for Cakephp #
I have create 1 file cron_scheduler.php which is copy of wamp/www/projectname/app/webroot/index.php file and it is also in the same folder
i have tried to run throw command prompt but didn't get any result.
how to run cronjob for Cakephp ? i don't have any idea
if anyone knows , please help me.
Thanks in advance.
<?php
if (!defined('DS')) {
define('DS', DIRECTORY_SEPARATOR);
}
/**
* These defines should only be edited if you have cake installed in
* a directory layout other than the way it is distributed.
* Each define has a commented line of code that explains what you
would change.
*
*/
if (!defined('ROOT')) {
//define('ROOT', 'FULL PATH TO DIRECTORY WHERE APP DIRECTORY IS
//LOCATED DO NOT ADD A TRAILING DIRECTORY SEPARATOR';
//You should also use the DS define to seperate your directories
define('ROOT', dirname(dirname(__FILE__)));
}
if (!defined('APP_DIR')) {
//define('APP_DIR', 'DIRECTORY NAME OF APPLICATION';
define('APP_DIR', basename(dirname(__FILE__)));
}
/**
* This only needs to be changed if the cake installed libs are located
* outside of the distributed directory structure.
*/
if (!defined('CAKE_CORE_INCLUDE_PATH'))
{
//define ('CAKE_CORE_INCLUDE_PATH', FULL PATH TO DIRECTORY WHERE
//CAKE CORE IS INSTALLED DO NOT ADD A TRAILING DIRECTORY SEPARATOR';
//You should also use the DS define to seperate your directories
define('CAKE_CORE_INCLUDE_PATH', ROOT);
}
///////////////////////////////
//DO NOT EDIT BELOW THIS LINE//
///////////////////////////////
if (!defined('WEBROOT_DIR'))
{
define('WEBROOT_DIR', 'webroot');
}
if (!defined('WWW_ROOT')) {
//define('WWW_ROOT', dirname(__FILE__) . DS);
define('WWW_ROOT', dirname(__FILE__) . DS . 'webroot' . DS);
}
if (!defined('CORE_PATH')) {
if (function_exists('ini_set')) {
ini_set('include_path', CAKE_CORE_INCLUDE_PATH .
PATH_SEPARATOR .
ROOT . DS . APP_DIR . DS . PATH_SEPARATOR . ini_get('include_path'));
define('APP_PATH', null);
define('CORE_PATH', null);
} else {
define('APP_PATH', ROOT . DS . APP_DIR . DS);
define('CORE_PATH', CAKE_CORE_INCLUDE_PATH . DS);
}
}
require CORE_PATH . 'cake' . DS . 'bootstrap.php';
define('CRON_DISPATCHER',true);
if($argc == 2)
{
$Dispatcher= new Dispatcher();
$Dispatcher->dispatch($argv[1]);
}
?>
> i have tried to run throw command promt but didn't get any result
> how to run cronjob for Cakephp ? i don't have any idea
if anyone knows , please help me.
Thanks
Step1: Create a shell file with name ReminderShell.php and Path should be PROJECT_DIR_PATH/PROJECT_NAME/app/Console/Command/ReminderShell.php Copy below script and paste it
class ReminderShell extends Shell {
var $tasks = array('Mail');
function main() {
$this->Mail->enroll_reminder();
}
}
Step2: Create Task file with name MailTask.php and path should be PROJECT_DIR_PATH/PROJECT_NAME/app/Console/Command/Task/MailTask.php
<?php
App::uses('CakeEmail', 'Network/Email');
class MailTask extends Shell {
var $uses = array('Contact');
public function enroll_reminder() {
$Email = new CakeEmail();
$Email->config('default');
$reminder = $this->Contact->find('all');
if (!empty($reminder)) {
foreach ($reminder as $val) {
$id = $val['Contact']['id'];
$name = $val['Contact']['first_name'];
$email = $val['Contact']['email'];
$Email->template('reminder')
->viewVars(array('fname' => $name))
->emailFormat('html')
->subject('xyz.com: Enrollment Reminder')
->to($email)
->from('noreply#xyz.com');
if ($Email->send()) {
$update_val['Contact']['id'] = $id;
$update_val['Contact']['enroll_reminder'] = 'sent';
$update_val['Contact']['enroll_reminder_date'] = date("Y-m-d H:i:s");
$this->Contact->save($update_val['Contact']);
$this->out($email.' Mail Sent');
}
}
}
}
Step3: Create a email template with name reminder.ctp and path should be PROJECT_DIR_PATH/PROJECT_NAME/app/View/Emails/html/reminder.ctp
Step4: Create email.php in config directory
Step5: Run below command in Terminal: Console/cake Reminder
PROJECT_DIR_PATH/PROJECT_NAME/app Console/cake Reminder
For complete files checkout from https://github.com/pankajkumarjha2010/cronjob-in-cakephp2.3.x
For cronjobs in CakePHP, you may have a look at http://book.cakephp.org/2.0/en/console-and-shells/cron-jobs.html. This works fine for me.
But please note, sometimes there are not all the environmental parameters available. I ran into this problem when accessing env('HTTP_HOST') within the cronjob methods. But when considering this, it should be no problem.