I tried to list all files and directories on a directory by using this format
dir1:::dir2:::file1:::file2:::
To achieve this, I wrote a batch script. Take a look at it :
#echo off
SETLOCAL ENABLEDELAYEDEXPANSION
SET M=
FOR %%d IN ('dir /B') DO SET M=!M!%%d:::
ECHO %M%
Well, it works for directories/files that doesn't contain spaces, but for those that contained it, it will show just the first word.
For example, suppose the files are "Blue hills.jpg" and "Sunset.jpg".
The expected result is of course
Blue hills.jpg:::Sunset.jpg:::
But what appears instead is
Blue:::Sunset.jpg
FYI, I use WinXP. *Is that matter? I've tried to put quotes in "%%d" but it doesn't work. How can I fix this?
Thanks for the help! And sorry for my bad english, I really have to improve it..
You need to run your for loop for file names containing any text (spaces included) "tokens=*". The /f switch is to search for text (filename text).
#echo off
SETLOCAL ENABLEDELAYEDEXPANSION
SET M=
FOR /f "tokens=*" %%d IN ('dir /B') DO SET M=!M!%%d:::
ECHO %M%
Works for files and directories with spaces.
If you use tokens=1 then you get the first word of each file name (using a space as separator). So you would see
Blue:::Sunset.jpg:::
If you use tokens=2 then you get the second word:
hills.jpg:::
Related
Have a quick question as below:
dir /b *. >>Index.txt
The above command can output all the current directories in a list into text file called index.txt.
However, the list are on the leftmost of each line, can we have some space at the beginning of each output lines at the index.txt?
I am looking for a batch file solution.
Any suggestions?
Depending upon your requirements, you could use something like this:
#(For /F "EOL=|Delims=" %%A In ('Dir /B/AD') Do #Echo %%A)>"Index.txt"
Or perhaps you would prefer to right align it too:
#Echo Off
Set "pad= "
( For /F "EOL=|Delims=" %%A In ('Dir /B/AD') Do ( Set "line=%pad%%%A"
Call Echo=%%line:~-24%%))>"Index.txt"
The latter example may need adjusting according to the number of characters in your directory names.
I have filenames in a directory in the format of Mumbai Short Call Agentwise-MUMBAI SHORT CALL-3-01092016. I would like to strip off everything after the second hyphen and keep the first portion of the filename.
Is there a good website that could direct me in how to accomplish this? Or, maybe one of you dos batch experts can lead me in how to do this?
for /f "tokens=1,2,* delims=-" %%a in ('dir /b *-*-*') do #ECHO ren "%%a-%%b-%%c" "%%a-%%b%%~xc"
for every file with the given mask *-*.*: get first (%%a) and second part (%%b) plus extension of the rest (rest: %%c; Extension of the rest:%%~xc)
Notes:
- if you shorten filenames, be aware of possible duplicates!
#ECHO just lists the rename commands. Remove #ECHO, if the output satisfies you
See for /? or for /f for more information
I have hundreds of csv files . csv files are stored in folders and sub folders . I want to search fifty csv file whose file names have been determined , for example 1.csv , 2.csv , 3.csv , ... , 50.csv . very troublesome if I searched one by one using the Windows search tool . I would like if the files are found , save in the folder named FOUND . please help to overcome this problem by using the batch programming / bat ? thank you very much
There's a number of approaches one can take, depending on how much automation you require... To help you get started, you may want to look at this it helped me (and indeed continues to do so) when I started learning batch. Furthermore I will provide one possible template for achieving your objective, as I have interpreted it. Perhaps it is not the most elegant or efficient method, but it introduces a number of batch commands that you may or may not have encountered, which in turn may help you develop your own method.
#echo off
setlocal enabledelayedexpansion
echo Please enter a drive letter:
set /p "drive=>"
echo Please enter a search string:
set /p "searchstring=>"
echo %searchstring%>search.txt
set /p search=<search.txt
set /a suffix=0
echo.>>search.txt
:LOOP
for /f "tokens=*" %%i in ("search.txt") do (
set /a suffix=suffix+1
set seq=%search% !suffix!
echo !seq!>>search.txt
)
if !suffix! leq 49 goto LOOP
for /f "tokens=*" %%i in (search.txt) do (
for /f "tokens=*" %%j in ('dir /b /s /a-d %drive%:\"%%i.csv" 2^>nul') do (
if not exist "%~dp0\found" md "%~dp0\found"
move /y "%%j" "%~dp0\found\%%~nxj"
)
)
pause
This is not intended as a definitive solution, though you may find it answers your original query/request. All the best.
Here's another working solution for you..
#ECHO OFF
SETLOCAL EnableDelayedExpansion
REM First Set your directories input and output
SET InputDir=C:\Directory to your CSV files\
SET OutputDir=C:\Directory to your CSV files\FOUND
REM check if the FOUND directory exist, if not, then create it.
IF NOT EXIST OutputDir (
mkdir %OutputDir%
)
REM Grab a scan of the input directory and save it to a temporary file list.
Dir /a /b %InputDir%>"%OutputDir%\Found.txt"
REM Set the files you would like to find.
SET "File1=1.csv"
SET "File2=2.csv"
SET "File3=50.csv"
REM The loop, to process the matching file(s).
FOR %%A IN (%File1%,%File2%,%File3%) DO (
FOR /F "usebackq" %%B IN ("%OutputDir%\Found.txt") DO (
IF %%A==%%B (
copy "%InputDir%\%%A" "%OutputDir%\%%A"
)
)
)
REM Clean up the temp file list.
DEL "%OutputDir%\Found.txt"
Make note, I didn't add quotes to the Input and Output variables, but instead added quotes to the copy portion of the code to compensate for white spaces in your directory path. I tried to keep it simple, so you could follow the logic of how it processed what you are looking for, you can now modify this to your liking.. Have fun. Cheers!
I've got some *.Xml files in a directory and its sub-directories. I need to loop through the XML files which have a specific constant at the end of their file name, and then echo/print their names without the constant part nor the extension (.Xml).
For example: these are the file names I have:
FileAAA_Constant.Xml
FileBBB.Xml
FileCCC.Xml
FileDDD_Constant.Xml
And this is the output I need:
FileAAA
FileDDD
I've tried this command:
For /R %%X in (*_Constant.Xml) do echo %%~nX
Which outputs this:
FileAAA_Constant
FileDDD_Constant
As you can see, it has removed the extension only, while I need to remove "_Constant.Xml" as well.
This works if the file names contains only one underscore, as indicated in your example:
for /F "delims=_" %%X in ('dir /S /B *_Constant.Xml') do echo %%X
If the desired file names may contain more than one underscore, use Pokechu22's answer.
Fairly easy if the exact length of the phrase is known; you just need to use the %var:~0,-3% syntax. Since "_Constant" is 9 chars long, you would want %var:~0,-9%, which takes text from the start (0) to 9 chars from the end (-9). Aditionally, delayed variable expansion also must be enabled with setlocal ENABLEDELAYEDEXPANSION for this to be run inside of your For loop.
Here's a full example:
#Echo off
setlocal ENABLEDELAYEDEXPANSION
for /R %%X in (*_Constant.Xml) do (
set FileNameTemp=%%~nX
echo !FileNameTemp:~0,-9!
)
Note that if you have a file named just _Constant.xml, this will produce "ECHO is off." rather than "" (no output). This can be solved by changing echo !FileNameTemp:~0,-9! to echo. !FileNameTemp:~0,-9!, but that puts a space before each output.
Here's the loop alone:
for /R %%X in (*_Constant.Xml) do (
set FileNameTemp=%%~nX
echo !FileNameTemp:~0,-9!
)
Happy Friday Think-Tank!
I need some assistance with a Batch .BAT script. Specifically I need help with some "IF statement syntax"
I have a script that is renaming files. There are two files, one ending in four digits and the other ending in five digits. The files will be renamed with variables I have already pre-set earlier within my script.
So here is a scenario: We have two files in a directory located at
c:\Users\username\Desktop\test-dir
There are two files within test-dir:
file1.12345
file2.1234
A four digit ending is one variable type (VAR1), whereas a file ending in five digits is another variable type (VAR2).
I need an if statement to:
a) read all the files(s) with the chosen directory (without using a wildcard if possible).
b) determine based on the number of digits after the "." which variable to use.
c) once making that determination rename the file with the appropriate variables.
The final re-naming convention is as so: yyyymmddtype.1234/12345
So basically it would use the datestamp variable I already created, the type variable I already created to be injected by the if statement, and append with the original ending digits of the file.
I know this seems like a lot, but I am more so a bash script guy. I have all the elements in place, I just need the if statement and what feels like a for loop of some kind to tie it all together.
Any help would be great!
Thank you!
Sorry, not the option you where asking for. Instead of iterating over the full list checking each file for extension conformance, iterate over a list of patterns that will filter file list, renaming matching files with the asociated "type"
for %%v will iterate over variable list, for %%a will split the content of the variable in pattern and type, for %%f will generate the file list, filter with findstr using the retrieved pattern and rename matching files with the corresponding "type"
Rename command is preceded with a echo to output commands to console. If the output is correct, remove the echo to rename the files.
#echo off
rem Variables defined elsewhere
set "folder=c:\somewhere"
set "timestamp=yyyymmdd"
rem Rename pattern variables in the form pattern;type
set "var1=\.....$;type1"
set "var2=\......$;type2"
set "var1=\.[^.][^.][^.][^.]$;type1"
set "var2=\.[^.][^.][^.][^.][^.]$;type2"
setlocal enableextensions disabledelayedexpansion
for %%v in ("%var1%" "%var2%") do for /f "tokens=1,* delims=;" %%a in ("%%~v") do (
for /f "tokens=*" %%f in ('dir /a-d /b "%folder%" ^| findstr /r /c:"%%~a"') do (
echo ren "%folder%\%%~f" "%timestamp%%%~b%%~xf"
)
)
endlocal
#ECHO OFF &SETLOCAL
set "yyyymmdd=yyyymmdd"
set "VAR1=VAR1"
set "VAR2=VAR2"
for /f "delims=" %%a in ('dir /b /a-d^|findstr /re ".*\....."') do echo(ren "%%~a" "%yyyymmdd%%VAR1%%%~xa"
for /f "delims=" %%a in ('dir /b /a-d^|findstr /re ".*\......"') do echo(ren "%%~a" "%yyyymmdd%%VAR2%%%~xa"
remove echo( to get it working.
If I understand you then this will rename the two files using preset variables for each one:
for %%a in ("%userprofile%\Desktop\test-dir\*") do (
if "%%~xa"==".12345" ren "%%a" "%variableA%-%variableB%%%~xa"
) else (
ren "%%a" "%variableC%-%variableD%%%~xa"
)
)