Say I have 3 arrays of arrays and when I write in any of them my counter goes up by one every insertion I do.How can I show on screen the data I inserted the same order I inserted them with that unique code it was printed when I was inserting them?
array ar1=new array[3];
array2 ar2=new array2[3];
array3 ar3=new array3[3];
I'm working on C# with 6 files. My main calls methods from the other 3 files. My base abstract class calls a counter (named code) from a constructor, which is being inserted on every array.My main is without Heredity, but calls the variables from the 3 files that are connected with heredity to the abstract base class.
This is my main and how I fill my first array.Same with different variables on the other two arrays.
i ++;
ar1[i] = new array();
{
Console.WriteLine("Inserting on first array");
Console.WriteLine("\n\nCode :{0}",code);
ar1[i].Inserting_data(); // this is the method where I fill my arrays
}
And this is how I try to call my previous insertions using a method again.
for (int x = 0; x <= i; x++)
{
Console.WriteLine("code :{0}",code); //trying to print the unique code but it prints total.
ar1[x].Print_data(); //the method for printing my insertions
}
If I leave the program like this when I insert data(up to 3 on every array) My counter is working fine and when I print them on screen, it prints them on the correct order but in the Console.WriteLine that there should be the unique code I want for every insertion (from 1 to 9 on that example, if I fill them all),my counter shows me the total insertions I have.
If I try rather than printing my counter, printing each variable from the For command,I get numbers from 0 to 2 max since that's what I put on my For. I can't unite my 3 arrays since each of them holds different variables and is on 3 different files.
Hope that helped.
I found the problem at last..
I had to add another variable on the base abstract class.Inside the constructor I had to write that the new variable (say s)was (s=+1+count++) and add it with a property(set,get) on my main.It worked fine.
Thanks for the time it took you to see this topic and ask some questions to help me.
Related
I'm trying to change the number of items in array, over which a for loop is running, during the for loop, with the objective that this changes the number of loops. In a very simplified version, the code would look something like this:
var loopArray: [Int] = []
loopArray.append(1)
loopArray.append(2)
loopArray.append(3)
loopArray.append(4)
loopArray.append(5)
for x in 0..<Int(loopArray.count) {
print(x)
if x == 4 {
loopArray.append(6)
}
}
When running this code, 5 numbers are printed, and while the number 6 is added to the Array, the loopArray.count does not seem to update. How can I make the .count dynamic?
This is a very simplified example, in the project I'm working on, appending numbers to the array depends on conditions that may or may not be met.
I have looked for examples online, but have not been able to find any similar cases. Any help or guidance is much appreciated.
sfung3 gives the correct way to do what you want, but I think there needs to be a bit of explanation as to why your solution doesn't work
The line
for x in 0..<Int(loopArray.count)
only evaluates loopArray.count once, the first time it is hit. This is because of the way for works. Conceptually a for loop iterates through the elements of a sequence. The syntax is something like
for x in s
where
s is a sequence, give it type S
x is a let constant (you can also make it a var but that is not relevant to the current discussion) with type S.Element
So the bit after the in is a sequence - any sequence. There's nothing special about the use of ..< here, it's just a convenient way to construct a sequence of consecutive integers. In fact, it constructs a Range (btw, you don't need the cast to Int, Array.count is already an Int).
The range is only constructed when you first hit the loop and it's effectively a constant because Range is a value type.
If you don't want to use Joakim's answer, you could create your own reference type (class) that conforms to Sequence and whose elements are Int and update the upper bound each time through the loop, but that seems like a lot of work to avoid a while loop.
you can use a while loop instead of a for loop.
var i = 0
while i < loopArray.count {
print(i)
if i == 4 {
loopArray.append(6)
}
i += 1
}
which prints
0 1 2 3 4 5
So im learning C and i've been working with arrays.One thing that I've learnt is that arrays start with index 0.So i keep thinking...if you want to create an array that holds 10 values..shoudn't you create it as say : int ar[9] , since it starts from 0-9 which is 10 elements? I keep seeing a lot of people initialising an array with 10 elements as such : int ar[10] and then while inserting data using for loops they write: for(int i=0;i<10;i++) which technically means the 11 element(ar[10]) has a garbage value right? or is this done on purpose ?
Although it is not clearly stated in my excercise, I am supposed to implement Radix sort recursively. I've been working on the task for days, but yet, I only managed to produce garbage, unfortunately. We are required to work with two methods. The sort method receives a certain array with numbers ranging from 0 to 999 and the digit we are looking at. We are supposed to generate a two-dimensional matrix here in order to distribute the numbers inside the array. So, for example, 523 is positioned at the fifth row and 27 is positioned at the 0th row since it is interpreted as 027.
I tried to do this with the help of a switch-case-construct, dividing the numbers inside the array by 100, checking for the remainder and then position the number with respect to the remainder. Then, I somehow tried to build buckets that include only the numbers with the same digit, so for example, 237 and 247 would be thrown in the same bucket in the first "round". I tried to do this by taking the whole row of the "fields"-matrix where we put in the values before.
In the putInBucket-method, I am required to extent the bucket (which I managed to do right, I guess) and then returning it.
I am sorry, I know that the code is total garbage, but maybe there's someone out there who understands what I am up to and can help me a little bit.
I simply don't see how I need to work with the buckets here, I even don't understand why I have to extent them, and I don't see any way to returning it back to the sort-method (which, I think, I am required to do).
Further description:
The whole thing is meant to work as follows: We take an array with integers ranging from 0 to 999. Every number is then sorted by its first digit, as mentioned above. Imagine you have buckets denoted with the numbers ranging from 0 to 9. You start the sorting by putting 523 in bucket 5, 672 in bucket 6 and so on. This is easy when there is only one number (or no number at all) in one of the buckets. But it gets harder (and that's where recursion might come in hand) when you want to put more than one number in one bucket. The mechanism now goes as follows: We put two numbers with the same first digit in one bucket, for example 237 and 245. Now, we want to sort these numbers again by the same algorithm, meaning we call the sort-method (somehow) again with an array that only contains these two numbers and sorting them again, but now my we do by looking at the second digit, so we would compare 3 and 4. We sort every number inside the array like this, and at the end, in order to get a sorted array, we start at the end, meaning at bucket 9, and then just put everything together. If we would be at bucket 2, the algorithm would look into the recursive step and already receive the sorted array [237, 245] and deliver it in order to complete the whole thing.
My own problems:
I don't understand why we need to extent a bucket and I can't figure it out from the description. It is simply stated that we are supposed to do so. I'd imagine that we would to it to copy another element inside it, because if we have the buckets from 0 to 9, putting in two numbers inside the same bucket would just mean that we would overwrite the first value. This might be the reason why we need to return the new, extended bucket, but I am not sure about that. Plus, I don't know how to go further from there. Even if I have an extened bucket now, it's not like I can simply stick it to the old matrix and copy another element into it again.
public static int[] sort(int[] array, int digit) {
if (array.length == 0)
return array;
int[][] fields = new int[10][array.length];
int[] bucket = new int[array.length];
int i = 0;
for (int j = 0; j < array.length; j++) {
switch (array[j] / 100) {
case 0: i = 0; break;
case 1: i = 1; break;
...
}
fields[i][j] = array[j]
bucket[i] = fields[i][j];
}
return bucket;
}
private static int[] putInBucket(int [] bucket, int number) {
int[] bucket_new = int[bucket.length+1];
for (int i = 1; i < bucket_new.length; i++) {
bucket_new[i] = bucket[i-1];
}
return bucket_new;
}
public static void main (String [] argv) {
int[] array = readInts("Please type in the numbers: ");
int digit = 0;
int[] bucket = sort(array, digit);
}
You don't use digit in sort, that's quite suspicious
The switch/case looks like a quite convoluted way to write i = array[j] / 100
I'd recommend to read the wikipedia description of radix sort.
The expression to extract a digit from a base 10 number is (number / Math.pow(10, digit)) % 10.
Note that you can count digits from left to right or right to left, make sure you get this right.
I suppose you first want to sort for digit 0, then for digit 1, then for digit 2. So there should be a recursive call at the end of sort that does this.
Your buckets array needs to be 2-dimensional. You'll need to call it this way: buckets[i] = putInBucket(buckets[i], array[j]). If you handle null in putInBuckets, you don't need to initialize it.
The reason why you need a 2d bucket array and putInBucket (instead of your fixed size field) is that you don't know how many numbers will end up in each bucket
The second phase (reading back from the buckets to the array) is missing before the recursive call
make sure to stop the recursion after 3 digits
Good luck
Let me cut to the main issue, I have a grid which is 50 by 50. And I need a way of having a true or false variable for each cell in the grid and the default value would be false, every time the method is called.
I need the array so I can see which cells I have visited so I don't need to revisited them for my path finding system that I'm working on .
But currently I have a double array[] [] which I need to loop every time I use this method. (up to 3 times a second but mostly never) which means looping 2500 value. Which doesn't sound very good. What would be the best solution, is this the best solution or am I missing something stupid.
Hope you can help and point me into the right direction.
Another possible improvement is using a single-dimensional vector, maybe wrapped into a class, that will contain 2500 elements and its indexes would mean (width*50+height). Like this:
private var _visited:Vector.<Boolean>;
function checkVisited(x:int,y:int):Boolean {
return _visited(x*50+y); // x and y are in 0-49 range
}
Vectors can be two-dimensional should you need them, you declare vector of vectors like this:
var _visited:Vector.<Vector.<Boolean>>;
Initialize with pushing the filled Vector.<Boolean> once, then just change the elements as you do with a normal array.
The main advantage of vectors is that they are solid, that is, if there are 50 elements in a vector, you are sure that there exists a value at any index from 0 to 49 (even if null, or NaN in case of Numbers), this also makes internal processing of vectors easier, as the Flash engine can calculate proper memory location by just using the index and the link to the vector, which is faster than first referencing the array about whether there is a value at that index, if yes, get its memory location, then reference.
From my experience of making tile based games with different grids I usually have a Tile class, that will contain all your necessary values, most typical would be:
posX:int
posY:int
isChecked:Boolean
You can add as many as you need for your app.
Then I have a Grid class that will create you grid and have some useful methods like giving neighbor tiles.
In the Grid class I make the grid this way:
public var tileLineArray:Vector.<Tile>;
public var tile2dArray:Vector.<Vector.<Tile>>;
public function makeGrid(w:int, h:int):void
{
tileLineArray = new Vector.<Tile>();
tile2dArray = new Vector.<Vector.<Tile>>();
for (var i:int = 0; i < gridWidth; i++)
{
var rowArray:Vector.<Tile> = new Vector.<Tile>();
for (var j:int = 0; j < gridHeight; j++)
{
var t:Tile = new Tile();
t.posX = i;
t.posY = j;
tileLineArray.push(t);
rowArray.push(t);
}
tile2dArray.push(rowArray);
}
}
What it will give you is that you can access tiles in a single line to by coordinates x,y;
var myTile:Tile = tileLineArray[lineID];
var myTile:Tile = tile2dArray[targetX][targetY];
I use Vectors in this example as they outperform Arrays and you keep the type of the stored object intact.
It is not a problem for Flash to loop through the array; if you want improve performance, break the loop if you've done all what you wanted with it, continue the loop if the tile does not meet the requirements and you don't need to process it.
Also, having a 2d array can improve performance, since you can process only the area of the array that you need.
One more advice is not to be afraid to make X more smaller arrays to store some data from the bigger array and loop trough the small ones. As the data of the arrays is not a primitive (int, uint etc.) but a Class, it will hold a pointer/reference to the object, so you're not actually making copies of the objects every time.
I have a dozens of arrays with different array names and I would like to do some mathematical calculations in to for loop array by array. I srucked in calling these array into for loop. Is there anybody can help me with this problem? text1 array contains array names. My "s" struct has all these arrays with the same name content of text1 array.
text1=['s.CustomerArray.DistanceDriven','s.CustomerArray.TimeDriven'];
for i=1:3
parameter=str2num(text1(i));
k=size(parameter,2);
a=100;
y=zeros(a,k);
end
After this part my some other calculations should start using "parameter"
Regards,
Eren
I think you are doing several things wrong, here are some pointers.
Rather than listing them manually, consider looping over the fieldnames which can be obtained automatically.
If you are looping over strings, make sure to use a cell array with , rather than a matrix.
If you have a constant, declare it outside the loop, rather than inside the loop. This won't break the code but just makes for obsolete evaluations.
If you want to store results obtained inside a loop, make sure to add an index to the variable that you loop over.
That being said, here is a guess at what you are trying to do:
f = fieldnames(s.CustomerArray);
y = cell(numel(f),1);
parameter = NaN(numel(f),1);
for t = 1:numel(f)
parameter(t) = s.CustomerArray.(f{t});
y{t} = zeros(100,numel(f{t}));
end