create a resultset of calendar dates - sql-server

Question

I should use a stored procedure to fill a calendar for 10 years in a SQL database!
Three columns should I fill in with the records: date,weekday or weekend, dayname( monday,...).
Can somebody help me?

Answer 1

You can do it dynamically like this:
WITH Dates AS (
SELECT CONVERT(DATE, getdate()) as [Date]
UNION ALL
SELECT DATEADD(DAY, 1, [Date])
FROM Dates
where Date < dateadd(yy, 10, getdate())
)
SELECT [Date]
FROM Dates
OPTION (MAXRECURSION 4000)

Answer 2

try this version (floors the datetime and adds all requested columns):
;WITH Dates AS (
SELECT DATEADD(day,DATEDIFF(day,0,GETDATE()),0) as DateOf,
CASE WHEN datename(weekday,getdate()) IN ('Saturday','Sunday') THEN 'Weekend'
ELSE 'WeekDay'
END DayType,
datename(weekday,getdate()) DayOfWeekName
UNION ALL
SELECT DateOf+1,
CASE WHEN datename(weekday,DateOf+1) IN ('Saturday','Sunday') THEN 'Weekend'
ELSE 'WeekDay'
END DayType,
datename(weekday,DateOf+1) DayOfWeekName
FROM Dates
where DateOf < dateadd(yy, 10, getdate())
)
SELECT DateOf,DayType,DayOfWeekName
FROM Dates
OPTION (MAXRECURSION 4000)
to insert into a table try this:
DECLARE #DateTable table (DateOf datetime, DayType char(7), DayOfWeekName varchar(10))
;WITH Dates AS (
SELECT DATEADD(day,DATEDIFF(day,0,GETDATE()),0) as DateOf,
CASE WHEN datename(weekday,getdate()) IN ('Saturday','Sunday') THEN 'Weekend'
ELSE 'WeekDay'
END DayType,
datename(weekday,getdate()) DayOfWeekName
UNION ALL
SELECT DateOf+1,
CASE WHEN datename(weekday,DateOf+1) IN ('Saturday','Sunday') THEN 'Weekend'
ELSE 'WeekDay'
END DayType,
datename(weekday,DateOf+1) DayOfWeekName
FROM Dates
where DateOf < dateadd(yy, 10, getdate())
)
INSERT INTO #DateTable (DateOf,DayType,DayOfWeekName)
SELECT DateOf,DayType,DayOfWeekName
FROM Dates
OPTION (MAXRECURSION 4000)
select top 10 * from #DateTable
OTUPUT:
DateOf DayType DayOfWeekName
----------------------- ------- -------------
2011-05-16 00:00:00.000 WeekDay Monday
2011-05-17 00:00:00.000 WeekDay Tuesday
2011-05-18 00:00:00.000 WeekDay Wednesday
2011-05-19 00:00:00.000 WeekDay Thursday
2011-05-20 00:00:00.000 WeekDay Friday
2011-05-21 00:00:00.000 Weekend Saturday
2011-05-22 00:00:00.000 Weekend Sunday
2011-05-23 00:00:00.000 WeekDay Monday
2011-05-24 00:00:00.000 WeekDay Tuesday
2011-05-25 00:00:00.000 WeekDay Wednesday
(10 row(s) affected)

Answer 3

I apporached this as a tally table problem. I am using spt_values from Master as my tally table. It only goes up to 2048 which is enough data for 5.5 years. You can create your own tally table with as many numbers as you need.
Declare #startDate Date = '1/1/2011';
SELECT DateAdd(d, number, #startDate) [Date],
CASE WHEN DATEPART(dw, DateAdd(d, number, #startDate)) IN (1,7) THEN 'Weekend' ELSE 'Weekday' END [WeekDayEnd],
DateName(weekday, DateAdd(d, number, #startDate)) DayOfWeek
FROM spt_values
WHERE type = 'P';
This gets the following results:
Date WeekDayEnd DayOfWeek
2011-01-01 Weekend Saturday
2011-01-02 Weekend Sunday
2011-01-03 Weekday Monday
2011-01-04 Weekday Tuesday
2011-01-05 Weekday Wednesday
2011-01-06 Weekday Thursday
2011-01-07 Weekday Friday
2011-01-08 Weekend Saturday
2011-01-09 Weekend Sunday
2011-01-10 Weekday Monday

Answer 4

USE THIS
set nocount on
SET DATEFIRST 7;
go
select date,
datename(dw,datepart(dw,date)) Day,
datepart(dw,date) Day,
'Segment' = case
when datepart(dw,date)in (5,6) then 'WEEK_END' else 'Week_day' end
from calenderdate
set nocount off
> set nocount on
>
> select date,
> substring(cast(datename(dw,datepart(dw,date))as
> varchar(10)),1,3) Day, 'Segment' =
> case when datepart(dw,date)in (5,6)
> then 'WEEK_END' else 'Week_day' end
> from calenderdate
>
> set nocount off
output
1/1/2011 Monday 7 Week_day
1/2/2011 Tuesday 1 Week_day