On success, the PID of the child
process is returned in the parent’s
thread of execution, and a 0 is
returned in the child’s thread of execution.
p = fork();
I'm confused at its manual page,is p equal to 0 or PID?
I'm not sure how the manual can be any clearer! fork() creates a new process, so you now have two identical processes. To distinguish between them, the return value of fork() differs. In the original process, you get the PID of the child process. In the child process, you get 0.
So a canonical use is as follows:
p = fork();
if (0 == p)
{
// We're the child process
}
else if (p > 0)
{
// We're the parent process
}
else
{
// We're the parent process, but child couldn't be created
}
p = fork();
/* assume no errors */
/* you now have two */
/* programs running */
--------------------
if (p > 0) { | if (p == 0) {
printf("parent\n"); | printf("child\n");
... | ...
Processes are structured in a directed tree where you only know your single-parent (getppid()). In short, fork() returns -1 on error like many other system functions, non-zero value is useful for initiator of the fork call (the parent) to know its new-child pid.
Nothing is as good as example:
/* fork/getpid test */
#include <sys/types.h>
#include <unistd.h> /* fork(), getpid() */
#include <stdio.h>
int main(int argc, char* argv[])
{
int pid;
printf("Entry point: my pid is %d, parent pid is %d\n",
getpid(), getppid());
pid = fork();
if (pid == 0) {
printf("Child: my pid is %d, parent pid is %d\n",
getpid(), getppid());
}
else if (pid > 0) {
printf("Parent: my pid is %d, parent pid is %d, my child pid is %d\n",
getpid(), getppid(), pid);
}
else {
printf("Parent: oops! can not create a child (my pid is %d)\n",
getpid());
}
return 0;
}
And the result (bash is pid 2249, in this case):
Entry point: my pid is 16051, parent pid is 2249
Parent: my pid is 16051, parent pid is 2249, my child pid is 16052
Child: my pid is 16052, parent pid is 16051
If you need to share some resources (files, parent pid, etc.) between parent and child, look at clone() (for GNU C library, and maybe others)
Once fork is executed, you have two processes. The call returns different values to each process.
If you do something like this
int f;
f = fork();
if (f == 0) {
printf("I am the child\n");
} else {
printf("I am the parent and the childs pid is %d\n",f);
}
You will see both the messages printed. They're being printed by two separate processes. This is they way you can differentiate between the two processes created.
This is the cool part. It's equal to BOTH.
Well, not really. But once fork returns, you now have two copies of your program running! Two processes. You can sort of think of them as alternate universes. In one, the return value is 0. In the other, it's the ID of the new process!
Usually you will have something like this:
p = fork();
if (p == 0){
printf("I am a child process!\n");
//Do child things
}
else {
printf("I am the parent process! Child is number %d\n", p);
//Do parenty things
}
In this case, both strings will get printed, but by different processes!
fork() is invoked in the parent process. Then a child process is spawned. By the time the child process spawns, fork() has finished its execution.
At this point, fork() is ready to return, but it returns a different value depending on whether it's in the parent or child. In the child process, it returns 0, and in the parent process/thread, it returns the child's process ID.
Fork creates a duplicate process and a new process context. When it returns a 0 value it means that a child process is running, but when it returns another value that means a parent process is running. We usually use wait statement so that a child process completes and parent process starts executing.
I think that it works like this:
when pid = fork(), the code should be executed two times, one is in current process, one is in child process.
So it explains why if/else both execute.
And the order is, first current process, and then execute the child.
Related
what I need is to have 3 children and 1 parent (the main program) because the children and parent are going to have diferent functionality.
I don't know why I can't do it properly, as far I have read, when you do a fork(), if it returns 0, you execute the child's code and the parent's code otherwise.
So, this is my program:
#include <stdlib.h>
#include <stdio.h>
#include <unistd.h>
int
main(int argc, char ** argv) {
printf ("Init Parent. PID =%d\n", getpid());
fork();
fork();
if (fork() == 0) {
printf ("Init Child. PID =%d\n", getpid());
sleep(1);
} else {
printf ("I am the parent. PID = %d\n",getpid());
sleep(1);
}
exit(0);
}
This is the output:
Init Parent. PID =9007
I am the parent. PID = 9007
I am the parent. PID = 9009
Init Child. PID =9010
Init Child. PID =9011
I am the parent. PID = 9008
I am the parent. PID = 9012
Init Child. PID =9013
Init Child. PID =9014
And this is what I want:
Init Parent. PID =9007
I am the parent. PID = 9007
Init Child. PID =9010
Init Child. PID =9011
Init Child. PID =9013
Init Child. PID =9014
I don't know why it says I am the parent 3 times and how to do it properly, because 1
if (fork() == 0)
seems bad.
I would really appreciate any help, thank you in advance.
You have to check for parent-child starting from after your first fork. Every time you call fork() you are spawning a child. What you are doing now is this:
Starting executing 1 program (+1 proc, 1 proc total)
First fork(): Main program spawns child (+1 proc, 2 procs total)
Second fork(): Child and main program spawn children. (+2 procs, 4 procs total)
Third fork(): All processes previously mentioned spawn children(+4 procs, 8 procs total).
The resulting process tree from your original code would look like this:
pi
/ | \
pi pi pi
/ | |
pi pi pi
|
pi
Possible solution(works for n-children):
int noProcs = 3;
int i;
for (i = 0; i < noProcs; ++i) {
if (fork() == 0) {
printf("in child\n");
//Do stuff...
exit(0);
}
}
//DONT FORGET: Reap zombies using wait()/waitpid()/SIGCHLD etc...
Note that after every fork() call, the children spawned are executing the same subsequent code. For each step in the loop's iteration, here's what happens after I spawn a child with fork():
Child process: executes child code, and calls exit(). This prevents us from looping and creating more children than intended.
Parent process: Bypasses the if(fork() == 0) statement's body and steps through the loop, spawning additional children as specified.
fork duplicates the process that calls it, creating a new (child) process that is in the exact same state and that continues running at the same point. The only difference between the parent and child is what is returned by the fork call.
So consider what happens with your code. You start with one process:
printf ("Init Parent. PID =%d\n", getpid());
so that one process prints a message
fork();
you fork, so now have two processes (parent and child)
fork();
both processes fork, so you now have 4 processes (parent, 2 children and grandchild)
if (fork() == 0) {
fork again, so you now have 8 processes -- parent, 3 children, 3 grandchildren, and a great-grandchild. Half of them (one child, two grandchildren, and the great-grandchild) have a 0 return from this fork, as they were the children created by this third fork. The other half are parents.
So after these 3 forks, you have 8 processes, 4 of which will print "Init Child" and 4 of which will print "I am the parent"
If you want just 3 direct children (and no grandchildren), you need to arrange your code such that the children do no call fork again. You could use something like:
if (fork() && fork() && fork())
printf ("I am the parent. PID = %d\n",getpid());
else
printf ("Init Child. PID =%d\n", getpid());
Change the code as below.
You need to check on every fork() its return code and not only on the last call of fork. I didn't run and try but this is the error I feel.
You said - you need 1 Parent and 3 child - so during first fork() - 1 child will be created and then for second fork() - 1 grandchild of child and 1 more child of a parent will be created.
EDIT:
parent
/ \
fork-1 fork-2
| |
child1 child-2
|
fork-2
|
child3
for(int i=0;i<2;i++)
{
if (fork()==0)
printf ("Init Child. PID =%d\n", getpid());
sleep(1);
} else {
printf ("I am the parent. PID = %d\n",getpid());
sleep(1);
}
}
I've been wracking my brain about this problem during an hour. I have to create a ring of processes with n processes (quantity is passed as an argument via cmd). The parent process sends his PID to his first child, and this one sends his parent's PID plus his own PID to his next brother, and it happens until we have created n children. After that, the parent process gets the addition of the PID of all his children.
Let's suppose that the parent process' PID is 3400 and we create two children, so the ring is made of three processes
3400 + 3401(first child's PID) + 3402(second child's PID) = 10203
The parent process should get this 10203.
I have thought about one "for" loop in which child processes send the addition of their brothers PID from brother to brother, using only one pipe. Nonetheless, I haven't come across a solution yet.
Given that the task is to use fork() and pipe(), you probably need to use an algorithm like:
Parent creates pipe for it to write to 1st child.
Parent keeps open the write end of pipe to 1st child.
Parent keeps open the read end of the pipe from Nth child.
For each child n = 1..N, Parent creates output pipe for nth child to talk to n+1th.
Parent forks nth child.
nth child closes the write end of its input pipe and the read end of its output pipe.
nth child reads sum of PIDs from input pipe, adds its own pid to the sum, and writes that to the output pipe, then exits.
Meanwhile, Parent closes both ends of the input pipe to the nth (except for the descriptors it must keep open), and loops back to create the n+1th child's pipe and then the child.
When all the children have been launched, parent writes its PID to 1st child and closes the write end of that pipe.
It then reads a response from the Nth child, closes the read end of the pipe, and prints the result.
What is less obvious how you can validate the sum, unless each child also writes its PID to standard output, or the parent (which knows all the child PIDs) computes the answer to verify it.
With zero marks because of the complete lack of error checking:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int main(int argc, char **argv)
{
int N = (argc > 1) ? atoi(argv[1]) : 10;
int c1_wr;
int cN_rd;
int p1[2];
int p2[2];
int pid_chk = getpid();
if (N <= 0 || N >= 100)
N = 10;
pipe(p1);
c1_wr = dup(p1[1]);
printf("%d children\n", N);
printf("Parent = %d\n", pid_chk);
for (int n = 0; n < N; n++)
{
int pid;
pipe(p2);
fflush(stdout);
if ((pid = fork()) == 0)
{
close(p1[1]);
close(p2[0]);
int pid_sum;
read(p1[0], &pid_sum, sizeof(pid_sum));
pid_sum += getpid();
write(p2[1], &pid_sum, sizeof(pid_sum));
close(p1[0]);
close(p2[1]);
exit(0);
}
printf("Child %2d = %d\n", n+1, pid);
pid_chk += pid;
close(p1[0]);
close(p1[1]);
p1[0] = p2[0];
p1[1] = p2[1];
}
cN_rd = p2[0];
close(p2[1]);
int pid_sum = getpid();
write(c1_wr, &pid_sum, sizeof(pid_sum));
close(c1_wr);
read(cN_rd, &pid_sum, sizeof(pid_sum));
close(cN_rd);
printf("PID sum = %d\n", pid_sum);
printf("PID chk = %d\n", pid_chk);
return 0;
}
Sample run:
10 children
Parent = 49686
Child 1 = 49688
Child 2 = 49689
Child 3 = 49690
Child 4 = 49691
Child 5 = 49692
Child 6 = 49693
Child 7 = 49694
Child 8 = 49695
Child 9 = 49696
Child 10 = 49697
PID sum = 546611
PID chk = 546611
The purpose of the fflush(stdout); becomes clear if (a) you omit it and (b) you run the output through a pipeline. It is necessary.
You need some kind of inter process communication (IPC). Commonly used methods for IPC are:
loopback socket
shared memory
You can find all the other methods in wikipedia IPC article.
If you're in control of the behavior of the child processes, and the parent process doesn't have important/hard-to-recreate state before launching the children, you can simplify things.
Instead of an IPC, you can have the parent recursively launch the children detached, terminate itself, and have the last child re-start the parent:
Invoke parent n, where n is number of children to spawn.
parent:
invokes child arg1-1 0 and terminates,
if invoked with "0" for arg1, it adds its own PID to arg2 and you're done, even though in terms of the process tree it's not really a "parent" of anything.
child:
invokes child arg-1 arg2+pid, where pid is child's own PID.
if invoked with "0" for arg1, it invokes parent 0 arg2+pid.
I'm creating child processes in a for-loop. Inside the child process, I can retrieve the child PID with getpid().
However, for some reason when I try to store the value of getpid() into a variable declared by the parent process, the change is nullified when I check for it in the parent process. I'm assuming this has to do with some sort of process variable scope. Not really familiar with C, so can't be too sure.
Anyhow what is a way of storing the result of getpid() of a child PID (when called from the child process) into a variable in the parent process?
Or maybe another approach is storing fork() into a variable in the parent and calling some function on that variable to retrieve the child's PID? I don't know how to do this either, so if this is the better way, how would you do this?
fork already returns the child's pid. Just store the return value.
look at man 2 fork:
RETURN VALUES
Upon successful completion, fork() returns a value of 0 to the child process and
returns the process ID of the child process to the parent process. Otherwise, a
value of -1 is returned to the parent process, no child process is created, and
the global variable errno is set to indicate the error.
As mentioned in previous answer that "fork() returns a value of 0 to the child process and returns the process ID of the child process to the parent process." So, the code can be written in this way:
pid = fork(); /* call fork() from parent process*/
if (0 == pid)
{
/* fork returned 0. This part will be executed by child process*/
/* getpid() will give child process id here */
}
else
{
/* fork returned child pid which is non zero. This part will be executed by parent process*/
/* getpid() will give parent process id here */
}
This link is very helpful and explains in detail.
if fork() is successfully created then it returns 0 value in the child process.
int main(void)
{
int id;
id= fork();
if(id==0)
{
printf("I am child process my ID is = %d\n" , getpid());
}
}
If you are calling fork in the following way:
pid = fork()
Then pid is in fact your child PID. So you can print it out from the parent.
Yes, the child process's pid is already returned with fork(), fork() is called once but return twice, different return value in parent and child process, so you can do this:
pid_t pid, pid_c;
pid = fork();
if (pid == -1) { // error
perror("Falied to fork");
} else if(pid == 0) { // execute in child process
// you can get child's pid by getpid() in child process:
pid_t tmp_pid_c = getpid();
execl("bin/ls", "ls", "./", NULL);
} else {
// you can also get child's pid that already returned by fork() in parent process
pid_c = pid;
}
There are two main functions to get the process id of parent process and child. getpid() and getppid()
I was given this starter code for a project, but am having difficulty understanding how the child process executes.
int pid ;
int child_info = -1;
if ( argv[0] == NULL ) /* nothing succeeds */
return 0;
if( (pid= fork()==-1)
perror("fork");
else if ( pid == 0 ){
signal(SIGINT, SIG_DFL);
signal(SIGQUIT, SIG_DFL);
execvp(argv[0], argv);
perror("cannot execute command");
exit(1);
}
else { //check if wait error or print out exit status
if ( wait(&child_info) == -1 )
perror("wait");
else {
printf("Exit status: %d, %d\n", child_info>>8, child_info&0377);
}
}
return child_info;
}
Looking at the code, the current process forks and in this case, the child inherits all of the relevant properties of the parent process, since there are no timers, signals or anything involved. However, the pid values of the new processes are in the 18000 range, so how can execvp(argv[0], argv) be executed since in this case, pid != 0.
From the fine manual for fork:
Upon successful completion, fork() shall return 0 to the child process and shall return the process ID of the child process to the parent process.
The first branch of the if is an error condition and will be executed in the parent process if there was an error. The second branch (pid == 0) is executed in the child process, the child does a bit of signal housekeeping and does the exec. The third branch is in the parent when there was no error.
In the parent, pid will be non-zero but in the new child process, pid will be zero.
It gets executed in the child process, where pid will be 0.
http://linux.die.net/man/2/fork
Fork returns the pid of the child to the parent process and 0 to the child process. so when asking for pid == 0 means "is this the child process?". If so, it executes the program passed through command line arguments.
There's only one new process created; the child.
fork() in the child process returns 0, which is what you're checking for.
fork() in the parent process (your original process) returns the child process' pid.
By checking the return of fork() for 0 you know if you're the parent or child; you're the child if it's 0.
int main()
{
...
if(!fork())
{
execvp(cmdName,cmdParam);
}
printf("In main()...");
return(0);
}
Assuming I have correctly passed the cmdName & cmdParam arguments, how do I wait for the process created by execvp to finish, before resuming the execution of main()?
Does the execvp() create a process which is a child of the newly fork()ed process?
In the parent process, fork returns the PID of the child process, so you can store that in a variable, and then use waitpid to wait for the child process to terminate.
Not really - the new child process created by fork is a duplicate of the parent, and execvp then replaces its process image with a new image. Effectively you initially have two 'copies' of the parent, one of which then 'becomes' the new program.
As noted you need to save the value of the fork call. You should really use more than an if on the fork. There are three cases:
0: you're the child process
0: you're the parent and got a child PID back
-1: something horrible happened and fork failed
You really want to know about case 3, it'll ruin your whole day. (also the exec call)
int main() {
int pid = fork();
if(-1 == pid) {
fprintf(stderr, "Big problems forking %s\n", strerror(errno);
exit(-1);//or whatever
}
else if (0 == pid) {
if (-1 == execvp(cmdName,cmdParam)) {
//like above, get some output about what happened
}
}
//no need to else here, execvp shouldn't return
// if it does you've taken care of it above
waitpid(pid, NULL, 0);
printf("Resuming main()...");
}
return(0);
}
For your first question:
Use waitpid(2) like this:
int pid = fork();
if (!pid)
{
execvp(cmdName, cmdParam);
}
waitpid(pid, NULL, 0);
printf("Resuming main()...\n");
For the second part: all exec function calls take the process over (none of them return)
You need to store the return value of fork(), which returns a different value to each executable (0 if you are the child PID if you are the parent), and then you need to do a waitpid