I am a complete novice with Linux. I have Mint on a laptop and have recently been playing around with it.
I wrote a simple C program and saved the file.
Then in the command line I typed
gcc -c myfile
and out popped a file called a.out. I naively (after years of Windows usage) expected a nice .exe file to appear. I have no idea what to do with this a.out file.
Name it with -o and skip the -c:
gcc -Wall -o somefile myfile
You should name your sourcefiles with a .c extension though.
The typical way of compiling e.g. two source files into an executable:
#Compile (the -c) a file, this produces an object file (file1.o and file2.o)
gcc -Wall -c file1.c
gcc -Wall -c file2.c
#Link the object files, and specify the output name as `myapp` instead of the default `a.out`
gcc -o myapp file1.o file2.o
You can make this into a single step:
gcc -Wall -o myapp file1.c file2.c
Or, for your case with a single source file:
gcc -Wall -o myapp file.c
The -Wall part means "enable (almost) all warnings" - this is a habit you should pick up from the start, it'll save you a lot of headaches debugging weird problems later.
The a.out name is a leftover from older unixes where it was an executable format. Linkers still name files a.out by default, event though they tend to produce ELF and not a.out format executables now.
a.out is the executable file.
run it:
./a.out
Related
I have reinstalled mingw in my system and downloaded the gcc compiler.
I was shocked after compiling the first file which was "subject.c" but the name of the compiled file which gcc returned was "a.exe". It should be "subject.exe" but do not know why this happened.
Can anyone please explain the reason behind this ?
expected:
gcc subject.c
ls
subject.c subject.exe
tried:
gcc subject.c
ls
subject.c a.exe
-o can be used to give the name of the output file.
For example,
gcc -Wall -Wextra -pedantic subject.c -o subject.exe
(Do enable your compiler's warnings!)
gcc names its output files, in the absence of other instructions, a.out or a.exe depending on system environment because that is what it's supposed to do.
To override this default behavior, you can use the -o flag which tells gcc that the next argument is the desired name for the output file. For instance:
gcc -o subject.exe subject.c
There is no automatic functionality built into gcc to strip a source file of its file extension and add .exe to the end but this can be done manually with Makefiles or other similar scripts, for instance you can write a Makefile with the following contents:
%.exe: %.c
gcc -o $# $<
Then a command like make subject.exe would be translated to gcc -o subject.exe subject.c, which may be what you're looking for.
There is functionality built into gcc to strip source files of their extensions during different parts of the compilation process, which may have been what confused you. For instance a call like gcc -c subject.c can be expected to produce an object file called subject.o, likewise gcc -S subject.c can be expected to produce an assembly language file called subject.s, however this does not apply to executable files not only for historical reasons, but because programs can be compiled from multiple source files and there is not always a clear way to choose a name for the executable output.
I am new to C and using GCC. How do I compile multiple C files and then run them? I have multiple miles and each has different functions and they are supposed to run through the main.c file. My friend showed me through Windows but I am having issues figuring out how to do it on Mac.
What I was told:
Compile both files individually first:
gcc -Wall -c .\main.c
gcc -Wall -c .\file.c
Then compile both together into an executable:
gcc -o program file.o main.o
Then run executable with .\program.exe
You should probably investigate makefiles, but this is quite easy. The following should do the trick.
gcc -o program file.c main.c
Feel free to add in whichever -W warning flags you want.
Note also that Macs do not use \ as a directory separator but rather /, and executable files do not typically end in .exe.
I am a Unix/Linux newbie who is trying to run a shell script written by a person who left no documentation and has since demised. This script contains line:
./search $opt1 $arg1 < $poly 2>&1 | tee $output
Which is trying to get the file $poly and call program ./search and divert the output to $output.
When I get to this line, I am given message: ./search: cannot execute binary file: Exec format error
search is a C program called from the script and is in the same folder as various other C programs to do with this project. Script and C programs were developed and originally executed on a Unix/Linux box which is no longer available, so I have been asked to try to resurrect this project but under Windows using gcc in NetBeans and cygwin.
The message : ./search: cannot execute binary file: Exec format error is most likely to do with the fact there is no executable file for search. When I try to build the C programs I get the following output:
C:\cygwin64\bin\make.exe -f Makefile
gcc -ansi -g -c cbuild.c
gcc -ansi -g -c complex.c
gcc -ansi -g -c mylib.c
gcc -ansi -g -c poly.c
gcc -ansi -g -c real.c
gcc -ansi -g -c zero.c
gcc -lgmp -lm -lrt -o cbuild cbuild.o complex.o mylib.o poly.o real.o zero.o
real.o: In function `rabs':
/cygdrive/c/../progs/real.c:9: undefined reference to `__imp___gmpf_abs'
/cygdrive/c/../progs/real.c:9:(.text+0x1e): relocation truncated to fit: R_X86_64_PC32 against undefined symbol `__imp___gmpf_abs'
real.o: In function `radd':
I assume that R_X86_64_PC32 refers to the environment I am using. I am using a 64 bit version of Netbeans with gcc 5.4.0 in a 64 bit version of cygwin on Windows 10.
Can anyone advise what I must to to resolve this so that I can build the C programs?
The problem is this:
gcc -lgmp -lm -lrt -o cbuild cbuild.o complex.o mylib.o poly.o real.o zero.o
By default, the linker will link libraries and objects in the order specified on the command line, and, when linking a library, will only include symbols needed by things before it on the command line. Since -lgmp is first, there are (as yet) no outstanding symbols (except main), so nothing is included from the library. When later objects need the symbols from it, they won't see them.
Change the order to
gcc -o cbuild cbuild.o complex.o mylib.o poly.o real.o zero.o -lgmp -lm -lrt
and it should work. Alternately, use the -Wl,--as_needed linker option to get the linker to remember earlier libraries and relink them if more symbols from them are referenced by later object files (requires a recent version of the GNU linker -- I have no idea if it works with cygwin).
This kind of misordering is usually a symptom of a broken Makefile. The normal Makefile structure has a bunch of variables that are set to control the default rules that know how to compile source files and link object files. The two variables relevant for linking are LDFLAGS and LDLIBS, and the difference is that LDFLAGS comes before all the object files on the command line and LDLIBS comes after all the object files.
So in order to make things work, you need to ensure that all of the -l options and other libraries are in LDLIBS:
LDLIBS = -lgmp -lrt -lm
and NOT in LDFLAGS
Suppose there are 2 c program named abc.c and xyz.c . Now we want to work with the 2 executables at a time. So we change the name of the ./a.out using
gcc -g abc.c -o abc
gcc -g xyz.c -o xyz
Even gcc -o abc abc.c works.
What does the -g and -o in the above commands specify or describe?
What is the significance of -g and -o in the command for renaming ./a.out file.
Thanks in advance.
-g means to leave debugging information in the output file, it's unrelated to renaming.
-o means to put the result in the specified file instead of the default filename (abc.o for object files, a.out for linked executable files).
From https://gcc.gnu.org/onlinedocs/gcc/Option-Summary.html:
-g
Produce debugging information in the operating system's native format (stabs, COFF, XCOFF, or DWARF). GDB can work with this debugging information.
-o file
Place output in file file. This applies to whatever sort of output is being produced, whether it be an executable file, an object file, an assembler file or preprocessed C code.
-g starts becoming useful once you use debuggers such as gdb and lldb. When you attach to a running program and advancing one line at a time printing/altering the state as it changes.
if we specify -g option while compiling, debugging symbols will be available in the output file which will be useful when you try to debug using GDB.
If we won't specify -o option, the output will be placed in default a.out file. So if we run
gcc a.c - output will be in a.out
gcc b.c - output is a.out which is replacing old a.out file
If you want the output not to be a.out file, you can give -o option while compiling
gcc abc.c -o a
-o and -g options are not related.
I wrote a C programm and saved it with a .c extension.
Then I compiled with the gcc but after that I only see my .c file and an .exe file. The program runs perfectly. But where is the .o file that I learned in theory? Has it been overwritten to .exe and all done by the gcc in on step? (Preprocessing, compiling, assembling and linking)
I'm on a VM running Debian.
By default, gcc compiles and links in one step. To get a .o file, you need to compile without linking. That's done with the -c option.
Suppose you want to compile two files separately, then link them. You would do the following:
gcc -c file1.c # creates file1.o
gcc -c file2.c # creates file2.o
gcc -o myexe file1.o file2.o
If you want just the output of the preprocessor, use the -E option along with the -o to specify the output file:
gcc -E file1.c -o file1-pp.c # creates file1-pp.c
Compile and link in two steps:
gcc -Wall -c tst.c
gcc tst.c -o tst
After first command you'll get a .o file.
if you did something like gcc test.c then it produces only the executable file (in order to compile only, see the -c option)
here is steps on compiling with gcc to create a .o file from your C file:
http://www.gnu.org/software/libtool/manual/html_node/Creating-object-files.html