SQL Server - Select top 2 rows - sql-server

Question

I'm attempting to write a query that will return
The most recent AccountDate with a record of 0 per locationID
Then the second most recent AccountDate per locationID. The record can be either 1 or 0.
If there are two AccountDates with the same date then return the most recent AccountDate based on DateAccountLoaded
How ever my solution doesn't look very elegant. Has anyone got a better way of achieving this.
Please see below my solution
CREATE TABLE [dbo].[TopTwoKeyed](
ID INT IDENTITY(1,1) PRIMARY KEY(ID),
[LocationID] [int] NULL,
[AccountDate] [date] NULL,
[Record] [tinyint] NULL,
[DateAccountLoaded] [date] NULL
)
INSERT INTO [dbo].[TopTwoKeyed] (
[LocationID],
AccountDate,
Record,
DateAccountLoaded
)
VALUES(1,'2009-10-31',0,'2011-03-23'),
(1,'2008-10-31',1,'2011-03-23'),
(1,'2008-10-31',0,'2010-03-22'),
(1,'2008-10-31',1,'2009-03-23'),
(1,'2011-10-31',1,'2010-03-22'),
(1,'2009-10-31',0,'2010-03-23'),
(2,'2011-10-31',0,'2010-03-23'),
(2,'2010-10-31',0,'2010-03-23'),
(2,'2010-10-31',1,'2010-03-23'),
(2,'2010-10-31',1,'2009-03-23'),
(3,'2010-10-31',0,'2010-03-23'),
(3,'2009-10-31',0,'2010-03-23'),
(3,'2008-10-31',1,'2010-03-23')
-- Get the most recent Account Date per locationID which has a record type of 0
SELECT f.LocationID
,f.AccountDate
,f.DateAccountLoaded
FROM (
SELECT ROW_NUMBER() OVER (PARTITION BY LocationID ORDER BY AccountDate DESC,DateAccountLoaded DESC) AS RowNumber
,LocationID AS LocationID
,AccountDate AS AccountDate
,DateAccountLoaded AS DateAccountLoaded
FROM [dbo].[TopTwoKeyed]
WHERE Record = 0
) f
WHERE f.RowNumber = 1
UNION ALL
SELECT ff.LocationID
,ff.AccountDate
,ff.DateAccountLoaded
FROM (
-- Get the SECOND most recent AccountDate. Can be either Record 0 or 1.
SELECT ROW_NUMBER() OVER (PARTITION BY LocationID ORDER BY AccountDate DESC,DateAccountLoaded DESC) AS RowNumber
,LocationID AS LocationID
,AccountDate AS AccountDate
,DateAccountLoaded 'DateAccountLoaded'
FROM [dbo].[TopTwoKeyed] tt
WHERE EXISTS
(
-- Same query as top of UNION. Get the most recent Account Date per locationID which has a record type of 0
SELECT 1
FROM (
SELECT ROW_NUMBER() OVER (PARTITION BY LocationID ORDER BY AccountDate DESC,DateAccountLoaded DESC) AS RowNumber
,LocationID AS LocationID
,AccountDate AS AccountDate
FROM [dbo].[TopTwoKeyed]
WHERE Record = 0
) f
WHERE f.RowNumber = 1
AND tt.LocationID = f.LocationID
AND tt.AccountDate < f.AccountDate
)
) ff
WHERE ff.RowNumber = 1
-- DROP TABLE [dbo].[TopTwoKeyed]

Answer 1

You could use a row_number subquery to find the most recent account date. Then you can outer apply to search for the next most recent account date:
select MostRecent.LocationID
, MostRecent.AccountDate
, SecondRecent.AccountDate
from (
select row_number() over (partition by LocationID order by
AccountDate desc, DateAccountLoaded desc) as rn
, *
from TopTwoKeyed
where Record = 0
) MostRecent
outer apply
(
select top 1 *
from TopTwoKeyed
where Record in (0,1)
and LocationID = MostRecent.LocationID
and AccountDate < MostRecent.AccountDate
order by
AccountDate desc
, DateAccountLoaded desc
) SecondRecent
where MostRecent.rn = 1
EDIT: To place the rows below eachother, you probably have to use a union. A single row_number can't work because the second row has different criterium for the Record column.
; with Rec0 as
(
select ROW_NUMBER() over (partition by LocationID
order by AccountDate desc, DateAccountLoaded desc) as rn
, *
from TopTwoKeyed
where Record = 0
)
, Rec01 as
(
select ROW_NUMBER() over (partition by LocationID
order by AccountDate desc, DateAccountLoaded desc) as rn
, *
from TopTwoKeyed t1
where Record in (0,1)
and not exists
(
select *
from Rec0 t2
where t2.rn = 1
and t1.LocationID = t2.LocationID
and t2.AccountDate < t1.AccountDate
)
)
select *
from Rec0
where rn = 1
union all
select *
from Rec01
where rn = 1