Batch rename sequential files by padding with zeroes - batch-file

Question

I have a bunch of files named like so:
output_1.png
output_2.png
...
output_10.png
...
output_120.png
What is the easiest way of renaming those to match a convention, e.g. with maximum four decimals, so that the files are named:
output_0001.png
output_0002.png
...
output_0010.png
output_0120.png
This should be easy in Unix/Linux/BSD, although I also have access to Windows. Any language is fine, but I'm interested in some really neat one-liners (if there are any?).

Answer 1

Python
import os
path = '/path/to/files/'
for filename in os.listdir(path):
prefix, num = filename[:-4].split('_')
num = num.zfill(4)
new_filename = prefix + "_" + num + ".png"
os.rename(os.path.join(path, filename), os.path.join(path, new_filename))
you could compile a list of valid filenames assuming that all files that start with "output_" and end with ".png" are valid files:
l = [(x, "output" + x[7:-4].zfill(4) + ".png") for x in os.listdir(path) if x.startswith("output_") and x.endswith(".png")]
for oldname, newname in l:
os.rename(os.path.join(path,oldname), os.path.join(path,newname))
Bash
(from: http://www.walkingrandomly.com/?p=2850)
In other words I replace file1.png with file001.png and file20.png with file020.png and so on. Here’s how to do that in bash
#!/bin/bash
num=`expr match "$1" '[^0-9]*\([0-9]\+\).*'`
paddednum=`printf "%03d" $num`
echo ${1/$num/$paddednum}
Save the above to a file called zeropad.sh and then do the following command to make it executable
chmod +x ./zeropad.sh
You can then use the zeropad.sh script as follows
./zeropad.sh frame1.png
which will return the result
frame001.png
All that remains is to use this script to rename all of the .png files in the current directory such that they are zeropadded.
for i in *.png;do mv $i `./zeropad.sh $i`; done
Perl
(from: Zero pad rename e.g. Image (2).jpg -> Image (002).jpg)
use strict;
use warnings;
use File::Find;
sub pad_left {
my $num = shift;
if ($num < 10) {
$num = "00$num";
}
elsif ($num < 100) {
$num = "0$num";
}
return $num;
}
sub new_name {
if (/\.jpg$/) {
my $name = $File::Find::name;
my $new_name;
($new_name = $name) =~ s/^(.+\/[\w ]+\()(\d+)\)/$1 . &pad_left($2) .')'/e;
rename($name, $new_name);
print "$name --> $new_name\n";
}
}
chomp(my $localdir = `pwd`);# invoke the script in the parent-directory of the
# image-containing sub-directories
find(\&new_name, $localdir);
Rename
Also from above answer:
rename 's/\d+/sprintf("%04d",$&)/e' *.png

Answer 2

Fairly easy, although it combines a few features not immediately obvious:
#echo off
setlocal enableextensions enabledelayedexpansion
rem iterate over all PNG files:
for %%f in (*.png) do (
rem store file name without extension
set FileName=%%~nf
rem strip the "output_"
set FileName=!FileName:output_=!
rem Add leading zeroes:
set FileName=000!FileName!
rem Trim to only four digits, from the end
set FileName=!FileName:~-4!
rem Add "output_" and extension again
set FileName=output_!FileName!%%~xf
rem Rename the file
rename "%%f" "!FileName!"
)
Edit: Misread that you're not after a batch file but any solution in any language. Sorry for that. To make up for it, a PowerShell one-liner:
gci *.png|%{rni $_ ('output_{0:0000}.png' -f +($_.basename-split'_')[1])}
Stick a ?{$_.basename-match'_\d+'} in there if you have other files that do not follow that pattern.

Answer 3

I actually just needed to do this on OSX. Here's the scripts I created for it - single line!
> for i in output_*.png;do mv $i `printf output_%04d.png $(echo $i | sed 's/[^0-9]*//g')`; done

Answer 4

For mass renaming the only safe solution is mmv—it checks for collisions and allows renaming in chains and cycles, something that is beyond most scripts. Unfortunately, zero padding it ain't too hot at. A flavour:
c:> mmv output_[0-9].png output_000#1.png
Here's one workaround:
c:> type file
mmv
[^0-9][0-9] #1\00#2
[^0-9][0-9][^0-9] #1\00#2#3
[^0-9][0-9][0-9] #1\0#2#3
[^0-9][0-9][0-9][^0-9] #1\0#2#3
c:> mmv <file

Answer 5

Here is a Python script I wrote that pads zeroes depending on the largest number present and ignores non-numbered files in the given directory. Usage:
python ensure_zero_padding_in_numbering_of_files.py /path/to/directory
Body of script:
import argparse
import os
import re
import sys
def main(cmdline):
parser = argparse.ArgumentParser(
description='Ensure zero padding in numbering of files.')
parser.add_argument('path', type=str,
help='path to the directory containing the files')
args = parser.parse_args()
path = args.path
numbered = re.compile(r'(.*?)(\d+)\.(.*)')
numbered_fnames = [fname for fname in os.listdir(path)
if numbered.search(fname)]
max_digits = max(len(numbered.search(fname).group(2))
for fname in numbered_fnames)
for fname in numbered_fnames:
_, prefix, num, ext, _ = numbered.split(fname, maxsplit=1)
num = num.zfill(max_digits)
new_fname = "{}{}.{}".format(prefix, num, ext)
if fname != new_fname:
os.rename(os.path.join(path, fname), os.path.join(path, new_fname))
print "Renamed {} to {}".format(fname, new_fname)
else:
print "{} seems fine".format(fname)
if __name__ == "__main__":
sys.exit(main(sys.argv[1:]))

Answer 6

$rename output_ output_0 output_? # adding 1 zero to names ended in 1 digit
$rename output_ output_0 output_?? # adding 1 zero to names ended in 2 digits
$rename output_ output_0 output_??? # adding 1 zero to names ended in 3 digits
That's it!

Answer 7

with bash split,
linux
for f in *.png;do n=${f#*_};n=${n%.*};mv $f $(printf output_"%04d".png $n);done
windows(bash)
for f in *.png;do n=${f#*_};mv $f $(printf output_"%08s" $n);done

Answer 8

I'm following on from Adam's solution for OSX.
Some gotchyas I encountered in my scenario were:
I had a set of .mp3 files, so the sed was catching the '3' in the '.mp3' suffix. (I used basename instead of echo to rectify this)
My .mp3's had spaces within their names, E.g., "audio track 1.mp3", this was causing basename+sed to screw up a little bit, so I had to quote the "$i" parameter.
In the end, my conversion line looked like this:
for i in *.mp3 ; do mv "$i" `printf "track_%02d.mp3\n" $(basename "$i" .mp3 | sed 's/[^0-9]*//g')` ; done

Answer 9

Using ls + awk + sh:
ls -1 | awk -F_ '{printf "%s%04d.png\n", "mv "$0" "$1"_", $2}' | sh
If you want to test the command before runing it just remove the | sh

Answer 10

I just want to make time lapse movie using
ffmpeg -pattern_type glob -i "*.jpg" -s:v 1920x1080 -c:v libx264 output.mp4
and got a similar problem.
[image2 # 000000000039c300] Pattern type 'glob' was selected but globbing is not supported by this libavformat build
glob not support on Windows 7 .
Also if file list like below, and uses %2d.jpg or %02d.jpg
1.jpg
2.jpg
...
10.jpg
11.jpg
...
[image2 # 00000000005ea9c0] Could find no file with path '%2d.jpg' and index in the range 0-4
%2d.jpg: No such file or directory
[image2 # 00000000005aa980] Could find no file with path '%02d.jpg' and index in the range 0-4
%02d.jpg: No such file or directory
here is my batch script to rename flies
#echo off
setlocal enabledelayedexpansion
set i=1000000
set X=1
for %%a in (*.jpg) do (
set /a i+=1
set "filename=!i:~%X%!"
echo ren "%%a" "!filename!%%~xa"
ren "%%a" "!filename!%%~xa"
)
after rename 143,323 jpg files,
ffmpeg -i %6d.jpg -s:v 1920x1080 -c:v libx264 output.mp4