I need to get the week number of the giving date. For Ex jan 1 = week no is 1, Jan 8 - week 2 like this.. any one help me out pls.
You should try something like this:
DECLARE #Dt datetime
SELECT #Dt='02-21-2008'
SELECT DATEPART( wk, #Dt)
This should return the weeknumbers you want.
SQL Server starts counting from the 1st of january. If you want to return the ISO weeknumbers, you need to do a bit more scripting. A nice howto is listed in this site: http://www.rmjcs.com/SQLServer/TSQLFunctions/ISOWeekNumber/tabid/207/Default.aspx
MSDN: DATEPART (Transact-SQL)
In response to Robin's comment:
But i need in such a way, that from
jan 1 to 7, it should return 1, from
jan 8 to 17 it should return 2 like
this.. hope u got my impression
In that case you could also write something like this.
select (datepart(dy, '2011-01-01') / 7) + 1
--returns 1
select (datepart(dy, '2011-01-02') / 7) + 1
--returns 1
select (datepart(dy, '2011-12-31') / 7) + 1
--returns 53
I don't know how SQL Server 2008 responds with the iso_week and wk parameter as I only got a SQL 2005 instance available at the moment.
Does this do what you want?
declare #T table (dt datetime)
insert into #T values
('2010-12-31'),
('2011-01-01'),
('2011-01-02'),
('2011-01-03'),
('2011-01-04'),
('2011-01-05'),
('2011-01-06'),
('2011-01-07'),
('2011-01-08')
select
dt,
(datediff(d, dateadd(year, datediff(year, 0, dt), 0), dt) / 7)+1
from #T
Result
dt
----------------------- -----------
2010-12-31 00:00:00.000 53
2011-01-01 00:00:00.000 1
2011-01-02 00:00:00.000 1
2011-01-03 00:00:00.000 1
2011-01-04 00:00:00.000 1
2011-01-05 00:00:00.000 1
2011-01-06 00:00:00.000 1
2011-01-07 00:00:00.000 1
2011-01-08 00:00:00.000 2
Related
I have a code that traces a number of week of the date in a period that set by parameters
CREATE TABLE #test
(
job int,
dateL datetime
)
INSERT INTO #test
VALUES (1, '2021-10-04'),
(2, '2021-10-05'),
(3, '2021-10-11'),
(4, '2021-10-12')
DECLARE #startdate datetime = '2021-10-05',
#enddate datetime = '2021-12-03'
SELECT
dateL,
(CASE
WHEN t.DateL BETWEEN #startDate and #endDate
THEN (DATEDIFF(wk,#startDate, t.DateL)) + 1
ELSE -1
END) AS WeekNumber
FROM
#test t
DROP TABLE #test
The results of this
dateL WeekNumber
---------------------------------------
2021-10-04 00:00:00.000 -1
2021-10-05 00:00:00.000 1
2021-10-11 00:00:00.000 2
2021-10-12 00:00:00.000 2
But it now quite what I need, and I don't understand how to set this to start count from #startDate.
So it should count like:
05.10 - 11.10 - first week
12.20 - 18.10 - second week
and so on,
So it would look like that
dateL WeekNumber
-----------------------------------
2021-10-04 00:00:00.000 -1
2021-10-05 00:00:00.000 1
2021-10-11 00:00:00.000 *1*
2021-10-12 00:00:00.000 2
I tried to set ##datefirst to
datepart(weekday, #startDate)
but it just ignores me.
Could someone may be recommend something, thanks!
I am trying to create a 13 period calendar in mssql but I am a bit stuck. I am not sure if my approach is the best way to achieve this. I have my base script which can be seen below:
Set DateFirst 1
Declare #Date1 date = '20180101' --startdate should always be start of
financial year
Declare #Date2 date = '20181231' --enddate should always be start of
financial year
SELECT * INTO #CalendarTable
FROM dbo.CalendarTable(#Date1,#Date2,0,0,0)c
DECLARE #StartDate datetime,#EndDate datetime
SELECT #StartDate=MIN(CASE WHEN [Day]='Monday' THEN [Date] ELSE NULL END),
#EndDate=MAX([Date])
FROM #CalendarTable
;With Period_CTE(PeriodNo,Start,[End])
AS
(SELECT 1,#StartDate,DATEADD(wk,4,#StartDate) -1
UNION ALL
SELECT PeriodNo+1,DATEADD(wk,4,Start),DATEADD(wk,4,[End])
FROM Period_CTE
WHERE DATEADD(wk,4,[End])< =#EndDate
OR PeriodNo+1 <=13
)
select * from Period_CTE
Which gives me this:
PeriodNo Start End
1 2018-01-01 00:00:00.000 2018-01-28 00:00:00.000
2 2018-01-29 00:00:00.000 2018-02-25 00:00:00.000
3 2018-02-26 00:00:00.000 2018-03-25 00:00:00.000
4 2018-03-26 00:00:00.000 2018-04-22 00:00:00.000
5 2018-04-23 00:00:00.000 2018-05-20 00:00:00.000
6 2018-05-21 00:00:00.000 2018-06-17 00:00:00.000
7 2018-06-18 00:00:00.000 2018-07-15 00:00:00.000
8 2018-07-16 00:00:00.000 2018-08-12 00:00:00.000
9 2018-08-13 00:00:00.000 2018-09-09 00:00:00.000
10 2018-09-10 00:00:00.000 2018-10-07 00:00:00.000
11 2018-10-08 00:00:00.000 2018-11-04 00:00:00.000
12 2018-11-05 00:00:00.000 2018-12-02 00:00:00.000
13 2018-12-03 00:00:00.000 2018-12-30 00:00:00.000
The result i am trying to get is
Even if I have to take a different approach I would not mind, as long as the result is the same as the above.
dbo.CalendarTable() is a function that returns the following results. I can share the code if desired.
I'd create a general number's table like suggested here and add a column Periode13.
The trick to get the tiling is the integer division:
DECLARE #PeriodeSize INT=28; --13 "moon-months" a 28 days
SELECT TOP 100 (ROW_NUMBER() OVER(ORDER BY (SELECT NULL))-1)/#PeriodeSize
FROM master..spt_values --just a table with many rows to show the principles
You can add this to an existing numbers table with a simple update statement.
UPDATE A fully working example (using the logic linked above)
DECLARE #RunningNumbers TABLE (Number INT NOT NULL
,CalendarDate DATE NOT NULL
,CalendarYear INT NOT NULL
,CalendarMonth INT NOT NULL
,CalendarDay INT NOT NULL
,CalendarWeek INT NOT NULL
,CalendarYearDay INT NOT NULL
,CalendarWeekDay INT NOT NULL);
DECLARE #CountEntries INT = 100000;
DECLARE #StartNumber INT = 0;
WITH E1(N) AS(SELECT 1 FROM(VALUES (1),(1),(1),(1),(1),(1),(1),(1),(1),(1))t(N)), --10 ^ 1
E2(N) AS(SELECT 1 FROM E1 a CROSS JOIN E1 b), -- 10 ^ 2 = 100 rows
E4(N) AS(SELECT 1 FROM E2 a CROSS JOIN E2 b), -- 10 ^ 4 = 10,000 rows
E8(N) AS(SELECT 1 FROM E4 a CROSS JOIN E4 b), -- 10 ^ 8 = 10,000,000 rows
CteTally AS
(
SELECT TOP(ISNULL(#CountEntries,1000000)) ROW_NUMBER() OVER(ORDER BY(SELECT NULL)) -1 + ISNULL(#StartNumber,0) As Nmbr
FROM E8
)
INSERT INTO #RunningNumbers
SELECT CteTally.Nmbr,CalendarDate.d,CalendarExt.*
FROM CteTally
CROSS APPLY
(
SELECT DATEADD(DAY,CteTally.Nmbr,{ts'2018-01-01 00:00:00'})
) AS CalendarDate(d)
CROSS APPLY
(
SELECT YEAR(CalendarDate.d) AS CalendarYear
,MONTH(CalendarDate.d) AS CalendarMonth
,DAY(CalendarDate.d) AS CalendarDay
,DATEPART(WEEK,CalendarDate.d) AS CalendarWeek
,DATEPART(DAYOFYEAR,CalendarDate.d) AS CalendarYearDay
,DATEPART(WEEKDAY,CalendarDate.d) AS CalendarWeekDay
) AS CalendarExt;
--The mockup table from above is now filled and can be queried
WITH AddPeriode AS
(
SELECT Number/28 +1 AS PeriodNumber
,CalendarDate
,CalendarWeek
,r.CalendarDay
,r.CalendarMonth
,r.CalendarWeekDay
,r.CalendarYear
,r.CalendarYearDay
FROM #RunningNumbers AS r
)
SELECT TOP 100 p.*
,(SELECT MIN(CalendarDate) FROM AddPeriode AS x WHERE x.PeriodNumber=p.PeriodNumber) AS [Start]
,(SELECT MAX(CalendarDate) FROM AddPeriode AS x WHERE x.PeriodNumber=p.PeriodNumber) AS [End]
,(SELECT MIN(CalendarDate) FROM AddPeriode AS x WHERE x.PeriodNumber=p.PeriodNumber AND x.CalendarWeek=p.CalendarWeek) AS [wkStart]
,(SELECT MAX(CalendarDate) FROM AddPeriode AS x WHERE x.PeriodNumber=p.PeriodNumber AND x.CalendarWeek=p.CalendarWeek) AS [wkEnd]
,(ROW_NUMBER() OVER(PARTITION BY PeriodNumber ORDER BY CalendarDate)-1)/7+1 AS WeekOfPeriode
FROM AddPeriode AS p
ORDER BY CalendarDate
Try it out...
Hint: Do not use a VIEW or iTVF for this.
This is non-changing data and much better placed in a physically stored table with appropriate indexes.
Not abundantly sure external links are accepted here, but I wrote an article that pulls of a 5-4-4 'Crop Year' fiscal year with all the code. Feel free to use all the code in these articles.
SQL Server Calendar Table
SQL Server Calendar Table: Fiscal Years
Consider the below data:
ID Reference Manager LeaseFirstStart LeaseStop
1 KLEIN John 2008-04-02 00:00:00.000 2010-04-01 00:00:00.000
2 HAWKER John 2008-12-18 00:00:00.000 2010-09-17 00:00:00.000
3 SLEEP Bob 2008-01-23 00:00:00.000 2009-01-22 00:00:00.000
4 CODD Bob 2009-08-03 00:00:00.000 2010-08-02 00:00:00.000
5 ALLEN Bob 2008-01-30 00:00:00.000 2009-07-31 00:00:00.000
The earliest month is Jan 2008 and the latest month is Sep 2010.
How can I count the number of leases that were current per month? The output should look like this:
Month Number of Leases
2008-01 2
2008-02 2
2008-03 2
2008-04 3
2008-05 3
2008-06 3
2008-07 3
2008-08 4
… …
Ultimately, I want to use the answer to the question to create the dataset below for use in excel by the user so they can see who had how many leases during the data period.
Month Manager Number of Leases
2008-01 Bob 2
2008-01 John 0
2008-02 Bob 2
2008-02 John 0
2008-03 Bob 2
2008-03 John 0
2008-04 Bob 2
2008-04 John 1
2008-05 Bob 2
2008-05 John 1
2008-06 Bob 2
2008-06 John 1
2008-07 Bob 2
2008-07 John 1
2008-08 Bob 3
2008-08 John 1
… … …
I know I've done it before, but it was a long time ago and I remember it being messy. Thanks in advance!
select sum (no) as no,datet from ( SELECT COUNT (*) as no ,(convert(varchar,datepart (yyyy,[ Start] )) + '-' + convert(varchar, MONTH([ Start] ))) as datet
FROM <tbl>
GROUP BY (convert(varchar,datepart (yyyy,[ Start] )) + '-' + convert(varchar, MONTH([ Start] )))
union SELECT COUNT (*) as no ,(convert(varchar,datepart (yyyy,[ End] )) + '-' + convert(varchar, MONTH([ End] ))) as datet
FROM <tbl>
GROUP BY (convert(varchar,datepart (yyyy,[ End] )) + '-' + convert(varchar, MONTH([ End] )) ) ) t
This is very logical question, finally I created the sql which gives the desired result.. I verified every date and month count and its all ok.
Declare #t table (ID int, Reference varchar(50), Manager varchar(50),LeaseFirstStart datetime,LeaseStop datetime)
insert into #t
values
(1,'KLEIN','John','2008-04-02 00:00:00.000','2010-04-01 00:00:00.000'),
(2,'HAWKER','John','2008-12-18 00:00:00.000','2010-09-17 00:00:00.000'),
(3,'SLEEP','Bob','2008-01-23 00:00:00.000','2009-01-22 00:00:00.000'),
(4,'CODD','Bob','2009-08-03 00:00:00.000','2010-08-02 00:00:00.000'),
(5,'ALLEN','Bob','2008-02-28 00:00:00.000','2009-07-31 00:00:00.000')
declare #lowerdate datetime , #currentdt datetime
select #lowerdate = min(leasefirststart), #currentdt= max(leasestop) from #t
;with cte as
(
select firstday,DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, FirstDay) + 1, 0)) Lastday, mng from
( select dateadd(m,datediff(m,0,#lowerdate)+v.number,0) as FirstDay
From master..spt_values v
Where v.type='P' and v.number between 0 and datediff(m, #lowerdate, #currentdt)
) as a
, (select distinct manager mng from #t ) as b
)
select (convert(varchar,datepart (yyyy,FirstDay )) + '-' + convert(varchar, MONTH(FirstDay ))) MonthAndYear ,mng as mng , count( manager ) cnt
from cte
left join #t on
(
firstday between LeaseFirstStart and LeaseStop
or
Lastday between LeaseFirstStart and LeaseStop
) and cte.mng = Manager
group by firstday, mng
order by FirstDay
Can you help out with a problem
I have table price table which has daily prices starting 31st Dec 2010 till todays date.The table contains daily prices
2009-12-31 00:00:00.000 1.0020945351
2010-01-01 00:00:00.000 1.0021009300
2010-01-04 00:00:00.000 1.0021910181
2010-01-05 00:00:00.000 1.0022005986
2010-01-06 00:00:00.000 1.0022428696
2010-01-07 00:00:00.000 1.0022647147
2010-01-08 00:00:00.000 1.0022842726
2010-01-11 00:00:00.000 1.0023374302
2010-01-12 00:00:00.000 1.0023465374
2010-01-13 00:00:00.000 1.0023638081
2010-01-14 00:00:00.000 1.0023856533
2010-01-00 00:00:00.000 1.0024083955
2010-01-18 00:00:00.000 1.0024779677
2010-01-19 00:00:00.000 1.0025020553
2010-01-20 00:00:00.000 1.002521135
2010-01-21 00:00:00.000 1.0025420688
2010-01-22 00:00:00.000 1.0025593397
2010-01-25 00:00:00.000 1.0026180146
2010-01-26 00:00:00.000 1.002637573
2010-01-27 00:00:00.000 1.0026648447
2010-01-28 00:00:00.000 1.0026957934
2010-01-29 00:00:00.000 1.0027267421
2010-02-01 00:00:00.000 1.0028195885
2010-02-02 00:00:00.000 1.0028573523
2010-02-03 00:00:00.000 1.0028964611
2010-02-04 00:00:00.000 1.00293557
2010-02-05 00:00:00.000 1.002973334
2010-02-08 00:00:00.000 1.0030879717
2010-02-09 00:00:00.000 1.0031279777
2010-02-10 00:00:00.000 1.003171166
2010-02-11 00:00:00.000 1.0032007452
2010-02-12 00:00:00.000 1.0032575895
2010-02-00 00:00:00.000 1.0033749191
2010-02-1 00:00:00.000 1.0034140292
2010-02-17 00:00:00.000 1.003452691
2010-02-18 00:00:00.000 1.0034918013
2010-02-19 00:00:00.000 1.0035395633
2010-02-22 00:00:00.000 1.0036664439
2010-02-23 00:00:00.000 1.0037042097
2010-02-24 00:00:00.000 1.0037510759
2010-02-25 00:00:00.000 1.0038001834
2010-02-26 00:00:00.000 1.003850077
I need to write a query to get index based on
(Last day of current month/Previous month last day) - 1 * 100.So that output comes something like this
31-Jan-10 0.01%
28-Feb-10 0.02%
31-Mar-10 0.00%
Following is one of the solution I thought about however please share best ideas to implement this problem
Extract last day of all the months with values into a temp table and then order by dates so that they subtract and put the values into another temp table
Looking forward to your help.
Try this....
DECLARE #StartDate DATETIME = '2010-01-01',
#EndDate DATETIME = GETDATE();
WITH data AS (
SELECT 1 AS i, CONVERT(DATETIME, NULL) AS StartDate, DATEADD(MONTH, 0, #StartDate) - 1 AS EndDate
UNION ALL
SELECT i + 1, data.EndDate, DATEADD(MONTH, i, #StartDate) - 1 AS EndDate
FROM data
WHERE DATEADD(MONTH, i, #StartDate) - 1 < #EndDate
)
SELECT (
((SELECT TOP 1 Rate FROM RateTable WHERE Date <= data.EndDate ORDER BY Date DESC) /
(SELECT TOP 1 Rate FROM RateTable WHERE Date <= data.StartDate ORDER BY Date DESC)- 1) * 100)
FROM DATA -- parenthesis were causing issues
WHERE data.StartDate IS NOT NULL
OPTION (MAXRECURSION 10000);
You'll need to replace the
(SELECT Rate FROM RateTable WHERE Date = data.StartDate)
and
(SELECT Rate FROM RateTable WHERE Date = data.EndDate)
With the values for your rate table. as you didn't mention column and table names in your question.
rwking indicated that there might be gaps in the rates table that would cause issues.
I've modified the subquery to bring back the first rate on or nearest the start and end dates.
Hope that helps
You can use the LAG function introduced in SQL2012 to make it a bit easier:
WITH DataWithOrder AS
(
SELECT DateField, PriceField,
ROW_NUMBER() OVER(PARTITION BY YEAR(DateField), Month(DateField) ORDER BY DateField DESC) AS Pos
FROM PriceTable
)
SELECT
DateField,
PriceField,
LAG(PriceField) OVER(ORDER BY DateField) AS PriceLastMonth,
((PriceField / LAG(PriceField) OVER(ORDER BY DateField)) - 1) * 100 AS PCIncrease
FROM DataWithOrder
WHERE Pos = 1
ORDER BY DateField
I took a very different approach than the other guy. His is more elegant and would work better if the daily data does represent every single day of every month. If there are gaps in days, however, as your sample data represents, you can try the following code.
with cte as (select mydate
, price
, ROW_NUMBER() over(partition by YEAR(mydate), MONTH(mydate)
order by day(mydate) desc) row_n
from #temp)
select mydate, price, ROW_NUMBER() over(order by mydate desc) row_num
into #temp2
from cte
where row_n = 1
alter table #temp2
add idx float
declare #counter int = 1
while #counter < (select MAX(row_num)+1 from #temp2)
begin
update t2
set t2.idx = ((t2.price/t3.price)-1)*100
from #temp2 t2 left join
#temp2 t3 on 1 = 1
where t2.row_num = #counter and t3.row_num = #counter + 1
set #counter = #counter + 1
end
select mydate, idx
from #temp2
As the other poster mentioned, you didn't provide column or table names. My process was to insert your data into a table called [#temp] with column names [mydate] and [price].
Also, the data sample you provided contains two invalid dates that I changed to arbitrary dates just for the purposes of getting code to run. (2010-01-00 and 2010-02-00)
I have a sql query that is grouping rows by calendar week
select count(*),datepart(wk,mydate)
from MyTable
where mydate between '12/26/2010' and '1/8/2011'
group by datepart(wk,mydate)
The date range is two weeks but three rows come back because Jan 1 is a saturday and is the only day in the range that DATEPART returns a 1 the other dates return 53 or 2.
I want jan 1 to be grouped with the dates that return a 53, but I want it to be a generic answer not something like CASE WHEN datepart(wk,mydate) = 53 then 1 else datepart(wk,mydate) end because that will work for that specific date range not for other years.
I'm just wondering what a good solution would be
thanks in advance.
We use to choose as week of a date, the week of his last sunday (first day of the week in SQL). So, for each date, you can ask for the week of his last sunday with the following query:
select count(*),datepart(wk,mydate-DATEPART(dw,mydate)+1)
from MyTable
where mydate between '12/26/2010' and '1/8/2011'
group by datepart(wk,mydate-DATEPART(dw,mydate)+1)
Perhaps you can use iso_week instead of wk.
select count(*),datepart(iso_week,mydate)
from MyTable
where mydate between '12/26/2010' and '1/8/2011'
group by datepart(iso_week,mydate)
Sample:
declare #T table (Val datetime)
insert into #T values
('2010-12-30'),
('2010-12-31'),
('2011-01-01'),
('2011-01-02'),
('2011-01-03'),
('2011-01-04'),
('2011-01-05')
select
Val,
datepart(iso_week, Val) as ISO_WEEK
from #T
Result:
Val ISO_WEEK
----------------------- -----------
2010-12-30 00:00:00.000 52
2010-12-31 00:00:00.000 52
2011-01-01 00:00:00.000 52
2011-01-02 00:00:00.000 52
2011-01-03 00:00:00.000 1
2011-01-04 00:00:00.000 1
2011-01-05 00:00:00.000 1
Try DateDiff() instead with your start date as the date to compare.