How can I save and open a file in winForms? - winforms

Question

I have this application where I use windowsForm and UserControl to draw some diagrams. After I am done I want to save them or I want to open an existing file that I created before and keep working on the diagram. So, I want to use the save and open dialog File to save or open my diagrams.
EDIT:
this is what i have :
//save the object to the file
public bool ObjectToFile(Object model, string FileName)
{
try
{
System.IO.MemoryStream _MemoryStream = new System.IO.MemoryStream();
System.Runtime.Serialization.Formatters.Binary.BinaryFormatter _BinaryFormatter = new System.Runtime.Serialization.Formatters.Binary.BinaryFormatter();
_BinaryFormatter.Serialize(_MemoryStream, model);
byte[] _ByteArray = _MemoryStream.ToArray();
System.IO.FileStream _FileStream = new System.IO.FileStream(FileName, System.IO.FileMode.Create, System.IO.FileAccess.Write);
_FileStream.Write(_ByteArray.ToArray(), 0, _ByteArray.Length);
_FileStream.Close();
_MemoryStream.Close();
_MemoryStream.Dispose();
_MemoryStream = null;
_ByteArray = null;
return true;
}
catch (Exception _Exception)
{
Console.WriteLine("Exception caught in process: {0}", _Exception.ToString());
}
return false;
}
//load the object from the file
public Object FileToObject(string FileName)
{
try
{
System.IO.FileStream _FileStream = new System.IO.FileStream(FileName, System.IO.FileMode.Open, System.IO.FileAccess.Read);
System.IO.BinaryReader _BinaryReader = new System.IO.BinaryReader(_FileStream);
long _TotalBytes = new System.IO.FileInfo(FileName).Length;
byte[] _ByteArray = _BinaryReader.ReadBytes((Int32)_TotalBytes);
_FileStream.Close();
_FileStream.Dispose();
_FileStream = null;
_BinaryReader.Close();
System.IO.MemoryStream _MemoryStream = new System.IO.MemoryStream(_ByteArray);
System.Runtime.Serialization.Formatters.Binary.BinaryFormatter _BinaryFormatter = new System.Runtime.Serialization.Formatters.Binary.BinaryFormatter();
_MemoryStream.Position = 0;
return _BinaryFormatter.Deserialize(_MemoryStream);
}
catch (Exception _Exception)
{
Console.WriteLine("Exception caught in process: {0}", _Exception.ToString());
}
return null;
}
and now I want to do this but it's not working
public void save()
{
SaveFileDialog saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.Filter = "txt files (*.txt)|*.txt";
saveFileDialog1.FilterIndex = 2;
saveFileDialog1.RestoreDirectory = true;
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
if (saveFileDialog1.OpenFile() != null)
{
ObjectToFile(model, saveFileDialog1.FileName);
}
}
}
but if I try without the fileDialog and i just use
ObjectToFile(model, "d:\\objects.txt");
this works. And I want to save it where I want and with my own name.

Answer 1

Check out the SaveFileDialog and OpenFileDialog classes. They are pretty similar, and can be used like this:
using(SaveFileDialog sfd = new SaveFileDialog()) {
sfd.Filter = "Text Files|*.txt|All Files|*.*";
if(sfd.ShowDialog() != DialogResult.OK) {
return;
}
ObjectToFile(sfd.FileName);
}
The mechanics of actually saving your file are, obviously, outside the scope of this answer.
Edit: I've updated my answer to reflect the new information in your post.