I have a small program that which is confusing me. I am trying using a loop to take input from user. In case input is wrong, it is repeated again but if it is right, it exits.
The code snippet is:
void main()
{
char user_status; // Checks User Status q = Quiz Master and p = Participant
int valid_status = '0'; // Checks If User Status Is Valid Or Not. Used In Some Loops. 0 = Invalid, 1 = Invalid.
printf("Welcome to General Knowledge Quiz Management System.\nThis application has been designed to help you conduct a quiz or test your GK.");
do
{
user_status = '0';
printf("\n\nPlease enter your role.\nQuiz Master = \'q\'\nParticipant = \'p\'\n");
scanf("%c", &user_status);
if (user_status == 'q'|| user_status == 'Q')
{
printf("Initializing Quiz Master Segment\n\n________________________________\n");
initiate_qm();
valid_status = '1';
}
else if (user_status == 'p' || user_status == 'P')
{
printf("Initializing Participant Segment");
initiate_pa();
valid_status = '1';
}
}
while (valid_status != '1')
printf("\nProgram Will Exit Now. Press Any Key To Return To Windows.");
getch();
}
I am expecting this output:
Please Enter Your Role
Quiz Master = 'q'
Participant = 'p'
Till now, it works great. When I input q/Q/p/P, it works great. But when I input something wrong, it does not give required output.
For example, if I input "abc", I should get the above text again asking me to input q or p. But instead, I get this:
Please Enter Your Role
Quiz Master = 'q'
Participant = 'p'
Please Enter Your Role
Quiz Master = 'q'
Participant = 'p'
Please Enter Your Role
Quiz Master = 'q'
Participant = 'p'
Please Enter Your Role
Quiz Master = 'q'
Participant = 'p'
_ (I have to input here)
Now, why is it repeating 3 extra times. One interesting thing to note is that if I input something that is 2 characters long, it repeats 2 extra times and if I leave it blank(just hit return), it does not repeat extra times.
I have to use only C. I am using Visual C++ 2010 to compile.
Thanks.
Because you have given scanf three characters to process. It removes first first character the first time it calls scanf getting 'a', but still has 'bc' left in the stdin buffer.
You need to check for leftover stuff in your buffer before you look for input again. And I'd avoid flushing the stdin buffer because it's undefined behavior. (http://www.gidnetwork.com/b-57.html)
You can read the remaining characters and discard them with
do{
scanf("%c", &user_status);
}while(user_status!='\n'); //This discards all characters until you get to a newline
right after you read the character you want.
You want
do
{
} while (condition);
As your forgot the semicolon, you get:
do
{
....
}
while(condition)
do something else;
You could have noticed that just by auto-indenting your code in an editor like I did on your question.
Also when you do some scanf you should rather include the \n in the format specification.
First of all, # include <stdio.h> and use getc(stdin) to get a character. It'll help you to prevent cursor from moving and putting unnecessary characters to console.
Secondly, write the welcome message before the loop.
Related
The following code does not execute the last else if statement when you assign to choice value 3.
#include<stdio.h>
#include<stdlib.h>
int main() {
puts("Specify with a number what is that you want to do.");
puts("1. Restore wallet from seed.");
puts("2. Generate a view only wallet.");
puts("3. Get guidance on the usage from within monero-wallet-cli.");
unsigned char choice;
choice = getchar();
if ( choice == '1' ) {
system("nice -19 ~/monero-x86_64-linux-gnu-v0.17.2.0/monero-wallet-cli --testnet --restore-deterministic-wallet");
exit(0);
}
else if ( choice == '2' ) {
system("nice -19 ~/monero-x86_64-linux-gnu-v0.17.2.0/monero-wallet-cli --testnet --generate-from-view-key wallet-view-only");
exit(0);
}
else if ( choice == '3' ) {
puts("Specify with a number what is that you want to do.");
puts("1. Get guidance in my addresses and UTXOs");
puts("2. Pay");
puts("3. Get guidance on mining.");
unsigned char choicetwo = getchar();
if ( choicetwo == '1' ) {
printf("Use \033address all\033 to get all your addresses that have any balance, or that you have generated at this session.");
printf("Use \033balance\033 to get your balance");
printf("Use \033show_transfers\033 to get ");
printf("Use \033show_transfers\033 out to get ");
printf("Use \033show_transfers in\033 to get your balance");
}
}
return 0;
}
I get the following output When I enter 3:
Specify with a number what is that you want to do.
1. Restore wallet from seed.
2. Generate a view only wallet.
3. Get guidance on the usage from within monero-wallet-cli.
3
Specify with a number what is that you want to do.
1. Get guidance in my addresses and UTXOs
2. Pay
3. Get guidance on mining.
I'm really blocked, something is missing and I have no clue why it does not proceed to take the input from the user for the second time.
When you enter "3" for the first input, you're actually inputting two characters: the character '3' and a newline. The first getchar function reads "3" from the input stream, and the second one reads the newline.
After accepting the first input, you'll want to call getchar in a loop until you read a newline to clear the input buffer.
choice = getchar();
while (getchar() != '\n');
I am trying something simple in C, a program to get the exchange and do some conversions.
To make sure scanf gets the right type I placed it into a while loop, which continues to ask for input until a number is inserted.
If I enter a character instead of a number it does not ask again for an input.
exRate = 0;
scanfRes = 0;
while(exRate <= 0){
printf("Enter the exchange rate:");
while(scanfRes != 1){
scanfRes = scanf(" %f", &exRate);
}
if(scanfRes == 1 && exRate > 0){
break;
}
printf("Exchange rate must be positive.\n");
}
UPDATE: As this is a course assignment, I was not supposed to use anything outside of the taught material. When I asked the academic staff about handling unexpected input, I got an answer that this is a scenario I am not supposed to take into consideration.
The answers and help in the comments is all useful and I added 1 to all useful suggestions. The staff answer makes this question no longer needed.
Change handling of scanf() result.
If the input is not as expected, either the offending input data needs to be read or EOF should be handled.
for (;;) {
printf("Enter the exchange rate:");
scanfRes = scanf("%f", &exRate);
if (scanfRes == 0) {
printf("Exchange rate must be numeric.\n");
// somehow deal with non-numeric input, here just 1 char read & tossed
// or maybe read until end-of-line
fgetc(stdin);
} else if (scanfRes == EOF) {
// Handle EOF somehow
return;
} exRate > 0){
break;
}
printf("Exchange rate must be positive.\n");
}
Note: the " " in " %f" is not needed. "%f" will consume leading white-space.
I have a work to do in which I have to keep a loop inside the function expecting the following parameters:
-"i" to insert
-"s" to search
-"q" to quit
How do I keep this loop? I've looked up some options and it seems to be possible using a while or a switch, but I am not sure which is the best way to read those chars (with a fscanf perhaps?). I am also not sure how to read the things after the parameter "i" as the input would be "i word 9", so after detecting the i to insert I have to read a string and an int.
Anyone has any idea how to do this? I am sorry is this seems simple, but I am new to programming.
edit: Here is what I have so far
while (loop) {
fscanf(stdin,"%c",&par);
if (strcmp(&par,"i")){
scanf("%s %d",palavra,p);
raiz = insere(raiz,&palavra,p);
}
else if (strcmp(&par,"b")){
scanf("%s",palavra);
busca(raiz,&palavra);
}
else if (strcmp(&par,"q"))
loop = 0;
}
edit 2: This is what I have now, I am having problems reading the string and integer when the parameter is i, somehow it crashes the function
while (1) {
c = getchar();
if (c == 'f')
break;
else if (c == 'i'){
fscanf(stdin,"%s",&palavra);
scanf("%d",&p);
raiz = insere(raiz,palavra,p);
}
else if (c == 'b') {
scanf("%s",palavra);
busca(raiz,palavra);
}
}
Thanks in advance!
The code you have doesn't look too bad compared to what I believe you want. You can replace the "while (loop)" with "while (1)" and then your exist code "loop = 0;" with "break;" which is a bit more standard way of doing things. Also "fscanf(stdin..." is the same as "scanf(..." ... scanf will read from stdin by default. You might want to check the docs for strcmp because it returns 0 for an exact match and I don't think that will do what you want in your 'if' statements. You should be able to use scanf to read in the values you want, is it giving you an error?
You are using 3 separated scans. That means you can't input this "i word 9", but input one command or parameter at the time separated by EOL(pressing enter).. i, enter, word, enter, 9, enter ... Then the function should actually get further in those "if"s. With those scans you also should consider printing information about expected inputs ("Choose action q/i/f")
And I would recommend using something to test those inputs.
if (scanf("%d", &p) == 0) {
printf("Wrong input");
break;
}
I am having a problem with a segmentation fault working in C, and I cannot figure out why this is occurring. I think it has something to do with misuse of the fget(c) function.
while((ch = fgetc(fp))!= EOF) {
printf("Got inside first while: character is currently %c \n",ch); //**********DELETE
while(ch != '\n') {
char word[16]; //Clear out word before beginning
i = i+1; //Keeps track of the current run thru of the loop so we know what input we're looking at.
while(ch != ' ') {
printf("%c ",ch); //**********DELETE
//The following block builds up a character array from the current "word" (separated by spaces) in the input file.
int len = strlen(word);
word[len] = ch;
word[len+1] = '\0';
printf("%s",word);
ch = fgetc(fp);
}
//The following if-else block sets the variables TextA, TextB, and TextC to the appropriate Supply Types from the input.
//This part may be confusing to read mentally, but not to trace. All it does is logically set TextA, B, and C to the 3 different possible values SupplyType.
if(word!=TextB && word!=TextC && i==1 && TextB!="") {
strcpy(TextA,word);
}
else if(word!=TextA && word!=TextC && i==1 && TextC!="") {
strcpy(TextB,word);
}
else if(word!=TextB && word!=TextA && i==1) {
strcpy(TextC,word);
}
switch(i) {
case 1:
if(TextA == word) {
SubTypeOption = 1;
}
else if(TextB == word) {
SubTypeOption = 2;
}
else if(TextC == word) {
SubTypeOption = 3;
}
break;
case 2:
//We actually ultimately don't need to keep track of the product's name, so we do nothing for case i=2. Included for readibility.
break;
case 3:
WholesalePrice = atof(word);
break;
case 4:
WholesaleAmount = atoi(word);
break;
case 5:
RetailPrice = atof(word);
break;
case 6:
RetailAmount = atoi(word);
break;
}//End switch(i)
ch = fgetc(fp);
}//End while(ch != '\n')
//The following if-else block "tallys up" the total amounts of SubTypes bought and sold by the owner.
if(SubTypeOption == 1) {
SubType1OwnersCost = SubType1OwnersCost + (WholesalePrice*(float)WholesaleAmount);
SubType1ConsumersCost = SubType1ConsumersCost + (RetailPrice *(float)RetailAmount);
}
else if(SubTypeOption == 2) {
SubType2OwnersCost = SubType2OwnersCost + (WholesalePrice*(float)WholesaleAmount);
SubType2ConsumersCost = SubType2ConsumersCost + (RetailPrice *(float)RetailAmount);
}
else if(SubTypeOption == 3) {
SubType3OwnersCost = SubType3OwnersCost + (WholesalePrice*(float)WholesaleAmount);
SubType3ConsumersCost = SubType3ConsumersCost + (RetailPrice *(float)RetailAmount);
}
}//End while((ch = fgetc(fp))!= EOF)
Using gdb (just a simple run of the a.out) I found that the problem is related to getc, but it does not tell which line/which one. However, my program does output "Got in side the first while: character is currently S". This S is the first letter in my input file, so I know it is working somewhat how it should, but then causes a seg fault.
Does anyone have any advice on what could be going wrong, or how to debug this problem? I am relatively new to C and confused mostly on syntax. I have a feeling I've done some small syntactical thing wrong.
By the way, this snippet of the code is meant to get a word from a string. Example:
Help me with this program please
should give word equaling "Help"
Update: Now guys I am getting kind of a cool error (although cryptic). When I recompiled I got something like this:
word is now w S
word is now w Su
word is now w Sup
... etc except it goes on for a while, building a pyramid of word.
with my input file having only the string "SupplyTypeA 1.23 1 1.65 1" in it.
UPDATE: Segmentation fault was fixed (the issue was, I was going past the end of the file using fgetc() ). Thanks everyone.
If anyone still glances at this, could they help me figure out why my output file does not contain any of the correct numbers it should? I think I am probably misusing atof and atoi on the words I'm getting.
Make sure you compile the program with -g -O0 options
Next step through the program line by line in GDB, watch and understand what your program is doing. Look at the various variables. This is the essential debugging skill.
WHen it dies type the command 'k' this will give you a stack trace the last line of the trace will have the failing line number, but you know that anyway because you were on the line shen you did a step command
There is no "fget" in good old C, but maybe you're using a more modern version that has something named "fget". Most likely, you meant to use "fgetc". When a C I/O function starts with "f", it usually wants a FILE* handle as an argument, as "fgetc" does. Try using "fgetc" instead, after reading the documentation for it.
have wrote this app which reads input from console.
for(; ; )
{
GetNumberOfConsoleInputEvents(stdinInput, &numEvents);
if (numEvents != 0) {
INPUT_RECORD eventBuffer;
ReadConsoleInput(stdinInput, &eventBuffer, 1, &numEventsRead);
if (eventBuffer.EventType == KEY_EVENT) {
if(eventBuffer.Event.KeyEvent.bKeyDown)
{
printf("%c",eventBuffer.Event.KeyEvent.uChar.AsciiChar);
dataBuffer[bufferLen++] = eventBuffer.Event.KeyEvent.uChar.AsciiChar;
dataBuffer[bufferLen] = '\0';
if ( dataBuffer[bufferLen] == 99 || eventBuffer.Event.KeyEvent.uChar.AsciiChar == '\r' ) {
printf("User Wrote: %s\n",dataBuffer);
memset(dataBuffer,0,sizeof(dataBuffer));
bufferLen = 0;
}
}
}
}
}
It puts the data on a buffer and then it prints out the buffer. The problem occurs when im using Shift or CapsLock to write Capital letters or ! # # $ % characters. Then it prints out NOTHING.
Ive tried something with the VK_LSHIFT code but didn't worked.
Also if try to write something in other language than English it prints out something like this ▒├╞▒├╞▒├│▒├│ It cannot recognize the other language.
Can someone give me a hint on how to fix those problems ?
Thanks!
ReadConsoleInput returns events for each keystroke. For example, if you type SHIFT+A to get a capital A then you'll receive four key events: SHIFT down, A down, A up, SHIFT up.
The SHIFT key does not have a corresponding ASCII code so eventBuffer.Event.KeyEvent.uChar.AsciiChar is set to zero. This zero terminates the string you are building in dataBuffer so you don't see anything typed after the SHIFT key.
The simplest fix is to ignore any key event with an ASCII code of zero.
Additionally, if you want this to work well with foreign languages you might do better to use ReadConsoleInputW and eventBuffer.Event.KeyEvent.uChar.UnicodeChar. Better yet, compile it all as a Unicode app.