I give two different date as a input. i want to find, what are date between two date..
For eg:
1'st Input is : 2011-02-20
2'nd input is : 2011-02-25
Output is:
2011-02-20
2011-02-21
2011-02-22
2011-02-23
2011-02-24
2011-02-25
Is there any function to find the between date...
otherwise how to find ?
You can use a CTE to achieve this.
DECLARE #StartDate DATETIME
DECLARE #EndDate DATETIME
SET #StartDate = '2011-02-20'
SET #EndDate = '2011-02-25'
;WITH GetDates AS
(
SELECT 1 as counter, #StartDate AS Date
UNION ALL
SELECT counter + 1, DATEADD( day, counter, #StartDate )
FROM GetDates
WHERE DATEADD( day, counter, #StartDate ) <= #EndDate
)
SELECT Date FROM GetDates
See:
Why should I consider using an auxiliary calendar table?
A calendar table can make it much
easier to develop solutions around any
business model which involves dates.
Last I checked, this encompasses
pretty much any business model you can
think of, to some degree. Constant
problems that end up requiring
verbose, complicated and inefficient
methods include the following
questions: How many business days
between x and y? ...
SELECT Date = #StartDate + number
FROM master..spt_values
WHERE type = 'P'
AND number BETWEEN 0 AND DATEDIFF(day, #StartDate, #EndDate)
Note: This solution is not applicable when the distance between the two dates is more than 2047 days.
Related
Looking for the most efficient and elegant way to do truncate the time to the minute
-- I need to truncate the time to the minute,
-- this code almost works but rounds up
SELECT
CAST('2021-09-02T15:15:30.9233333' AS datetime2(7)) AS EventDatetime2,
CAST(CAST('2021-09-02T15:15:30.9233333' AS datetime2(7)) AS TIME(0)) AS EventTime
As Larnu posted, if you want to round up or down depending on the seconds value, a simple convert to smalldatetime will do.
If you want to truncate, there are several ways, the simplest is probably just to add minutes to midnight (only posting because I prefer without the magic dates like 1900-01-01):
DECLARE #dt datetime2(7) = '2021-09-02T15:15:30.9233333';
DECLARE #d datetime2(7) = CONVERT(date, #dt);
SELECT DATEADD(MINUTE, DATEDIFF(MINUTE, #d, #dt), #d);
Another way is more intuitive but a little ugly:
DECLARE #dt datetime2(7) = '2021-09-02T15:15:30.9233333';
SELECT SMALLDATETIMEFROMPARTS
(
DATEPART(YEAR, #dt),
DATEPART(MONTH, #dt),
DATEPART(DAY, #dt),
DATEPART(HOUR, #dt),
DATEPART(MINUTE, #dt)
);
If you want to "round" to the nearest minute you could just CONVERT the value to a smalldatetime; they are only accurate to 1 minute:
SELECT CONVERT(smalldatetime,CONVERT(datetime2,'2021-09-02T15:15:30.9233333'));
If you want to, you can then CONVERT back to your original data type.
If you want to truncate (so strip the minutes) you could use the old DATEDIFF and DATEADD method:
DECLARE #DateTime2 datetime2(7) = '2021-09-02T15:15:30.9233333';
SELECT DATEADD(MINUTE,DATEDIFF(MINUTE,'19000101',#DateTime2),CONVERT(datetime2(7),'19000101'));
Just another option using left() and the implicit conversion.
Depending on the actual USE CASE, the outer convert() is optional
Example
DECLARE #dt datetime2(7) = '2021-09-02T15:15:30.9233333';
select convert(smalldatetime,left(#dt,16))
Results
2021-09-02 15:15:00
Combining the DATEADD and CAST(... AS SMALLDATETIME) approaches effectively gives you a minute "floor", like so:
SELECT CAST('2021-09-02T15:15:30.9233333' AS DATETIME2(7)) AS EventDatetime2,
CAST(CAST('2021-09-02T15:15:30.9233333' AS DATETIME2(7)) AS TIME(0)) AS EventTime,
CAST(CAST(DATEADD(
SECOND,
(DATEPART(SECOND, CAST('2021-09-02T15:15:30.9233333' AS DATETIME2(7))) * -1),
CAST('2021-09-02T15:15:30.9233333' AS DATETIME2(7))) AS SMALLDATETIME) AS TIME(0));
EventDatetime2
EventTime
(No column name)
2021-09-02 15:15:30.9233333
15:15:31
15:15:00
The DATEADD in this example subtracts the number of seconds from the datetime before converting it to a smalldatetime, so when that cast/convert does its rounding it will always go to the lower minute.
If, however, your input value is the sort of string literal that the wording of your question implies, you could also do this:
SELECT CAST(SUBSTRING('2021-09-02T15:15:30.9233333', CHARINDEX('T', '2021-09-02T15:15:30.9233333')+1, 6) + '00' AS TIME(0));
and get this result:
15:15:00
I have a query that takes two datetime variables (Start date and end date) and appends two differing fixed times to allow for a business trading time offset.
An example of a test query using this logic is:
DECLARE #startdate datetime;
DECLARE #enddate datetime;
SET #startdate = convert(datetime,'2017-01-01')
SET #enddate = convert(datetime,'2017-01-02')
SELECT *
FROM ig_Business..Check_Item_Detail CID (NOLOCK)
JOIN ig_business..Check_Sales_Detail CSD (NOLOCK) ON CSD.transaction_data_id = CID.transaction_data_id
WHERE csd.tendered_date_time BETWEEN DATEADD(m, DATEDIFF(m, 0, convert(date, #STARTDATE)), 0) + '06:00:00'
AND DATEADD(m, DATEDIFF(m, 0, convert(date, #ENDDATE)), 0) + '05:59:59'
However, the result set for this query is empty, and I am unsure why, because when I run
select DATEADD(m, DATEDIFF(m, 0, convert(date, #STARTDATE)), 0) + '06:00:00'
i get back a seemingly valid datetime : 2017-01-01 06:00:00.000
An example of what is returned when I remove the time restriction:
i get back a seemingly valid datetime : 2017-01-01 06:00:00.000
You're not.
You're getting back a date that has been automatically cast to a string, and have glued another string on the end, giving you a string that looks like a datetime.
If you want to add something to the date, use another dateadd(). This will give you a BETWEEN comparison with actual datetimes.
Right now you are doing a "between" with a datetime and a string.
I'm surprised it doesn't throw an error.
If 2012+, you can use format() to append a time to a date/datetime value
Example
Declare #startdate date = '2017-01-01'
Select format(#startdate,'yyyy-MM-dd 06:00:00')
Returns
2017-01-01 06:00:00
This format() can be included in your where
...
Where SomeDateTime between format(#startdate,'yyyy-MM-dd 06:00:00')
and format(#enddate,'yyyy-MM-dd 17:00:00')
I want to get date from yyyy-mm-dd to yyyy-mm-dd in SQL.
Example: I have two parameter #startdate : 2015-12-28 and #enddate : 2016-01-02, and database in SQLServer, datatype is varchar(10)
DATE_ORDER
28-12-2015
30-12-1996
29-12-2016
30-12-1997
24-12-2015
27-12-1993
03-01-2016
01-01-1992
02-01-2016
etc...
Ok,now I want to get data from #startdate : 2015-12-28 and #enddate : 2016-01-02. I use SELECT * FROM TABLE_X WHERE DATE_ORDER >= #startdate AND DATE_ORDER <= #enddate . But the results are not what I expected. Here are the results I want
28-12-2015
30-12-1996
29-12-2016
30-12-1997
01-01-1992
02-01-2016
I think to solve this problem, I need to do two things :
First, get date range from #startdate to #enddate , in here 28/12/2015, 29/12/2015, 30/12/2015, 31/12/2015, 01/01/2016, 02/01/2016.
The second: get the date in database same in range 28/12, 29/12, 30/12, 31/12, 01/01, 02/01, ignoring the year.
Can you give me some ideas about this ?
Your actual format is "105-italian" find details here.
You can convert your existing VARCHAR(10)-values with this line to real datetime
SELECT CONVERT(DATETIME,YourColumn,105)
Next thing to know is, that you should not use BETWEEN but rather >=StartDate AND < NakedDateOfTheFollowingDay to check date ranges
So to solve your need Get date-range from 2015-12-28 to 2016-01-02 you might do something like this:
DECLARE #Start DATETIME={d'2015-12-28'};
DECLARE #End DATETIME={d'2016-01-02'};
SELECT *
FROM YourTable
WHERE CONVERT(DATETIME,YourDateColumn,105)>=#Start AND CONVERT(DATETIME,YourDateColumn,105)<#End+1
Attention Be aware, that the conversion lets your expression be not sargable. No index will be used.
Better was to store your date as correctly typed data to avoid conversions...
Try this query
SET DATEFIRST 1
DECLARE #wk int SET #wk = 2
DECLARE #yr int SET #yr = 2011
--define start and end limits
DECLARE #todate datetime, #fromdate datetime
SELECT #fromdate = dateadd (week, #wk, dateadd (YEAR, #yr-1900, 0)) - 4 -
datepart(dw, dateadd (week, #wk, dateadd (YEAR, #yr-1900, 0)) - 4) + 1
SELECT #todate = #fromdate + 6
;WITH DateSequence( Date ) AS
(
SELECT #fromdate AS Date
UNION ALL
SELECT dateadd(DAY, 1, Date)
FROM DateSequence
WHERE Date < #todate
)
--select result
SELECT * FROM DateSequence OPTION (MaxRecursion 1000)
So, after the 2nd or 3rd edit, it slowly becomes clear, what you want (i hope).
So you REALLY WANT to get the dates with the year beeing ignored.
As someone pointed out already, date-values are stored internally not as string, but as internal datatype date (whatever that is in memory, i don't know).
If you want to compare DATES, you cannot do that with ignorance of any part. If you want to, you have to build a NEW date value of day and month of given row and a hard coded year (2000 or 1 or whatever) for EVERY row.
SELECT * FROM TABLE_X WHERE convert(date,'2000' + substring(convert(char(8),convert(datetime, 'DATE_ORDER', 105),112),5,4),112) >= #startdate AND convert(date,'2000' + substring(convert(char(8),convert(datetime, 'DATE_ORDER', 105),112),5,4),112) <= #enddate
If your startdate and enddate go OVER sylvester, you have to do 2 queries, on from startdate to 1231, one from 0101 to enddate.
My stored proc has the following select statement:
select Name,Holiday from tblNames where ID = #ID and DATENAME(YEAR, GETDATE()) = #Year
When executing the statement I have an error
"Error converting data type int to nvarchar."
How can I convert #Year parameter to a correct year?
The return type of the datename function is nvarchar, you want the datepart function that returns an integer value, so change to DATEPART(YEAR, GETDATE()) instead.
datename is what you would use to get the name of a month or weekday.
Or you could use the year(getdate()) function instead as Gordon L mentioned in a comment.
I'd recommend to switch back from fixing specific error message to the original question. You have a date in your table and need to filter it by range. So just provide to server the range bounds. This will also avoid any conversions of stored data. To avoid tail time issue you may append '23:59:59.997' to the upper bound of range or (my advice) provide next date and compare by < instead of <=
set #startdate = ...
set #enddate = dateadd(dd, 1, ...)
select *
from mytable
where t.date >= #startdate and t.date < #enddate
Complicated conversions can make it impossible to use appropriate index. If you can convert your arguments and provide prepared values to server - strive to do so.
I need to calculate difference in workdays between two dates. Is there a built in function for this in SQL Server? Can someone please provide an example on how to do this?
Here is something I wrote quickly. Just encapsulate it into a function or whatever you need.
declare #StartDate datetime
declare #EndDate datetime
declare #TotalDiff int
declare #NumberOfWeekends int
SET #StartDate = '3/12/2013'
SET #EndDate = '3/22/2013'
SET #NumberOfWeekends = 0
SET #TotalDiff = DATEDIFF(d,#StartDate, #EndDate)
If #TotalDiff > 7
SET #NumberOfWeekends = #TotalDiff / 7
else if DATEPART(dd, #EndDate) < DATEPART(DD, #StartDate)
SET #NumberOfWeekends = 1
select (#TotalDiff - 2*#NumberOfWeekends) as TotalWorkDays
No, there is nothing built in to SQL Server to directly give you number of working days between two dates, however there are a few built-in functions which will enable you to write one.
Firstly, a few caveats
The world cannot agree what a "Working Day" is. For most of us it's Saturday and Sunday. For most of the Middle East it's Friday & Saturday (with Sunday being a normal working day)
The world most certainly cannot agree on what constitutes a public holiday, which are almost always considered non-working days.
You have not specified how you would like to handle these cases so lets make some assumptions:
Saturday and Sunday will be non-working days
Public holidays will not be taken into acount
Now, determining if a particular days is saturday or sunday in sql is easy, given a #date of type DateTime:
IF DATENAME(dw,#date) IN ('Saturday','Sunday')
With that in mind, given a start and end date, you can just count incrementally from #startDate to #endDate
DECLARE #startDate DATETIME = '2013-01-01'
DECLARE #endDate DATETIME = '2013-01-20'
DECLARE #currDate DATETIME = #startDate
DECLARE #numDays INT = 0
WHILE #currDate<#endDate
BEGIN
IF DATENAME(dw,#currDate) NOT IN ('Saturday','Sunday')
SET #numDays = #numDays + 1
SET #currDate = DATEADD(day,1,#currDate)
END
SELECT #numDays
Note: This is non-inclsive so wont count #endDate. You could change it to be inclusive by changing WHILE #currDate<#endDate to WHILE #currDate<=#endDate
My solution does not count the #EndDate, so if you need to change that, just add 1 to #d2.
First, I calculate the number of days from an "initial" day (which happens to be 1/1/1900, a Monday) to #StartDate and #EndDate:
DECLARE #d1 int = DATEDIFF(Day, 0, #StartDate);
DECLARE #d2 int = DATEDIFF(Day, 0, #EndDate);
Then, the total number of days between #StartDate and #EndDate is:
#d2 - #d1
From this, I substract the number of Sundays and the number of Saturdays in the interval, each calculated as a difference simlar to the total days, but now for whole weeks (7 days). To get the number of whole weeks, I use integer division by 7 and the fact that the "initial" day (0) is a Monday. The number of Sundays in the interval is
#d2/7 - #d1/7
and the number of Saturdays is
(#d2+1)/7 - (#d1+1)/7
Putting all together, my solution is:
DECLARE #StartDate DATETIME = '20180101'
DECLARE #EndDate DATETIME = '20180201'
DECLARE #d1 int = DATEDIFF(Day, 0, #StartDate)
DECLARE #d2 int = DATEDIFF(Day, 0, #EndDate)
SELECT #d2 - #d1 - (#d2/7 - #d1/7) - ((#d2+1)/7 - (#d1+1)/7) AS workdays