Calculating value using previous value of a row in T-SQL - sql-server

Question

I got following table and want to calculate value of Column2 on each row using the value of the same column (Column2) from the previous row in a sql without using cursor or while loop.
Id Date Column1 Column2
1 01/01/2011 5 5 => Same as Column1
2 02/01/2011 2 18 => (1 + (value of Column2 from the previous row)) * (1 + (Value of Column1 from the current row)) i.e. (1+5)*(1+2)
3 03/01/2011 3 76 => (1+18)*(1+3) = 19*4
and so on
Any thoughts?

Answer 1

Assuming at least SQL Server 2005 for the recursive CTE:
;with cteCalculation as (
select t.Id, t.Date, t.Column1, t.Column1 as Column2
from YourTable t
where t.Id = 1
union all
select t.Id, t.Date, t.Column1, (1+t.Column1)*(1+c.Column2) as Column2
from YourTable t
inner join cteCalculation c
on t.Id-1 = c.id
)
select c.Id, c.Date, c.Column1, c.Column2
from cteCalculation c

Answer 2

I solved the problem, just mentioned.
This is my code:
;with cteCalculation as (
select t.Id, t.Column1, t.Column1 as Column2
from table_1 t
where t.Id = 1
union all
select t.Id, t.Column1, (1+t.Column1)*(1+c.Column2) as Column2
from table_1 t
inner join cteCalculation c
on t.Id-1 = c.id
),
cte2 as(
select t.Id, t.Column1 as Column3
from table_1 t
where t.Id = 1
union all
select t.Id, (select column2+1 from cteCalculation c where c.id = t.id) as Column3
from table_1 t
inner join cte2 c2
on t.Id-1 = c2.id
)
select c.Id, c.Column1, c.Column2, c2.column3
from cteCalculation c
inner join cte2 c2 on c.id = c2.id
The result is as I was expected:
1 5 5 5
2 2 18 19
3 3 76 77

Answer 3

Here is an example using ROW_NUMBER() if the Id's aren't necessarily in order:
;with DataRaw as (
select 1 as Id, '01/01/11' as Date, 5 as Column1 union
select 2 as Id, '02/01/11' as Date, 2 as Column1 union
select 4 as Id, '03/01/11' as Date, 3 as Column1
),
Data as (
select RowId = ROW_NUMBER() over (order by Id), Id, Date, Column1 from DataRaw
),
Data2 as (
select
RowId, id, Date, Column1, Column1 as Column2
from
Data d
where
RowId = 1
union all
select
d1.RowId, d1.id, d1.Date, d1.Column1, (1+d1.column1)*(1+d2.column2) as column2
from
Data d1
cross join
Data2 d2
where
d2.RowId + 1 = d1.RowId
)
select
Id, Date, Column1, Column2
from
Data2

Answer 4

edit: shoudld have read the question better...
Another go woudl be this:
;with DataRaw as (
select 1 as Id, '01/01/11' as Date, 5 as Column1 union
select 2 as Id, '02/01/11' as Date, 2 as Column1 union
select 4 as Id, '03/01/11' as Date, 3 as Column1
),
Data as (
select Ord = ROW_NUMBER() over (order by Id), Id, Date, Column1 from DataRaw
),
select -- formula goes here, using current and prev as datasources.
from data current
left join data prev on current.Ord = prev.Ord + 1 -- pick the previous row by adding 1 to the ordinal
I think a normal join to get to the previous row would be faster than a CTE. You;d have to check for yourself though.
Looks easier to me.
Good luck, GJ