I would like to get all the files that a sub-folder holds in a string array.
So, I have tried something like the following:
var IOstore = IsolatedStorageFile.GetUserStoreForApplication();
string searchpath = System.IO.Path.Combine("product", ProductName);
string filesInSubDirs[] = IOstore.GetFileNames(searchpath);
But I got all the files in the "product" folder. I have also tried with "productname" only as the parameter.
Thanks for your help.
The search pattern for a sub-folder needs to include "*.*" at the end to pattern match any file, which would make your code something like the following:
var IOstore = IsolatedStorageFile.GetUserStoreForApplication();
string searchpath = System.IO.Path.Combine("product", ProductName);
searchpath = string.Format("{0}\\*.*", searchpath);
string filesInSubDirs[] = IOstore.GetFileNames(searchpath);
Something you might want to try. (this is sort of a left field answer, sorry). In my dropbox client http://sharpdropbox.codeplex.com/) I have a set of facades for System.IO.File, System.IO.FileInfo, System.IO.Directory, and System.IO.DirectoryInfo. They work pretty good and I have tested them.
Basically, you add a Using or Import for System.IO.IsolatedStorage and then PSFile, PSDirectory, PSFileInfo, or PSDirectoryInfo. It's saved me from having to remember all the nuances... for instance if you are querying a directory, it knows to add a slash, etc. BTW, the "PS" prefix stands for "Persisted Storage" which is what IsolatedStorage is sometimes called (starting them with an "I" implies they are interfaces.. and having no prefix makes things even more confusing).
Anyway, you can grab the code from source or I believe the last release had the DLLs for them (it's called something like "IsolatedStorageFacade-WP7")
Related
I need to read a text file with readLines() and I've already found this question, but the code in the answers always uses some variation of javaClass; it seems to work only inside a class, while I'm using just a simple Kotlin file with no declared classes. Writing it like this is correct syntax-wise but it looks really ugly and it always returns null, so it must be wrong:
val lines = object {}.javaClass.getResource("file.txt")?.toURI()?.toPath()?.readLines()
Of course I could just specify the raw path like this, but I wonder if there's a better way:
val lines = File("src/main/resources/file.txt").readLines()
Thanks to this answer for providing the correct way to read the file. Currently, reading files from resources without using javaClass or similar constructs doesn't seem to be possible.
// use this if you're inside a class
val lines = this::class.java.getResourceAsStream("file.txt")?.bufferedReader()?.readLines()
// use this otherwise
val lines = object {}.javaClass.getResourceAsStream("file.txt")?.bufferedReader()?.readLines()
According to other similar questions I've found, the second way might also work within a lambda but I haven't tested it. Notice the need for the ?. operator and the lines?.let {} syntax needed from this point onward, because getResourceAsStream() returns null if no resource is found with the given name.
Kotlin doesn't have its own means of getting a resource, so you have to use Java's method Class.getResource. You should not assume that the resource is a file (i.e. don't use toPath) as it could well be an entry in a jar, and not a file on the file system. To read a resource, it is easier to get the resource as an InputStream and then read lines from it:
val lines = this::class.java.getResourceAsStream("file.txt").bufferedReader().readLines()
I'm not sure if my response attempts to answer your exact question, but perhaps you could do something like this:
I'm guessing in the final use case, the file names would be dynamic - Not statically declared. In which case, if you have access to or know the path to the folder, you could do something like this:
// Create an extension function on the String class to retrieve a list of
// files available within a folder. Though I have not added a check here
// to validate this, a condition can be added to assert if the extension
// called is executed on a folder or not
fun String.getFilesInFolder(): Array<out File>? = with(File(this)) { return listFiles() }
// Call the extension function on the String folder path wherever required
fun retrieveFiles(): Array<out File>? = [PATH TO FOLDER].getFilesInFolder()
Once you have a reference to the List<out File> object, you could do something like this:
// Create an extension function to read
fun File.retrieveContent() = readLines()
// You can can further expand this use case to conditionally return
// readLines() or entire file data using a buffered reader or convert file
// content to a Data class through GSON/whatever.
// You can use Generic Constraints
// Refer this article for possibilities
// https://kotlinlang.org/docs/generics.html#generic-constraints
// Then simply call this extension function after retrieving files in the folder.
listOfFiles?.forEach { singleFile -> println(singleFile.retrieveContent()) }
In order to have the same url that work for both Jar or in local, the url (or path) needs to be a relative path from the repository root.
..meaning, the location of your file or folder from your src folder.
could be "/main/resources/your-folder/" or "/client/notes/somefile.md"
The url must be a relative path from the repository root.
it must be "src/main/resources/your-folder/" or "src/client/notes/somefile.md"
Now you get the drill, and luckily for Intellij Idea users, you can get the correct path with a right-click on the folder or file -> copy Path/Reference.. -> Path From Repository Root (this is it)
Last, paste it and do your thing.
I am trying to write a GUI that will display the name of the sketch it was generated from using a simple text() command. However, I am running into trouble getting any of the general JS solutions to work for me. Many solutions I have found use the filename reserved word but that does not seem to be reserved in Processing 3.5.4. I have also tried parsing the strings using a similar method to what can be found here. I am very new to processing and this is only my 2nd attempt at using Processing.
Any advice would be greatly appreciated
You can get the path (as a string) to the sketch with sketchPath().
From there you could either parse the string (pull off everything after the last slash) to get the sketch name, or you can use sketchFile() to get a reference to the file itself and get the name from there:
String path = sketchPath();
File file = sketchFile(path);
String sketchName = file.getName();
println(sketchName);
You could combine this all into one line like so:
String sketchName = sketchFile(sketchPath()).getName();
Solved, now working example!
I have a set of time series that is populated in a folder structure as follows:
TimeSeriesData\Config_000000\seed_001\Aggregate_Quantity.txt
…
TimeSeriesData\Config_000058\seed_010\Aggregate_Quantity.txt
And in each file there is a first line containing a character, followed by lines containing the data. E.g.
share
-21.75
-20.75
…
Now, I would like to import all those files (at best, without specifying ex post the number of configs and seeds, at worst with supplying it) into single time series of the like: “AggQuant_config_seed” where config relates to the config ID and seed to the seed id.
I tried the following (using the non-preferred way), but “parsing” the “path” does not work / I do not know how to do it.
string base = "TimeSeriesData/Config_"
string middle = "/seed_"
string endd = "/Aggregate_Quantity.txt"
string path = ""
loop for (i=0;i<=58;i+=1)
loop for (j=1;j<=10;j+=1)
path = ""
sprintf path "%s%06d%s%03d%s",base,i,middle,j,endd
append #path #will be named share
rename share Agg_Q_$i_$j #rename
endloop
endloop
To sum up the problem, the following does not work:
string path="somwhere/a_file.txt" #string holding path
#wrong: append $path #use append on string
append #path #works!
And if possible, a way to search recursively through a set of folders, using the folder information together with file-information for the variable name, would be nice. Is that possible within gretl?
I realize that in many cases I would like to refer to a specific “help” section like those for functions and commands, but for operators instead (like “$”, which is obviously wrong here).
Intuitively, although I know this is wrong, it would look something like this:
secondFileNamePart = "7"
file = open(('test+secondFileNamePart.txt'), 'w')
With the name of the new file being test7.
Obviously though, this does not work. Is their any way to do this, or if not a workaround? I want to create a user specified number of files, all with different names.
You should consider reading the Python tutorial - string concatenation is a basic topic.
secondFileNamePart = '7'
file = open('test'+secondFileNamePart+'.txt', 'w')
I want to create a copy of a database to a folder not under the data either locally or on a server I have code that looks like this:
var arcName:String = "C:\Archive\MyArchives\SomeName.nsf"
var arcDB:NotesDatabase = appDB.createCopy("", arcName);
When the action finishes (it does not generate any errors) I can't find the database anywhere. if I change the arcName to "Archives\Myarchives\SomeName,nsf" the process works correctly. But I don't want these Archives under Data.
Using the full path does not seem to make it move out from under the Data folder.
This may be a case of string escaping - in SSJS, like most C-lineage languages, \ is the escape character. Give it a shot with \\ in place of each. In my testing, it works as database.createCopy("", "C:\\Archive\\MyArchives\\SomeName.nsf").