I am trying to do pagination from the accommodation controller but with data from the MemberWall model.
here is the code
Accommodation
$data = $this->Accommodation->Member->MemberWall->paginate('MemberWall');
MemberWall
var $paginate = array(
'limit' => 4,
'order' => array(
'MemberWall.created' => 'asc'
)
);
I get this error
SQL Error: 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use nea.... Query: paginate
Thanks, Alex
Here is the REAL answer.
$data = $this->paginate($this->Accommodation->Member->MemberWall);
I had trouble finding this in the docs too. You can actually pass a model object into the paginate method.
I've tried and it works in both ways:
$this->paginate('MemberWall');
$this->paginate($this->Accommodation->Member->MemberWall);
In my code I use something like;
$this->loadModel('MemberWall');
$this->paginate = array(.....);
$data = $this->paginate('MemberWall');
$this->paginate('MemberWall'); iirc is the way it works
The MemberWall $paginate array (your second snippet) looks like it's defined in member_walls_controller.php It will not be accessible from accommodations_controller.php
$this->Accommodation->Member->MemberWall->paginate('MemberWall'); is calling a method on the MemberWall model. paginate() is a controller method.
Read Custom-Query-Pagination, particularly the last section.
I'm not sure that you can paginate that far down a relationship and it indicates to me that you probably need to rethink your datamodel and logic.
The 1.2 manual is better written on this topic.
Related
I am trying to find records from CallForwardingCondition model using following line of code:
$this->loadModel('CallForwardingCondition');
$this->set('callForwardingCondition', $this->CallForwardingCondition->findByType('list'));
In SQL Dump following query is done when page is reloaded:
SELECT `CallForwardingCondition`.`type`, `CallForwardingCondition`.`description` FROM `vpbx`.`call_forwarding_condition` AS `CallForwardingCondition` WHERE `CallForwardingCondition`.`type` = 'list' LIMIT 1
How can I direct Cakephp to findByType which will result in following query?
SELECT `CallForwardingCondition`.`type`, `CallForwardingCondition`.`description` FROM `vpbx`.`call_forwarding_condition` AS `CallForwardingCondition` WHERE `CallForwardingCondition`.`type` LIKE '%' LIMIT 10
For CakePHP 2.x you need to use find('all') and pass it the required conditions and limit:-
$result = $this->CallForwardingCondition->find('all',[
'conditions' => ['CallForwardingCondition.type Like' => '%'],
'limit' => 10
);
findByType is a special find method that will only return the first record matching the type passed as the find method's parameter which is why it isn't returning what you want. You can read more about the findBy magic functions in the official docs.
try this:
$result = $this-> CallForwardingCondition ->find('all',['limit'=>10,'conditions'=>['CallForwardingCondition.type Like'=>'%'])->toArray();
I don't think you can't use findBy with limit. If you want to use limit, you must use findAllBy<fieldName>. Even findAllBy<fieldName>, you can't use LIKE.
This is findAllBy from cakephp
findAllBy<fieldName>(string $value, array $fields, array $order, int $limit, int $page, int $recursive)
So if you want to covert it, you must do the following way;
$this->CallForwardingCondition->findAllByType('something',['CallForwardingCondition.*'],['CallForwardingCondition.id'=>'desc'],'10');
This is findBy from cakephp doc.
findBy<fieldName>(string $value[, mixed $fields[, mixed $order]]);
Hope this help for you.
I am using CakePHP 2.1.3; I want to create a virtual field dynamically in a controller. Is it possible?
The problem is when I am trying to find max value in a table it gives me another array from the model array. Please ask if you need more information.
When I am trying to execute the following query,
$find_max_case_count = $this->CaseMaster->find('first', array(
'conditions' => array(
'CaseMaster.CLIENT_ID' => $client_id,
'CaseMaster.CASE_NO LIKE' => '%-%'
),
'fields' => array('max(CaseMaster.CASE_NO) AS MAX_NO')
));
It is giving me an array like:
[0]=> array([MAX_NO]=> 52)
However I want it to be like as:
[CaseMaster] => array([MAX_NO] => 52)
I found a solution. I can make the virtual field at runtime. The code should looks like:
$this->CaseMaster->virtualFields['MAX_NO'] = 0;
Write it just above the find query and the query will remain same as it was written.
This link was helpful to find out the solution.
There is no way (as far as I am knowledgeable) to create virtual fields "on the fly". What virtual fields are is "arbitrary SQL expressions" that will be executed when a find runs through the Model and "will be indexed under the Model's key alongside other Model fields".
What do you need to do with "dynamically created virtual fields"? If you explain what exactly you need to accomplish maybe we can provide a different (even more suitable? :) ) solution? I'd personally be happy to help you.
After you editing your question I can say that what you're getting is the way the array should be returned, this is because of the fields parameter. If you want to get a different structure out of it I suggest applying a callback to format it.
Firstly move the method inside the CaseMaster Model:
public function getMaxCaseCount($client_id){
$data = $this->find('first', array(
'conditions' => array(
'CaseMaster.CLIENT_ID' => $client_id,
'CaseMaster.CASE_NO LIKE' => '%-%'),
'fields' => array('max(CaseMaster.CASE_NO) AS MAX_NO')));
return array_map(array('CaseMaster', '__filterMaxCaseCount'), $data);
}
private function __filterMaxCaseCount($input){
//This is just an example formatting
//You can do whatever you would like here.
$output['CaseMaster'] = $input[0];
return $output;
}
The array_map function will apply the __filterMaxCaseCount callback method so that when you call:
$this->CaseMaster->getMaxCaseCount($client_id);
from your controller you will get the data in the way you need it. The array_map function could also look like this:
return array_map(array($this, '__filterMaxCaseCount'), $data);
because you're in the same Class.
Just adding your model alias to field definition also works for this purpose
'fields' => array('max(CaseMaster.CASE_NO) AS CaseMaster__MAX_NO')
I am tring to do the following:
My 'Company' Models are being stored in a 'default' datasource. In to
model I set the var $useDbConfig = 'default';
My 'User' Models are being stored in another datasource called
'users_db'. In this model I set the var $useDbConfig = 'users_db';
There is a 'belongsTo' relationship between 'Company' and 'User' models.
I want to do a recursive find query that brings back all users for each company in one go. I have the feeling that I cannot do this with Cake as it currently is.
When I try the following:
$res2 = $this->Company->find('all', array(
'conditions' => array('Company.id' => 1),
'recursive'=>2
));
I get a message that it cannot find the users table(its looking in the default source):
Error: Table user_groups for model User was not found in datasource default.
Is there any way I can do this?
Many thanks for any help you can provide.....
kSeudo.
Why not replace the your original statement by this:
$this->loadModel('User');
$res2 = $this->User->find('all',
array( 'conditions' => array( 'User.company_id' => 1 ) ));
This will produce the results you want.
Otherwise, if you wanted something tidier, you could add a fetch_users() function to your Company class that implemented a similar logic.
Ok, problem solved. Once I set the datasource in the model correctly everything seems to work fine.
Thanks guys
I have a model with the name Deal class Deal extends AppModel
Now in my controller I call a method in the Deal model called getDeal()
$dealInfo = Deal::getDeal($dealID);
I want the info returned to me but the var_dump displays blank
function getDeal($dealID){
$deal = $this->Deal->find('first', array(
'conditions' =>
'Deal.id' =>$dealID
) ,
'fields' => array(
'Deal.id'
) ,
'recursive' => 1,
));
}
This is the first time I'm working in cakePHP, so this question might sound a bit dumb
When you're just using an id as your find condition you can use CakePHP's dynamic finder methods.
Dynamic finders work like this.
$this->Model->findByModelFieldName();
In your example it would be
$this->findById($dealId, array(
'fields' => array('Deal.id'),
'recursive' => 1
));
I don't know if I'm just being mental, but is this simply because you're not returning anything from getDeal()?
Try adding return $deal; and see if that helps. Your question doesn't state exactly where you're doing the var_dump so I might be well off.
Edit:
As per the discussion with you and 8vius, we've established that this isn't right, and you simply need to change $this->Deal->find() to $this->find() because its being run from the model.
Check your function declaration, $deal_id does not exist and as you can see from the parameter you pass to the function which should me $deal_id and not dealID. So you have a misdeclared function calling find with a variable that does not exist.
In CakePHP, I have two tables, Countries & Networks. They have a HABTM relationship and are joined by countries_networks.
I'm trying to get all countries from the countries table where the 'name' field in Networks = 'o2'
I've realised I can't do this using a basic find(), so I've been experimenting with the containable behaviour. I have managed to restrict the returned data, but it looks as though 'containable' doesn't exactly work as I want. Heres my code:
$countries = $this->Country->find('all', array('contain' => array(
'Network' => array(
'conditions' => array('Network.name =' => "o2"),
)
)));
This query however returns ALL countries, and the Network.name if its 'o2'. What I really need to do is return ONLY the countries that have a Network.name of 'o2', and no others.
Can anyone help? Thanks.
"=' =>"
What is it? there is no needed to use "=" symbol after "Network.name"
Your query returns you exactly what your ask.
Try to select from Network.
$countries = $this->Country->Network->find('first', array(
'conditions' => array('Network.name' => "o2"),
'contain' => array('Country')
));
$countries = $countries['Country'];
You should be able to do something like this:
$this->Country->hasAndBelongsToMany['Network']['conditions'] = array('Network.name'=>'o2');
$myCountries = $this->Country->find('all');
I haven't tested this, but it should get you pretty close to where you need to be.
Also, bear in mind that changing the hasAndBelongsToMany array like this will affect all subsequent queries against that model during the current page load (but it will be reset the next time the model is instantiated).
I'm on my way out the door, so sorry for the brief explanation.
I think what you want is a HABTM relationship, but to be able to filter based on the associated model's data. To do this, check out the "Containable" behavior in Cake's manual. Pretty sure that's what you're after.