This question already has an answer here:
Canonical vs. non-canonical terminal input
(1 answer)
Closed 4 years ago.
I'm trying to write a simple program that asks a user to choose from a menu in a loop.
I use getchar() to get the input, however i've noticed that when I enter a char and press 'Enter' the program makes two loops (as if i pressed twice) one the char as an input and another for 'Enter' as an input.
How do I fix this?
getchar() returns the first character in the input buffer, and removes it from the input buffer. But other characters are still in the input buffer (\n in your example). You need to clear the input buffer before calling getchar() again:
void clearInputBuffer() // works only if the input buffer is not empty
{
do
{
c = getchar();
} while (c != '\n' && c != EOF);
}
The easiest way is to filter out the enter key as the return value from getchar
char c = (char)getchar();
if ( c != '\n' ) {
...
}
Add a getchar() after the getchar() :P
How about
#include <stdio.h>
/*! getline() reads one line from standard input and copies it to line array
* (but no more than max chars).
* It does not place the terminating \n in line array.
* Returns line length, or 0 for empty line, or EOF for end-of-file.
*/
int getline(char line[], int max)
{
int nch = 0;
int c;
max = max - 1; /* leave room for '\0' */
while ((c = getchar()) != EOF) {
if (c == '\n')
break;
if (nch < max) {
line[nch] = c;
nch = nch + 1;
}
}
if (c == EOF && nch == 0)
return EOF;
line[nch] = '\0';
return nch;
}
Source
You've kind of answered your own question; you have to deal with the newline character somehow.
There are several options. If your menu options are numbered, you can use scanf() to read in an integer value and switch based on that:
printf("Pick an option: ");
fflush(stdout);
scanf("%d", &option);
switch(option)
{
case 0 : do_something(); break;
case 1 : do_something_else(); break;
...
default: bad_option(); break;
}
The advantage of this option is that the %d conversion specifier skips over any leading whitespace, including newline characters, so you don't have to worry about any unread \n clogging up the input stream (in fact, most of the conversion specifiers skip leading whitespace; %c doesn't, making it behave a lot like getchar()).
The disadvantage of this option is that if someone fat-fingers a non-digit character in their input, it won't be read with the %d conversion specifier, and will stay stuck in the input stream until a call to getchar() or scanf() with a %s or %c conversion specifier.
A better option is to read all input as character strings using fgets(), then parse and validate as necessary.
/**
* Prints a prompt to stdout and reads an input response, writing
* the input value to option.
*
* #param prompt [in] - prompt written to stdout
* #param option [out] - option entered by user
*
* #return - 1 on success, 0 on failure. If return value is 0, then option
* is not changed.
*/
int getOption(const char *prompt, char *option)
{
char input[3]; // option char + newline + 0 terminator
int result = 0;
printf("%s: ", prompt);
fflush(stdout);
if (fgets(input, sizeof input, stdin))
{
/**
* Search for a newline character in the input buffer; if it's not
* present, then the user entered more characters than the input buffer
* can store. Reject the input, and continue to read from stdin until
* we see a newline character; that way we don't leave junk in the
* input stream to mess up a future read.
*/
char *newline = strchr(input, '\n');
if (!newline)
{
printf("Input string is too long and will be rejected\n");
/**
* Continue reading from stdin until we find the newline
* character
*/
while (!newline && fgets(input, sizeof input, stdin))
newline = strchr(input, '\n');
}
else
{
*option = input[0];
result = 1;
}
}
else
printf("Received error or EOF on read\n");
return result;
}
Yes, that's a lot of work to read in one stupid menu option, and that's the simple version. Welcome to the wonderful world of interactive input processing in C.
Related
So, I'm working on a simple hangman game in C, and I have the function read_guess, shown below.
void read_guess(char *guesses, char *p_current_guess)
{
int valid_guess = 0;
// Repeatedly takes input until guess is valid
while (valid_guess == 0)
{
printf(">>> ");
fgets(p_current_guess, 2, stdin);
if (!isalpha(*p_current_guess)) printf("Guesses must be alphabetic. Please try again.\n\n");
else
{
valid_guess = 1;
// Iterates over array of guesses and checks if letter has already been guessed
for (int i = 0; guesses[i] != '\0'; i++)
{
if (guesses[i] == *p_current_guess)
{
printf("You have already guessed this letter. Please try again.\n\n");
valid_guess = 0;
break;
}
}
}
}
}
I've tried all the standard input functions (including getchar), but with all of them, when an input larger than one character is supplied, instead of taking just the first character and moving on (or asking again), the rest of the input is "pushed back", and the next time input is requested, whether it be because the input contained a non-alphabetic character or the next round begins, the rest of the input is automatically processed. This repeats for each character of the input.
How can I avoid this?
You are using fgets which is good, but unfortunately not the right way...
fgets reads up to an end of line or at most 1 less the the number of character asked. And of course remaining characters are left for the next read operation...
The idiomatic way would be to ensure reading up to the end of line, whatever the length, or at least up to a much larger length.
Simple but could fail in more than SIZE characters on input:
#define SIZE 64
...
void read_guess(char *guesses, char *p_current_guess)
{
char line[SIZE];
int valid_guess = 0;
// Repeatedly takes input until guess is valid
while (valid_guess == 0)
{
printf(">>> ");
fgets(line, SiZE, stdin); // read a line of size at most SIZE-1
p_current_guess[0] = line[0]; // keep first character
p_current_guess[1] = '\0';
...
Robust but slightly more complex
/**
* Read a line and only keep the first character
*
* Syntax: char * fgetfirst(dest, fd);
*
* Parameters:
* dest: points to a buffer of size at least 2 that will recieve the
* first character followed with a null
* fd : FILE* from which to read
*
* Return value: dest if one character was successfully read, else NULL
*/
char *readfirst(dest, fd) {
#define SIZE 256 // may be adapted
char buf[SIZE];
char *cr = NULL; // return value initialized to NULL if nothing can be read
for (;;) {
if(NULL == fgets(buff, sizeof(buff), fd)) return cr; // read error or end of file
if (0 == strcspn(buff, "\n")) return cr; // end of file
if (cr == NULL) { // first read:
cr = dest; // prepare to return first char
dest[0] = buff[0];
dest[1] = 0;
}
}
}
You can then use it simply in your code:
void read_guess(char *guesses, char *p_current_guess)
{
int valid_guess = 0;
// Repeatedly takes input until guess is valid
while (valid_guess == 0)
{
printf(">>> ");
fgetfirst(p_current_guess, stdin);
You can discard all input until end-of-line, each time you want to ask for input.
void skip_to_eol(FILE* f, int c)
{
while (c != EOF && c != '\n')
c = fgetc(f);
}
...
char c = getchar(); // instead of fgets
skip_to_eol(stdin, c);
You can use getch() function on windows to get single character. and this is linux equivalent
What is the equivalent to getch() & getche() in Linux?
This question already has an answer here:
Canonical vs. non-canonical terminal input
(1 answer)
Closed 4 years ago.
I'm trying to write a simple program that asks a user to choose from a menu in a loop.
I use getchar() to get the input, however i've noticed that when I enter a char and press 'Enter' the program makes two loops (as if i pressed twice) one the char as an input and another for 'Enter' as an input.
How do I fix this?
getchar() returns the first character in the input buffer, and removes it from the input buffer. But other characters are still in the input buffer (\n in your example). You need to clear the input buffer before calling getchar() again:
void clearInputBuffer() // works only if the input buffer is not empty
{
do
{
c = getchar();
} while (c != '\n' && c != EOF);
}
The easiest way is to filter out the enter key as the return value from getchar
char c = (char)getchar();
if ( c != '\n' ) {
...
}
Add a getchar() after the getchar() :P
How about
#include <stdio.h>
/*! getline() reads one line from standard input and copies it to line array
* (but no more than max chars).
* It does not place the terminating \n in line array.
* Returns line length, or 0 for empty line, or EOF for end-of-file.
*/
int getline(char line[], int max)
{
int nch = 0;
int c;
max = max - 1; /* leave room for '\0' */
while ((c = getchar()) != EOF) {
if (c == '\n')
break;
if (nch < max) {
line[nch] = c;
nch = nch + 1;
}
}
if (c == EOF && nch == 0)
return EOF;
line[nch] = '\0';
return nch;
}
Source
You've kind of answered your own question; you have to deal with the newline character somehow.
There are several options. If your menu options are numbered, you can use scanf() to read in an integer value and switch based on that:
printf("Pick an option: ");
fflush(stdout);
scanf("%d", &option);
switch(option)
{
case 0 : do_something(); break;
case 1 : do_something_else(); break;
...
default: bad_option(); break;
}
The advantage of this option is that the %d conversion specifier skips over any leading whitespace, including newline characters, so you don't have to worry about any unread \n clogging up the input stream (in fact, most of the conversion specifiers skip leading whitespace; %c doesn't, making it behave a lot like getchar()).
The disadvantage of this option is that if someone fat-fingers a non-digit character in their input, it won't be read with the %d conversion specifier, and will stay stuck in the input stream until a call to getchar() or scanf() with a %s or %c conversion specifier.
A better option is to read all input as character strings using fgets(), then parse and validate as necessary.
/**
* Prints a prompt to stdout and reads an input response, writing
* the input value to option.
*
* #param prompt [in] - prompt written to stdout
* #param option [out] - option entered by user
*
* #return - 1 on success, 0 on failure. If return value is 0, then option
* is not changed.
*/
int getOption(const char *prompt, char *option)
{
char input[3]; // option char + newline + 0 terminator
int result = 0;
printf("%s: ", prompt);
fflush(stdout);
if (fgets(input, sizeof input, stdin))
{
/**
* Search for a newline character in the input buffer; if it's not
* present, then the user entered more characters than the input buffer
* can store. Reject the input, and continue to read from stdin until
* we see a newline character; that way we don't leave junk in the
* input stream to mess up a future read.
*/
char *newline = strchr(input, '\n');
if (!newline)
{
printf("Input string is too long and will be rejected\n");
/**
* Continue reading from stdin until we find the newline
* character
*/
while (!newline && fgets(input, sizeof input, stdin))
newline = strchr(input, '\n');
}
else
{
*option = input[0];
result = 1;
}
}
else
printf("Received error or EOF on read\n");
return result;
}
Yes, that's a lot of work to read in one stupid menu option, and that's the simple version. Welcome to the wonderful world of interactive input processing in C.
In this scenario, user input is taken from stdin using fgets. Normally to end a while loop when a user hits enter I would use strcmp between the fgets value and \n, but we are not allowed to use #include <string.h> in this particular assignment. Using C99.
You can't, since the fgets() function returns when it finds an \n
I'm assuming you mean when the user input a single \n and nothing else. Itmight be a better idea to use fgetc() instead, which will return the \n.
This means you need to buffer the inout yourself, something like this:
char inputBuffer[120] = "";
char ch;
char chCount = 0;
while (1) {
ch = fgetc(stdin);
if (ch == '\n') {
/* Empty buffer? */
if (inputBuffer[0] == '\0')
/* Oui! */
break;
/* Buffer isn't empty - do something with it... */
fprintf(stdout, "Input buffer: %s\n", inputBuffer);
/* Clear the buffer for the next line of input and reset the
* counter. */
inputBuffer[0] = '\0';
chCount = 0;
}
else {
if (chCount < 119) {
/* Add the byte to the buffer. */
inputBuffer[chCount++] = ch;
inputBuffer[chCount] = '\0';
}
}
}
The above loop will output any input string or break if a single \n is entered.
What would be the best way to imitate the functionality of gets with scanf?
Here is my current attempt
int main()
{
char cvalue[20]; //char array to store input string
int iloop=0; //integer variable for loop
for(iloop=0;iloop<20;iloop++) // for loop to get the string char by char
{
scanf("%c",&cvalue[iloop]); //getting input
if(cvalue[iloop]=='\n') //if input is newline skip further looping
break;
} // end of loop
cvalue[iloop]='\0'; //set end of the character for given input
printf("%s",cvalue); //printing the given string
return 0;
}
You could use scanf this way to work like gets
scanf("%[^\n]",&a);
You need to observe the usually dangers of gets().
The challenge to using scanf() is
1) Insuring that \n is consumed. scanf("%[^\n]",... does not do this.
2) Insuring the str gets a \0 if only a \n is read.
3) Dealing with EOF and I/O errors and return 0.
4) Insure leading whitespace are read into str as scanf("%s" skips them.
#include <stdio.h>
// On success, the gets() returns str.
// If EOF encountered, the eof indicator is set (feof).
// If this happens before any characters could be read,
// pointer returned is a null pointer.
// If a read error occurs, the error (ferror) is set
// and a null pointer is also returned.
char *gets_via_scanf( char * str ) {
// Reads characters from stdin & saves them into str until \n or the end-of-file.
// \n, if found, is not copied into str.
int retval = scanf("%[^\n]",str); // %[ does not skip leading whitespace
if (retval == EOF) return 0;
if (retval == 0) {
*str = '\0'; // Happens when users only types in \n
}
char ch;
scanf("%c",&ch); // Consume leftover \n, could be done with getc()
return str;
}
Your attempt doesn't really imitate gets(), since gets() just keeps putting bytes into the supplied buffer until the end of line is reached. You should realize then that gets() is dangerous and should be avoided. It does not offer any protection from buffer overflow. So, it is also questionable to imitate it.
Given that, your attempt has a couple flaws that I see. First, it loops to the complete size of the input buffer. This doesn't leave you any room to store the NUL terminator if the input line is 20 bytes or longer. This means that you may attempt to store the \0 at cvalue[20], which outside the array boundary. You can fix this by shortening your for loop by one:
for(iloop=0;iloop<19;iloop++) // for loop to get the string char by char
The second flaw is that you do not check to see if the scanf() call succeeds. If you detect failure, you should also leave the loop:
if (scanf("%c",&cvalue[iloop]) != 1) { //getting input
break;
}
Below was my attempt at creating a safer version of gets() implemented with scanf().
char *getsn (char *s, size_t sz) {
char c;
char fmt[sizeof(sz) * CHAR_BIT + sizeof("[^\n]")];
if (sz == 0) return 0;
if (sz == 1) {
s[0] = '\0';
return s;
}
s[sz-2] = '\0';
snprintf(fmt, sizeof(fmt), "%%%lu%s", (unsigned long)sz-1, "[^\n]");
switch (scanf(fmt, s)) {
case 0: s[0] = '\0';
scanf("%c", &c);
return s;
case 1: scanf("%c", &c);
if (s[sz-2] != '\0' && c != '\n') {
ungetc(c, stdin);
}
return s;
default: break;
}
return 0;
}
The safer version uses snprintf() to create a format string that limits how many characters should be stored by the scanf(). So if the provided sz parameter was 100, the resulting format string would be "%99[^\n]". Then, it makes sure to only strip out the \n from the input stream if it was actually encountered.
gcc 4.4.2
I was reading an article about scanf. I personally have never checked the return code of a scanf.
#include <stdio.h>
int main(void)
{
char buf[64];
if(1 == scanf("%63s", buf))
{
printf("Hello %s\n", buf);
}
else
{
fprintf(stderr, "Input error.\n");
}
return 0;
}
I am just wondering what other techniques experienced programmers do when they use scanf when they want to get user input? Or do they use another function or write their own?
Thanks for any suggestions,
EDIT =========
#include <stdio.h>
int main(void)
{
char input_buf[64] = {0};
char data[64] = {0};
printf("Enter something: ");
while( fgets(input_buf, sizeof(input_buf), stdin) == NULL )
{
/* parse the input entered */
sscanf(input_buf, "%s", data);
}
printf("Input [ %s ]\n", data);
return 0;
}
I think most programmers agree that scanf is bad, and most agree to use fgets and sscanf. However, I can use fgets to readin the input. However, if I don't know what the user will enter how do I know what to parse. For example, like if the user was to enter their address which would contain numbers and characters and in any order?
Don't use scanf directly. It's surprisingly hard to use. It's better to read an entire line of input and to then parse it (possibly with sscanf).
Read this entry (and the entries it references) from the comp.lang.c FAQ:
http://c-faq.com/stdio/scanfprobs.html
Edit:
Okay, to address your additional question from your own edit: If you allow unstructured input, then you're going to have to attempt to parse the string in multiple ways until you find one that works. If you can't find a valid match, then you should reject the input and prompt the user again, probably explaining what format you want the input to be in.
For anything more complicated, you'd probably be better off using a regular expression library or even using dedicated lexer/parser toolkits (e.g. flex and bison).
I don't use scanf() for interactive user input; I read everything as text using fgets(), then parse the input as necessary, using strtol() and strtod() to convert text to numeric values.
One example of where scanf() falls down is when the user enters a bad numeric value, but the initial part of it is valid, something like the following:
if (scanf("%d", &num) == 1)
{
// process num
}
else
{
// handle error
}
If the user types in "12e4", scanf() will successfully convert and assign the "12" to num, leaving "e4" in the input stream to foul up a future read. The entire input should be treated as bogus, but scanf() can't catch that kind of error. OTOH, if I do something like:
if (fgets(buffer, sizeof buffer, stdin))
{
int val;
char *chk;
val = (int) strtol(buffer, &chk, 10);
if (!isspace(*chk) && *chk != 0)
{
// non-numeric character in input; reject it completely
}
else
{
// process val
}
}
I can catch the error in the input and reject it before using any part of it. This also does a better job of not leaving garbage in the input stream.
scanf() is a great tool if you can guarantee your input is always well-formed.
scanf() has problems, in that if a user is expected to type an integer, and types a string instead, often the program bombs. This can be overcome by reading all input as a string (use getchar()), and then converting the string to the correct data type.
/* example one, to read a word at a time */
#include <stdio.h>
#include <ctype.h>
#define MAXBUFFERSIZE 80
void cleartoendofline( void ); /* ANSI function prototype */
void cleartoendofline( void )
{
char ch;
ch = getchar();
while( ch != '\n' )
ch = getchar();
}
main()
{
char ch; /* handles user input */
char buffer[MAXBUFFERSIZE]; /* sufficient to handle one line */
int char_count; /* number of characters read for this line */
int exit_flag = 0;
int valid_choice;
while( exit_flag == 0 ) {
printf("Enter a line of text (<80 chars)\n");
ch = getchar();
char_count = 0;
while( (ch != '\n') && (char_count < MAXBUFFERSIZE)) {
buffer[char_count++] = ch;
ch = getchar();
}
buffer[char_count] = 0x00; /* null terminate buffer */
printf("\nThe line you entered was:\n");
printf("%s\n", buffer);
valid_choice = 0;
while( valid_choice == 0 ) {
printf("Continue (Y/N)?\n");
scanf(" %c", &ch );
ch = toupper( ch );
if((ch == 'Y') || (ch == 'N') )
valid_choice = 1;
else
printf("\007Error: Invalid choice\n");
cleartoendofline();
}
if( ch == 'N' ) exit_flag = 1;
}
}
I make a loop call fgets until the end of the line is read, and then call sscanf to parse the data. It's a good idea to check whether sscanf reaches the end of the input line.
I rarely use scanf. Most of the times, I use fgets() to read data as a string. Then, depending upon the need, I may use sscanf(), or other functions such as strto* family of functions, str*chr(), etc., to get data from the string.
If I use scanf() or fgets() + sscanf(), I always check the return values of the functions to make sure they did what I wanted them to do. I also don't use strtok() to tokenize strings, because I think the interface of strtok() is broken.