conflicting types for allocArray - c

guys I'm trying to compile my program in c but I'm getting this error (conflicting types for allocArray)?
Here is my code:
#include <stdio.h>
#include <stdlib.h>
int number(int);
char *allocArray(int);
int main ()
{
printf("Enter a number: ");
int userNumber;
scanf("%d", &userNumber);
int m= number(userNumber);
printf("\nThe number is %d", m);
printf("\n");
printf("*****************************************************\n");
printf("The array is %s", alloArray(5));
}
int number(int n)
{
int num = n;
return num;
}
char *alloArray(int num)
{
char *addr;
addr = (char *) malloc(num);
//addr = char[num];
return addr;
}

You've misspelt allocArray as alloArray (twice, in fact).

Related

May I have some problem with memory allocated

I have this code and after the first write in the array(successful data write ) then we get null as message and I don't know why.
I have tried many things, please help me.
my code is:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct course {
int marks;
char *subject;
};
int main(int argc, char *argv[])
{
struct course *ptr;
int i, noOfRecords;
printf("Enter the number of records: ");
scanf("%d", &noOfRecords);
//Memory allocation for noOfRecords structures
ptr = (struct course *)malloc(noOfRecords * sizeof(struct course));
ptr->subject=(char*)malloc(20*sizeof(char));
for (i = 0; i < noOfRecords; ++i) {
printf("Enter the name of the subject and marks respectively:\n");
scanf("%s %d", (ptr + i)->subject, &(ptr + i)->marks);
}
printf("Displaying Information:\n");
for (i = 0; i < noOfRecords; ++i){
printf("%s\t%d\n", (ptr + i)->subject, (ptr + i)->marks);
}
return 0;
}
As stated in question comments, you need to allocate memory for ALL subject members, not just the first:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct course {
int marks;
char *subject;
};
int main(int argc, char *argv[])
{
struct course *ptr;
int i, noOfRecords;
printf("Enter the number of records: ");
scanf("%d", &noOfRecords);
//Memory allocation for noOfRecords structures
ptr = (struct course *)malloc(noOfRecords * sizeof(struct course));
for (i = 0; i < noOfRecords; ++i) {
printf("Enter the name of the subject and marks respectively:\n");
(ptr + i)->subject = (char*) malloc(20*sizeof(char));
scanf("%s %d", (ptr + i)->subject, &((ptr + i)->marks));
}
printf("Displaying Information:\n");
for (i = 0; i < noOfRecords; ++i) {
printf("%s\t%d\n", (ptr + i)->subject, (ptr + i)->marks);
}
return 0;
}
Also, I suggest you to:
Use a #define for subject max length
Always check user input or limit it (truncate or force to retype). You might get unexpected behaviors if user inserts more than 19 chars plus \0 for subject.
Use typedef struct {...} course;. It will be much easier to handle arrays.
Remember to free the memory you claimed.
As a result:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
// From https://stackoverflow.com/a/17387990/2928168
#define MAX_SUBJECT "20"
typedef struct {
int marks;
char *subject;
} Course;
int main(int argc, char *argv[])
{
Course *courses;
int i, noOfRecords;
printf("Enter the number of records: ");
scanf("%d", &noOfRecords);
// Memory allocation for noOfRecords structures
courses = (Course *) malloc(noOfRecords * sizeof(Course));
for (i = 0; i < noOfRecords; ++i) {
printf("Enter the name of the subject and marks respectively:\n");
courses[i].subject = (char*) malloc(atoi(MAX_SUBJECT)*sizeof(char));
scanf("%" MAX_SUBJECT "s %d", courses[i].subject, &(courses[i].marks));
//fgets(courses[i].subject, sizeof(buf), stdin);
}
printf("Displaying Information:\n");
for (i = 0; i < noOfRecords; ++i) {
printf("%s\t%d\n", courses[i].subject, courses[i].marks);
free(courses[i].subject);
}
free(courses);
return 0;
}
Edit
You can even use the trick from https://stackoverflow.com/a/6671729/2928168 to increase performance:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX_SUBJECT 20
#define Q(x) #x
#define QUOTE(x) Q(x)
#define MAX_SUBJECT_STR QUOTE(MAX_SUBJECT)
typedef struct {
int marks;
char *subject;
} Course;
int main(int argc, char *argv[])
{
Course *courses;
int i, noOfRecords;
printf("Enter the number of records: ");
scanf("%d", &noOfRecords);
// Memory allocation for noOfRecords structures
courses = (Course *) malloc(noOfRecords * sizeof(Course));
for (i = 0; i < noOfRecords; ++i) {
printf("Enter the name of the subject and marks respectively:\n");
courses[i].subject = (char*) malloc(MAX_SUBJECT*sizeof(char));
scanf("%" MAX_SUBJECT_STR "s %d", courses[i].subject, &(courses[i].marks));
//fgets(courses[i].subject, sizeof(buf), stdin);
}
printf("Displaying Information:\n");
for (i = 0; i < noOfRecords; ++i) {
printf("%s\t%d\n", courses[i].subject, courses[i].marks);
free(courses[i].subject);
}
free(courses);
return 0;
}

C strcmp segmentation fault

#include <string.h>
#include<stdio.h>
#include<stdlib.h>
typedef struct bank
{
char an;
char name;
char type;
int bal;
};
int main()
{
int i=0,n;
printf("Enter the number of accounts\n");
scanf("%d",&n);
struct bank a[n];
printf("Enter the details of the users\n");
for(i=0;i<n;i++)
{
scanf("%s%s%s%d",a[i].an,a[i].name,a[i].type,&a[i].bal);
}
printf("The details of the users are\n");
for(i=0;i<n;i++)
{printf("%s\n%s\n%s\n%d\n\n",a[i].an,a[i].name,a[i].type,a[i].bal);}
char atype[10];
printf("Enter the type of account you want to search\n");
scanf("%s",atype);
char typ[10];
char s[]="savings";
char c[]="current";
int result,res1,res2;
result = strcmp(atype,s);
if(result == 0)
{
for(i=0;i<n;i++)
{
typ[10] = a[i].type;
res1 = strcmp(typ,s);
if(res1 == 0)
{
printf("%s\n%s\n%s\n%d\n\n",
a[i].an,a[i].name,a[i].type,a[i].bal);
}
printf("\n");
}
} else
{
for(i=0;i<n;i++)
{
typ[10] = a[i].type;
res2 = strcmp(typ,c);
if(res2 == 0)
{
printf("%s\n%s\n%s\n%d\n\n",
a[i].an,a[i].name,a[i].type,a[i].bal);
}
printf("\n");
}
}
}
so basically ik its my homework but i did everythimg and i still cannot resolve the segmentation fault.please help
i think its something to do with strcmp() function but oh well
i checked all the sources but couldnt really find any fix.
any help would be appreciated.
For starters:
This
typ[10] = ...
accesses typ one past its valid memory. This invokes undefined behaviour, so anything can happen from then on.
In C array indexing is 0-based. So for char[10] the highest allowed index would be 9. Access the 1st element would be done by using 0.
You have made 2 mistakes here .
First your struct bank declaration was wrong. You forgot to declare name an and type as string. You declared it as just character(char).It should be like :-
struct bank
{
char an[100]; // assuming 100 is max size of input strings
char name[100];
char type[100];
int bal;
};
second you cannot do typ[10] = a[i].type; you should use strcpy() Something like this :-
strcpy(typ,a[i].type);
So this corrected code will work :-
#include <string.h>
#include <stdio.h>
#include <stdlib.h>
struct bank // change made 1
{
char an[100];
char name[100];
char type[100];
int bal;
};
int main()
{
int i = 0, n;
printf("Enter the number of accounts\n");
scanf("%d", &n);
struct bank a[n];
printf("Enter the details of the users\n");
for (i = 0; i < n; i++)
{
scanf("%s%s%s%d", a[i].an, a[i].name, a[i].type, &a[i].bal);
}
printf("The details of the users are\n");
for (i = 0; i < n; i++)
{
printf("%s\n%s\n%s\n%d\n\n", a[i].an, a[i].name, a[i].type, a[i].bal);
}
char atype[10];
printf("Enter the type of account you want to search\n");
scanf("%s", atype);
char typ[10];
char s[] = "savings";
char c[] = "current";
int result, res1, res2;
result = strcmp(atype, s);
if (result == 0)
{
for (i = 0; i < n; i++)
{
strcpy(typ,a[i].type); // change made 2
res1 = strcmp(typ, s);
if (res1 == 0)
{
printf("%s\n%s\n%s\n%d\n\n",
a[i].an, a[i].name, a[i].type, a[i].bal);
}
printf("\n");
}
}
else
{
for (i = 0; i < n; i++)
{
strcpy(typ,a[i].type); // change made 3
res2 = strcmp(typ, c);
if (res2 == 0)
{
printf("%s\n%s\n%s\n%d\n\n",
a[i].an, a[i].name, a[i].type, a[i].bal);
}
printf("\n");
}
}
}
So your mistake was not with strcmp()

How to use pointers to allocate an array inside another function

I'm 2nd year computer engineer and still in learning process of C language. I'd like to undesrtand how to dynamically alocate an array by using function instead of allocate inside the main.
Here is the code that works when I allocate array inside main.
#include <stdio.h>
#include <stdlib.h>
#include <windows.h>
#include <time.h>
#define ESC_KEY 27
#define NUM_1_KEY 49
#define NUM_2_KEY 50
void find_two_largest(int a[], int n, int *largest, int *second_largest);
void arrayInit(int *,int *, int, int);
void randGenArray(int [], int);
void inputArray(int[], int);
void result(int, int);
void loading(void);
int menu(void);
int main(void)
{
system("color f5");
int n,i,largest,largest_2, *a;
arrayInit(a,&n, 2, 10);
if(menu())
randGenArray(a,n);
else
inputArray(a,n);
find_two_largest(a,n,&largest,&largest_2);
result(largest,largest_2);
return 0;
}
void find_two_largest(int a[], int n, int *largest, int *second_largest)
{
int i=0,j=0;
system("cls");
loading();
*largest = 0;
*second_largest = *largest;
for (i=1;i<n;i++){
if(*largest<a[i])
*largest=a[i];
}
for(j=1;j<n;j++){
if(*largest==a[j])
continue;
else{
if(*second_largest<a[j])
*second_largest=a[j];
}
}
return;
}
void randGenArray(int a[], int n)
{
srand(time(NULL));
int i;
for(i=0; i<n; i++){
a[i]=rand()%100;
Sleep(10);
printf("\n>> Integer %d: %d", i+1, a[i]);
}
printf("\n\n\nPress any key to continue...");
getch();
return;
}
void inputArray(int a[], int n)
{
int i;
for(i=0; i<n; i++){
printf("\n Please enter integer %d: ", i+1);
scanf("%d",&a[i]);
}
return;
}
int menu(void)
{
char _char;
printf("\n Please choose one of the following options:\n 1.Fill array manually\n 2.Fill array by random numbers\n\n ");
while(1)
{
_char = getch();
switch(_char)
{
case ESC_KEY:
printf("\n\n Thank you for using our software!\n\n");
exit(0);
case NUM_1_KEY:
system("cls");
return 0;
case NUM_2_KEY:
system("cls");
return 1;
default:
break;
}
}
}
void arrayInit(int *a,int *n, int min, int max)
{
printf("\n Please enter a length of the array: ");
do{
scanf("%d", n);
if (*n<min||*n>max)
printf("\nThe ranged is limited. Please enter the value between %d and %d.\n", min, max);
} while(*n<min||*n>max);
a = (int*)calloc(*n,sizeof(int));
return;
}
void loading(void)
{
printf("\n Loading");
printf(".");
Sleep(300);
printf(".");
Sleep(300);
printf(".");
Sleep(300);
system("cls");
return;
}
void result(int l, int l2)
{
system("cls");
printf("\n Largest = %d Second Largest = %d",l,l2);
Sleep(500);
printf("\n\n\n Thank you using our software! ;D\n\n");
return;
}
But if you cut and paste this line from arrayInit to main and change *n to n - it will work!
a = (int*)calloc(*n,sizeof(int));
I'm sorry for asking about so stupid and obvious things but I didn't figure it out by myself. Thank you for any advice.
Here is a simple program which will show you how to do that -
#include <stdio.h>
#include <stdlib.h>
void create(int **p,int n); // function taking arguments as int ** and n is number of elements
int main(void) {
int *a;
int n=5,i; // declare and initialize n
create(&a,n); // pass address of a to function
for(i=0;i<n;i++){
a[i]=i; // store value of i in a[i]
printf("%d\n",i); // print a[i]
}
free(a); // free the allocated memory
return 0;
}
void create(int **p, int n){
*p=calloc(n,sizeof(int)); // allocate memory to *p (type- is int *)
}
Working Code
You must change your function return type
void * arrayInit(int *n, int min, int max)
{
printf("\n Please enter a length of the array: ");
do{
scanf("%d", n);
if (*n<min||*n>max)
printf("\nThe ranged is limited. Please enter the value between %d and %d.\n", min, max);
} while(*n<min||*n>max);
return calloc(*n,sizeof(int));
}
And call it from main in this way: a = arrayInit(&n, 2, 10);

C ascii to hex code

I need to convert an ascii input to hex input. I am very bad with C so if you could include some explanation that would be very helpful. This code is just a bunch of bits and pieces but most is probably wrong or useless. Afterwards i need to use user input to select the string but the hard part is getting it to convert at all.
#include <stdio.h>
#include <stdio.h>
#include <stdlib.h>
void crypt(char *buf, char *keybuf, int keylen) {
//This is meant to encrypt by xor-ing with the sentence and key entered//
//It is also supposed to replace the original buf with the new version post-xor//
int i;
int *xp;
xp=&i;
for(i=0; i<keylen; i++) {
buf[i]=buf[i]^keybuf[i];
xp++;
}
}
int convertkey(char *keybuf) {
int keylen=0;
//I need to add something that will return the length of the key by incrementing keylen according to *keybuf//
return keylen;
}
int main(int argc, char * argv[]){
char x;
char *xp;
xp = &x;
char a[47];
char *ap;
ap=a;
printf("Enter Sentence: ");
scanf("%[^\n]",a);
printf("Enter key: ");
scanf("%d",xp);
printf("You entered the sentence: %s\n",a);
printf("You entered the key: %d\n",x);
convertkey(xp);
crypt(ap,xp,x);
printf("New Sentence: %s\n",a);
return 0;
}
Such as it is, I have reorganised your posted code so at least it compiles, even if the intent is unclear. Perhaps you can take it on from here.
#include <stdio.h>
#include <stdlib.h>
// moved out of main()
void crypt(char *buf, char *keybuf, int keylen) {
int i; // added declaration
for(i=0; i<keylen; i++) { // corrected syntax and end condition
buf[i]=buf[i]^keybuf[i];
//xp++; // out of scope
}
}
// moved out of main()
int convertkey(char *keybuf) {
int keylen=0;
return keylen;
}
int main(int argc, char * argv[]){
int x=0;
int *xp;
xp = &x; // xp=&x{0};
return 0; // exit(0);
}
This is the final product I was looking for but was very poor at explaining/coding.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
void crypt(char *buf, char *keybuf, int keylen) {
int i;
int length= strlen(buf)-1;
for(i=0; i<length; i++) {
buf[i]=buf[i]^keybuf[i%keylen];
printf("%c",buf[i]);
}
printf("\n");
}
int convertkey(char *keybuf) {
int i=0;
for(i=0;keybuf[i]!='\n';i++){
if(keybuf[i]>='0' & keybuf[i]<='9'){
keybuf[i]=keybuf[i]-'0';
}
else if(keybuf[i]>='a' & keybuf[i]<='f'){
keybuf[i]=(keybuf[i]-'a')+10;
}
}
return i;
}
int main(int argc, char * argv[]){
char keychars[12];
char a[48];
char *ap;
int i;
ap=a;
printf("Enter Sentence: ");
fgets(a, 48, stdin);
printf("Enter Key: ");
fgets(keychars, 12, stdin);
for (i=0; i<strlen(keychars); i++) {
char c = keychars[i];
printf("keychars[%d]=%c (character), %d (decimal), %x (hex)\n", i, c, c, c);
}
crypt(ap,keychars,convertkey(keychars));
return 0;
}

Error: too few arguments to function 'strcmp'

I am having a few issues with my code. First: when I try to compile, I get error: too few arguments to function 'strcmp'. I have looked all over and made multiple changes and am still unable to get it to work. Second: when my code does compile (if I remove the strcmp part), it will not complete the count functions correctly. Can anyone please assist? Thank you!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int count(char array[], int size);
int stringLen(char array[]);
int convert(char ch);
int value, n;
int main()
{
//char * str;
//char s;
char a[100];
char b[100];
char c[100];
int charCount = stringLen(a);
int lCount = count(a, charCount);
printf("Enter your string: \n");
scanf("%s \n", a);
printf("Enter your string: \n");
scanf("%s \n", b);
printf("Enter your string: \n");
scanf("%s \n", c);
printf("The count is %d, length is %d\n", lCount, charCount);
int i;
for(i = 0; i < charCount; i++)
{
char c = a[i];
printf("Char %s = %d \n", &c, value);
}
n = strcmp(char string1[], char string2[], char string3[]);
printf("The first string in the alphabet is: %d \n", n);
return 0;
}
int stringLen(char array[])
{
char count;
int index;
while(array[index] !=0)
{
count++;
index++;
}
return count;
}
int count(char array[], int size)
{
int count;
int i;
for(i = 0; i < size; i++)
{
if(array[i] == 'a')
{
count ++;
}
else if(array[i] == 'A')
{
count ++;
}
}
return count;
}
This is not right way to use strcmp.
n = strcmp(char string1[], char string2[], char string3[]);
strcmp is used for compararison of string. See doc
int result = strcmp (string1,string2)
If strings are same, function will return 0.

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