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Closed 12 years ago.
int main()
{
int x = 2, y = 6, z = 6;
x = y == z;
printf("%d", x);
}
== has higher precedence than =, and y==z is 1.
I will end the answer there, because this looks like homework.
http://codepad.org/fp4ZYJX5
The output is:
1
Have a look at this, which explains a similar, yet more complex question and will answer yours as well.
Output is 1
If you want more help we can give you
Related
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Closed 9 years ago.
can anyone supply a complicate example using loop invariant example such as sum(int n) is so trivial that it can not show the power of loop invariant. I want a example that is not that obivious, and we can use method like loop invariant to solve it.
The Wikipedia example is quite good:
for (int i = 0; i < n; i++) {
x = y + z;
a[i] = 6 * i + x * x;
}
Two invariant can be moved (y + z and x * x). The advantage of this example is that after LICM has been applied, you can apply other optimizations on the code to have something very easy.
There are plenty on papers/slides/courses about that, you sure can find a satisfying example.
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Closed 9 years ago.
I'm learning c and I can't figure out the problem with this code:
#include <stdio.h>
int main(){
int i = 0;
while(i > 10){
printf("hello");
i++;
}
getch();
return 0;
}
I don't get any errors and have tried running it on codeblocks and wxdev c++. So is there something I'm doing wrong. Thanks.
You set
i = 0;
and then test
i > 10
which is always false.
You might want
while (i < 10)
instead.
I is not greater than 10 so it doesnt meet the requirement to enter the while loop
while(i > 10){
...but i is 0 so it's false and skips.
You probably meant to instead write;
while(i < 10) {
Reason: i is not greater than 10.
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Closed 10 years ago.
void main(){
int i;
i=printf("how r u?\n");
i=printf("%d",i);
printf("%d",i);}
The above code gives the result as:
how r u?
91
My question:
How does stores 9 and 1??
From the man page: Upon successful return, these functions return the number of characters printed.... If an output error is encountered, a negative value is returned.
So you are getting 9 and i because printf wrote out 9 and 1 characters respectively.
This is also relevant: Why does printf return a value?
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Closed 10 years ago.
Program to understand sizeof operator:
#include<stdio.h>
#include<conio.h>
#include<string.h>
main()
{
char *mess[]={ //array of pointers
"amol is a good boy",
"robin singh",
"genious boy",
"bitch please"
};
printf("%d",sizeof(mess)); // what does sizeof operator do?
}
Please explain the output of this code.
It is the storage size in bytes of 4 pointers to char.
You have your answer right in your question. It has a size of an array of pointers.
So the size is 4 * size of a pointer. (which is 32 on my system.) Your system might vary.
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Closed 12 years ago.
i am learning C programming, i was trying to write a recursive function by using this prototype:
void fact(int *n);
The parameter of this function should be passed by reference. Thanks for your help.
I don't feel to be helpful in giving a complete solution -- this is just to show there is an answer:
void fact(int *n)
{
if (*n > 1)
{
int tmp = *n - 1;
fact(&tmp);
*n *= tmp;
}
}
I would never write a factorial function this way.