I've been asked to change a pivot query that currently displays a week ending date, category and hours by date for one week in a row. I've been asked to display a comment field at the end of the row and I can't figure out how to alter the query to do this.
The table is structured like this
Category Date Comments Hours
test 8/2/2010 myComment 2
test 8/3/2010 8
test 8/4/2010 4
test 8/5/2010 3
test 8/6/2010 5
I would like the data to display like this. I have a query that will diplay all of this except the comment. On the front End I'm only going to allow one comment per week and add it to the Monday date row in the table for each week/category combination.
WeekEnding Category SunHrs MonHrs TuesHrs WedHrs ThuHrs FriHrs SatHrs Comment
8/7/2010 test 0 1 1 1 1 1 1 myComment
Here is the query before adding the comment field which works fine.
DECLARE #WeekEnding datetime
DECLARE #UserName nvarchar(245)
SET #WeekEnding = '09/04/2010'
SET #UserName = 'brogers'
SELECT
#WeekEnding WeekEnding
,CategoryID
,isnull([1], 0) SunHrs
,isnull([2], 0) MonHrs
,isnull([3], 0) TueHrs
,isnull([4], 0) WedHrs
,isnull([5], 0) ThuHrs
,isnull([6], 0) FriHrs
,isnull([7], 0) SatHrs
from (select CategoryID, Datepart(dw, TimeEntryDate) DOW, TimeEntryDuration Hours
from dbo.aspnet_starterkits_TimeEntry
where TimeEntryDate between dateadd(dd, -6, #WeekEnding) and #WeekEnding) Source
pivot (max(Hours) for DOW in ([1],[2],[3],[4],[5],[6],[7]) ) as pvt
I'm not sure how to add the comment field to the end of the row. When I do add it I get a result like this
WeekEnding Category SunHrs MonHrs TuesHrs WedHrs ThuHrs FriHrs SatHrs Comment
8/7/2010 test 0 0 1 1 1 1 0
8/7/2010 test 0 1 0 0 0 0 0 myComment
I only want one row per weekending/category combination and one comment per row in the output.
Here is the query that where I added the comment field and displays incorrectly.
Can anyone point out how to display one comment per week/categroy row?
DECLARE #WeekEnding datetime
DECLARE #UserName nvarchar(245)
SET #WeekEnding = '09/04/2010'
SET #UserName = 'brogers'
SELECT
#WeekEnding WeekEnding
,TimeEntryDescription
,CategoryID
,isnull([1], 0) SunHrs
,isnull([2], 0) MonHrs
,isnull([3], 0) TueHrs
,isnull([4], 0) WedHrs
,isnull([5], 0) ThuHrs
,isnull([6], 0) FriHrs
,isnull([7], 0) SatHrs
from (select
CategoryID,
Datepart(dw, TimeEntryDate) DOW,
TimeEntryDuration Hours,
TimeEntryDescription
from dbo.aspnet_starterkits_TimeEntry
where TimeEntryDate between dateadd(dd, -6, #WeekEnding) and #WeekEnding) Source
pivot (max(Hours) for DOW in ([1],[2],[3],[4],[5],[6],[7]) ) as pvt
Even though the source table has a comment field for every day of the week, I only want one comment per week and one row per week/category combination.
I will restrict the input to only allow one per week (monday for example) and want this one comment to display at the end of the row on the output query.
This is probably easier with an old style pivot
;With [Source] As
(
select
CategoryID,
Datepart(dw, TimeEntryDate) DOW,
TimeEntryDuration Hours,
TimeEntryDescription
from dbo.aspnet_starterkits_TimeEntry
where TimeEntryDate between dateadd(dd, -6, #WeekEnding) and #WeekEnding
)
SELECT
#WeekEnding WeekEnding
,TimeEntryDescription
,CategoryID
,max(case when DOW = 1 then [Hours] else 0 end) SunHrs
,max(case when DOW = 2 then [Hours] else 0 end) MonHrs
,max(case when DOW = 3 then [Hours] else 0 end) TueHrs
,max(case when DOW = 4 then [Hours] else 0 end) WedHrs
,max(case when DOW = 5 then [Hours] else 0 end) ThuHrs
,max(case when DOW = 6 then [Hours] else 0 end) FriHrs
,max(case when DOW = 7 then [Hours] else 0 end) SatHrs
,max(comment) as comment
from [Source]
group by
TimeEntryDescription
,CategoryID
Join the pivot table with the source table on date and retrieve min(comment).
DECLARE #WeekEnding datetime
DECLARE #UserName nvarchar(245)
SET #WeekEnding = '09/04/2010'
SET #UserName = 'brogers'
;with Report as (
SELECT
#WeekEnding WeekEnding
,TimeEntryDescription
,CategoryID
,isnull([1], 0) SunHrs
,isnull([2], 0) MonHrs
,isnull([3], 0) TueHrs
,isnull([4], 0) WedHrs
,isnull([5], 0) ThuHrs
,isnull([6], 0) FriHrs
,isnull([7], 0) SatHrs
from (select
CategoryID,
Datepart(dw, TimeEntryDate) DOW,
TimeEntryDuration Hours,
TimeEntryDescription
from dbo.aspnet_starterkits_TimeEntry
where TimeEntryDate between dateadd(dd, -6, #WeekEnding) and #WeekEnding) Source
pivot (max(Hours) for DOW in ([1],[2],[3],[4],[5],[6],[7]) ) as pvt
)
select *
,(select min(comment) from dbo.aspnet_starterkits_TimeEntry te where TimeEntryDate between dateadd(dd, -6, #WeekEnding) and #WeekEnding)) [Comment]
from Report r
Related
I try this SQL query to get current total and also last 2 months records and current month record means total 3 months..
Select distinct
tblRv.Owner,
(Select Count(*) as total from tblvv WHERE MasterID =tblRv.ID and Name <> '')
as currentdata
from tblRe
inner join tblRv
On tblRe.RID = tblRv.RID
WHERE
tblRe.StartDate between dateadd(m, -2, getdate()) and getdate() and
//tblRe.StartDate >= '2016-07-01 00:00:00' AND
//tblRe.EndDate <= '2016-07-08 23:59:59'
and tblRe.Region = 'uk' and
tblRv.Owner='Roh'
order by tblRv.Owner
when i exe this show me like this
OwnerName currentdata
Roh 1
Roh 2
Roh 3
Roh 5
and when i check individually write query and check from date 2016-07-01 and todate 2016-07-30 dates then this show me data 3 and 2016-06-01 00:00:00 and 2016-06-31 23:59:59 show me data 1 and 2016-05-01 00:00:00 ,2016-05-31 23:59:59 show me data 0
so i want data like this
owner july june may
roh 3 1 0
also when there will be current month i.e. aug then data must display last 2 months i.e.june july
Select
tblRv.Owner
,DATENAME(MONTH,tblRe.StartDate) as [Month]
,ISNULL(SUM(total),0) as currentdata
from tblRe
INNER JOIN tblRv ON tblRe.RID = tblRv.RID
LEFT JOIN (
Select Count(*) as total ,MasterID
from tblvv
WHERE Name <> ''
GROUP BY MasterID
) tblvv
ON tblvv.MasterID =tblRv.ID
WHERE tblRe.StartDate >= DATEADD(MONTH, -2, GETDATE())
AND tblRe.EndDate <= GETDATE()
AND tblRe.Region = 'uk'
AND tblRv.[Owner] ='Roh'
GROUP BY tblRv.Owner
,DATENAME(MONTH,tblRe.StartDate)
order by tblRv.[Owner]
You can try doing a pivot query where the three columns to be pivoted are the current, previous, and previous previous month in your data set. Note that I had to rewrite your query to remove the subqueries in the SELECT clause, because this makes it impossible to do aggregation of those columns.
SELECT tblRv.Owner,
SUM(CASE WHEN tblRe.StartDate = GETDATE() THEN t.total ELSE 0 END) AS currMonth,
SUM(CASE WHEN tblRe.StartDate = DATEADD(m, -1, GETDATE())
THEN t.total ELSE 0 END) AS prevMonth,
SUM(CASE WHEN tblRe.StartDate = DATEADD(m, -2, GETDATE())
THEN t.total ELSE 0 END) AS lastPrevMonth
FROM tblRe
INNER JOIN tblRv
ON tblRe.RID = tblRv.RID
INNER JOIN
(
SELECT MasterID, COUNT(*) AS total
FROM tblvv
GROUP BY MasterID
WHERE Name <> ''
) AS t
ON tblRv.ID = t.MasterID
WHERE tblRe.StartDate BETWEEN DATEADD(m, -2, GETDATE()) AND GETDATE() AND
tblRe.Region = 'uk' AND
tblRv.Owner = 'Roh'
GROUP BY tblRv.Owner
ORDER BY tblRv.Owner
I have a query that I have been using to track users sales. Previously they ere required to make a quota each month. Now, however they would like to change the rule to allow them to start any month, so they may go from June to June or whatever. they also want users to start over immediately if they miss a month. This does seem to be a more equitable system because if they didn't make the quota in March, for example, they were unable to count any they made after that month for the entire year. This really messes up my query though, and I don't know how to fix it. anyone have a solution?
here is the existing t-sql.
#Year int
AS
BEGIN
DECLARE #DateStart datetime
DECLARE #DateStop datetime
SELECT #DateStart = CONVERT(DATETIME, CONVERT( char(4), #Year) + '-01- 01')
SELECT #DateStop = CONVERT(DATETIME, CONVERT( char(4), #Year + 1) + '-01- 01')
SET NOCOUNT ON;
SELECT r.riderid,
r.dname,
DATEPART(yyyy, m.ridedate),
SUM(CASE DATEPART(mm, m.datesale) WHEN 1 THEN m.quota ELSE 0 END) AS [jan],
SUM(CASE DATEPART(mm, m.datesale) WHEN 2 THEN m.quota ELSE 0 END) AS [feb],
SUM(CASE DATEPART(mm, m.datesale) WHEN 3 THEN m.quota ELSE 0 END) AS [mar],
SUM(CASE DATEPART(mm, m.datesale) WHEN 4 THEN m.quota ELSE 0 END) AS [apr],
SUM(CASE DATEPART(mm, m.datesale) WHEN 5 THEN m.quota ELSE 0 END) AS [may],
SUM(CASE DATEPART(mm, m.datesale) WHEN 6 THEN m.quota ELSE 0 END) AS [jun],
SUM(CASE DATEPART(mm, m.datesale) WHEN 7 THEN m.quota ELSE 0 END) AS [jul],
SUM(CASE DATEPART(mm, m.datesale) WHEN 8 THEN m.quota ELSE 0 END) AS [aug],
SUM(CASE DATEPART(mm, m.datesale) WHEN 9 THEN m.quota ELSE 0 END) AS [sep],
SUM(CASE DATEPART(mm, m.datesale) WHEN 10 THEN m.quota ELSE 0 END) AS [oct],
SUM(CASE DATEPART(mm, m.datesale) WHEN 11 THEN m.quota ELSE 0 END) AS [nov],
SUM(CASE DATEPART(mm, m.datesale) WHEN 12 THEN m.quota ELSE 0 END) AS [dec],
SUM(m.quota) as [tot]
FROM users u
JOIN mysales m
ON m.riderid = u.riderid
Where m.datesale Between #DateStart AND #DateStop
GROUP BY DATEPART(yyyy, m.datesale), u.userid
ORDER BY DATEPART(yyyy, m.datesale), SUM(m.quota) DESC
END
OK -here is data
The table holds the users id, the customer id , amount of sale and date of sale
The query pulls the user, the sum of sales by month. User 250 made quota in July/2016, but did not in August, so he should get an entry in #quota for July, and September, but because he did not in August he has to restart in September; user# 300 has made quota from Jan 2016 to SEPT so he has qualified for his bonus as long as he finishes the 12 months. User 350 has successfully finished the year and should get a bonus. at this time in prod there is no quota table, would that simplify? What I need is a list of users that are in the running.
--drop table #sales
--drop table #quota
create table #sales
(
--saleid int --PK
userid int -- salesperson FK
, customerid int --FK
, sale_amt decimal
, date_sale datetime
)
insert into #sales values
(300,1301,542.90,'3-2-2016'),
(300,1301,782.70,'3-4-2016'),
(300,1541,600.70,'3-7-2016'),
(300,903,640.71,'3-10-2016'),
(300,1745,900.01,'3-29-2016'),
(300,1440,2040.71,'2-10-2016'),
(300,903,640.71,'2-20-2016'),
(300,414,1489.00,'1-18-2016'),
(300,1645,1322.00,'1-20-2016'),
(300,1200,1156.09,'4-2-2016'),
(300,1204,1456.00,'4-20-2016'),
(250,1140,156.89,'4-12-2016'),
(250,1240,1176.69,'4-14-2016'),
(250,840,480.61,'4-17-2016'),
(250,1940,500.71,'5-17-2016'),
(250,1425,4800.61,'6-1-2016'),
(250,1840,701.32,'6-15-2016'),
(250,1840,701.32,'7-15-2016'),
(250,1840, 2701.32,'8-15-2016'),
(450,8421,2500.61,'7-17-2015'),
(450,8422,2500.1,'8-17-2015'),
(450,843,2500.1,'9-17-2015'),
(450,8431,2500.00,'10-17-2015'),
(450,1431,2500.00,'11-17-2015'),
(450,4311,2500.00,'12-17-2015'),
(450,4310,2500.00,'1-17-2016'),
(450,1310,2500.00,'2-17-2016'),
(450,1310,2500.00,'3-17-2016'),
(450,130,2500.00,'4-17-2016'),
(450,1130,2500.00,'5-17-2016'),
(450,113,2500.00,'6-17-2016')
Select userid
, sum(sale_amt) Sale
, DATEPART(mm,date_sale) as[month]
from #sales
group by userid, DATEPART(mm,date_sale) order by userid
create table #quota
(
qid int --PK
, userid int -- salesperson FK
, quota bit -- awarded when sales => $2500.00
, datesale datetime -- date quota made
)
Just one possible way to write a query that looks back #running_months number of months to verify that no quotas have been missed during the window for each user:
select userid from users u
where not exists (
select 1 from #sales s
where s.userid = u.userid
and date_sale > dateadd(month, -#running_months - 1, current_timestamp)
and datediff(month, sales_date, current_timestamp) between 1 and #running_months
group by month(sales_amt)
having sum(sales_amt) < 2500
)
EDIT: I later realized that you probably do have users with no sales during a month so you'll probably need to actually verify the condition that all the months are over quota rather than none of the months are under quota:
select userid from users u
where userid in (
select userid from
(
select userid from #sales s
where s.userid = u.userid
and date_sale > dateadd(month, -#running_months - 1, current_timestamp)
and datediff(month, sales_date, current_timestamp) between 1 and #running_months
group by month(sales_amt)
having sum(sales_amt) >= 2500
) q
group by userid
having count(*) = #running_months
)
I am trying to get the totals of each month as of YTD (Years to date) Can someone please help me figure out how to integrate this in my query? thank you This is what I have so far.
DECLARE #Year int
set #Year = 2013
select a.first_name, a.last_name
, COUNT(CASE WHEN MONTH(b.Funded_date) = 1 THEN 1 ELSE NULL END) January
, COUNT(CASE WHEN MONTH(b.Funded_date) = 2 THEN 1 ELSE NULL END) February
, COUNT(CASE WHEN MONTH(b.Funded_date) = 3 THEN 1 ELSE NULL END) March
, COUNT(CASE WHEN MONTH(b.Funded_date) = 4 THEN 1 ELSE NULL END) April
From tContact a Join tContract b ON a.contact_id = b.contract_id
Group by a.first_name, a.last_name
This is just an example of how you could count up rows that fall under a certain month.
SELECT MONTH(b.Funded_date) AS 'MonthNum',
COUNT(*) AS 'Total'
FROM Table AS b
WHERE YEAR(b.Funded_date) = 2014
GROUP BY MONTH(b.Funded_date)
Hopefully this will help you with your query.
Thanks
What I tried to do here is create an upper bound record for each month in tContract then join that back into the query you already had. It is joined on dates that are between the beginning of the year and the current month.
DECLARE #Year int
set #Year = 2013
select Ms.thismonth, count(B.thing_You_are_Totalling) from (
select thisMonth = dateadd(month,datediff(month,0,Funded_date),0)
from tContract
where moid = 2005405
and year(Funded_date) = #Year
group by dateadd(month,datediff(month,0,Funded_date),0)
) Ms
inner join (select * from tContact a inner join tContract ON a.contact_id = tContract.contract_id) B
on B.Funded_date >=dateadd(year,datediff(year,0,B.Funded_date),0) -- beginning of year
and B.Funded_date <= Ms.thisMonth -- this month
where year(B.Funded_date) = #Year -- restrict to only this year
group by thisMonth, first_name, last_name
I don't have your full table definition so there might be some issues (maybe a SqlFiddle is in order)
Not sure if this is what you are asking for.
select a.first_name, a.last_name
, COUNT(CASE WHEN MONTH(b.Funded_date) = 1 THEN 1 ELSE NULL END) January
, COUNT(CASE WHEN MONTH(b.Funded_date) = 2 THEN 1 ELSE NULL END) February
, COUNT(CASE WHEN MONTH(b.Funded_date) = 3 THEN 1 ELSE NULL END) March
, COUNT(CASE WHEN MONTH(b.Funded_date) = 4 THEN 1 ELSE NULL END) April
, COUNT(*) TotalCount
, SUM(CASE WHEN MONTH(b.Funded_date) = 1 THEN Amount ELSE NULL END) JanuaryAmount
, SUM(CASE WHEN MONTH(b.Funded_date) = 2 THEN Amount ELSE NULL END) FebruaryAmount
, SUM(CASE WHEN MONTH(b.Funded_date) = 3 THEN Amount ELSE NULL END) MarchAmount
, SUM(CASE WHEN MONTH(b.Funded_date) = 4 THEN Amount ELSE NULL END) AprilAmount
From tContact a Join tContract b ON a.contact_id = b.contact_id
WHERE YEAR(b.Funded_date) = #Year
Group by a.first_name, a.last_name
How about this:
declare #year int = 2013
select a.first_name
, a.last_name
, month(b.Funded_date) [Month]
, datename(month, dateadd(month, month(date_of_birth_dt), - 1)) [MonthName]
, count(month(b.Funded_date)) [Total]
from tContact a
where a.[Year] = #year
group by a.first_name, a.last_name, month(b.Funded_date)
It returns the total of each Month for the year 2013. a.[Year] might not the the name of the field that you have so adjust accordingly. Also, [Month] returns numeric value for month.
Use the Count(*) As Total function. I'm sure this will help you
SELECT MONTH(b.Funded_date) AS 'MonthNum',
COUNT(*) AS 'Total'
FROM Table AS b
WHERE YEAR(b.Funded_date) = 2014
GROUP BY MONTH(b.Funded_date)
I have my database table ABC as shown below :
ItemId Month Year Sales
1 1 2013 333
1 2 2013 454
2 1 2013 434
and so on .
I would like to write a query to find the top 3 items that have had the highest increase in sales from last month to this month , so that I see somethinglike this in the output.
Output :
ItemId IncreaseInSales
1 +121
9 +33
6 +16
I came up to here :
select
(select Sum(Sales) from ABC where [MONTH] = 11 )
-
(select Sum(Sales) from ABC where [MONTH] = 10)
I cannot use a group by as it is giving an error . Can anyone point me how I can
proceed further ?
Assuming that you want the increase for a given month, you can also do this with an aggregation query:
select top 3 a.ItemId,
((sum(case when year = #YEAR and month = #MONTH then 1.0*sales end) /
sum(case when year = #YEAR and month = #MONTH - 1 or
year = #YEAR - 1 and #Month = 1 and month = 12
then sales end)
) - 1
) * 100 as pct_increase
from ABC a
group by a.ItemId
order by pct_increase desc;
You would put the year/month combination you care about in the variables #YEAR and #MONTH.
EDIT:
If you just want the increase, then do a difference:
select top 3 a.ItemId,
(sum(case when year = #YEAR and month = #MONTH then 1.0*sales end) -
sum(case when year = #YEAR and month = #MONTH - 1 or
year = #YEAR - 1 and #Month = 1 and month = 12
then sales
end)
) as difference
from ABC a
group by a.ItemId
order by difference desc;
Here is the SQL Fiddle that demonstrates the below query:
SELECT TOP(3) NewMonth.ItemId,
NewMonth.Month11Sales - OldMonth.Month10Sales AS IncreaseInSales
FROM
(
SELECT s1.ItemId, Sum(s1.Sales) AS Month11Sales
FROM ABC AS s1
WHERE s1.MONTH = 11
AND s1.YEAR = 2013
GROUP BY s1.ItemId
) AS NewMonth
INNER JOIN
(
SELECT s2.ItemId, Sum(s2.Sales) AS Month10Sales
FROM ABC AS s2
WHERE s2.MONTH = 10
AND s2.YEAR = 2013
GROUP BY s2.ItemId
) AS OldMonth
ON NewMonth.ItemId = OldMonth.ItemId
ORDER BY NewMonth.Month11Sales - OldMonth.Month10Sales DESC
You never mentioned if you could have more than one record for an ItemId with the same Month, so I made the query to handle it either way. Obviously you were lacking the year = 2013 in your query. Once you get past this year you will need that.
Another option could be something on these lines:
SELECT top 3 a.itemid, asales-bsales increase FROM
(
(select itemid, month, sum(sales) over(partition by itemid) asales from ABC where month=2
and year=2013) a
INNER JOIN
(select itemid, month, sum(sales) over(partition by itemid) bsales from ABC where month=1
and year=2013) b
ON a.itemid=b.itemid
)
ORDER BY increase desc
if you need to cater for months without sales then you can do a FULL JOIN and calculate increase as isnull(asales,0) - isnull(bsales,0)
You could adapt this solution based on PIVOT operator:
SET NOCOUNT ON;
DECLARE #Sales TABLE
(
ItemID INT NOT NULL,
SalesDate DATE NOT NULL,
Amount MONEY NOT NULL
);
INSERT #Sales (ItemID, SalesDate, Amount)
VALUES
(1, '2013-01-15', 333), (1, '2013-01-14', 111), (1, '2012-12-13', 100), (1, '2012-11-12', 150),
(2, '2013-01-11', 200), (2, '2012-12-10', 150), (3, '2013-01-09', 900);
-- Parameters (current year & month)
DECLARE #pYear SMALLINT = 2013,
#pMonth TINYINT = 1;
DECLARE #FirstDayOfCurrentMonth DATE = CONVERT(DATE, CONVERT(CHAR(4), #pYear) + '-' + CONVERT(CHAR(2), #pMonth) + '-01');
DECLARE #StartDate DATE = DATEADD(MONTH, -1, #FirstDayOfCurrentMonth), -- Begining of the previous month
#EndDate DATE = DATEADD(DAY, -1, DATEADD(MONTH, 1, #FirstDayOfCurrentMonth)) -- End of the current month
SELECT TOP(3) t.ItemID,
t.[2]-t.[1] AS IncreaseAmount
FROM
(
SELECT y.ItemID, y.Amount,
DENSE_RANK() OVER(ORDER BY y.FirstDayOfSalesMonth ASC) AS MonthNum -- 1=Previous Month, 2=Current Month
FROM
(
SELECT x.ItemID, x.Amount,
DATEADD(MONTH, DATEDIFF(MONTH, 0, x.SalesDate), 0) AS FirstDayOfSalesMonth
FROM #Sales x
WHERE x.SalesDate BETWEEN #StartDate AND #EndDate
) y
) z
PIVOT( SUM(z.Amount) FOR z.MonthNum IN ([1], [2]) ) t
ORDER BY IncreaseAmount DESC;
SQLFiddle demo
Your sample data seems to be incomplete, however, here is my try. I assume that you want to know the three items with the greatest sales-difference from one month to the next:
WITH Increases AS
(
SELECT a1.itemid,
a1.sales - (SELECT a2.sales
FROM dbo.abc a2
WHERE a1.itemid = a2.itemid
AND ( ( a1.year = a2.year
AND a1.month > 1
AND a1.month = a2.month + 1 )
OR ( a1.year = a2.year + 1
AND a1.month = 1
AND a2.month = 12 ) ))AS IncreaseInSales
FROM dbo.abc a1
)
SELECT TOP 3 ItemID, MAX(IncreaseInSales) AS IncreaseInSales
FROM Increases
GROUP BY ItemID
ORDER BY MAX(IncreaseInSales) DESC
Demo
SELECT
cur.[ItemId]
MAX(nxt.[Sales] - cur.[Sales]) AS [IncreaseInSales]
FROM ABC cur
INNER JOIN ABC nxt ON (
nxt.[Year] = cur.[Year] + cur.[month]/12 AND
nxt.[Month] = cur.[Month]%12 + 1
)
GROUP BY cur.[ItemId]
I'd do this this way. It should work in all the tagged versions of SQL Server:
SELECT TOP 3 [ItemId],
MAX(CASE WHEN [Month] = 2 THEN [Sales] END) -
MAX(CASE WHEN [Month] = 1 THEN [Sales] END) [Diff]
FROM t
WHERE [Month] IN (1, 2) AND [Year] = 2013
GROUP BY [ItemId]
HAVING COUNT(*) = 2
ORDER BY [Diff] DESC
Fiddle here.
The reason why I'm adding the HAVING clause is that if any item is added in only one of the months then the numbers will be all wrong. So I'm only comparing items that are only present in both months.
The reason of the WHERE clause would be to filter in advance only the needed months and improve the efficiency of the query.
An SQL Server 2012 solution could also be:
SELECT TOP 3 [ItemId], [Diff] FROM (
SELECT [ItemId],
LEAD([Sales]) OVER (PARTITION BY [ItemId] ORDER BY [Month]) - [Sales] Diff
FROM t
WHERE [Month] IN (1, 2) AND [Year] = 2013
) s
WHERE [Diff] IS NOT NULL
ORDER BY [Diff] DESC
I have little table which gives me a very hard time:
Person datetime1 datetime2
Eric 2012-10-01 09:00:05.000 2012-10-01 22:00:00.000
Anna 2012-10-02 06:00:05.000 2012-10-03 12:00:05.000
Richard 2012-10-03 09:00:05.000 2012-10-04 02:00:05.000
Chuck 2012-10-01 12:00:05.000 2012-10-01 23:00:05.000
I am trying to write a query, which gives me statistics table. This table contains information about when a user logged in and out (daily granularity):
Date logged_in logged_off
2012-10-01 2 2
2012-10-02 1 0
2012-10-03 1 1
2012-10-04 0 1
According to my research, a pivot command could solve the problem?
select Person,
SUM(case when datetime1 = '2012-10-01' then 1 else 0 end) as [loggeed_in],
SUM(case when datetime2 = '2012-10-01' then 1 else 0 end) as [logged_of]
from table
group by Person
This is not working... Do you have any ideas?
This will fix the current query, but don't know if it will solve the whole problem...
select Person,
SUM(case when convert(varchar(10), datetime1, 111) = '2012/10/01' then 1 else 0 end) as [loggeed_in],
SUM(case when convert(varchar(10), datetime2, 111) = '2012/10/01' then 1 else 0 end) as [logged_of]
from table
group by Person
EDIT: I believe this will better suit requirements...
SELECT
[Date] = dt,
logged_in = (
SELECT COUNT(*)
FROM table1
WHERE convert(varchar(10), datetime1, 111) = convert(varchar(10), dt, 111)),
logged_off = (
SELECT COUNT(*)
FROM table1
WHERE convert(varchar(10), datetime2, 111) = convert(varchar(10), dt, 111))
FROM (
SELECT TOP 1000
row_number() OVER(ORDER BY (SELECT 0)) AS N
FROM master.dbo.syscolumns sc1, master.dbo.syscolumns sc2) tally
CROSS APPLY(
SELECT dt = DATEADD(dd, tally.N - 1, '2012-10-1')) tallydt
WHERE dt BETWEEN (SELECT MIN(dateadd(dd, -1, datetime1)) FROM table1) AND (SELECT MAX(datetime2) FROM table1)
GROUP BY dt
ORDER BY dt
Here is the working solution:
WITH O AS (
SELECT
CAST([login Date & Time] AS DATE) loginDate
,COUNT(*) logined
FROM table
GROUP BY CAST([login Date & Time] AS DATE)
), C AS (
SELECT
CAST([Close Date & Time] AS DATE) CloseDate
,COUNT(*) Closed
FROM table
WHERE [Close Date & Time] IS NOT NULL
GROUP BY CAST([Close Date & Time] AS DATE)
)
SELECT
COALESCE(C.CloseDate, O.loginDate) TheDate
--,O.loginDate
--,C.CloseDate
,O.logined
,C.Closed
FROM O
FULL JOIN C
ON O.loginDate = C.CloseDate
ORDER BY TheDate