Assign multiple values to array in C - c

Question

Is there any way to do this in a condensed form?
GLfloat coordinates[8];
...
coordinates[0] = 1.0f;
coordinates[1] = 0.0f;
coordinates[2] = 1.0f;
coordinates[3] = 1.0f;
coordinates[4] = 0.0f;
coordinates[5] = 1.0f;
coordinates[6] = 0.0f;
coordinates[7] = 0.0f;
return coordinates;
Something like coordinates = {1.0f, ...};?

Answer 1

If you really to assign values (as opposed to initialize), you can do it like this:
GLfloat coordinates[8];
static const GLfloat coordinates_defaults[8] = {1.0f, 0.0f, 1.0f ....};
...
memcpy(coordinates, coordinates_defaults, sizeof(coordinates_defaults));
return coordinates;

Answer 2

Although in your case, just plain initialization will do, there's a trick to wrap the array into a struct (which can be initialized after declaration).
For example:
struct foo {
GLfloat arr[10];
};
...
struct foo foo;
foo = (struct foo) { .arr = {1.0, ... } };

Answer 3

The old-school way:
GLfloat coordinates[8];
...
GLfloat *p = coordinates;
*p++ = 1.0f; *p++ = 0.0f; *p++ = 1.0f; *p++ = 1.0f;
*p++ = 0.0f; *p++ = 1.0f; *p++ = 0.0f; *p++ = 0.0f;
return coordinates;

Answer 4

You can use:
GLfloat coordinates[8] = {1.0f, ..., 0.0f};
but this is a compile-time initialisation - you can't use that method in the current standard to re-initialise (although I think there are ways to do it in the upcoming standard, which may not immediately help you).
The other two ways that spring to mind are to blat the contents if they're fixed:
GLfloat base_coordinates[8] = {1.0f, ..., 0.0f};
GLfloat coordinates[8];
:
memcpy (coordinates, base_coordinates, sizeof (coordinates));
or provide a function that looks like your initialisation code anyway:
void setCoords (float *p0, float p1, ..., float p8) {
p0[0] = p1; p0[1] = p2; p0[2] = p3; p0[3] = p4;
p0[4] = p5; p0[5] = p6; p0[6] = p7; p0[7] = p8;
}
:
setCoords (coordinates, 1.0f, ..., 0.0f);
keeping in mind those ellipses (...) are placeholders, not things to literally insert in the code.

Answer 5

I went with an array initialization method:
#include <stdarg.h>
void int_array_init(int *a, const int ct, ...) {
va_list args;
va_start(args, ct);
for(int i = 0; i < ct; ++i) {
a[i] = va_arg(args, int);
}
va_end(args);
}
called like,
const int node_ct = 8;
int expected[node_ct];
int_array_init(expected, node_ct, 1, 3, 4, 2, 5, 6, 7, 8);
The C99 array initialization, like this:
const int node_ct = 8;
const int expected[node_ct] = { 1, 3, 4, 2, 5, 6, 7, 8 };
And in the configure.ac:
AC_PROG_CC_C99
had the compiler on my dev box perfectly happy. The compiler on the server complained with:
error: variable-sized object may not be initialized
const int expected[node_ct] = { 1, 3, 4, 2, 5, 6, 7, 8 };
and
warning: excess elements in array initializer
const int expected[node_ct] = { 1, 3, 4, 2, 5, 6, 7, 8 };
for each element
It doesn't complain at all about, for example:
int expected[] = { 1, 2, 3, 4, 5 };
I like the check on size, and that the varargs support is acting more robustly than the support for the array initializer.
Find PR with sample code at https://github.com/wbreeze/davenport/pull/15/files
Regarding https://stackoverflow.com/a/3535455/608359 from #paxdiablo, I liked it; but, felt insecure about having the number of times the initializaion pointer advances synchronized with the number of elements allocated to the array. Worst case, the initializing pointer moves beyond the allocated length. As such, the diff in the PR contains,
int expected[node_ct];
- int *p = expected;
- *p++ = 1; *p++ = 2; *p++ = 3; *p++ = 4;
+ int_array_init(expected, node_ct, 1, 2, 3, 4);
The int_array_init method will safely assign junk if the number of
arguments is fewer than the node_ct. The junk assignment ought to be easier
to catch and debug.

Answer 6

Exactly, you nearly got it:
GLfloat coordinates[8] = {1.0f, ..., 0.0f};

Answer 7

If you are doing these same assignments a lot in your program and want a shortcut, the most straightforward solution might be to just add a function
static inline void set_coordinates(
GLfloat coordinates[static 8],
GLfloat c0, GLfloat c1, GLfloat c2, GLfloat c3,
GLfloat c4, GLfloat c5, GLfloat c6, GLfloat c7)
{
coordinates[0] = c0;
coordinates[1] = c1;
coordinates[2] = c2;
coordinates[3] = c3;
coordinates[4] = c4;
coordinates[5] = c5;
coordinates[6] = c6;
coordinates[7] = c7;
}
and then simply call
GLfloat coordinates[8];
// ...
set_coordinates(coordinates, 1.0f, 0.0f, 1.0f, 1.0f, 0.0f, 1.0f, 0.0f, 0.0f);

Answer 8

typedef struct{
char array[4];
}my_array;
my_array array = { .array = {1,1,1,1} }; // initialisation
void assign(my_array a)
{
array.array[0] = a.array[0];
array.array[1] = a.array[1];
array.array[2] = a.array[2];
array.array[3] = a.array[3];
}
char num = 5;
char ber = 6;
int main(void)
{
printf("%d\n", array.array[0]);
// ...
// this works even after initialisation
assign((my_array){ .array = {num,ber,num,ber} });
printf("%d\n", array.array[0]);
// ....
return 0;
}