if I have a .txt that has the following:
2005050 "2/19/2005"
2005060 "3/1/2005"
2005070 "3/11/2005"
2005080 "3/21/2005"
2005090 "3/31/2005"
Is there a way for the batch file to read and always add .png in the end of a character of 7.
For example.
2005050.png "2/19/2005"
2005060.png "3/1/2005"
2005070.png "3/11/2005"
2005080.png "3/21/2005"
2005090.png "3/31/2005"
This batch file will split each line at the first space, and append .png to the string before the split. The script reads lines from infile.txt and outputs to outfile.txt.
#echo off
echo. > outfile.txt
for /f "tokens=1*" %%i in (infile.txt) do echo %%i.png %%j >> outfile.txt
Update
Or to delete the outfile.txt first....
#echo off
del /q /f outfile.txt
for /f "tokens=1*" %%i in (infile.txt) do echo %%i.png %%j >> outfile.txt
Another Update
To just add new records to outfile.txt do something like....
#echo off
for /f "tokens=1*" %%i in (infile.txt) do (
find "%%i.png %%j" outfile.txt > nul
if errorlevel 1 then (
echo %%i.png %%j >> outfile.txt
)
)
Sed for windows
sed -r "s/^(.......)(.*)/\1.png\2/" file
My Answer failed: I did try: but I couldn't get the SET to WORK within the FOR
#echo off
set str1=ooo
set str2=ppp
for /f "tokens=*" %%a in ('type testprog.txt') do (
set str=!%%a!
echo %%str:~0,7%%.png %%str:~-5,14%% >> tempprog.txt
)
move tempprog.txt testprog.txt
start testprog.txt
Maybe someone can edit a working version as I would like to see what
I did wrong...
Related
I have a batch to check the duplicate line in TXT file (over one million line) with 13MB, that will be running over 2hr...how can I speed up that? Thank you!!
TXT file
11
22
33
44
.
.
.
44 (over one million line)
Existing Batch
setlocal
set var1=*
sort original.txt>sort.txt
for /f %%a in ('type sort.txt') do (call :run %%a)
goto :end
:run
if %1==%var1% echo %1>>duplicate.txt
set var1=%1
goto :eof
:end
This should be the fastest method using a Batch file:
#echo off
setlocal EnableDelayedExpansion
set var1=*
sort original.txt>sort.txt
(for /f %%a in (sort.txt) do (
if "%%a" == "!var1!" (
echo %%a
) else (
set "var1=%%a"
)
)) >duplicate.txt
This method use findstr command as in aschipfl's answer, but in this case each line and its duplicates are removed from the file after being revised by findstr. This method could be faster if the number of duplicates in the file is high; otherwise it will be slower because the high volume data manipulated in each turn. Just a test may confirm this point...
#echo off
setlocal EnableDelayedExpansion
del duplicate.txt 2>NUL
copy /Y original.txt input.txt > NUL
:nextTurn
for %%a in (input.txt) do if %%~Za equ 0 goto end
< input.txt (
set /P "line="
findstr /X /C:"!line!"
find /V "!line!" > output.txt
) >> duplicate.txt
move /Y output.txt input.txt > NUL
goto nextTurn
:end
#echo off
setlocal enabledelayedexpansion
set var1=*
(
for /f %%a in ('sort q42574625.txt') do (
if "%%a"=="!var1!" echo %%a
set "var1=%%a"
)
)>"u:\q42574625_2.txt"
GOTO :EOF
This may be faster - I don't have your file to test against
I used a file named q42574625.txt containing some dummy data for my testing.
It's not clear whether you want only one instance of a duplicate line or not. Your code would produce 5 "duplicate" lines if there were 6 identical lines in the source file.
Here's a version which will report each duplicated line only once:
#echo off
setlocal enabledelayedexpansion
set var1=*
set var2=*
(
for /f %%a in ('sort q42574625.txt') do (
if "%%a"=="!var1!" IF "!var2!" neq "%%a" echo %%a&SET "var2=%%a"
set "var1=%%a"
)
)>"u:\q42574625.txt"
GOTO :EOF
Supposing you provide the text file as the first command line argument, you could try the following:
#echo off
for /F "usebackq delims=" %%L in ("%~1") do (
for /F "delims=" %%K in ('
findstr /X /C:"%%L" "%~1" ^| find /C /V ""
') do (
if %%K GTR 1 echo %%L
)
)
This returns all duplicate lines, but multiple times each, namely as often as each occurs in the file.
I found this line of code on this site that echos a text file line by line:
FOR /F %%i IN (filename.txt) DO echo %%i
I am trying to echo a specific line in the text file. How would I accomplish this?
This method get the desired result in a faster way, especially if the file is large.
#echo off
set "line=100"
(for /L %%i in (1,1,%line%) do set /P "result=") < filename.txt
echo %result%
This will echo line 100.
#echo off
set "var=100"
for /f "tokens=1,* delims=:" %%a in ('findstr /n "^" "filename.txt" ^|findstr "^%var%:"') do echo %%b
Lines starting with : will not be complete.
So, I have probably a simple question but I cannot seem to find an easy answer.
Issue: I have a file that contains a set of lines such as:
%windir%\file.exe
%windir%\file2.dll
and so forth...
What I am trying to do is echo the actual file path to a second file such that the resulting output would be something like:
C:\Windows\file.exe
C:\Windows\file2.dll
and so forth...
The actual source file could have other variables such as %programfiles% but all of them have a resulting actual path.
I am currently using a for /f loop but when I echo the variable, I just get the environment variable returned rather than the actual path to the file.
Is there a solution out there for batch scripting?
The actual script is below. Note I am all for making this more efficient as time to get the information is important.
#echo off
setlocal enabledelayedexpansion
reg.exe query "HKLM\System\CurrentControlSet\Services" >> registry_hklm_installed_services_tmp.txt 2>nul
reg.exe query "HKLM\System\ControlSet001\Services" >> registry_hklm_installed_services_tmp.txt 2>nul
reg.exe query "HKLM\System\ControlSet002\Services" >> %temp_outpath%\registry_hklm_installed_services_tmp.txt 2>nul
reg.exe query "HKLM\System\ControlSet002\Services" >> registry_hklm_installed_services_tmp.txt 2>nul
for /f "delims=?" %%a in (registry_hklm_installed_services_tmp.txt) do (
set regkey=%%a
call :getvalue
)
goto :parsereg
:getvalue
reg.exe query "!regkey!\Parameters" /v ServiceDll > nul 2>&1 && goto regkeyexist
goto :eof
:regkeyexist
for /f "tokens=2*" %%b in ('reg.exe query "!regkey!\Parameters" /v ServiceDll') do set ImagePath=%%c
call :regag
goto :eof
:regag
echo !ImagePath! >> registry_hklm_installed_services_tmp2.txt
goto :eof
:parsereg
for /f "delims=?" %%a in (registry_hklm_installed_services_tmp2.txt) do echo %%a >> registry_hklm_installed_services_tmp3.txt
You can use the for /f command to cycle through the lines in the file like you are doing, and pass the line from the file to a subroutine inside the batch file, which will resolve it while it is being passed. Give the following:
Test.txt
%windir%\test.txt
%programfiles%\Test2.txt
This batch file will resolve the environment variables:
#echo off
setlocal ENABLEDELAYEDEXPANSION
for /f "delims=" %%i in (Test.txt) do call :Expand "%%i"
endlocal
goto TheEnd
:Expand
set _var=%1
echo !_var:"=!
:TheEnd
This is how the output looks when you run it:
c:\>Test.bat
C:\Windows\test.txt
C:\Program Files (x86)\Test2.txt
You can redirect the result to a new text file like this:
Test.bat > NewFile.txt
Or you can modify the original Test.bat to output the modified filename under Expand instead of echoing it to the console. It is important to include the quotes around %%i ("%%i") or spaces in the resolved paths will break into multiple variables when calling Expand (e.g., %1, %2, %3, etc.). The !_var:"=! removes the quotes.
This will also expand the variables.
#echo off
for /f "delims=" %%a in (Test.txt) do call echo %%a
pause
Test.txt
%windir%\test.txt
%programfiles%\Test2.txt
#ECHO OFF
SETLOCAL
FOR /f "delims=" %%a IN (q22726616.txt) DO (
FOR /f "delims=" %%b IN ('echo %%a') DO (
ECHO %%b
)
)
GOTO :EOF
I used a file named q22726616.txt containing your data for my testing.
[fixed following response - %%b line]
I have the command below that is supposed to loop through each line in filelist.txt, store the result of the executable in temp.txt and then set IDCH to the single line in temp.txt
for /F "tokens=*" %%A in (d:\fetchdoc\filelist.txt) do (
D:\fetchdoc\filehdr.exe %%A 3 > temp.txt
set /p IDCH=<temp.txt
echo %IDCH%
del temp.txt
)
This is what I get back for each loop with echo on:
D:\fetchdoc\images\export>(
D:\fetchdoc\filehdr.exe 142120_1 3 1>temp.txt
set /p IDCH= 0<temp.txt
echo
del temp.txt
)
ECHO is on.
For some reason, there is a problem when it tries to set the IDCH variable. When I try to echo the variable, I get nothing.
You can avoid using a temp file, taking the result of your binary execution and storeing directly in variable:
#echo off
setlocal enabledelayedexpansion
for /F "tokens=*" %%A in (d:\fetchdoc\filelist.txt) do (
for /F "delims=" %%x in ('D:\fetchdoc\filehdr.exe "%%A" 3') do set IDCH=%%x
echo !IDCH!
)
How to delete last n lines from file using batch script
I don't have any idea about batch files, I am writing batch file for the first time.
How should I write this batch file?
For Windows7
Try it for
<Project_Name>
<Noter>
<Common>
<File>D:\Project_Name\Util.jar</File>
<File>D:\Project_Name\Noter.bat</File>
<File>D:Project_Name\Noter.xml</File>
<File>D:Project_Name\Noter.jar</File>
</Common>
<Project_Name>
<File>D:\Util.bat</File>
<File>D:\Util.xml</File>
<File>D:\log.bat</File>
</Project_Name>
</Noter>
<CCNET>
This the complete script for remove last N line
count the total line
set Line = Line - N , remain just processing lines number
#echo OFF
setlocal EnableDelayedExpansion
set LINES=0
for /f "delims==" %%I in (infile.txt) do (
set /a LINES=LINES+1
)
echo Total Lines : %LINES%
echo.
:: n = 5 , last 5 line will ignore
set /a LINES=LINES-5
call:PrintFirstNLine > output.txt
goto EOF
:PrintFirstNLine
set cur=0
for /f "delims==" %%I in (infile.txt) do (
echo %%I
::echo !cur! : %%I
set /a cur=cur+1
if "!cur!"=="%LINES%" goto EOF
)
:EOF
exit /b
Here call:PrintFirstNLine > output.txt will give the output in an external file name as output.txt
Output for sample Input
<Project_Name>
<CBA_Notifier>
<Common>
<File>D:\CBA\CBA_Notifier\Project_Name\IPS-Util.jar</File>
<File>D:\CBA\CBA_Notifier\Project_Name\Notifier.bat</File>
<File>D:\CBA\CBA_Notifier\Project_Name\Notifier.xml</File>
<File>D:\CBA\CBA_Notifier\Project_Name\Notifier.jar</File>
</Common>
<Project_Name>
<File>D:\CBA\CBA_Notifier\IPS-Util.bat</File>
remove last 5 line
Update
:PrintFirstNLine
set cur=0
for /F "tokens=1* delims=]" %%I in ('type "infile.txt" ^| find /V /N ""') do (
if "%%J"=="" (echo.) else (
echo.%%J
set /a cur=cur+1
)
if "!cur!"=="%LINES%" goto EOF
)
This script will takes 1 arguement, the file to be trunkated, creates a temporary file and then replaces the original file with the shorter one.
#echo off
setlocal enabledelayedexpansion
set count=
for /f %%x in ('type %1 ^| find /c /v ""') do set /a lines=%%x-5
copy /y nul %tmp%\tmp.zzz > nul
for /f "tokens=*" %%x in ('type %1 ^| find /v ""') do (
set /a count=count+1
if !count! leq %lines% echo %%x>>%tmp%\tmp.zzz
)
move /y %tmp%\tmp.zzz %1 > nul
If the original file is 5 or less lines, the main output routine will noT create a file. To combat this, I use the copy /y null to create a zero byte file.
If you would rather not have an empty file, just remove the copy /y nul line, and replace it with the following line:
if %lines% leq 0 del %1
You should use one method or the other, otherwise source files with 5 or less lines will remain untouched. (Neither replaced or deleted.)
to delete last lines from your file,
1 copy starting lines that are needed from file like from- e:\original.txt
2 paste them in new file like- e:\new\newfile1.txt
code is thanks to the person giving me this code:
remember all may be done if you have motive and even blood hb =6. but help of nature is required always as you are a part of it
#echo off & setLocal enableDELAYedeXpansion
set N=
for /f "tokens=* delims= " %%a in (e:\4.txt) do (
set /a N+=1
if !N! gtr 264 goto :did
e:\new4.txt echo.%%a
)
:did
if you have 800 files then use excel to make code for 800 and then copy it to notepad and using Ctrl+h replace space with no space. then rename file as haha.bat . run in folder with files numbered 1.txt 2.txt 3.txt etc. any enquirers welcome Erkamaldev#gmail.com " Long Live Bharata"
A slow method with less coding:
set input=file.txt
set remove=7
for /f "delims=" %i in ('find /c /v "" ^< "%cd%\%input%"') do set lines=%i
set /a lines-=remove
for /l %i in (1,1,!lines!) do findstr /n . log.txt | findstr /b %i:
May be redirected to a file.
Each line is prefixed with the line number; may be removed with extra coding.
A faster version with /g flag in my answer at:
How to split large text file in windows?
Tested in Win 10 CMD, on 577KB file, 7669 lines.