I have one query related to designing WPF using MVVM
Here is the scenario :
1> I have one WPF screen which contains various user controls which are reusable in some other screens too.
2> Can i have separate ViewModel class for each of those user controls , what could be ideal design in this scenario
3> Should i separate my Viewmodel based on individual screen or on UserControls .
4> If i create separate viewmodels based on UserControls how i should integrate it .
Is there any design guidelines around this !!
Urgent Help appreciated ..
This post describes what I do in certain scenario, I don't know if it is a best practice or not but it works for me.
I create ViewModel for my Window that holds all the user controls, so this called ContainerViewModel and I create an instance of that Viewmodel and put it in the DataContext of the Window. From that moment all the UserControls can access that ViewModel with Binding.
The next thing to do is to create a property on my ContainerViewModel for everty UserControl that holds the ViewModel for each UserControl.
Then use binding to attach the usercontrols ViewModel to the DataContext property of the Usercontrol.
example of the viewmodels and a window with 2 listboxes instead of usercontrols:
Viewmodel classes without any implementation but just empty classes to show the concept:
public class ContainerViewModel
{
public ContainerViewModel()
{
ViewModelForControl1 = new Control1ViewModel();
ViewModelForControl2 = new Control2ViewModel();
}
public Control1ViewModel ViewModelForControl1 { get; set; }
public Control2ViewModel ViewModelForControl2 { get; set; }
}
public class Control1ViewModel { }
public class Control2ViewModel { }
Window xaml:
<Window x:Class="ConfigHellp.UI.Windows.ContainerWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:vm="clr-namespace:ConfigHellp.UI.ViewModel"
mc:Ignorable="d"
DataContext="{DynamicResource ContainerViewModel}" >
<Window.Resources>
<vm:ContainerViewModel x:Key="ContainerViewModel" d:IsDataSource="True" />
</Window.Resources>
<StackPanel>
<ListBox DataContext="{Binding ViewModelForControl1}" />
<ListBox DataContext="{Binding ViewModelForControl2}" />
</StackPanel>
</Window>
this depends on how complex the embedding of the UserControl into the environment is. If you think that its to much effort to build the view model logic for your user control again and again (which is also a very nice source for mistakes), you should infact encapsulate the logic in a single viewmodel for your control. If the user control will be an ListItem for example, i generally suggest you to build an own viewmodel for the control.
The infrastructure will be than:
A general viewmodel for your WPF screen, which holds instances of the viewmodels for your usercontrols. That DataContext of the screen will be the general viewmodel. The users controls's DataContext will be a Binding to the PropertyPath of the user control viewmodel in your general viewmodel. e.g:
In WPF Screen:
<ListBox DataContext="{Binding}" ItemsSource="{Binding Path=ItemList}">
<ListBox.ItemTemplate>
<yourControls:YourUserControl />
</ListBox.ItemTemplate>
</ListBox>
In the general viewmodel:
public class ScreenViewModel : INotifyPropertyChanged
{
private ObservableCollection<YourUserControlViewModel> _itemList =
new ObservableCollection<YourUserControlViewModel>();
public ObservableCollection<YourUserControlViewModel> ItemList
{
get { return _itemList; }
set { _itemList = value; }
}
}
This will automatically generate a your user control for each viewmodel in the ItemList of your general view model.
Related
I'm developing WPF MVVM application and I want to create a Window with many panels that changes when user choose another panel from navigation.
I've read this article but it's not working due to Can't put a Page in a Style error. I can't find any answer about how to create a WPF application that navigate through different panels in one single window, how I can achieve what I want using MVVM pattern?
You can place various panels in a Grid, sharing the same space (overlapping) and change Visibility to make "Visible" only the one you want shown.
I've used this thecnique same time ago, and is compatible with MVVM too.
I have created an ContentPresenter and bind it to the MainWindow ViewModel and set the DataTemplate for each ViewModels.
<ContentPresenter Name="WindowContent" Content="{Binding CurrentPageViewModel}"/>
<Window.Resources>
<DataTemplate DataType="{x:Type viewModels:MainViewModel}">
<views:MainView />
</DataTemplate>
</Window.Resources>
And so when the binded property is changed, ContentPresenter display proper ViewModel and due to DataTemplate, the actual View.
public IPageViewModel CurrentPageViewModel
{
get
{
return _currentPageViewModel;
}
set
{
if (_currentPageViewModel != value)
{
_currentPageViewModel = value;
PropertyChanged?.Invoke(this, new PropertyChangedEventArgs("CurrentPageViewModel"));
}
}
}
private IPageViewModel _currentPageViewModel;
Every ViewModel implements simple IPageViewModel interface so only ViewModels could be set as content of ContentPresenter.
I have searched and tried for days and finally must ask the question here.
I have a Silverlight 5 application, Using MVVM Light, where I want to be able to dynamically switch views in the main view.
For the sake of simplicity, lets say I have 2 buttons.
Button1 will switch to TestView1.
Button2 will switch to TestView2.
<Button Content="TestView1" Grid.Column="1" Command="{Binding CallTestView1Command}" HorizontalAlignment="Left" Margin="185,17,0,0" VerticalAlignment="Top" Width="75"/>
<Button Content="TestView2" Grid.Column="1" Command="{Binding CallTestView2Command}" HorizontalAlignment="Left" Margin="280,17,0,0" VerticalAlignment="Top" Width="75"/>
The way I have done it is by binding a relaycommand to the button and then instanciating a new viewmodel of the corresponding view.
ie:
private RelayCommand _callTestView1Command;
public RelayCommand CallTestView1Command
{
get
{
return _callTestView1Command ??
(_callTestView1Command = new RelayCommand(() =>
{
CurrentView = ViewModelLocator.NinjectKernel.Get<TestViewModel1>();
}));
}
}
The CurrentViewmodel is then set to the new viewmodel.
In the MainView I have bound the CurrentView to a ContentControl:
<Border x:Name="displayedView" Grid.Row="2">
<ContentControl Content="{Binding CurrentView}" />
</Border>
This will actually work to some extend, since the CurrentView will change but instead of actually showing the content of the view it simply shows the Namespace of the ViewModel that is instanciated.
So far I have primarily used the knowledge taken from these sources:
http://rachel53461.wordpress.com/2011/05/28/switching-between-viewsusercontrols-using-mvvm/
Loading Views into ContentControl and changing their properties by clicking buttons
but they do not solve my problem, or I do not quite understand how to actually show the views.:-(
So does anyone have a good explanation on how to switch the views correct in Silverlight 5 using MVVM Light from GalaSoft.
Thanks
The part you are missing is the DataTemplates that tell WPF how to render your ViewModels
<Window.Resources>
<DataTemplate TargetType="{x:Type local:TestViewModel1}">
<local:TestView1 />
</DataTemplate>
<DataTemplate TargetType="{x:Type local:TestViewModel2}">
<local:TestView2 />
</DataTemplate>
</Window.Resources>
When you insert an object in the Visual Tree, such as placing a ViewModel object in ContentControl.Content, it will get drawn by default using a TextBlock bound to the .ToString() of the object, which is why you are only seeing the namespace.classname of the ViewModel in your ContentControl
By defining an implicit DataTemplate in your Resources somewhere (that's a DataTemplate with only a TargetType defined - no x:Key), you are telling WPF to draw the specified object using the specified DataTemplate anytime it tries to draw that object, instead of using the default TextBlock bound to the .ToString() of the object.
It should be noted that implicit DataTemplates are not supported in earlier versions of Silverlight, however they are supported in 5.0+. For earlier versions of Silverlight, I usually use a DataTemplateSelector instead.
Id first suggest that you do not display your views via a ContentControl but look into using the navigation Frame in the silverlight toolkit. Also, we dont want our ViewModel creating Views... that'd not be so good. We don't mind, however, if our ViewModel does business logic and DETERMINES which view to show. Get the toolkit here: http://silverlight.codeplex.com/
Now setup your XAML as so in your main page:
<Border x:Name="displayedView" Grid.Row="2">
<navigation:Frame x:Name="ContentFrame" />
</Border>
Since you are using MVVM Light, we will use messaging. Your View model will get the command to change views, determine which view to change, then send a message to the main page to instruct it to change views.
Setup a listener in your main page for a navigate request as so:
public MainPage()
{
InitializeComponent();
Messenger.Default.Register<Uri>(this, "NavigationRequest", (uri) => ContentFrame.Navigate(uri));
}
Next, setup your command in your view model.
private RelayCommand _callTestView1Command;
public RelayCommand CallTestView1Command
{
get
{
return _callTestView1Command ??
(_callTestView1Command = new RelayCommand(() =>
{
Messenger.Default.Send<Uri>(new Uri("/Views/.../Page.xaml", UriKind.Relative), "NavigationRequest");
}));
}
}
These are the basics that work for me. You can expand on this and get real "architecty". For example, you can create a base class for you view models that sends the navigation requests, create a helper class that generates URIs (so they are not hard coded everywhere in your app, etc etc. Good luck!
So i actually solved this problem, in a way where there is no need to create datatemplates in the MainView, which i did not like. imo the MainView should know nothing about the views it is displaying, when we are talking about switching the views.
Prerequisite: You must use MVVM Light from GalaSoft for this solution
This is my test solution:
Two buttons are added to my MainView, Each button will open a new view. The clickevent are bound to Commands.
<Button Content="TestView1" Grid.Column="1" Command="{Binding CallTestView1Command}" HorizontalAlignment="Left" Margin="185,17,0,0" VerticalAlignment="Top" Width="75"/>
<Button Content="TestView2" Grid.Column="1" Command="{Binding CallTestView2Command}" HorizontalAlignment="Left" Margin="280,17,0,0" VerticalAlignment="Top" Width="75"/>
In the MainView i have a Border that should contain the views than can switch.
Since all views inherit from UserControl i bind the content to the property CurrentView of the MainViewModel
<Border x:Name="displayedView" Grid.Row="2">
<UserControl Content="{Binding CurrentView}" />
</Border>
In the MainViewModel i have the property CurrentView.
public const string CurrentViewPropertyName = "CurrentView";
private UserControl _currentView;
/// <summary>
/// Sets and gets the "CurrentView property.
/// Changes to that property's value raise the PropertyChanged event.
/// </summary>
public UserControl CurrentView
{
get
{
return _currentView;
}
set
{
if (_currentView == value)
{
return;
}
RaisePropertyChanging(CurrentViewPropertyName);
_currentView = value;
RaisePropertyChanged(CurrentViewPropertyName);
}
}
When a button is clicked the corresponding Command is called in the MainViewModel:
private RelayCommand _callTestView1Command;
public RelayCommand CallTestView1Command
{
get
{
return _callTestView1Command ??
(_callTestView1Command = new RelayCommand(() =>
{
CurrentView = new TestView1();
}));
}
}
private RelayCommand _callTestView2Command;
public RelayCommand CallTestView2Command
{
get
{
return _callTestView2Command ??
(_callTestView2Command = new RelayCommand(() =>
{
CurrentView = new TestView2();
}));
}
}
As seen each command will set CurrentView to a new view, and the views will switch in the MainView, because CurrentView will raise a ProperTyChanged Event.
This will actually work to some extend, since the CurrentView will
change but instead of actually showing the content of the view it
simply shows the Namespace of the ViewModel that is instanciated.
Because you are changing the CurrentView property to a viewmodel instance and bind that as the Content. This is wrong as the Content should be a view and you should set the DataContext of that view to a viewmodel.
The simplest thing you can do here is to create a View instance inside the command and set the viewmodel as its DataContext and then you can set the view to the CurrentView property. Of course this would violate the MVVM pattern so you should move this responsibility to a separate component. Instead of writing your own navigating logic I suggest you to pick up an existing solution as this kind of task is not as straightforward as it seems.
I suggest to use the Prism library
Part of my app has a month-view calendar interface, but I'm having trouble with item selection. The interface is set up so that each of the days in the view contains a ListBox of items, much like the month view in Outlook. The problem I'm experiencing is that I need to maintain a single item selection across all of the ListBoxes.
Below is a sample that should adequately describe my situation. I need to maintain a single selection between both ListBoxes.
<Window x:Class="StackOverflow.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="MainWindow" Height="350" Width="525">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition />
<ColumnDefinition />
</Grid.ColumnDefinitions>
<ListBox ItemsSource="{Binding Numbers}"
SelectedItem="{Binding SelectedObject"/>
<ListBox Grid.Column="1" ItemsSource="{Binding Dates}"
SelectedItem="{Binding SelectedObject"/>
</Grid>
</Window>
And the view model for the window:
class MainWindowViewModel : DependencyObject
{
public static readonly DependencyProperty SelectedObjectProperty =
DependencyProperty.Register("SelectedObject", typeof(object),
typeof(MainWindowViewModel),
new UIPropertyMetadata(null));
public ObservableCollection<int> Numbers { get; set; }
public ObservableCollection<DateTime> Dates { get; set; }
public object SelectedObject
{
get { return GetValue(SelectedObjectProperty); }
set { SetValue(SelectedObjectProperty, value); }
}
}
In this primitive example, I would expect that when the SelectedObject property of my view model gets set to an item that's not in one ListBox, the selection would be removed in that ListBox, but that doesn't happen. I understand that I can simply name each ListBox, and hook into the SelectionChanged event. I'd prefer to not have to do that with an entire month-view calendar. There has to be a better way.
In a previous iteration of the app, I was able to create a SelectionManager static class with an attached property that was used to maintain selection. However, I can't use this now as the classes I'm using for my items are not DependencyObjects, and I'd really prefer not to have to create DependencyObject wrapper classes as this will considerably complicate my architecture.
Thanks.
EDIT 1: Added a view model class as requested.
Bind both ListBoxes to the same collection (make an observable collection of DatesAndNumber objects or something along those lines) and use converters and/or data templates to get the desired output. Then you can simply set IsSynchronizedWithCurrentItem to true on both ListBoxes to get the desired effect.
Reference: http://msdn.microsoft.com/en-us/library/system.windows.controls.primitives.selector.issynchronizedwithcurrentitem.aspx
how about using ICollectionView and its associated filter ?
here is a link which explains it better
http://marlongrech.wordpress.com/2008/11/22/icollectionview-explained/
I figured it out by creating a separate selection manager class and an ISelectable interface. You can read about the details on CodeProject.
I have created a user control that consists of a expander, listbox and checkboxes. I am not able to access the checkboxes (child control) and I want to generate the number of expanders based on the number of rows in a table dynamically. Can anyone suggest the possible solutions to
This is extremely vague. In most cases you would just expose some of the internal control's properties, e.g. if you want to create dynamic content you would expose the ItemsSource and ItemTemplate of an internal ListBox of whatever you use so it can be set from outside, e.g.
<UserControl x:Class="Test.UserControls.Bogus" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008" Name="control">
<StackPanel>
<TextBlock Text="Lorem Ipsum:" />
<ItemsControl ItemsSource="{Binding ElementName=control, Path=ItemsSource}"
ItemTemplate="{Binding ElementName=control, Path=ItemTemplate}" />
</StackPanel>
</UserControl>
public partial class Bogus : UserControl
{
public static readonly DependencyProperty ItemsSourceProperty = ItemsControl.ItemsSourceProperty.AddOwner(typeof(Bogus));
public IEnumerable ItemsSource
{
get { return (IEnumerable)GetValue(ItemsSourceProperty); }
set { SetValue(ItemsSourceProperty, value); }
}
public static readonly DependencyProperty ItemTemplateProperty = ItemsControl.ItemTemplateProperty.AddOwner(typeof(Bogus));
public DataTemplate ItemTemplate
{
get { return (DataTemplate)GetValue(ItemTemplateProperty); }
set { SetValue(ItemTemplateProperty, value); }
}
public Bogus()
{
InitializeComponent();
}
}
Usage:
<uc:Bogus ItemsSource="{Binding Data}">
<uc:Bogus.ItemTemplate>
<DataTemplate>
<TextBlock Text="{Binding Name}" Foreground="Red" />
</DataTemplate>
</uc:Bogus.ItemTemplate>
</uc:Bogus>
You can of course also encapsulate a lot of logic which you do not need exposed.
Since you want a varying amount of expanders you might have an ItemsControl (unlike a ListBox it has no selection) which already defines an ItemTemplate which contains an expander. You probably can also create a partial template as shown in this answer of mine.
Sounds like you need to navigate the visual tree. The simplest way of doing this is via Linq-to-VisualTree. To find all the CheckBoxes that are a child of 'this', use the following query:
IEnumerable<CheckBox> checks = this.Descendants<CheckBox>().Cast<CheckBox>();
Your application is running in an Application instance. Access the usercontrol components with Application.usercontrol.ComponentName if it is not a UI update. If you make UI updates, you have to run the access in a separate dispatcher thread. In that case, use BackgroundWorker.
For example, I am running my main application class MainWindow and accessing it as,
MainWindow rootWindow = Application.Current.MainWindow as MainWindow;
Now access the usercontrol and properties of components as:
rootWindow.usercontrolX.ComponentY.PropertyZ
Define properties in the child's class for each of those controls. You will be able to access them from the Parent User Control, assuming you have added the Child User Control within the Parent User Control.
Parent User Control.. SingalData is the child User Contol
<my:C1TabItem Header="Signal">
<local:SignalData Width="1036" OnSignalNameChange="SignalInputTab_OnSignalNameChange" Loaded="SignalInputTab_Loaded" Height="353" VerticalAlignment="Top" MinHeight="353" HorizontalAlignment="Left"></local:SignalData>
In the Child User Contorl class, if you have a component named tabProductList you add a property -
public C1.WPF.C1TabControl TabProductList
{
get { return this.tabProductList; }
}
And finally, from your parent class you can reference it as -
C1TabItem tbItem = (C1TabItem)c1TabControl1.SelectedItem;
SignalData sigInp = (SignalData)tbItem.Content;
if (sigInp.TabProductList.SelectedIndex == 0)
{
....
I'm creating a wpf user control which is in mvvm pattern.
So we have : view(with no code in codebehind file), viewmodel,model,dataaccess files.
I have MainWindow.xaml as a view file, which I need to bind with MainWindowModel.cs.
Usually, in a a wpf application we can do this with onStartUp event in App.xaml file. But in user control, as we do not have App.xaml...How do I achieve it ?
Please help :(...Thanks in Advance !!!
You can use a ContentControl, with a DataTemplate to bind the UserControl (View) to the ViewModel :
<DataTemplate DataType="{x:Type vm:MyViewModel}">
<v:MyUserControl />
</DataTemplate>
...
<ContentControl Content="{Binding Current}" />
WPF will pick the DataTemplate automatically based on the type of the Content
I know this is an old, answered question, but I have a different approach. I like to make implicit relationships in the App.xaml file:
<Application.Resources>
<DataTemplate DataType="{x:Type ViewModels:KioskViewModel}">
<Views:KioskView />
</DataTemplate>
</Application.Resources>
With this, there is no need to set a DataContext anywhere.
UPDATE >>>
In response to #Vignesh Natraj's request, here is a fuller explanation:
Once you have set up the DataTemplate in a Resources element, you can display the KioskView in this example by adding an instance of the KioskViewModel anywhere in your XAML. This could be filling the MainWindow, or just inside a particular section of the screen. You could also host multiple instances of the KioskViewModel in a ListBox and it will generate multiple KioskView instances.
You can add an instance of the KioskViewModel to your XAML in a couple of ways, depending on your requirements. One way is to declare the XML namespace for the project that contains the KioskViewModel.cs file and simply add an instance of it in a ContentControl to the page where you want your view to appear. For example, if you had a UserControl called MainView and the KioskViewModel.cs file was in a Kiosk.ViewModels namespace, you could use basic XAML like this:
<UserControl x:Class="Kiosk.Views.MainView"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:ViewModels="clr-namespace:Kiosk.ViewModels">
<UserControl.Resources>
<ViewModels:KioskViewModel x:Key="KioskViewModel" />
<DataTemplate DataType="{x:Type ViewModels:KioskViewModel}">
<Views:KioskView />
</DataTemplate>
</UserControl.Resources>
<ContentControl Content="{StaticResource KioskViewModel}" />
</UserControl>
I prefer to use the MVVM design pattern with WPF, so I would have a base view model class providing useful functionality such as implementing the essential INotifyPropertyChanged interface. I then have a property called ViewModel in the main (top level) view model of type BaseViewModel. This provides me with a nice way to change the ViewModel property to any view model that has derived from BaseViewModel and therefore to be able to change the associated view from the view model.
For example, in the MainViewModel.cs class that is bound to MainView there is a field and relating property:
private BaseViewModel viewModel = new KioskViewModel();
public BaseViewModel ViewModel
{
get { return viewModel; }
set { viewModel = value; NotifyPropertyChanged("ViewModel"); }
}
As you can see, it starts off as a KioskViewModel instance, but can be changed to any other view at any time in response to user interaction. For this setup, the XAML is very similar, but instead of declaring an instance of the view model in the Resources element, we bind to the property in the MainViewModel:
<UserControl x:Class="Kiosk.Views.MainView"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:ViewModels="clr-namespace:Kiosk.ViewModels">
<ContentControl Content="{Binding ViewModel}" />
</UserControl>
Note that for this example, we would need to declare two (or more to make this approach useful) DataTemplates in the App.xaml file:
<Application.Resources>
<DataTemplate DataType="{x:Type ViewModels:MainViewModel}">
<Views:MainView />
</DataTemplate>
<DataTemplate DataType="{x:Type ViewModels:KioskViewModel}">
<Views:KioskView />
</DataTemplate>
</Application.Resources>
I've been using MVVM Light Toolkit which has a ViewModelLocator class that you can put properties to the viewmodels in. You then create a reference to the ViewModelLocator in your Mainwindow.xaml like so:
<vm:ViewModelLocator x:Key="Locator" d:IsDataSource="True"/>
In the grid panel, or whatever you're using, you can then set the datacontext like this:
<Grid DataContext="{Binding MainWindowViewModel, Source={StaticResource Locator}}">
...
</Grid>
You could also go with MEFedMVVM which potentially adds a bit more flexibility in terms of being able to swap different viewModel implementations into the view.
The flexibility in both of these libraries is that you don't have to use their ViewModel base classes if you don't want to - the ViewModelLocator and the MEFedMVVM can work with any class.
There are endless ways to do it, wich all fall in one of the two categories:"view first" or "model first".
In a "view first" mode the view (e.g. your mainwindow) is created first and then (e.g. in the codebehind) the View instantiates the ViewModel and sets it as its datacontext):
private void WindowLoaded(object sender, EventArgs args)
{
this.DataContext = ViewModelService.GetViewModelX();
}
In a "model first" mode the ViewModel is there first and then instanciated the View.
// method of the viewmodel
public void LoadView()
{
// in this example the view abstracted using an interface
this.View = ViewService.GetViewX();
this.View.SetDataContext(this);
this.View.Show();
}
The examples given here are just one way of many. You could look at the various MVVM frameworks and see how they do it.
We can use ObjectDataProvider to call a method inside an object ..as follows :
<ObjectDataProvider ObjectType="{x:Type local:TemperatureScale}"
MethodName="ConvertTemp"
x:Key="convertTemp">
Is there anyway to do the same using DataTemplate
You can probably look at MSDN. I find it as a good resource, though it doesn't explain how to use usercontrols,you will find your way out.