Whats wrong with this trigger? - wpf

I'm learning about WPF templates and I'm creating one for a button. I'm using a trigger to change the Fill property of the Ellipse on 'IsMouseOver'. When I set the trigger to the 'Fill' property directly, it works. But when I try to reference a specific SolidColorBrush, I get a compile error.
This works:
<ControlTemplate x:Key="GhostButtonTemplate" TargetType="Button">
<Grid>
<Ellipse Name="Border" Stroke="DarkGray" Fill="Gray">
</Ellipse>
<ContentPresenter ... />
</Grid>
<ControlTemplate.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter TargetName="Border" Property="Fill" Value="Black"/>
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
This causes error:
<ControlTemplate x:Key="GhostButtonTemplate" TargetType="Button">
<Grid>
<Ellipse Name="Border" Stroke="DarkGray">
<Ellipse.Fill>
<SolidColorBrush Color="Gray" x:Name="FillBrush"/>
</Ellipse.Fill>
</Ellipse>
<ContentPresenter ... />
</Grid>
<ControlTemplate.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter TargetName="FillBrush" Property="Color" Value="Black"/>
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
Error is:
Cannot find the Trigger target
'FillBrush'. (The target must appear
before any Setters,Triggers, or
Conditions that use it.)
Can anyone explain why the second case doesn't work? Thanks.

Rather than naming the brush you use the Ellipse
Edit, yeah you know this :P
<ControlTemplate x:Key="GhostButtonTemplate" TargetType="Button">
<Grid>
<Ellipse Name="Border" Stroke="DarkGray">
<Ellipse.Fill>
<SolidColorBrush Color="Gray" x:Name="FillBrush"/>
</Ellipse.Fill>
</Ellipse>
<ContentPresenter ... />
</Grid>
<ControlTemplate.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter TargetName="Border" Property="Fill" Value="Black"/>
</Trigger>
</ControlTemplate.Triggers>

Related

WPF Textbox Template assistance

I am working on setting up a template for a textbox - and I am running into an issue with setting up the style for the box and am hoping for some assistance. Here is what I have so far:
---
<Window.Resources>
<Style TargetType="{x:Type TextBox}">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type TextBoxBase}">
<Border x:Name="Border">
<ScrollViewer x:Name="PART_ContentHost" Focusable="false" HorizontalScrollBarVisibility="Hidden" VerticalScrollBarVisibility="Hidden"/>
</Border>
<ControlTemplate.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter TargetName="Border">
<Setter.Value>
<Border BorderThickness="1" BorderBrush="Black" CornerRadius="0">
<Border.Background>
<RadialGradientBrush GradientOrigin="0.225,-0.616" RadiusY="0.863" RadiusX="0.757">
<GradientStop Color="#EEFFFFFF"/>
<GradientStop Color="#00FFFFFF" Offset="0.696"/>
</RadialGradientBrush>
</Border.Background>
</Border>
</Setter.Value>
</Setter>
</Trigger>
<Trigger Property="IsKeyboardFocused" Value="True">
</Trigger>
<Trigger Property="IsKeyboardFocused" Value="False">
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
</Window.Resources>
---
When I try to compile this, I get a message stating:
Severity Code Description Project File Line Suppression State
Error MC3000 'The 'Setter' start tag on line 22 position 34 does not match the end tag of 'Trigger'. Line 35, position 31.' XML is not valid.
Anyone have any idea on what I missed here or am doing wrong? I think that I have closed all of the lines correctly.
The setter isn't working quite how you think it is. You're currently creating a border in your template and giving it an x:Name="Border", but then trying to overwrite it in the trigger, with the assumption that it will replace the existing border altogether:
<Setter TargetName="Border">
<Setter.Value>
<Border BorderThickness="1" BorderBrush="Black" CornerRadius="0">
That's not how setters work. Setters need three things:
A reference to an object that you want to modify (although in some cases this is implied).
The name of a property of that object that you wish to modify.
The new value for that property.
You're only providing 1 and 3, hence the error. Instead of trying to replace the border you have to instead modify the properties of the existing border:
<ControlTemplate.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter TargetName="Border" Property="BorderThickness" Value="1" />
<Setter TargetName="Border" Property="BorderBrush" Value="Black" />
<Setter TargetName="Border" Property="CornerRadius" Value="0" />
<Setter TargetName="Border" Property="Background">
<Setter.Value>
<RadialGradientBrush GradientOrigin="0.225,-0.616" RadiusY="0.863" RadiusX="0.757">
<GradientStop Color="#EEFFFFFF"/>
<GradientStop Color="#00FFFFFF" Offset="0.696"/>
</RadialGradientBrush>
</Setter.Value>
</Setter>
</Trigger>
</ControlTemplate.Triggers>
In practice you'd typically wrap all these up in their own style and apply that instead to keep the code clean, but that's an implementation detail.
If you really do want to replace the actual border object then there are ways to do it (e.g. by changing the template itself), but in most cases the above should suffice.

Trigger won't change Background

I'm trying to create a template for buttons in order to prevent the graying of the control when it is disabled, it is working just fine, but for some reason it won't change Backgrounds once I set a colour for it the Button Properties.
Here is the button I made:
<Style TargetType="Button" x:Key="TestButton">
<Setter Property="SnapsToDevicePixels" Value="true" />
<Setter Property="OverridesDefaultStyle" Value="true" />
<Setter Property="MinHeight" Value="29px" />
<Setter Property="MinWidth" Value="103px" />
<Setter Property="Foreground" Value="Black" />
<Setter Property="Background" Value="#EEEEEE"/>
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="Button">
<Border TextBlock.Foreground="{TemplateBinding Foreground}" x:Name="Border">
<Border.Background>
<SolidColorBrush Color="{TemplateBinding Background}" />
</Border.Background>
<Border.BorderBrush>
<SolidColorBrush Color="Black" />
</Border.BorderBrush>
<Border.BorderThickness>
<Thickness Top="0.75" Bottom="0.75" Right="0.75" Left="0.75"/>
</Border.BorderThickness>
<Border.CornerRadius>
<CornerRadius TopLeft="3" TopRight="3" BottomLeft="3" BottomRight="3"/>
</Border.CornerRadius>
<ContentPresenter Margin="2"
HorizontalAlignment="Center"
VerticalAlignment="Center"
RecognizesAccessKey="True" />
</Border>
<!--Triggers-->
<ControlTemplate.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Background" Value="#E1F3FD" />
</Trigger>
<Trigger Property="IsPressed" Value="True">
<Setter Property="Background" Value="#C4E9FF" />
<Setter Property="Effect">
<Setter.Value>
<DropShadowEffect Color="Black" Direction="500" ShadowDepth="1" BlurRadius="5" Opacity="0.5" />
</Setter.Value>
</Setter>
</Trigger>
<Trigger Property="IsEnabled" Value="false">
<Setter TargetName="Border" Property="Background" Value="{Binding RelativeSource={RelativeSource AncestorType=Button}, Path=Background}"/>
<Setter Property="Opacity" Value="0.5" />
</Trigger>
<Trigger Property="IsEnabled" Value="True" >
<Setter TargetName="Border" Property="Background" Value="{Binding RelativeSource={RelativeSource AncestorType=Button}, Path=Background}" />
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
When I call it gives me two diferent results, the one that works is the following:
<Button Style="{DynamicResource ResourceKey=TestButton}" Content="Button" Height="66" Name="button1" Width="149" Click="button1_Click" />
But when I add a Background to it, it stops changing Backgrounds for some reason:
<Button Style="{DynamicResource ResourceKey=TestButton}" Background="Orange" Content="Button" Height="66" Name="button1" Width="149" Click="button1_Click" />
It wont change the color because you "overlay" the color with the color you defined in MainWindow.xaml.
Its called dependency property value precedence.
To read more about it take a look at this:
http://msdn.microsoft.com/en-us/library/ms743230.aspx
What happens in your case is that you defined a background in style and in trigger but then you set the value in MainWindow. The value set in MainWindow is considered the local value and the ones set in style are "style - values".
If you take a look at the link I gave you you will see that local value comes first before "style - values".
Local values are very powerful.
That is why your Button will always be Orange even when disabled. The property system will try to find a value for the background when your trigger fires and it will always find the local one because that is the value with the highest prority.
In order to make this work properly you will have to use SetCurrentValue instead of SetValue when setting the value of Button's background. (Means you will have to override Buttons code)
Take a look at this:
http://msdn.microsoft.com/en-us/library/system.windows.dependencyobject.setcurrentvalue.aspx
This method is used by a component that programmatically sets the value of one of its own properties without disabling an application's declared use of the property. The SetCurrentValue method changes the effective value of the property, but existing triggers, data bindings, and styles will continue to work.
Edit:
Example to understand dependency property value precedence and hit testing.
<Window.Resources>
<Style TargetType="{x:Type Grid}">
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Background" Value="Yellow" />
</Trigger>
</Style.Triggers>
</Style>
<Style TargetType="{x:Type TextBlock}">
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Background" Value="Red" />
</Trigger>
</Style.Triggers>
</Style>
</Window.Resources>
<Grid>
<TextBlock Height="20" Margin="40" Text="asdfasdfa" VerticalAlignment="Bottom"/>
<Rectangle Height="100" VerticalAlignment="Bottom" >
<Rectangle.Fill>
<LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0">
<GradientStop Offset="0"/>
<GradientStop Color="White" Offset="1"/>
</LinearGradientBrush>
</Rectangle.Fill>
</Rectangle>
</Grid>
If you look at DependecyProperty value precedence order you will see that setting a value explicitly (treated as local value) on a control will override any values set by the trigger.
Just a note: the Background property is of type Brush, so you should write
<Border Background="{TemplateBinding Background}" ...>
...
</Border>
instead of
<Border ...>
<Border.Background>
<SolidColorBrush Color="{TemplateBinding Background}" />
</Border.Background>
...
</Border>

How do you change Background for a Button MouseOver in WPF?

I have a button on my page with this XAML:
<Button Content="Button" HorizontalAlignment="Left" VerticalAlignment="Bottom"
Width="50" Height="50" HorizontalContentAlignment="Left"
BorderBrush="{x:Null}" Foreground="{x:Null}" Margin="50,0,0,0">
<Button.Style>
<Style TargetType="Button">
<Setter Property="Background" Value="Green"/>
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Background" Value="Red"/>
</Trigger>
</Style.Triggers>
</Style>
</Button.Style>
</Button>
But when I put mouse over my button, button's background changes to default windows gray background.What's The Problem?
This is the button picture before and after mouseover:
Before:
After:
To remove the default MouseOver behaviour on the Button you will need to modify the ControlTemplate. Changing your Style definition to the following should do the trick:
<Style TargetType="{x:Type Button}">
<Setter Property="Background" Value="Green"/>
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type Button}">
<Border Background="{TemplateBinding Background}" BorderBrush="Black" BorderThickness="1">
<ContentPresenter HorizontalAlignment="Center" VerticalAlignment="Center"/>
</Border>
</ControlTemplate>
</Setter.Value>
</Setter>
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Background" Value="Red"/>
</Trigger>
</Style.Triggers>
</Style>
EDIT: It's a few years late, but you are actually able to set the border brush inside of the border that is in there. Idk if that was pointed out but it doesn't seem like it was...
All of the answers so far involve completely replacing the default button behavior with something else. However, IMHO it is useful and important to understand that it's possible to change just the part you care about, by editing the existing, default template for a XAML element.
In the case of dealing with the hover effect on a WPF button, the change in appearance in a WPF Button element is caused by a Trigger in the default style for the Button, which is based on the IsMouseOver property and sets the Background and BorderBrush properties of the top-level Border element in the control template. The Button element's background is underneath the Border element's background, so changing the Button.Background property doesn't prevent the hover effect from being seen.
With some effort, you could override this behavior with your own setter, but because the element you need to affect is in the template and not directly accessible in your own XAML, that approach would be difficult and IMHO overly complex.
Another option would be to make use the graphic as the Content for the Button rather than the Background. If you need additional content over the graphic, you can combine them with a Grid as the top-level object in the content.
However, if you literally just want to disable the hover effect entirely (rather than just hiding it), you can use the Visual Studio XAML Designer:
While editing your XAML, select the "Design" tab.
In the "Design" tab, find the button for which you want to disable the effect.
Right-click that button, and choose "Edit Template/Edit a Copy...". Select in the prompt you get where you want the new template resource to be placed. This will appear to do nothing, but in fact the Designer will have added new resources where you told it, and changed your button element to reference the style that uses those resources as the button template.
Now, you can go edit that style. The easiest thing is to delete or comment-out (e.g. Ctrl+E, C) the <Trigger Property="IsMouseOver" Value="true">...</Trigger> element. Of course, you can make any change to the template you want at that point.
When you're done, the button style will look something like this:
<p:Style x:Key="FocusVisual">
<Setter Property="Control.Template">
<Setter.Value>
<ControlTemplate>
<Rectangle Margin="2" SnapsToDevicePixels="true" Stroke="{DynamicResource {x:Static SystemColors.ControlTextBrushKey}}" StrokeThickness="1" StrokeDashArray="1 2"/>
</ControlTemplate>
</Setter.Value>
</Setter>
</p:Style>
<SolidColorBrush x:Key="Button.Static.Background" Color="#FFDDDDDD"/>
<SolidColorBrush x:Key="Button.Static.Border" Color="#FF707070"/>
<SolidColorBrush x:Key="Button.MouseOver.Background" Color="#FFBEE6FD"/>
<SolidColorBrush x:Key="Button.MouseOver.Border" Color="#FF3C7FB1"/>
<SolidColorBrush x:Key="Button.Pressed.Background" Color="#FFC4E5F6"/>
<SolidColorBrush x:Key="Button.Pressed.Border" Color="#FF2C628B"/>
<SolidColorBrush x:Key="Button.Disabled.Background" Color="#FFF4F4F4"/>
<SolidColorBrush x:Key="Button.Disabled.Border" Color="#FFADB2B5"/>
<SolidColorBrush x:Key="Button.Disabled.Foreground" Color="#FF838383"/>
<p:Style x:Key="ButtonStyle1" TargetType="{x:Type Button}">
<Setter Property="FocusVisualStyle" Value="{StaticResource FocusVisual}"/>
<Setter Property="Background" Value="{StaticResource Button.Static.Background}"/>
<Setter Property="BorderBrush" Value="{StaticResource Button.Static.Border}"/>
<Setter Property="Foreground" Value="{DynamicResource {x:Static SystemColors.ControlTextBrushKey}}"/>
<Setter Property="BorderThickness" Value="1"/>
<Setter Property="HorizontalContentAlignment" Value="Center"/>
<Setter Property="VerticalContentAlignment" Value="Center"/>
<Setter Property="Padding" Value="1"/>
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type Button}">
<Border x:Name="border" BorderBrush="{TemplateBinding BorderBrush}" BorderThickness="{TemplateBinding BorderThickness}" Background="{TemplateBinding Background}" SnapsToDevicePixels="true">
<ContentPresenter x:Name="contentPresenter" Focusable="False" HorizontalAlignment="{TemplateBinding HorizontalContentAlignment}" Margin="{TemplateBinding Padding}" RecognizesAccessKey="True" SnapsToDevicePixels="{TemplateBinding SnapsToDevicePixels}" VerticalAlignment="{TemplateBinding VerticalContentAlignment}"/>
</Border>
<ControlTemplate.Triggers>
<Trigger Property="IsDefaulted" Value="true">
<Setter Property="BorderBrush" TargetName="border" Value="{DynamicResource {x:Static SystemColors.HighlightBrushKey}}"/>
</Trigger>
<!--<Trigger Property="IsMouseOver" Value="true">
<Setter Property="Background" TargetName="border" Value="{StaticResource Button.MouseOver.Background}"/>
<Setter Property="BorderBrush" TargetName="border" Value="{StaticResource Button.MouseOver.Border}"/>
</Trigger>-->
<Trigger Property="IsPressed" Value="true">
<Setter Property="Background" TargetName="border" Value="{StaticResource Button.Pressed.Background}"/>
<Setter Property="BorderBrush" TargetName="border" Value="{StaticResource Button.Pressed.Border}"/>
</Trigger>
<Trigger Property="IsEnabled" Value="false">
<Setter Property="Background" TargetName="border" Value="{StaticResource Button.Disabled.Background}"/>
<Setter Property="BorderBrush" TargetName="border" Value="{StaticResource Button.Disabled.Border}"/>
<Setter Property="TextElement.Foreground" TargetName="contentPresenter" Value="{StaticResource Button.Disabled.Foreground}"/>
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
</p:Style>
(Note: you can omit the p: XML namespace qualifications in the actual codeā€¦I provide them here only because the Stack Overflow XML code formatter gets confused by <Style/> elements that don't have a fully-qualified name with XML namespace.)
If you want to apply the same style to other buttons, you can just right-click them and choose "Edit Template/Apply Resource" and select the style you just added for the first button. You can even make that style the default style for all buttons, using the normal techniques for applying a default style to elements in XAML.
This worked well for me.
Button Style
<Style x:Key="TransparentStyle" TargetType="{x:Type Button}">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="Button">
<Border>
<Border.Style>
<Style TargetType="{x:Type Border}">
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Background" Value="DarkGoldenrod"/>
</Trigger>
</Style.Triggers>
</Style>
</Border.Style>
<Grid Background="Transparent">
<ContentPresenter></ContentPresenter>
</Grid>
</Border>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
Button
<Button Style="{StaticResource TransparentStyle}" VerticalAlignment="Top" HorizontalAlignment="Right" Width="25" Height="25"
Command="{Binding CloseWindow}">
<Button.Content >
<Grid Margin="0 0 0 0">
<Path Data="M0,7 L10,17 M0,17 L10,7" Stroke="Blue" StrokeThickness="2" HorizontalAlignment="Center" Stretch="None" />
</Grid>
</Button.Content>
</Button>
Notes
The button displays a little blue cross, much like the one used to close a window.
By setting the background of the grid to "Transparent", it adds a hittest, which means that if the mouse is anywhere over the button, then it will work. Omit this tag, and the button will only light up if the mouse is over one of the vector lines in the icon (this is not very usable).
Just want to share my button style from my ResourceDictionary that i've been using.
You can freely change the onHover background at the style triggers.
"ColorAnimation To = *your desired BG(i.e #FFCEF7A0)". The button BG will also automatically revert to its original BG after the mouseOver state.You can even set how fast the transition.
Resource Dictionary
<Style x:Key="Flat_Button" TargetType="{x:Type Button}">
<Setter Property="Width" Value="100"/>
<Setter Property="Height" Value="50"/>
<Setter Property="Margin" Value="2"/>
<Setter Property="FontFamily" Value="Arial Narrow"/>
<Setter Property="FontSize" Value="12px"/>
<Setter Property="FontWeight" Value="Bold"/>
<Setter Property="Cursor" Value="Hand"/>
<Setter Property="Foreground">
<Setter.Value>
<SolidColorBrush Opacity="1" Color="White"/>
</Setter.Value>
</Setter>
<Setter Property="Background" >
<Setter.Value>
<SolidColorBrush Opacity="1" Color="#28C2FF" />
</Setter.Value>
</Setter>
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type Button}">
<Border x:Name="border"
SnapsToDevicePixels="True"
BorderThickness="1"
Padding="4,2"
BorderBrush="Gray"
CornerRadius="3"
Background="{TemplateBinding Background}">
<Grid>
<ContentPresenter
Margin="2"
HorizontalAlignment="Center"
VerticalAlignment="Center"
RecognizesAccessKey="True" />
</Grid>
</Border>
</ControlTemplate>
</Setter.Value>
</Setter>
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="true">
<Trigger.EnterActions>
<BeginStoryboard>
<Storyboard>
<ColorAnimation To="#D2F898"
Storyboard.TargetProperty="(Control.Background).(SolidColorBrush.Color)"
FillBehavior="HoldEnd" Duration="0:0:0.25" AutoReverse="False" RepeatBehavior="1x"/>
</Storyboard>
</BeginStoryboard>
</Trigger.EnterActions>
<Trigger.ExitActions>
<BeginStoryboard>
<Storyboard>
<ColorAnimation
Storyboard.TargetProperty="(Control.Background).(SolidColorBrush.Color)"
FillBehavior="HoldEnd" Duration="0:0:0.25" AutoReverse="False" RepeatBehavior="1x"/>
</Storyboard>
</BeginStoryboard>
</Trigger.ExitActions>
</Trigger>
</Style.Triggers>
</Style>
all you have to do is call the style.
Example Implementation
<Button Style="{StaticResource Flat_Button}" Height="Auto"Width="Auto">
<StackPanel>
<TextBlock Text="SAVE" FontFamily="Arial" FontSize="10.667"/>
</StackPanel>
</Button>
A slight more difficult answer that uses ControlTemplate and has an animation effect
(adapted from https://learn.microsoft.com/en-us/dotnet/framework/wpf/controls/customizing-the-appearance-of-an-existing-control)
In your resource dictionary define a control template for your button like this one:
<ControlTemplate TargetType="Button" x:Key="testButtonTemplate2">
<Border Name="RootElement">
<Border.Background>
<SolidColorBrush x:Name="BorderBrush" Color="Black"/>
</Border.Background>
<Grid Margin="4" >
<Grid.Background>
<SolidColorBrush x:Name="ButtonBackground" Color="Aquamarine"/>
</Grid.Background>
<ContentPresenter HorizontalAlignment="{TemplateBinding HorizontalContentAlignment}" VerticalAlignment="{TemplateBinding VerticalContentAlignment}" Margin="4,5,4,4"/>
</Grid>
<VisualStateManager.VisualStateGroups>
<VisualStateGroup x:Name="CommonStates">
<VisualState x:Name="Normal"/>
<VisualState x:Name="MouseOver">
<Storyboard>
<ColorAnimation Storyboard.TargetName="ButtonBackground" Storyboard.TargetProperty="Color" To="Red"/>
</Storyboard>
</VisualState>
<VisualState x:Name="Pressed">
<Storyboard>
<ColorAnimation Storyboard.TargetName="ButtonBackground" Storyboard.TargetProperty="Color" To="Red"/>
</Storyboard>
</VisualState>
</VisualStateGroup>
</VisualStateManager.VisualStateGroups>
</Border>
</ControlTemplate>
in your XAML you can use the template above for your button as below:
Define your button
<Button Template="{StaticResource testButtonTemplate2}"
HorizontalAlignment="Center" VerticalAlignment="Center"
Foreground="White">My button</Button>
Hope it helps
For change button style
1st: define resource styles
<Window.Resources>
<Style x:Key="OvergroundIn" TargetType="Button">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="Button">
<Grid Background="#FF16832F">
<ContentPresenter TextBlock.Foreground="White" TextBlock.TextAlignment="Center" Margin="0,8,0,0" ></ContentPresenter>
</Grid>
</ControlTemplate>
</Setter.Value>
</Setter>
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="Button">
<Grid Background="#FF06731F">
<ContentPresenter TextBlock.Foreground="White" TextBlock.TextAlignment="Center" Margin="0,8,0,0" ></ContentPresenter>
</Grid>
</ControlTemplate>
</Setter.Value>
</Setter>
</Trigger>
</Style.Triggers>
</Style>
<Style x:Key="OvergroundOut" TargetType="Button">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="Button">
<Grid Background="#FFF35E5E">
<ContentPresenter TextBlock.Foreground="White" TextBlock.TextAlignment="Center" Margin="0,8,0,0" ></ContentPresenter>
</Grid>
</ControlTemplate>
</Setter.Value>
</Setter>
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="Button">
<Grid Background="#FFE34E4E">
<ContentPresenter TextBlock.Foreground="White" TextBlock.TextAlignment="Center" Margin="0,8,0,0" ></ContentPresenter>
</Grid>
</ControlTemplate>
</Setter.Value>
</Setter>
</Trigger>
</Style.Triggers>
</Style>
</Window.Resources>
2nd define button code
<Border Grid.Column="2" BorderBrush="LightGray" BorderThickness="2" CornerRadius="3" Margin="2,2,2,2" >
<Button Name="btnFichar" BorderThickness="0" Click="BtnFichar_Click">
<Button.Content>
<Grid>
<TextBlock Margin="0,7,0,7" TextAlignment="Center">Fichar</TextBlock>
</Grid>
</Button.Content>
</Button>
</Border>
3th code behind
public void ShowStatus()
{
switch (((MainDto)this.DataContext).State)
{
case State.IN:
this.btnFichar.BorderBrush = new SolidColorBrush(Color.FromRgb(243, 94, 94));
this.btnFichar.Style = Resources["OvergroundIn"] as Style;
this.btnFichar.Content = "Fichar Salida";
break;
case State.OUT:
this.btnFichar.BorderBrush = new SolidColorBrush(Color.FromRgb(76, 106, 83));
this.btnFichar.Style = Resources["OvergroundOut"] as Style;
this.btnFichar.Content = "Fichar Entrada";
break;
}
}

How are WPF Buttons and TextBlock styles related?

I have a custom style for my 'default' Buttons, and also created a custom style for TextBlocks. If I remove the TextBlock style entirely, everything works fine, but once the TextBlock styling is added in for some reason the Button style is used on the Button's text 'default' state. It seems like some kind of inheritance is going on here but I can't see where in the msdn docs. What's going on?
I'm using Expression Blend 4-- and also another odd thing is that the preview in Blend looks fine, but when I RUN the application, the button styles are incorrect in their default state. Here's the styles which seem to be conflicting:
<ResourceDictionary>
<Style TargetType="{x:Type Button}">
<Style.Triggers>
<Trigger Property="IsMouseOver"
Value="True">
<Setter Property="Foreground">
<Setter.Value>
<LinearGradientBrush StartPoint="0.5,0" EndPoint="0.5,1">
<GradientStop Color="White" Offset="0"/>
<GradientStop Color="#FFFDFF00" Offset="1"/>
</LinearGradientBrush>
</Setter.Value>
</Setter>
<Setter Property="RenderTransformOrigin" Value="0.5,0.5"/>
<Setter Property="RenderTransform">
<Setter.Value>
<TransformGroup>
<ScaleTransform ScaleY="1.20" ScaleX="1.20"/>
<SkewTransform/>
<RotateTransform/>
<TranslateTransform/>
</TransformGroup>
</Setter.Value>
</Setter>
</Trigger>
</Style.Triggers>
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type Button}">
<Grid>
<ContentPresenter RecognizesAccessKey="True" SnapsToDevicePixels="{TemplateBinding SnapsToDevicePixels}">
<ContentPresenter.Effect>
<DropShadowEffect BlurRadius="3" ShadowDepth="4"/>
</ContentPresenter.Effect>
</ContentPresenter>
</Grid>
<ControlTemplate.Triggers>
<Trigger Property="IsFocused" Value="True"/>
<Trigger Property="IsDefaulted" Value="True"/>
<Trigger Property="IsMouseOver" Value="True"/>
<Trigger Property="IsPressed" Value="True"/>
<Trigger Property="IsEnabled" Value="False"/>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
<Setter Property="FontFamily" Value="/Rtk;component/Fonts/#Segoe Print"/>
<Setter Property="FontWeight" Value="Bold"/>
<Setter Property="FontSize" Value="18"/>
<Setter Property="Foreground" Value="White"/>
<Setter Property="HorizontalAlignment" Value="Center"/>
<Setter Property="VerticalAlignment" Value="Center"/>
<Setter Property="Background" Value="{x:Null}"/>
</Style>
<Style TargetType="{x:Type TextBlock}">
<Setter Property="TextWrapping" Value="NoWrap"/>
<Setter Property="TextTrimming" Value="None"/>
<Setter Property="Foreground" Value="White"/>
<Setter Property="FontSize" Value="16"/>
<Setter Property="Effect">
<Setter.Value>
<DropShadowEffect BlurRadius="3" ShadowDepth="4"/>
</Setter.Value>
</Setter>
<Setter Property="FontFamily" Value="/Rtk;component/Fonts/#Segoe Print"/>
</Style>
</ResourceDictionary>
This is how I am using the Button control itself:
<Button Content="Button Text" FontSize="24"/>
(note that this fontsize is different from the size I specified in the default style, 18 - I want to override it in this button's case)
Edit:
The actual button entry looks like this in MainWindow.xaml, there's no other customizations other than the style changes I posed from App.xaml:
<Button Content="Button" HorizontalAlignment="Left" Margin="336,0,0,274.226" VerticalAlignment="Bottom" Width="75"/>
To illustrate what I'm seeing:
Just a fast wild guess, but when the content of a button is a string, isn't it default a textblock?
As people have suggested, your Button contains a Textblock created to hold the content, it is picking up the style from app.xaml, you can work around this in a few ways, here are a couple:
Put an explicit textblock into your button, and apply no style:
<Button Margin="272,192,277,0" VerticalAlignment="Top">
<TextBlock Text="Button" Style="{x:Null}"/>
</Button>
Put a textblock into your button style, also with a null style:
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type Button}">
<Grid>
<TextBlock Text="{TemplateBinding Content}" Style="{x:Null}">
<TextBlock.Effect>
<DropShadowEffect BlurRadius="3" ShadowDepth="4"/>
</TextBlock.Effect>
</TextBlock>
</Grid>
<ControlTemplate.Triggers>
<Trigger Property="IsFocused" Value="True"/>
<Trigger Property="IsDefaulted" Value="True"/>
<Trigger Property="IsMouseOver" Value="True"/>
<Trigger Property="IsPressed" Value="True"/>
<Trigger Property="IsEnabled" Value="False"/>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
Hopefully one of those 2 will work for you.
Looking only ay the code you posted, I can't see how the TextBlock Style would in any way influence the appearance of the Buttons - unless the Content of the Buttons consists (directly or indirectly) of TextBlocks. Can you post a more complete code sample, possibly including the Button's XAML?

How can I set a property of a DropShadowEffect via a Trigger in a ControlTemplate?

I have a Button ControlTemplate and I'm trying to modify a DropShadowEffect on a Border by using a Trigger. Here is my Xaml:
<Button.Template>
<ControlTemplate TargetType="Button">
<Border x:Name="ButtonBorder" Margin="10" CornerRadius="5" Background="Gray">
<Border.Effect>
<DropShadowEffect ShadowDepth="5" x:Name="BorderEffect" />
</Border.Effect>
<ContentPresenter HorizontalAlignment="Center" />
</Border>
<ControlTemplate.Triggers>
<Trigger Property="Button.IsMouseOver" Value="True">
<Setter Property="Background" TargetName="ButtonBorder" Value="LightGray" />
</Trigger>
<Trigger Property="Button.IsPressed" Value="True">
<Setter Property="Margin" TargetName="ButtonBorder" Value="13,13,7,7" />
<!-- this is where I get the error -->
<Setter Property="ShadowDepth" TargetName="BorderEffect" Value="2" />
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Button.Template>
I get an error stating that the BorderEffect cannot be found.
I have also tried:
<Setter Property="Effect.ShadowDepth" TargetName="ButtonBorder" Value="2" />
But I also get an error telling me that the property ShadowDepth could not be found on the object of type Effect (because it's using the base class instead of DropShadowEffect)
How can I solve this?
You can set the Effect as a whole in the setter.value
<Setter Property="Margin" TargetName="ButtonBorder" Value="13,13,7,7" />
<Setter Property="Effect" TargetName="ButtonBorder" >
<Setter.Value>
<DropShadowEffect ShadowDepth="2" />
</Setter.Value>
</Setter>
</Trigger>

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