I have a table in which comma seprated id of another table i want to use the following query in cakephp in proper form with find function
"select * from special_offers where find_in_set('".$storeId."', stores) and user_id = '". $userId ."'";
Use like this
$data = $this->SpecialOffer->find('all',array('conditions' => array('SpecialOffer.user_id' => $userId ,'FIND_IN_SET(\''. $storeId .'\',SpecialOffer.stores1)')));
Hope this may help you
i am beginner in cakephp , and i want use SQL IN operator in find method , i have words table.
my code is :
$this->Word->find('Word.wordid in (83,82)');
, and this code create this query :
SELECT `Userword`.`userwordid`, `Userword`.`userid`, `Userword`.`wordid`,
`Userword`.`date`, `Userword`.`levelid` FROM `userwords` AS `Userword` WHERE
`Userword`.`wordid` = (82)
but i need this query
SELECT `Userword`.`userwordid`, `Userword`.`userid`, `Userword`.`wordid`,
Userword`.`date`, `Userword`.`levelid` FROM `userwords` AS `Userword` WHERE
`Userword`.`wordid` IN (83,82)
how can getting like this query (using IN operator )
thanks.
you need to let cake take care of that - simply use it as it was a string (but make sure it is an array):
$arrayOfIds = [1, 5, ...];
$this->Word->find('all', array(
'conditions' => array('Word.wordid' => $arrayOfIds)
));
I'd like to insert data into a mysql table using 'the cakephp way'.
I have a multi-stage program that stores data to a session, and toward the end of the program I'd like to write the session data to the database. I could do this using a standard sql insert statement but would like to know how this should be done using cakephp. (Most of the cakephp doc discusses sending data from a webform, and I'd like to manually submit session data.)
Should I manually format the session data in this format and then send this to the model? And if so, is there a helper function for this?
Array
(
[ModelName] => Array
(
[fieldname1] => 'value'
[fieldname2] => 'value'
)
)
Yes, that's the way to do it. There's really no need for a helper function, just use the ones you normally would.
$name = 'Foo';
$city = 'Bar';
$this->ModelName->save(
array(
'name' => $name,
'city' => $city
)
);
I'm trying to do a Cakephp Find query, and I'm having a little where clausule:
$pending = $this->Transaction->find('all', array('conditions' => array('Transaction.amount >' => 'Transaction.recieved')));
I'd expect it would generate something like this:
SELECT * From `transactions` as `Transaction` WHERE `Transaction`.`amount` > `Transaction`.`recieved`
However, it's producing the following SQL:
SELECT * From `transactions` as `Transaction` WHERE `Transaction`.`amount` > 'Transaction.recieved'
Notice the small difference between
`Transaction`.`recieved`
and
'Transaction.recieved'
Why is this? My SQL query is failing now.
Cake has no way of knowing that you didn't intend to use a string (i.e. it's syntactically identical to for example array( 'Transaction.name' => 'foo' )). It works if you give the condition as a single string:
'conditions' => array( 'Transaction.amount > Transaction.received' )
I am facing a problem while fetching values using paginate function in cakephp. In the "to" field of message I have CSV fields of userid. To search messages for a single user. I am using the code below...
$this->set('message', $this->paginate('Message', array(
'or'=> array(
"Message.to LIKE" => "".$this->Session->read('Auth.User.id').",",
"Message.to LIKE" => ",".$this->Session->read('Auth.User.id').","
)
)));
But the query is formed in this manner which is not what I want.. I want to two conditions with OR condition.
SELECT `Message`.`id`, `Message`.`timestamp`, `Message`.`to`, `Message`.`from`,
`Message`.`message`, `Message`.`subject`, `Message`.`urgent`, `Message`.`read`,
`Message`.`tag`, `Message`.`open`, `Message`.`reply_id`, `User`.`id`,
`User`.`fname`, `User`.`lname`, `User`.`user`, `User`.`password`,
`User`.`photo`, `User`.`created`, `User`.`access`, `User`.`login`,
`User`.`status`, `User`.`role`
FROM `messages` AS `Message`
LEFT JOIN `users` AS `User` ON (`Message`.`to` = `User`.`id`)
WHERE `Message`.`to` LIKE ',1,'
ORDER BY `Message`.`timestamp` desc
LIMIT 5
The problem is that your conditions array stumbles across a PHP limitation: an array can not have two keys with the same name.
'or'=> array(
"Message.to LIKE" => "".$this->Session->read('Auth.User.id').",",
"Message.to LIKE" => ",".$this->Session->read('Auth.User.id').","
)
You are using the key "Message.to LIKE" twice, so only the last one gets used.
The workaround looks like this:
'or'=> array(
array("Message.to LIKE" => $this->Session->read('Auth.User.id') . ","),
array("Message.to LIKE" => "," . $this->Session->read('Auth.User.id') . ",")
)
Oh, and you should seriously think about a) database normalization and b) code readability.
I think part of the problem might be that he is using LIKE with only the literal exact match syntax.
If any of the following assumptions are incorrect then ignore this..
But it seems like you are searching for user#domain.tld in the to string and having to attach an 'or' condition to match the case where the recipient is listed as a single email address in a string of comma separated email addresses...
I don't think cake adds the '%' character to LIKE queries automagically so perhaps you could try adding it to the query. This should make it match both cases with a single condition in the find call.
<?php
... snip ...
'conditions' => array(
"Message.to LIKE" => "%" . $this->Session->read( 'Auth.User.id' ) . "%"
),
... snip ...
?>
Just make the condition into an array
$this->set('message', $this->paginate('Message', array(
"Message.to LIKE" => array("".$this->Session->read('Auth.User.id').",",",".$this->Session->read('Auth.User.id').",")
)));